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A parallel beam of light of wavelength `6000Å` gets diffracted by a single slit of width 0.3 mm. The angular position of the first minima of diffracted light is :A. `6xx10^(-3)` radB. `1.8xx10^(-3)` radC. `3xx10^(-3)` radD. `2xx10^(-3)` rad |
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Answer» Correct Answer - D We have d `sin theta =n lambda` `0.3xx10^(-3) xx theta=6000xx10^(-10)` The angular position ` theta=2xx10^(-3)` rad |
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