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12 g of gas occupy a volume of `4xx10^(-3) m^(3)` at a temperature of `76^(@)C`.after the gas is heated at constant pressure, its density becomes `6xx10^(-4) g//cm^(3)`.What is the temperature to which the gas was heated?A. 1000 KB. 1400 KC. 1200 KD. 800 K |
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Answer» Correct Answer - B Volume at `7^(@)C = 4xx10^(-3)m^(3)` Let it be heated to x K. `Volume =(12)/(6xx10^(-4))cm^(3)=2xx10^(4)cm^(3)` Since, `V/T=constant` `therefore` " " `(4xx10^(-3))/(280)=(2xx10^(-2))/(x)` `therefore`" " `x=(2xx10^(-2)xx280)/(4xx10^(-3)=1400 K` |
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