1.

1). x < y2). x > y3). x = y OR the relationship cannot be determined.4). x ≤ y

Answer»

I. x2 – 12x + 35 = 0

⇒ x25X – 7x + 35 = 0

⇒ x(x – 5) – 7(x – 5) = 0

⇒ (x – 7) (x – 5) = 0

⇒ x = 7 OR x = 5

II. y216Y + 63 = 0

⇒ y2 – 7y – 9y + 63 = 0

⇒ y (y – 7) – 9(y – 7) = 0

⇒ (y – 9) (y – 7) = 0

⇒ y = 9 OR y = 7

So, when x = + 7, x = y when y = 7 and x < y when y = 9.

And when x = 5, x < y when y = 7 and x < y when y = 9.

∴ x ≤ y. 



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