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An edge of a variable cube is increasing at therate of 3 cm per second. How fast is the volume of the cube increasing whenthe edge is 10 cm long? |
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Answer» Let x be the edge of cube and V be the volume. Given ` (dx)/(dt) = 3 cm//sec` Now ,` V=x^(3) rArr (dV)/(dt) = 3x^(2)(dx)/(dt)` at x = 10 cm ` (dV)/(dt) = 3 xx 10^(2) xx 3 = 900 cm^(3)//sec` |
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