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An incident wave is represented by `y(x,t)=20sin(2x-4t)`. Write the expression for reflected wave (i) from a rigid boundary (ii) from an open boundary. |
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Answer» (i) The wave reflected from rigid boudnary is `y(x,t)=-20sin(-2x-4t)` `=20sin(2x+4t)` (ii) The wave reflected from open boundary is `y(x,t)=20sin(-2x-4t)` `=-20sin(2x+4t)`. |
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