A bag contain 8 pink ball and 6 green ball, If 2 ball are picked up th

1.	A bag contain 8 pink ball and 6 green ball, If 2 ball are picked up then what is the probability of both are of same colour?1. 91/1112. 43/913. 21/474. 43/97
Answer» Correct Answer - Option 2 : 43/91 Given: Pink ball = 8 Green ball = 6 Formula used: ⁿC_r = n!/((n-r)! × r!) P(A) = n(E)/n(S) where, n(E) → Required events, n(S) = Sample space Calculation: Let S be the sample space then, n(S) be the number of ways to select 2 ball from 14 ball of the same colour n(S) = ¹⁴C₂ ⇒ n(S) = (14 × 13)/2 ⇒ 91 Let E be the event of getting 2 ball of same colour n(E) = ⁸C₂ +⁶C₂ ⇒ (8 × 7)/2 + (6 × 5)/2 ⇒ 28 + 15 ⇒ 43 P(A) = n(E)/n(S) ⇒ P(A) = 43/91 ⇒ 43/91 ∴ The probability of getting both balls of same colour is 43/91.

A bag contain 8 pink ball and 6 green ball, If 2 ball are picked up then what is the probability of both are of same colour?1. 91/1112. 43/913. 21/474. 43/97

Answer» Correct Answer - Option 2 : 43/91

Given:

Pink ball = 8

Green ball = 6

Formula used:

ⁿC_r = n!/((n-r)! × r!)

P(A) = n(E)/n(S)

where, n(E) → Required events, n(S) = Sample space

Calculation:

Let S be the sample space then,

n(S) be the number of ways to select 2 ball from 14 ball of the same colour

n(S) = ¹⁴C₂

⇒ n(S) = (14 × 13)/2

⇒ 91

Let E be the event of getting 2 ball of same colour

n(E) = ⁸C₂ +⁶C₂

⇒ (8 × 7)/2 + (6 × 5)/2

⇒ 28 + 15

⇒ 43

P(A) = n(E)/n(S)

⇒ P(A) = 43/91

⇒ 43/91

∴ The probability of getting both balls of same colour is 43/91.

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