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A transverse harmonic wave on a string is described by `y(x,t)=3.0 sin (36t+0.018x +pi//4)`, where x and y are in cm and t is in s. The positive direction of x is from left to right.A. The wave is travelling from right to left.B. The speed of the wave is `20m//s`C. Frequency of the wave is 5.7 HzD. The least distance betweent two successive crests in the wave is 2.5cm |
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Answer» Correct Answer - A::B::C The given equation is `y(x,t)=3.0sin [36t+0.018x+(pi)/(4)]` (a As positive direction is from left to right and x positive, therefore, wave is travelling from right to left. (b) Compare the given equation with the standard form `y=rsin[(2pit)/(T)+(2pix)/(lambda0+phi)]` `(2pi)/(T)=36, (2pi)/(lambda)=0.018` speed of wave, `upsilon=(lambda)/(T)=(36)/(0.018)=2000cm//s=20m//s` (c) Again, `T=(2pi)/(36)=(pi)/(18)` Frequency, `v=(1)/(V)=(18)/(pi)Hz=5.7Hz` |
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