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51.

Write temperature difference in terms of heat capacity and heat energy?(a) ΔT = q/C(b) ΔT = qC(c) ΔT = C/q(d) ΔT = qm/CThe question was asked in unit test.Question is from Thermodynamics Applications in division Thermodynamics of Chemistry – Class 11

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Right option is (a) ΔT = Q/C

Explanation: As we know that q = CΔT, where q is the heat energy, C is the specific heat and ΔT is the TEMPERATURE difference, When the temperature difference is expressed in TERMS of the heat capacity and heat energy, it is given as ΔT = q/C.

52.

The specific heat at constant pressure is given by the expression ____________(a) CV = dq/dT(b) CP = dq/dT(c) CV = dqdt(d) CP = dq/dtThis question was addressed to me during an internship interview.This interesting question is from Thermodynamics Applications topic in section Thermodynamics of Chemistry – Class 11

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Correct option is (b) CP = DQ/dT

To elaborate: As we know that dq = CdT; where Q is the heat energy, C is the SPECIFIC heat and T is the temperature. At constant pressure, specific heat is given as CP. The specific heat at constant pressure is given by the expression CP = dq/dt.

53.

If gas is expanded freely from 1 litre to 5 litres at a temperature of 60-degree centigrade what is the work done?(a) Positive(b) Negative(c) 0(d) InfinityI got this question by my school principal while I was bunking the class.The question is from Thermodynamics Applications topic in division Thermodynamics of Chemistry – Class 11

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Right answer is (c) 0

The best I can explain: When gas is expanded freely in a vacuum there is ZERO pressure exerted. The formula for WORK done is given by pressure X change in volume = 0 x 4. So the work done is zero in the process of FREE expansion.

54.

What is the difference in heat capacities at constant volume and pressure?(a) Universal volume constant(b) Universal gas constant(c) Universal pressure constant(d) Universal temperature constantI had been asked this question during a job interview.My question comes from Thermodynamics Applications topic in chapter Thermodynamics of Chemistry – Class 11

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Correct OPTION is (B) Universal gas constant

To elaborate: We all KNOW that ΔH = ΔU + nRΔT; ΔH = nCPΔT and ΔU = nCvΔT; ΔH – ΔU = nCPΔT – nCvΔT = n(CP – CV) ΔT. By equating L.H.S. and R.H.S., we get n(CP – CV) ΔT = nRΔT; CP – CV = R. Hence it’s PROVEN that difference of heat capacities at constant volume and pressure is the universal gas constant.

55.

The value of the product of a universal gas constant and the temperature difference is given by 10 kJ/mol at 1 mole and the internal energy is given by 20 KJ, what is the enthalpy of this system in KJ?(a) 30(b) 10(c) 20(d) 200The question was asked in class test.My question comes from Thermodynamics Applications topic in chapter Thermodynamics of Chemistry – Class 11

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Correct answer is (a) 30

For explanation I WOULD say: We know that ΔH = ΔU + nRΔT; where ΔHis the enthalpy, ΔU is the internal energy, n is the number of moles, R is the UNIVERSAL gas CONSTANT and ΔT is the temperature DIFFERENCE. So enthalpy is 10 KJ + 20KJ = 30 KJ.

56.

Which of the following is an intensive property?(a) Volume(b) Colour(c) Enthalpy(d) Internal energyThis question was posed to me by my college director while I was bunking the class.This key question is from Thermodynamics Applications in section Thermodynamics of Chemistry – Class 11

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The correct answer is (b) Colour

To ELABORATE: An INTENSIVE property does not depend on the quantity or size of the object, whereas extensive property depends on the quantity and size of the object. Here VOLUME, enthalpy and INTERNAL ENERGY are extensive properties, while colour is an intensive property.

57.

6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?(a) 30 Newton metre(b) 80 Newton metre(c) 50 Newton metres(d) 20 Newton metreThis question was posed to me in an international level competition.This intriguing question comes from Thermodynamics Applications in section Thermodynamics of Chemistry – Class 11

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The correct CHOICE is (d) 20 NEWTON metre

To elaborate: The expression for work DONE is given by pressure x volume difference, here an ideal gas has a volume difference of 4 litres at 5 ATM pressure. So the work done = 10 – 6 litersx 5ATM = 20 Newton metre.

58.

Expansion of gas under zero pressure is free expansion.(a) True(b) FalseI got this question during an interview for a job.I'm obligated to ask this question of Thermodynamics Applications topic in section Thermodynamics of Chemistry – Class 11

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Right option is (a) True

Explanation: The EXPANSION of a gas in a VACUUM without PRESSURE is called free expansion. During the free expansion of gas, the work is not done WHETHER the process is reversible or Irreversible. So the above statement is considered to be true.

59.

When the pressure of 3 atm is exerted over a surface area of a 10-metre square, what is a force that is applied?(a) 30 Newton(b) 3.33 Newton(c) 0.33 Newton(d) 0.3 NewtonThe question was posed to me in an online interview.The doubt is from Thermodynamics Applications in section Thermodynamics of Chemistry – Class 11

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Right choice is (a) 30 Newton

Easy explanation: Force is defined as the product of pressure and the surface area so here as pressure is 3 atm and surface area is 10-metre SQUARE. The force that is APPLIED EQUALS 3 atm x 10-metre square = 30 Newton.

60.

When an ideal gas is compressed in a piston using 5 atm of pressure through a 50-metre cube of volume, what is the amount of work done?(a) 10 Newton metre(b) 0.1 Newton metre(c) 250 Newton metre(d) 55 Newton metreI got this question at a job interview.This interesting question is from Thermodynamics Applications topic in section Thermodynamics of Chemistry – Class 11

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The CORRECT option is (c) 250 Newton metre

Best explanation: When a PRESSURE P is exerted through a volume V the work done is given by P ΔV, so here pressure is 5 atm and volume is a 50-metre cube. The work that is done is 5 atm X 50-metre cube = 250 Newton metre.

61.

The temperature of an object increases slowly, then the energy of that object _________(a) increases slowly(b) decreases quickly(c) increases quickly(d) decreases slowlyThe question was asked in an interview for job.My question is based upon Thermodynamic Terms in chapter Thermodynamics of Chemistry – Class 11

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Right ANSWER is (a) INCREASES SLOWLY

To explain: Energy of a substance is directly PROPORTIONAL to its temperature. As we know that HEAT energy of a substance is q = mcΔT. If the temperature increases slowly then the energy also increases slowly.

62.

If the work is done on an adiabatic wall, then which of the following is true?(a) ΔU = -W(b) ΔU = W(c) ΔU + W = 0(d) ΔU = -WThis question was posed to me by my school teacher while I was bunking the class.I want to ask this question from Thermodynamic Terms topic in chapter Thermodynamics of Chemistry – Class 11

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The correct option is (b) ΔU = W

To explain: In an adiabatic process, the total energy is always zero. We have that ΔH = ΔU + W, as ΔH is zero, we get ΔU + W = 0; ΔU = -W. But as work is done on the SYSTEM by OBSERVING no heat W BECOMES NEGATIVE, so ΔU = -(-)W = W. Hence ΔU = W.

63.

An open system allows the transfer of ________(a) only mass(b) only energy(c) both mass and energy(d) neither mass nor energyI have been asked this question in class test.Asked question is from Thermodynamic Terms in portion Thermodynamics of Chemistry – Class 11

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Correct option is (c) both mass and energy

The BEST explanation: An open system allows the TRANSFER of both mass and energy into the system from the surroundings. An example of an open system is the HUMAN BODY, we consume food, energy and excrete waste.

64.

The first law of thermodynamics states that the energy of an isolated system is constant.(a) true(b) falseThis question was posed to me in final exam.This intriguing question originated from Thermodynamic Terms in section Thermodynamics of Chemistry – Class 11

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Correct option is (a) true

For explanation I would SAY: The FIRST LAW of thermodynamics is commonly stated as the law of conservation of energy that is energy can neither be created nor be destroyed, in other terms we can also say that the energy of an ISOLATED system is constant.

65.

Both isolated and closed systems are the same.(a) True(b) FalseI got this question in class test.Question is from Thermodynamic Terms topic in division Thermodynamics of Chemistry – Class 11

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Right answer is (b) FALSE

The explanation: An OPEN system allows only energy transfer whereas an isolated system neither allows energy nor mass transfer through the system from the SURROUNDINGS. Isolated and CLOSED systems are not the same. So the above STATEMENT is false.

66.

An adiabatic process pressure is related to volume as _________(a) PV = constant(b) PV^γ constant(c) PV^3 constant(d) PV^2 constantThe question was posed to me in examination.The question is from Thermodynamic Terms topic in section Thermodynamics of Chemistry – Class 11

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The correct choice is (B) PV^γ constant

Easy EXPLANATION: Let P is pressure and V is volume whereas Gamma is the ratio of specific HEAT capacity at constant pressure and volume. The relation between pressure and volume in an adiabatic process is GIVEN by PV^γ constant.

67.

In an adiabatic process the work done is 50 KJ, what is its internal energy?(a) 50 KJ(b) 25 KJ(c) -50 KJ(d) -25 KJThe question was posed to me in exam.The question is from Thermodynamic Terms in division Thermodynamics of Chemistry – Class 11

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The correct option is (c) -50 KJ

To elaborate: The TOTAL energy in an adiabatic process is zero, so internal energy is equal to the NEGATIVE of the work DONE. Here work done is given by 50 kilojoules, so the internal energy is -50 kilojoules as the SUM of internal energy and the work done should be zero.

68.

The system that does not allow the heat to pass through its boundary between the system and surroundings is called as ______________ system.(a) adiabatic(b) open(c) isothermal(d) closeThis question was posed to me in unit test.This interesting question is from Thermodynamic Terms topic in portion Thermodynamics of Chemistry – Class 11

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The CORRECT option is (a) adiabatic

Explanation: An adiabatic system does not allow the EXCHANGE of heat between system and surroundings. Energy is TRANSFERRED to the surrounding only through work Done. In the adiabatic process, the TOTAL energy is given as zero.

69.

Which of the following property cannot be used to describe the state of a system?(a) pressure(b) volume(c) temperature(d) universal gas constantI have been asked this question in semester exam.I'm obligated to ask this question of Thermodynamic Terms topic in division Thermodynamics of Chemistry – Class 11

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Correct option is (d) universal gas constant

Explanation: State functions are used to specify the state of a thermodynamic system. The state is described by measurable macroscopic particles like PRESSURE, TEMPERATURE, VOLUME, amount, etc and the is P, V and T are called state VARIABLES.

70.

When work is done on system or by a system there is a change in _________(a) external energy(b) internal energy(c) adiabatic energy(d) isothermal energyThe question was asked in final exam.My query is from Thermodynamic Terms in section Thermodynamics of Chemistry – Class 11

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Correct answer is (b) internal energy

To explain: When a WORK is done or by the system, heat passes into out of the system and matter ENTERS or leaves the system, there is a change in internal energy of the system. It is REPRESENTED by the symbol “U”.