1.

A ball of mass 200 grams falls from height of 5 meter ? What is its kinetic energy when it just reaches the ground ? (g = 9.18 ms-2 )

Answer»

m = 200 grams 

= 0.2 kg 

h = 5 m u 

= 0 v = 7 

 v2 -u2 = 2gh 

v2– 02 = 2 x 9.8 x 5 

v2 = 98 

kinetic energy, KE = \(\frac{1}{2}mv^2\)

\(\frac{1}{2} \times \frac{200}{1000}\) x 98 

= 9.8 joule



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