1.

At what temperature will the speed of sound be double its value at 273K?

Answer» `T_(2)=?T_(2)=273K, v_(2)=2v_(1)`
As `(v_(2))/(v_(1))=sqrt((T_(2))/(T_(1)))=2, T_(2)=4T_(1)=4xx273`
`T_(2)=1092K`


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