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A set of 25 tuning forks is arranged in order of decreasing frequency. Each fork gives 3 beats with succeding one. The first fork is octave of the last. Calculate the frequency of the first and 16th fork. |
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Answer» Let frequency of last fork be n. `:.` Freq. of 1st fork `=2n,` freq. of 2nd fork `=[2n-3],` freq. of 3rd fork `(2n-6)` `=2n-3(3-1) ` and so on `:.` freq. of 25th fork `=2n-3(25-1)=n` `:.` `n=72` Hence, freq. of 1st fork `=2n=144Hz` and freq. of 16th fork `=144-3(16-1)` `=99Hz` |
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