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A wave, `y_( `(x, t)`)=0.03 sin pi(2t-0.01x)` tavels in a medium. Here, `x` is in metre. The instantaneous phase differenc ( in rad) between the two point separated by `25cm` isA. `pi//800`B. `pi//400`C. `pi//200`D. `pi//100` |
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Answer» Correct Answer - B `y=0.03sinpi(2t-0 .01x)` `=0.03sin(2pit-0.01pix)` …(i) Comparting it with the equation `y=rsin (omegat-(2pi)/(lambda)x)`, we have `(2pi)/(lambda)=0.01pi` or `lambda-(2)/(0.01)=200m` Phase diff, `Deltaphi=(2pi)/(lambda)Deltax=(2pi)/(200)xx(25)/(100)=(pi)/(400)rad` |
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