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A tuning fork of frequency 220Hz produces sound waves of wavelength 1.5m in air at NTP. Calculate the increase in wavelength, when temperature of air in `27^(@)C`. |
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Answer» Here,`v=220Hz. lambda _(0)=1.5m.` Speed of sound at N.T.P, `v_(0)=vlambda_(0)=220xx1.5=330m//s` Now, `T=27^(@)C=(27+273)K=300K` If v is speed of sound in air at 300K. Then `v=v_(0)sqrt((T)/(T_(0)))=330xxsqrt((300)/(273))` `=330xx1.048=345.93m//s` wavelength of sound waves at 300K. `lambda=(upsilon)/(v)=(345.93)/(220)=1.57m` `:.` Increase in wavelength `=lambda-lambda_(0)` `=1.57-1.5=0.07m` |
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