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1051.

An echo is heard after 0.8 seconds, when a person fires a cracker 132.8 m from a high building. Calculate the speed of sound.

Answer»

Given, 

Time for echo = 0.8 sec 

Height of building = 132.8 m 

Distance travelled by sound = 2×height 

Distance travelled = 2×132.8 = 265.6 m

Speed of Sound = \(\frac{distance}{time}\) = \(\frac{265.6}{0.8}\) = 332ms-1

1052.

A radar sends a signal to an aeroplane at a distance 45 km away with a speed of 3 × 108 m s-1. After how much time is the signal received back from the aeroplane?

Answer»

Velocity = 2D/Time

3 × 108 = 2 x 45 x 1000/ Time

Time = 90000/ 3 × 108 = 3 × 10-4 second

1053.

A ship on the surface of water sends a signal and receives it back froma a submarine inside water after 4 s. Calculate the distance of the submarine from the ship. (The speed of sound in water is 1450 m s-1)

Answer»

2 D = velocity × time

D = (velocity × time) / 2 = 1450 × 4 / 2 = 2900 m = 2.9 km

1054.

A man standing 48 m away from a wall fires a gun calculate the time after which an echo is heard. (The speed of sound in air is 320 m s-1).

Answer»

Velocity = 2 × D/Time

Time after which an echo is heard = 2 D/Velocity = 2 × 48 / 320 = 0.3 seconds

1055.

The speed of sound is 310ms-1. A person fires a gun. An echo is heard after 1.5s. Calculate the distance of person from the cliff from which echo is heard.

Answer»

Speed of sound = 310ms-1 

time after which echo is heard t = 1.5s distance from cliff d = ? 

2d = Speed × t

1056.

An enemy plane is at a distance of 300km from a radar. In how much lime the radar will be able to detect the plane? Take velocity of radiowaves as 3 × 108ms-1 . 

Answer»

d=300 t = ? v = 3 × 108ms-1 

t=2d/v = 2 × 300 × 1000m/3 ×108 ms-1 

= 0.002 s = 2 × 10-3s

1057.

Why an echo is not heard when distance between source of sound and reflecting body is 10 m?

Answer»

A sound persists in our ear for 0.1 s. At temperature 22℃ in air and speed of sound 344 ms-1, the total distance covered by sound between the point of generation and reflecting surface should be at least (344 m/s) x 0.1 s = 34.4 m. Thus, the minimum distance between the point of generation and reflecting surface should be half of it i.e. 17.2 m. So, we cannot hear the echo in a smaller room of 10 m.

1058.

At normal temperature, for an echo to be heard the reflecting surface should be at a minimum distance of …………m.(A) 34.4 (B) 17.2 (C) 10 (D) 20

Answer»

Correct option is: (B) 17.2

1059.

Why is sound heard more clearly through solids?

Answer»

Transmission of sound occurs at a different speed through different mediums. Transmission of sound is faster through a solid than through a liquid and gas.

1060.

The frequency of sound waves which can be heard by human is _______.A. less than 20 HzB. greater than 20 kHzC. between 20 Hz and 20 kHzD. None of these

Answer» Correct Answer - C
1061.

Hertz is a unit of: (A) frequency (B) wavelength (C) wave speed (D) displacement

Answer»

The answer is (A) frequency

1062.

Which of the following frequency of sound can be heard by a dog but not by a man? (a) 50,000 hertz (b) 15,000 hertz.

Answer»

(a) 50,000Hz can be heard by dog but not human being.

1063.

The amplitude of a sound is doubled and the frequency is reduced to one fourth the intensity of sound at the same point will be: (A) increased by a factor of 2 (B) increased by a factor of 4 (C) decreased by a factor of 2 (D) decreased by a factor of 4

Answer»

The answer is (D) decreased by a factor of 4

1064.

Can sound travel through vacuum?

Answer»

No, sound cannot travel through vacuum.

1065.

Two astronauts cannot hear each other on the moon. Why?

Answer»

Sound is a mechanical wave and requires a medium to propagate. As the moon has no atmosphere, it has an absence of air. So, there is no medium for sound to propagate. So, two astronauts cannot hear each other on the moon.

1066.

Name the type of waves which are used by astronauts to communicate with one another on moon.

Answer»

Astronauts use radio waves for communications.

1067.

The frequency of the waves used in ultrasonography is: (A) 20 Hz (B) Below 20 Hz (C) 20 Hz to 20000 Hz (D) Above 20000 Hz

Answer»

The answer is (B) Below 20 Hz

1068.

Give scientific reason:Astronauts on the moon cannot hear each other directly.

Answer»

Two astronauts on the moon talking to each other directly, will be unable to listen to each other, even if they are very close to each other. The moon does not have atmosphere. Since there is no medium which is necessary for generation and propagation of sound, between the astronauts, direct sound propagation between them is not possible. Therefore, the astronauts use some technology like the one used in our cell-phones to communicate with each other. The waves used in cell-phone do not need any medium for propagation.

1069.

The minimum time required to hear an echo, (A) 0.1 S (B) 0.5 S (C) 1 S (D) 2 S

Answer»

The answer is (A) 0.1 S

1070.

The region of minimum density through which a wave propagates is called: (A) Compression (B) Rarefaction (C) Crest (D) Trough

Answer»

The answer is (B) Rarefaction

1071.

Give scientific reason:As the sound wave propagates from one place to the other in air, the air itself is not required to move from one place to the other.

Answer»

Propagation of sound through air occurs due to energy transfer by vibrating air molecules in one region to those in the adjacent region away from the source. The molecules simply vibrate about their mean positions. Hence, the air itself is not required to move from one place to the other.

1072.

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake withn a speed of `2 m//s` and a wavelength of `1.5 m`. When these waves move into a shallower part of the lake, their speed decreases to `1.6 m//s`, though their frequency remains the same. Find the wavelength of the wave in the shallower water.

Answer» In the first case, as `v_1 = 2 m//s, lamda_1 = 1.5 m, v = (v)/(lamda) = (2 m//s)/(1.5 m) = (4)/(3) Hz`
In the second case, when the waves move into a shallower part of the lake, `v_2 = 1.6 m//s`
Since `v` remains the same, wavelength of the waves in the shallower water, i.e.,
`lamda_2 = (v_2)/(v) = (1.6 m//s)/((4//3) Hz) = 1.2 m`.
1073.

A long nail has been driven halfway into the side a barn. How should you hit the nail withn a hammer generate a longitudinal wave ? How should you hit it to generate a transverse wave ?

Answer» To generate alongitudinal wave, hit the nail on the head in a direction parallel to its length.
Tom generate a transverse wave, hit the nail in a direction that is perpendicular to its length.
1074.

State whether the following statement is true or false: Sound produced by a vibrating body travels to our ears by the actual movement of air.

Answer»

Sound produced by a vibrating body travels to our ears by the actual movement of air False

1075.

How does sound reach our ears from the source of its production?

Answer»

Soufid travels in the form of waves. It reaches our ears from the source of its production, in the form of waves.

1076.

Why should we not put a pin or pencil in our ears?

Answer»

No, we must never put a pin or pencil in our ears, because it can tear our ear diaphragm.

1077.

Name any two common musical instruments and identify their vibrating parts.

Answer»
DholakDiaphragm (stretched membrane)
SitarStrings of the Sitar
FluteAir column inside the flute
1078.

Write true or false for the statementIn a longitudinal wave, compression and rarefaction are formed.

Answer»

True In a longitudinal wave, compression and rarefaction are formed.

1079.

A source is producing 1500 sound waves in 3 seconds. If the distance covered by a compression and an adjacent rarefaction be 68 cm, find: (a) frequency, (b) wavelength, and (c) velocity, of the sound wave.

Answer» (a) Frequency. We known that frequency of a wave is the number of waves produced in 1 second.
Here, No.of waves produced in 3 seconds = 1500
So, No. of waves produced in 1 second `= (1500)/(3) = 500`
So, the frequency of this sound wave is 500 hertz.
(b) Wavelength. in a sound wave, the distance covered by a compression and an adjacent rarefaction is equal to its wavelength. This distance has been given to be 68 cm. So, the wavelength `(lambda)` of this sound wave is 68 cm.
(c) Velocity. The formula for calculating the velocity of a sound wave is:
`v = f xx lambda`
Here, Frequency `f = 500 Hz` (Calculated above)
And, Wavelength, `lambda = 68cm` (Calculated above) ltbr. `= (68)/(100)m`
`= 0.68m`
Putting these values of f and `lambda` in the above formula, we get:
`v = 500 xx 0.68`
`= 340 m//s`
Thus, the velocity (or speed) of the sound waves is 340 m/s.
1080.

Define Crest and Trough.

Answer»

Crest: It is the highest point the medium rises to while the propagation of waves.

Trough: It is the lowest point a medium fall to while the propagation of the wave.

1081.

Transverse waves and longitudinal waves.

Answer»

Transverse wave: In a transverse wave, particles oscillate up and down about their mean position in a direction perpendicular to the direction of propagation of wave. e.g. light waves 

Longitudinal wave: In a longitudinal wave, the individual particles of the medium move in a direction parallel to the direction of propagation of the wave. The particles oscillate back and forth about their position of rest. e.g. Sound wave

1082.

Which of the following can produce longitudinal waves as well as transverse waves under different conditions? a) water b) TV transmitterc) slinky d) tuning fork

Answer»

The correct answer is c) slinky

1083.

Which of the following terms apply to sound waves in air and which to water waves? Transverse, rarefaction, trough, crest, compression, longitudinal

Answer»

Sound waves in air: longitudinal, compression, rarefaction Water waves: transverse, crest, trough

1084.

Write true of false for the following statements: Sound waves are transverse whereas light waves are longitudinal in nature.

Answer»

False 

Explanation: 

Sound waves are longitudinal waves. They propagate when the particles of the medium oscillate back and forth about their position of rest and do not move from one place to another. 

Light waves are transverse waves but the particles in oscillation are not of the medium as it is not a mechanical wave. 

1085.

Observe the following table and answer the following questions.XYElectrons88Protons88Neutrons89a) What is the mass number of X? b) What is the mass number of Y? c) What is the relation between X and Y? d) Which element do they represent? 

Answer»

a) Mass number of X = 16 (∵ number protons + number neutrons) 

b) Mass number of Y = 17 

c) Isotopes 

d) Oxygen ( \(^{16}_8O\) )

1086.

Explain why, Sodium ion, Na+ has completely filled K and L shells.

Answer»

1. A sodium ion, Na+ has 10 electrons in it. 

2. Now, the maximum capacity of K shell is 2 electrons and that of L shell is 8 electrons. 

3. Taken together, the maximum capacity of K and L shells is 2 + 8 = 10 electrons. 

4. A sodium ion Na+ has completely filled K and L shells because its 10 electrons can completely fill up K and L shells.

1087.

The unit of wavelength in S.l. system is ………………….. A) metreB) hertz C) decibel D) m/s

Answer»

Correct option is A) metre

1088.

If the particles of the medium vibrate along the direction of wave, then the wave is called a ………………….. A) longitudinal B) transverse C) stationary D) electromagnetic

Answer»

Correct option is A) longitudinal

1089.

The regions where the density and pressure of particles is high are called as ………………… A) crustsB) troughs C) compressions D) rarefactions

Answer»

C) compressions

1090.

Sound waves are …………….. waves. A) stationary B) longitudinalC) transverse D) electromagnetic

Answer»

B) longitudinal

1091.

When a sound wave travels in air …………….. and ……………… of air at a place varies. A) volume, density B) pressure, volume C) density, pressure D) frequency, speed

Answer»

C) density, pressure

1092.

The regions where the density and pressure of particles is low are called as ……………. A) crusts B) troughs C) compressions D) rarefactions

Answer»

D) rarefactions

1093.

The distance between two consecutive compressions is …………. A) speed B) wavelength C) frequencyD) time period

Answer»

Correct option is B) wavelength

1094.

Region of low dense particles …………………. A) compression B) rarefaction C) crust D) trough

Answer»

B) rarefaction

1095.

Distance between two consecutive compressions is …………….. A) wavelength B) frequency C) time period D) amplitude

Answer»

Correct option is A) wavelength

1096.

Region of high dense particles is ……………… A) compression B) rarefaction C) crust D) trough

Answer»

A) compression

1097.

Maximum variation in the density is ……………… A) wavelength B) frequency C) time period D) amplitude

Answer»

Correct option is D) amplitude

1098.

Number of oscillations in one second is called ……………… A) wavelength B) frequency C) time period D) amplitude

Answer»

Correct option is B) frequency

1099.

Frequency is expressed in a) Kilometer b) Hertz c) gram d) Degree centigrade

Answer»

Frequency is expressed in Hertz.

1100.

What is sound pollution? Write effects of sound pollution. Suggest some measures to control sould pollution.

Answer»

The unwanted sound in our surroundings is called sound pollution.

Effects of sound pollution on biodiversity:

1. The first harmful effect is loss of hearing. 

2. It also leads to several health related problems, 

e.g : Sleeplessness, hypertension, increase in blood pressure, etc. 

3. It effects the mental health of people. 

4. In animals, noise can increase the risk of death by altering predator or prey detection and avoidance, interfere with reproduction and navigation and contribute to permanent hearing loss. 

5. Noise pollution causes poor quality of crops.

6. Under water animals such as whales and dolphins too experience discomfort due to noise pollution caused by submarines, shipping companies and sonars. Cuttle fish and octopus suffer serious damage from noise pollution.

The steps to reduce sound pollution : 

1. Attach silencers to the bikes and other machines to reduce sound. 

2. Manufacture machines that work with lesser noise. 

3. During the use of TVs and taperecorders tune down volume of sound.

4. Plant trees to reduce sound pollution.