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An organ pipe is in resonance with a tuning fork. What change will have to be made in the length l to maintain resonance if (i) temperature increases (ii) air is replaced by hydrogen (iii) pressure is made higher ? |
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Answer» If organ pipe is open, its fundamental frequency is `v=(upsilon)/(2l)=(1)/(2l)sqrt((lambdaP)/(rho))` (i) If temperature increase , `upsilon` increases. To keep v constant, l must be incresed. (ii) When air is replaced by hydrogen, `rho` decreases. To keep v constant, l must be increased. (iii) When pressure is made higher, `rho` increases and `P//rho` remains constant. Therefore, no change is required in resonance length. |
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