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1). 503/5902). 497/5903). 500/6904). 400/690 |
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Answer» TOTAL number of balls = 40 + 20 = 60 Total number of events = 60C2 Probability of getting both red balls = 40C2/60C2 Probability of getting UNDAMAGED ball = 50C2/60C2 Probability of getting undamaged red ball = 32C2/60C2 ∴ Probability of REQUIRE condition = [40C2 + 50C2– 32C2]/60C2 = [40 × 39 + 50 × 49 – 32 × 31]/[60 × 59] = [1560 + 2450 - 992]/3540 = 3018/3540 = 503/590 |
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