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A wave travelling along a string is given by `y(x,t)=0.05 sin (40x-5t)`, in which numerical constants are in SI units. Calculate the displacement at distance 35 cm from origin, and time 10 sec. |
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Answer» The given equation is `y(x,t)=0.05sin(40x-5t)` Compare it with standard form `y=rsin((2pi)/(lambda)x-(2pit)/(T))` `r=0.05m,, (2pi)/(lambda)=40radm^(-1),(2pi)/(T)=5rad//s` `lambda=(2pi)/(40)=(pi)/(20)m=15.7cm` `T=(2pi)/(5)s=1.26s` `v=(1)/(T)=(5)/(2pi)=0.8Hz` At `x=35cm=0.35m and t=10s,` `y=0.05 sin (40xx0.35-5xx10)` `=0.05sin(-36)=-0.05sin36metre` |
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