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Calculate the fundamental frequency of a sonometer wire fo length 20cm, tension 25N, cross sectional area `10^(-2)cm^(2)` and density of material `=10^(4)kg//m^(3)`. |
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Answer» `v_(1)=?l=20cm=(1)/(5)m,T=25N,` `a=10^(2)cm^(2)=10^(-6)m^(2), rho=10^(4)kg//m^(3)` Mass per unit length of wire, `m=axx1xxrho=10^(-6)xx1,rho=10^(4)=10^(-2)kgm^(-1)` `v_(1)=(1)/(2l)sqrt((T)/(m))=(1)/(2xx1//5)sqrt((25)/(10^(-2)))=(5)/(2)xx50` `=125Hz` |
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