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7^(3+j) mod 19 =(a) 7^j mod 19(b) 1 mod 19(c) 7^3 + 7^j mod 19(d) All of the mentioned are trueI had been asked this question during a job interview.This is a very interesting question from Number Theory topic in division More Number Theory of Cryptograph & Network Security

Answer»

The correct CHOICE is (a) 7^j mod 19

To explain I would say: 7^(3+j)mod 19 = 7^3 * 7^j mod 19 = 7^j mod 19 ( since 7^3 mod 19 = 1 ).



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