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A wire having a linear mass density of `5.0xx10^(-3)kgm^(-1)` is stretched between two rigid supports with a tension of 45N. The wire resonates at a frequency of 420Hz. The next higher frequency at which the wire resonates is 490Hz. Find the length of the wire. |
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Answer» Suppose the wire vibratees at a frequency of 420 Hz is nth harmonic and at a frequency of 490 Hz in `(n+10)` the harmonic. As, `v=(n)/(2l)sqrt((T)/(m)):. 420=(n)/(2l)sqrt((T)/(m))` …(i) `490=(n+1)sqrt((T)/(m))` `:. (490)/(420)=(n+1)/(n) :. n=6` From (i) , `420=(6)/(2l)sqrt((450)/(5xx10^(-3)))=(900)/(l)` `l=(900)/(420)=2.1m` |
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