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An oscillating cirucuit consits of capacitance `C=10 mu F`, inductance `L=25 Mh`, and active resistance `R=1.0 Omega. ` How mancy oscilaltion periods does it take for the current amplitude to decrease e`-` fold ? |
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Answer» Current decreases `e` fold in time `t=(1)/(beta)=(2L)/(R) sec=(2L)/(RT) ` oscillations `=(2L)/(R)(omega)/( 2pi)` `=(L)/(piR)sqrt((1)/(LC)-(R^(2))/(4L^(2)))=(1)/(2pi)sqrt((4L)/( R^(2)C)-1)=15.9` oscillations |
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