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A person deep inside water cannot hear sound produced in air. Why? |
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Answer» As speed of sound in water is roughly four times the speed of sound in air, therefore `mu=(sini)/(sinr)=(v_(a))/(v_(w))=(1)/(4)=0.25` For refraction, `r_(max)=90^(@)` `:. (sini)_(max)=0.25` `:. i_(max)=sin^(-1)(0.25)~~1.4^(@).` That is why most of sound produced in air and falling at `/_igt14^(@)` gets reflected in air only and person deep inside water cannot hear the sound. |
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