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A 0.2kg of mass hangs at the end of a spring. When 0.002kg more mass is added to the end of the spring, it stretches 7 cm more. If the 0.02 kg mass is removed what will be the period of vibration of the system?

Answer» `k=(F)/(x)=(0.02xx9.8)/(0.07)=2.8N//m`
`T=2pisqrt((m)/(k))=2pisqrt((0.2)/(2.8))=1.68s `


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