A bag contains 8 white, 5 black and 4 blue balls. One ball is drawn ra

1.	A bag contains 8 white, 5 black and 4 blue balls. One ball is drawn randomly, what is the probability that it is neither white nor blue ball?1. 5/172. 8/173. 4/174. 6/17
Answer» Correct Answer - Option 1 : 5/17 Given: Total number of balls in box = (4 blue + 5 black + 8 white) balls = 17 balls Formula used: Probability of event = (Number of favourable outcomes)/(Total number of outcomes) Calculations: Let, E1 = event of picking a white ball E2 = event of picking a blue ball Then, P(E1 ) = 8/17 P(E2) = 4/17 ⇒ Probability of picking a cap that it is either blue or white = 4/17 + 8/17 = 12/17 the probability that it is neither white nor blue ball = 1 -12/17 = 5/17 ∴ The probability that it isneither white nor blue ball is 5/17

A bag contains 8 white, 5 black and 4 blue balls. One ball is drawn randomly, what is the probability that it is neither white nor blue ball?1. 5/172. 8/173. 4/174. 6/17

Answer» Correct Answer - Option 1 : 5/17

Given:

Total number of balls in box = (4 blue + 5 black + 8 white) balls = 17 balls

Formula used:

Probability of event = (Number of favourable outcomes)/(Total number of outcomes)

Calculations:

Let,

E1 = event of picking a white ball

E2 = event of picking a blue ball

Then,

P(E1 ) = 8/17

P(E2) = 4/17

⇒ Probability of picking a cap that it is either blue or white = 4/17 + 8/17 = 12/17

the probability that it is neither white nor blue ball = 1 -12/17 = 5/17

∴ The probability that it isneither white nor blue ball is 5/17

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