Saved Bookmarks
| 1. |
A slab consists of two layers of different materials of the same thickness and having thermal conductivities `K_(1)` and `K_(2)`. The equivalent thermal conductivity of the slab isA. K1 + K2B. K1 + K2/2C. 2K1 + K2 /K1 + k2D. K1 + K2/2KK2 |
|
Answer» Correct Answer - B `(K_(eq))_(11)= (k_(1)+k_(2))/2` |
|