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A transverse wave is represented by the equation `y=y_0sin.(2pi)/(lamda)(vt-x)` For what value of `lamda`, the maximum particle velocity equal to two times the wave velocity?A. `lambda=2piy_(0)`B. `lambda=(piy_(0))/(3)`C. `lambda=(piy_(0))/(2)`D. `lambda=piy_(0)` |
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Answer» Correct Answer - D Particle velocity `=(dy)/(dt)=[y_(0)cos((2pip)/(lambda))(upsilont-x)](2pi)/(lambda)upsilon` `((dy)/(dt))_(max)=y_(0)(2piupsilon)/(lambda)=2upsilon` `lambda=piy_(0)` |
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