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1). x < y2). x > y3). x = y OR the relationship cannot be determined.4). x ≤ y |
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Answer» I. x2 – 12x + 35 = 0 ⇒ x2 – 5X – 7x + 35 = 0 ⇒ x(x – 5) – 7(x – 5) = 0 ⇒ (x – 7) (x – 5) = 0 ⇒ x = 7 OR x = 5 ⇒ y2 – 7y – 9y + 63 = 0 ⇒ y (y – 7) – 9(y – 7) = 0 ⇒ (y – 9) (y – 7) = 0 ⇒ y = 9 OR y = 7 So, when x = + 7, x = y when y = 7 and x < y when y = 9. And when x = 5, x < y when y = 7 and x < y when y = 9. ∴ x ≤ y. |
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