67486 + Interview Questions in Secondary School in Physics Page 20 InterviewSolution

951.	A body in equilibrium must not be
Answer» Answer: HOPE it helps you friend:) mark as brainliest please! EXPLANATION: For an object to be in equilibrium, it MUST be experiencing no ACCELERATION. This means that both the net force and the net torque on the object must be zero.

951.

A body in equilibrium must not be

Answer»

Answer:

HOPE it helps you friend:) mark as brainliest please!

For an object to be in equilibrium, it MUST be experiencing no ACCELERATION. This means that both the net force and the net torque on the object must be zero.

Discussion

952.	Well, my age is 17 years.
Answer» OO you are only 1 YEAR ELDER than me

Discussion

953.	Principle of an inflated balloon when piest and released
Answer» ANSWER: BALLOONS and Rockets When the neck of an INFLATED balloon is released, the stretched rubber material pushes against the air in the balloon. ... The GASES exert an equal and OPPOSITE force on the rocket itself. This is the reaction force.

953.

Principle of an inflated balloon when piest and released

Answer»

ANSWER:

BALLOONS and Rockets

When the neck of an INFLATED balloon is released, the stretched rubber material pushes against the air in the balloon. ... The GASES exert an equal and OPPOSITE force on the rocket itself. This is the reaction force.

Discussion

954.	Shatabdi express starts from rest and attains velocity of 180 km height in 2 minutes if acceleration in uniform find acceleration and displacement of the train
Answer» ANSWER: given, U = 0 m/s v = 180 * (5/18) m/s = 50 m/s t = 2 * 60 sec = 120 sec to FIND, a = ? s = ? formulas v = u + at _ _ _(1) s = ut + (1/2)a(t^2) _ _ _(2) v^2 = u^2 + 2as _ _ _(3) solution putting the VALUE of u, v and t in eq(1) v = u + at → 50 = 0 + a120 → 50/120 = a → a = 5/12 m/(s^2) putting the value of a and t in eq(2) s = ut + (1/2)a(t^2) →s = (0 120) + ((1/2) * (5/12) * 120 * 120) →s = 0 + 51060 →s = 3000m →s = 3 km

954.

Shatabdi express starts from rest and attains velocity of 180 km height in 2 minutes if acceleration in uniform find acceleration and displacement of the train

Answer»

ANSWER:

given,

U = 0 m/s
v = 180 * (5/18) m/s = 50 m/s
t = 2 * 60 sec = 120 sec

to FIND,

a = ?
s = ?

formulas

v = u + at _ _ _(1)
s = ut + (1/2)a(t^2) _ _ _(2)
v^2 = u^2 + 2as _ _ _(3)

solution

putting the VALUE of u, v and t in eq(1)

v = u + at

→ 50 = 0 + a*120

→ 50/120 = a

→ a = 5/12 m/(s^2)

putting the value of a and t in eq(2)

s = ut + (1/2)a(t^2)

→s = (0 * 120) + ((1/2) * (5/12) * 120 * 120)

→s = 0 + 5*10*60

→s = 3000m

→s = 3 km

Discussion

955.	Classify the following is insulators and conductors
Answer» ANSWER: Answer -uplod FULL QUESTION

955.

Classify the following is insulators and conductors

Answer»

ANSWER:

Answer -uplod FULL QUESTION

Discussion

956.	Solid s cannot be composed give reste
Answer» Answer: Solids are HELD in fixed positions, they can only vibrate. because the particles cannot move, solids have a definite shape and VOLUME, and can't flow. Because the particles are ALREADY packed closely TOGETHER , solids can't easily be compressed.

956.

Solid s cannot be composed give reste

Answer»

Answer:

Solids are HELD in fixed positions, they can only vibrate. because the particles cannot move, solids have a definite shape and VOLUME, and can't flow. Because the particles are ALREADY packed closely TOGETHER , solids can't easily be compressed.

Discussion

957.	ध्वनि तरंग व पाण्यात उठणारे तरंग यांतील फरक
Answer» ANSWER: 音波と音波の違い音波と音波の違い Explanation: 音波と音波の違い

957.

ध्वनि तरंग व पाण्यात उठणारे तरंग यांतील फरक

Answer»

ANSWER:

音波と音波の違い音波と音波の違い

Explanation:

音波と音波の違い

Discussion

958.	Essay on Isaac Newton
Answer» Answer: He is WELL known for his work on the laws of motion, optics, gravity, and calculus. In 1687, Newton published a book called the Philosophiæ Naturalis Principia Mathematica in which he presents his theory of universal gravitation and three laws of motion. Newton BUILT the first practical REFLECTING telescope in 1668. Explanation: MAKE me as BRAINLIEST

958.

Essay on Isaac Newton

Answer»

Answer:

He is WELL known for his work on the laws of motion, optics, gravity, and calculus. In 1687, Newton published a book called the Philosophiæ Naturalis Principia Mathematica in which he presents his theory of universal gravitation and three laws of motion. Newton BUILT the first practical REFLECTING telescope in 1668.

Explanation:

MAKE me as BRAINLIEST

Discussion

959.	एक वर्गाकार कुण्डली की भुजा 20cm है तथा यह चुंबकीय क्षेत्र के समांतर रखी गई है यदि चुंबकीय क्षेत्र 0.25Wb/M है तो कुंडली से गुजरने वाला क्रक्स ज्ञात कीजिए
Answer» SORRY i DONT KNOW this QUESTION's ANSWER

Discussion

960.	Difference between scaler and vector qunatity
Answer» Answer: SCALAR QUANTITY has only magnitude...e.g. distance. Vector quantity has both magnitude and DIRECTION..e.g. FORCE.

960.

Difference between scaler and vector qunatity

Answer»

Answer:

SCALAR QUANTITY has only magnitude...e.g. distance.

Vector quantity has both magnitude and DIRECTION..e.g. FORCE.

Discussion

961.	In a right angle triangle length of base is 4cm and perpendicular component is 3cm find sin theta,cos theta,tan theta
Answer» Explanation: sin THETA = opposite /HYPOTENUSE cos theta =adjecant /hypotenuse (hypotenuse)^2= (base)^2+(perpendicular component)^2 (4)^2+(3)^2=16+9=25 hence hypotenuse =5cm hence sin theta =4/5 cos theta=3/5 than theta= sin theta/cos theta =4/3

961.

In a right angle triangle length of base is 4cm and perpendicular component is 3cm find sin theta,cos theta,tan theta

Answer»

Explanation:

sin THETA = opposite /HYPOTENUSE

cos theta =adjecant /hypotenuse

(hypotenuse)^2= (base)^2+(perpendicular component)^2

(4)^2+(3)^2=16+9=25

hence hypotenuse =5cm

hence sin theta =4/5

cos theta=3/5

than theta= sin theta/cos theta =4/3

Discussion

962.	What intrument used in "liebestraum"??
Answer» ANSWER: CELLO and Piano Explanation: COMPOSED by FRANZ LISZT (1811-1886).

962.

What intrument used in "liebestraum"??

Answer»

ANSWER:

CELLO and Piano

Explanation:

COMPOSED by FRANZ LISZT (1811-1886).

Discussion

963.	Find an expression for the electric field strength at a distance point suit situated 1) On the axis and2) Along the equatorial line of electric dipole.
Answer» Answer Consider an electric dipole AB. The charges −q and +q of dipole are situated at A and B respectively as shown in the figure. The separation between the charges is 2a. The direction of dipole moment is from −q to +q. (i) At axial or end-on POSITION : Consider a point P on the axis of dipole at a distance r from mid-point O of electric dipole. The distance of point P from charge +q at B is BP=r−a And distance of point P from charge −q at A is, AP=r+a. Let E 1 and E 2 be the electric field strengths at point P due to charges +q and −q respectively. We know that the direction of electric field due to a point charge is away from positive charge and towards the negative charge. THEREFORE, E 1 = 4πϵ 0 1 (r−a) 2 q (from B to P) and E 2 = 4πϵ 0 1 (r+a) 2 q (from P to A) Clearly the directions of electric field strengths E 1 are E 2 along the same line but opposite to each other and E 1 >E 2 because positive charge is nearer. ∴ The resultant electric field due to electric dipole has magnitude equal to the difference of E 1 and E 2 direction from B to P i.e. E=E 1 −E 2 = 4πϵ 0 1 (r−a) 2 q − 4πϵ 0 1 (r+a) 2 q = 4πϵ 0 q [ (r−a) 2 1 − (r+a) 2 1 ]= 4πϵ 0 q [ (r 2 −a 2 ) 2 (r+a) 2 −(r−a) 2 ] = 4πϵ 0 q (r 2 −a 2 ) 2 4ra = 4πϵ 0 1 (r 2 −a 2 ) 2 2(q2a)r But q.2l=p (electric dipole moment) ∴E= 4πϵ 0 1 (r 2 −a 2 ) 2 2pr ....(i) If the dipole is infinitely small and point P is far away from the dipole, then r>>1, therefore equation (i) may be expressed as E= 4πϵ 0 1 r 4 2pr or E= 4πϵ 0 1 r 3 2p ....(ii) This is the expression for the electric field strength at axial position due to a short electric dipole. (ii) At a point of equatorial line: Consider a point P on broad side on the position of dipole formed of charges +q and −q at separation 2a. The distance of point P from mid-point (O) of electric dipole is r. Let E 1 and E 2 be the electric field strengths due to charges +q and −q of electric dipole. From fig. AP=BP= r 2 +a 2 ∴ E = 4πϵ 0 1 r 2 +a 2 q along B to P E 2 = 4πϵ 0 1 r 2 +a 2 q along P to A Clearly E 1 and E 2 are equal in magnitude i.e. ∣ E 1 ∣=∣ E 2 ∣ or E 1 =E 2 To find the resultant of E 1 and E 2 , we resolve them into rectangular components. Component of E 1 parallel to AB=E 1 cosθ, in the direction to BA Component of E 1 perpendicular to AB=E 1 sinθ along OP Component of E 2 parallel to AB=E 2 cosθ in the direction BA ∴ Resultant electric field at P is E=E 1 cosθ+E 2 cosθ But E 1 =E 2 = 4πϵ 0 1 (r 2 +a 2 ) q From the figure, cosθ= POB OB = r 2 +a 2 l = (r 2 +a 2 ) 1/2 l E=2E 1 cosθ=2× 4πϵ 0 1 (r 2 +a 2 ) q ⋅ (r 2 +a 2 ) 1/2 l = 4πϵ 0 1 (r 2 +a 2 ) 3/2 2ql But q.2l=p= electric dipole moment .... (iii) ∴E= 4πϵ 0 1 (r 2 +a 2 ) 3/2 p If dipole is INFINITESIMAL and point P is far away, we have a< 2 may be neglected as compared to r 2 and so equation (iii) gives E= 4πϵ 0 1 (r 2 ) 3/2 P = 4πϵ 0 1 r 3 P i.e., electric field strength due to a short dipole at BROADSIDE on position E= 4πϵ 0 1 r 3 p in the direction parallel to BA ....(iv) Its direction is parallel to the axis of dipole from positive to negative charge. It may be noted clearly from equations (ii) and (iv) that electric field strength due to a short dipole at any point is inversely proportional to the cube of its distance from the dipole and the electric field strength at axial position is twice that at broad-side on position for the same distance. Important: Note the important point that the electric field due to a dipole at large distances falls off as r 3 1 and not as r 2 1 as in the case of a point charge.

963.

Find an expression for the electric field strength at a distance point suit situated 1) On the axis and2) Along the equatorial line of electric dipole.

Answer»

Answer

Consider an electric dipole AB. The charges −q and +q of dipole are situated at A and B respectively as shown in the figure. The separation between the charges is 2a.

The direction of dipole moment is from −q to +q.

(i) At axial or end-on POSITION : Consider a point P on the axis of dipole at a distance r from mid-point O of electric dipole.

The distance of point P from charge +q at B is

BP=r−a

And distance of point P from charge −q at A is, AP=r+a.

Let E

1

and E

2

be the electric field strengths at point P due to charges +q and −q respectively.

We know that the direction of electric field due to a point charge is away from positive charge and towards the negative charge. THEREFORE,

E

1

=

4πϵ

0

1

(r−a)

2

q

(from B to P) and E

2

=

4πϵ

0

1

(r+a)

2

q

(from P to A)

Clearly the directions of electric field strengths

E

1

are

E

2

along the same line but opposite to each other and E

1

>E

2

because positive charge is nearer.

∴ The resultant electric field due to electric dipole has magnitude equal to the difference of E

1

and E

2

direction from B to P i.e.

E=E

1

−E

2

=

4πϵ

0

1

(r−a)

2

q

−

4πϵ

0

1

(r+a)

2

q

=

4πϵ

0

q

[

(r−a)

2

1

−

(r+a)

2

1

]=

4πϵ

0

q

[

(r

2

−a

2

)

2

(r+a)

2

−(r−a)

2

]

=

4πϵ

0

q

(r

2

−a

2

)

2

4ra

=

4πϵ

0

1

(r

2

−a

2

)

2

2(q2a)r

But q.2l=p (electric dipole moment)

∴E=

4πϵ

0

1

(r

2

−a

2

)

2

2pr

....(i)

If the dipole is infinitely small and point P is far away from the dipole, then r>>1, therefore equation (i) may be expressed as

E=

4πϵ

0

1

r

4

2pr

or E=

4πϵ

0

1

r

3

2p

....(ii)

This is the expression for the electric field strength at axial position due to a short electric dipole.

(ii) At a point of equatorial line: Consider a point P on broad side on the position of dipole formed of charges +q and −q at separation 2a. The distance of point P from mid-point (O) of electric dipole is r. Let

E

1

and

E

2

be the electric field strengths due to charges +q and −q of electric dipole.

From fig. AP=BP=

r

2

+a

2

∴

E

=

4πϵ

0

1

r

2

+a

2

q

along B to P

E

2

=

4πϵ

0

1

r

2

+a

2

q

along P to A

Clearly

E

1

and

E

2

are equal in magnitude i.e. ∣

E

1

∣=∣

E

2

∣ or E

1

=E

2

To find the resultant of

E

1

and

E

2

, we resolve them into rectangular components.

Component of

E

1

parallel to AB=E

1

cosθ, in the direction to

BA

Component of

E

1

perpendicular to AB=E

1

sinθ along OP

Component of

E

2

parallel to AB=E

2

cosθ in the direction

BA

∴ Resultant electric field at P is E=E

1

cosθ+E

2

cosθ

But E

1

=E

2

=

4πϵ

0

1

(r

2

+a

2

)

q

From the figure, cosθ=

POB

OB

=

r

2

+a

2

l

=

(r

2

+a

2

)

1/2

l

E=2E

1

cosθ=2×

4πϵ

0

1

(r

2

+a

2

)

q

⋅

(r

2

+a

2

)

1/2

l

=

4πϵ

0

1

(r

2

+a

2

)

3/2

2ql

But q.2l=p= electric dipole moment .... (iii)

∴E=

4πϵ

0

1

(r

2

+a

2

)

3/2

p

If dipole is INFINITESIMAL and point P is far away, we have a<

2

may be neglected as compared to r

2

and so equation (iii) gives

E=

4πϵ

0

1

(r

2

)

3/2

P

=

4πϵ

0

1

r

3

P

i.e., electric field strength due to a short dipole at BROADSIDE on position

E=

4πϵ

0

1

r

3

p

in the direction parallel to

BA

....(iv)

Its direction is parallel to the axis of dipole from positive to negative charge.

It may be noted clearly from equations (ii) and (iv) that electric field strength due to a short dipole at any point is inversely proportional to the cube of its distance from the dipole and the electric field strength at axial position is twice that at broad-side on position for the same distance.

Important: Note the important point that the electric field due to a dipole at large distances falls off as

r

3

1

and not as

r

2

1

as in the case of a point charge.

Discussion

964.	A student is running on a straight track with a velocity of 5m per second. With help of a graph show how much distance is run by him in a minute.
Answer» Explanation: For convenience, let the students (constant) speed be v0 and the buss initial position be x0. Note that these quantities are for separate OBJECTS, the student and the bus. The initial position of the student is taken to be zero and the initial velocity of the bus is taken to be zero. The positions of student x1 and bus x2 as functions of time are then x1=v0t,x2=x0+(l/2)at2 A. Setting x1=x2 and solving for the time t gives t=(1/a)(v0±v02−2ax0) = (1/0.2)((5.0)±52−2(0.2)(40.0)) = 10.40 s The student will be likely to hop on the bus the FIRST time she passes it [see part (d) for a discussion of the later time]. During this time, the student has run a distance v0t = (5 m/s)(10 s) = 50 m B.The speed of the bus is v = at = 0.2 x 10 = 20 m/s C.The results can be verified by noting that the x lines for the student and the bus INTERSECT at two points. D. At the later time, the student has passed the bus, maintaining her constant speed, but the accelerating bus then catches up with her. At this later time, the buss velocity is (0.2 ms−2) (40 s) = 8.0 m/s. E. No; v02<2ax0, and the roots of the quadratic are imaginary.When the student runs at 3.5 m/s the two lines do not intersect. F. For the student to catch the bus, v02<2ax0 and so the minimum speed is 2(0.2ms−2(40m) = 4.0 m/s. She would be running for a time 0.2ms−24.0m/s = 20s, and cover a distance of (4.0 m/s)(20 s) = 80.0 m. However, when the student runs at 4.0 m/s, the lines intersect at one point (x = 80 m).

964.

A student is running on a straight track with a velocity of 5m per second. With help of a graph show how much distance is run by him in a minute.

Answer»

Explanation:

For convenience, let the students (constant) speed be v0 and the buss initial position be x0. Note that these quantities are for separate OBJECTS, the student and the bus. The initial position of the student is taken to be zero and the initial velocity of the bus is taken to be zero. The positions of student x1 and bus x2 as functions of time are then

x1=v0t,x2=x0+(l/2)at2

A. Setting x1=x2 and solving for the time t gives

t=(1/a)(v0±v02−2ax0)

= (1/0.2)((5.0)±52−2(0.2)(40.0)) = 10.40 s

The student will be likely to hop on the bus the FIRST time she passes it [see part (d) for a discussion of the later time]. During this time, the student has run a distance v0t = (5 m/s)(10 s) = 50 m

B.The speed of the bus is v = at = 0.2 x 10 = 20 m/s

C.The results can be verified by noting that the x lines for the student and the bus INTERSECT at two points.

D. At the later time, the student has passed the bus, maintaining her constant speed, but the accelerating bus then catches up with her. At this later time, the buss velocity is (0.2 ms−2) (40 s) = 8.0 m/s.

E. No; v02<2ax0, and the roots of the quadratic are imaginary.When the student runs at 3.5 m/s the two lines do not intersect.

F. For the student to catch the bus, v02<2ax0 and so the minimum speed is 2(0.2ms−2(40m) = 4.0 m/s. She would be running for a time 0.2ms−24.0m/s = 20s, and cover a distance of (4.0 m/s)(20 s) = 80.0 m.

However, when the student runs at 4.0 m/s, the lines intersect at one point (x = 80 m).

Discussion

965.	calculate (1) speed (2) wavelength of light in diamond for a ray of light of wavelength 800 nm in air, when refraction index of diamond is 2.24. Speed of light in air is 3×10⁸ m/s
Answer» EXPLANATION: PLEASE SEE the attached PICTURE dear

965.

calculate (1) speed (2) wavelength of light in diamond for a ray of light of wavelength 800 nm in air, when refraction index of diamond is 2.24. Speed of light in air is 3×10⁸ m/s

Answer»

EXPLANATION:

PLEASE SEE the attached PICTURE dear

Discussion

966.	what do you mean by normal temperature pressure and standard temperature and pressure?? answer in easy words.
Answer» TUMHARA MARZI HO TOH krna✌✌✌✌✌✌✌✌✌✌

Discussion

967.	the magnification produced by a mirror is -1 what is your conclusion by the nature of mirror used and the position of the object
Answer» Answer: THE MIRROR IS A CONCAVE MIRROR AND THE OBJECT IS PLACED AT CENRE OF CURVATURE pls MARK BRAINLIEST

967.

the magnification produced by a mirror is -1 what is your conclusion by the nature of mirror used and the position of the object

Answer»

Answer:

THE MIRROR IS A CONCAVE MIRROR AND THE OBJECT IS PLACED AT CENRE OF CURVATURE

pls MARK BRAINLIEST

Discussion

968.	: You have been given with a spherical mirror which is used in solar furnace. Ramesh allows a ray of light along the principal axis to fall on this mirror. Suresh placed an object at a distance of 10 cm in front of mirror and formed image 3 times enlarge that of an object Sanya while doing experiment found that the mirror produced magnification of +4. i) Identify the type of mirror and define principle focus. ii) Can it form virtual and magnified image why/why not? 21
Answer» ANSWER: I don't UNDERSTAND the QUESTION

968.

: You have been given with a spherical mirror which is used in solar furnace. Ramesh allows a ray of light along the principal axis to fall on this mirror. Suresh placed an object at a distance of 10 cm in front of mirror and formed image 3 times enlarge that of an object Sanya while doing experiment found that the mirror produced magnification of +4. i) Identify the type of mirror and define principle focus. ii) Can it form virtual and magnified image why/why not? 21

Answer»

ANSWER:

I don't UNDERSTAND the QUESTION

Discussion

969.	A ball is thrown with horizontal velocity 6.0 metre per second what is the velocity after 3.0 S of flight
Answer» ANSWER: EXPLANATION: PLS MARK BRAINLIEST

969.

A ball is thrown with horizontal velocity 6.0 metre per second what is the velocity after 3.0 S of flight

Answer»

ANSWER:

EXPLANATION:

PLS MARK BRAINLIEST

Discussion

970.	89. In an experiment to study dependence of current on the potential difference across a given resistor, students kept the plug key in the circuit closed for time T1 and then open for time T2.The time T1 and T2 for students P, Q, R and S are given in the table below.The best choice of open and closed times is that ofstudent:Student Closed time t1 secondsPQRS(a) P(c) R30606045Opentimte2 seconds60301515(b) Q(d) S
Answer» Answer: students P, Q, R and S are GIVEN in the table below. The BEST choice of open and closed times is that of STUDENT: Student Closed time t1 SECONDS

970.

89. In an experiment to study dependence of current on the potential difference across a given resistor, students kept the plug key in the circuit closed for time T1 and then open for time T2.The time T1 and T2 for students P, Q, R and S are given in the table below.The best choice of open and closed times is that ofstudent:Student Closed time t1 secondsPQRS(a) P(c) R30606045Opentimte2 seconds60301515(b) Q(d) S

Answer»

Answer:

students P, Q, R and S are GIVEN in the table below.

The BEST choice of open and closed times is that of

STUDENT:

Student Closed time t1 SECONDS

Discussion

971.	A train is moving with a constant speed of 40 km/hr. Draw time-speed graph. From this, draw time-distance graph upto 5 hours from the start
Answer» ANSWER: PLEASE MARK me BRAINIEST

971.

A train is moving with a constant speed of 40 km/hr. Draw time-speed graph. From this, draw time-distance graph upto 5 hours from the start

Answer»

ANSWER:

PLEASE MARK me BRAINIEST

Discussion

972.	An empty bottle of 25mL capacity weight 22.6g. When completely filled with turpentine oil, it weighs 43.8g. Find the density of turpentine oil.
Answer» ANSWER: HOPE it's HELPFUL DEAR!

972.

An empty bottle of 25mL capacity weight 22.6g. When completely filled with turpentine oil, it weighs 43.8g. Find the density of turpentine oil.

Answer»

ANSWER:

HOPE it's HELPFUL DEAR!

Discussion

973.	Don't spam This is a warning
Answer» ANSWER: ASK some ONE ELSE EXPLANATION:

973.

Don't spam This is a warning

Answer»

ANSWER:

ASK some ONE ELSE

EXPLANATION:

Discussion

974.	I)The particle performing uniform circular motion of radius r=3cm.To find angular acceleration.
Answer» EXPLANATION: द पार्टिकल परफॉर्मिंग यूनिफॉर्म सर्कुलर मोशन ऑफ रेडियस r=3 CM टू फाइंड एंगुलर एक्सीलरेशन

974.

I)The particle performing uniform circular motion of radius r=3cm.To find angular acceleration.

Answer»

EXPLANATION:

द पार्टिकल परफॉर्मिंग यूनिफॉर्म सर्कुलर मोशन ऑफ रेडियस r=3 CM टू फाइंड एंगुलर एक्सीलरेशन

Discussion

975.	Hlo dear friends plz give very long answer explain pressure in liquids with an example?
Answer» Answer: PRESSURE OF LIQUID ON WALLS OF CONTAINER - EXAMPLE When water is filled in a BUCKET, the water exerts a force on the walls of the bucket from inside. If the strength of the bucket is LOW, the pressure may cause the bucket to BURST.

975.

Hlo dear friends plz give very long answer explain pressure in liquids with an example?

Answer»

Answer:

PRESSURE OF LIQUID ON WALLS OF CONTAINER - EXAMPLE

When water is filled in a BUCKET, the water exerts a force on the walls of the bucket from inside. If the strength of the bucket is LOW, the pressure may cause the bucket to BURST.

Discussion

976.	With reference to the figure, showing a light inextensible string passing over a fixed frictionless pulley, the tension T3 is (A) 24.5 N (B) 29.4 N (C) 18.6 N (D) 68.6 N T1 T2 5 kg 4 kg T3 3 kg
Answer» ANSWER: I HOPE you UNDERSTAND that

976.

With reference to the figure, showing a light inextensible string passing over a fixed frictionless pulley, the tension T3 is (A) 24.5 N (B) 29.4 N (C) 18.6 N (D) 68.6 N T1 T2 5 kg 4 kg T3 3 kg

Answer»

ANSWER:

I HOPE you UNDERSTAND that

Discussion

977.	Explain nuclear energy through an example.
Answer» ANSWER: Nuclear ENERGY is a source of power which is CREATED from energy released by a nuclear reaction. ... An example of nuclear energy is the electricity GENERATED by a nuclear REACTOR, which is the major power source used in Japan. Explanation: Hope it's being helpful to you

977.

Explain nuclear energy through an example.

Answer»

ANSWER:

Nuclear ENERGY is a source of power which is CREATED from energy released by a nuclear reaction. ... An example of nuclear energy is the electricity GENERATED by a nuclear REACTOR, which is the major power source used in Japan.

Explanation:

Hope it's being helpful to you

Discussion

978.	Construction and working of hydraluic press
Answer» ANSWER: A hydraulic press works on the principle of Pascal's LAW, which states that when pressure is applied to a confined fluid, the pressure change OCCURS throughout the entire fluid. Within the hydraulic press, there is a PISTON that works as a pump, that provides a modest mechanical force to a small area of the sample.

978.

Construction and working of hydraluic press

Answer»

ANSWER:

A hydraulic press works on the principle of Pascal's LAW, which states that when pressure is applied to a confined fluid, the pressure change OCCURS throughout the entire fluid. Within the hydraulic press, there is a PISTON that works as a pump, that provides a modest mechanical force to a small area of the sample.

Discussion

979.	Given mass of copper,current and time.how can you calculate the electrochemical equivalent of copper
Answer» Explanation: RID G DISRESPECT HANDLES CAPITALS half of history and mishi who are you

979.

Given mass of copper,current and time.how can you calculate the electrochemical equivalent of copper

Answer»

Explanation:

RID G DISRESPECT HANDLES CAPITALS half of history and mishi who are you

Discussion

980.	What is the formula for velocity ratio of a differentia wheel axle
Answer» ANSWER: HENCE, the velocity RATIO of the system= 2pR/2pr = R/r. Thus the velocity ratio of a wheel and AXLE is the ratio of the radius of the wheel to the radius of the axle.

980.

What is the formula for velocity ratio of a differentia wheel axle

Answer»

ANSWER:

HENCE, the velocity RATIO of the system= 2pR/2pr = R/r. Thus the velocity ratio of a wheel and AXLE is the ratio of the radius of the wheel to the radius of the axle.

Discussion

981.	Distance is 1000 m time is 5 s
Answer» ANSWER: SPEED = DISTANCE time give d=1000m t=5 s 1000 = 20m/s 5

981.

Distance is 1000 m time is 5 s

Answer»

ANSWER:

SPEED = DISTANCE

time

give d=1000m

t=5 s

1000 = 20m/s

5

Discussion

982.	7. How large the atmospheric pressure yet we do not get crushed under the hugeatmospheric pressure.Give reason , why?
Answer» Answer: The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure. It is the force exerted on a surface by the air above it as gravity pulls it to Earth. Atmospheric pressure is commonly measured with a BAROMETER. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes. Meteorologists describe the atmospheric pressure by how high themercury rises. An atmosphere (atm) is a unit of measurement equal to the average air pressure at sea level at a temperature of 15 degrees Celsius (59 degrees FAHRENHEIT). One atmosphere is 1,013 millibars, or 760 millimeters (29.92 inches) of mercury. Atmospheric pressure drops as altitude increases. The atmospheric pressure on Denali, Alaska, is about half that of HONOLULU, Hawai'i. Honolulu is a city at sea level. Denali, also known as Mount McKinley, is the highest peak in NORTH America. As the pressure decreases, the amount of oxygen available to breathe also decreases. At very high altitudes, atmospheric pressure and available oxygen get so low that people can become sick and even die. Mountain climbers use bottled oxygen when they ascend very high peaks. They also take time to get used to the altitude because quickly moving from HIGHER pressure to lower pressure can cause decompression sickness. Decompression sickness, also called "the bends", is also a problem for scuba divers who come to the surface too quickly. Aircraft create artificial pressure in the cabin so passengers remain comfortable while flying. Atmospheric pressure is an indicator of weather. When a low-pressure system moves into an area, it usually leads to cloudiness, wind, and precipitation. High-pressure systems usually lead to fair, calm weather.

982.

7. How large the atmospheric pressure yet we do not get crushed under the hugeatmospheric pressure.Give reason , why?

Answer»

Answer:

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure. It is the force exerted on a surface by the air above it as gravity pulls it to Earth.

Atmospheric pressure is commonly measured with a BAROMETER. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes. Meteorologists describe the atmospheric pressure by how high themercury rises.

An atmosphere (atm) is a unit of measurement equal to the average air pressure at sea level at a temperature of 15 degrees Celsius (59 degrees FAHRENHEIT). One atmosphere is 1,013 millibars, or 760 millimeters (29.92 inches) of mercury.

Atmospheric pressure drops as altitude increases. The atmospheric pressure on Denali, Alaska, is about half that of HONOLULU, Hawai'i. Honolulu is a city at sea level. Denali, also known as Mount McKinley, is the highest peak in NORTH America.

As the pressure decreases, the amount of oxygen available to breathe also decreases. At very high altitudes, atmospheric pressure and available oxygen get so low that people can become sick and even die.

Mountain climbers use bottled oxygen when they ascend very high peaks. They also take time to get used to the altitude because quickly moving from HIGHER pressure to lower pressure can cause decompression sickness. Decompression sickness, also called "the bends", is also a problem for scuba divers who come to the surface too quickly.

Aircraft create artificial pressure in the cabin so passengers remain comfortable while flying.

Atmospheric pressure is an indicator of weather. When a low-pressure system moves into an area, it usually leads to cloudiness, wind, and precipitation. High-pressure systems usually lead to fair, calm weather.

Discussion

983.	Explain the construction and working of hydraulic brakes?
Answer» Answer: Hydraulic brakes work on the PRINCIPLE of Pascal's law. According to this law whenever PRESSURE is APPLIED on a FLUID it travels uniformly in all the directions. ... As braking force is generateddue to hydraulic pressure,theyare known as hydraulic brakes. Liquids are used instead of gas as liquids are incompressible.

983.

Explain the construction and working of hydraulic brakes?

Answer»

Answer:

Hydraulic brakes work on the PRINCIPLE of Pascal's law. According to this law whenever PRESSURE is APPLIED on a FLUID it travels uniformly in all the directions. ... As braking force is generateddue to hydraulic pressure,theyare known as hydraulic brakes. Liquids are used instead of gas as liquids are incompressible.

Discussion

984.	Calculate the distance and the displacement of an object moving in a circular part of diameter20m after completing 3rounds.Btw sorry
Answer» Answer: In ONE complete CYCLE, it comes back to its INITIAL position, so the displacement of the OBJECT is zero. Distance travelled = circumference of the CIRCLE = 2πr =2×722×3.5 =22m

984.

Calculate the distance and the displacement of an object moving in a circular part of diameter20m after completing 3rounds.Btw sorry

Answer»

Answer:

In ONE complete CYCLE, it comes back to its INITIAL position, so the displacement of the OBJECT is zero.

Distance travelled = circumference of the CIRCLE = 2πr

=2×722×3.5

=22m

Discussion

985.	Hlo dear friends plz answer in very pong what is meant by physical properties of matter?
Answer» Answer: Physical PROPERTIES are properties that can be measured or OBSERVED without changing the chemical nature of the substance. Some examples of physical properties are: COLOR (INTENSIVE) DENSITY (intensive)

985.

Hlo dear friends plz answer in very pong what is meant by physical properties of matter?

Answer»

Answer:

Physical PROPERTIES are properties that can be measured or OBSERVED without changing the chemical nature of the substance. Some examples of physical properties are: COLOR (INTENSIVE) DENSITY (intensive)

Discussion

986.	Draw a labelled diagram in the object is kept at F and the object is kept at CDon't SpamSpam will be reported
Answer» ANSWER: what are you TALKING about the FM the OBJECT there is no diagram LABELLED here

986.

Draw a labelled diagram in the object is kept at F and the object is kept at CDon't SpamSpam will be reported

Answer»

ANSWER:

what are you TALKING about the FM the OBJECT there is no diagram LABELLED here

Discussion

987.	Give me an example of work done against force?
Answer» ANSWER: The work done against FORCE LISTS 0 actions because we are now enjoying our LIFE due to them.

987.

Give me an example of work done against force?

Answer»

ANSWER:

The work done against FORCE LISTS 0 actions because we are now enjoying our LIFE due to them.

Discussion

988.	I am a physical property that express thermal energy of particles . What is my name ?
Answer» KINETIC energy do LIKE and MARK if you are SATISFIED

988.

I am a physical property that express thermal energy of particles . What is my name ?

Answer»

KINETIC energy

do LIKE and MARK if you are SATISFIED

Discussion

989.	the diagram below shows two metal spheres mounted on a portable insulating support a student is given a glass rod and a piece of silk without allowing any contact between glass rod or silk piece with any of the spheres describe how a student can charge the two spheres with equal but opposite charges
Answer» ANSWER: where is the DIAGRAM????!!!

989.

the diagram below shows two metal spheres mounted on a portable insulating support a student is given a glass rod and a piece of silk without allowing any contact between glass rod or silk piece with any of the spheres describe how a student can charge the two spheres with equal but opposite charges

Answer»

ANSWER:

where is the DIAGRAM????!!!

Discussion

990.	Define circular motion and state it charcterise
Answer» EXPLANATION: CIRCULAR MOTION is a SPECIAL case of curvilinear motion If this answer help you pls mark ar branliest

990.

Define circular motion and state it charcterise

Answer»

EXPLANATION:

CIRCULAR MOTION is a SPECIAL case of curvilinear motion

If this answer help you pls mark ar branliest

Discussion

991.	A block of density OF 0.o6g/cm3,weighing 3.06N In air,float freely ina liquid of density 0.9g/cm3.calculate the volume of the portion immersed (g=10m/s2
Answer» $\rm\small\underline\red{Question:-}$ $\rm\bullet{ \: Density = 0.06 \frac{g}{cm} ^{(3)} }$ $\rm\bullet{ \: Air= 3.06 \: N}$ $\rm\bullet{ \: Liquid \: density = 0.9\frac{g}{cm} ^{(3)} }$ $\rm\small\underline\red{ \: Find:-}$ CALCULATE the VOLUME of the PORTION IMMERSED. $\rm\small\underline\red{Solution:-}$ $\rightarrow\rm\small\green{ F = mg }$ $\rightarrow \rm \small{3.06 = 3 \times 10}$ $\rm\rightarrow{m = \frac{3.06}{1000} \: g m}$ $\rightarrow\rm\small{Volume = \frac {3.06}{1000 } {(0.9)} \: }$ $\rm\rightarrow \: \frac{306 \times\cancel {10} }{ \cancel{1000} \times 9}$ $\rightarrow\rm \small\frac{\cancel{30}}{ \cancel{900}}$ $\dashrightarrow\rm\small\fbox\green{ Volume = 3 m }$ ___________________________ #SHIVAM @Shivam #Qualityanswer

991.

A block of density OF 0.o6g/cm3,weighing 3.06N In air,float freely ina liquid of density 0.9g/cm3.calculate the volume of the portion immersed (g=10m/s2

Answer»

$\rm\small\underline\red{Question:-}$

$\rm\bullet{ \: Density = 0.06 \frac{g}{cm} ^{(3)} }$

$\rm\bullet{ \: Air= 3.06 \: N}$

$\rm\bullet{ \: Liquid \: density = 0.9\frac{g}{cm} ^{(3)} }$

$\rm\small\underline\red{ \: Find:-}$

CALCULATE the VOLUME of the PORTION IMMERSED.

$\rm\small\underline\red{Solution:-}$

$\rightarrow\rm\small\green{ F = mg }$

$\rightarrow \rm \small{3.06 = 3 \times 10}$

$\rm\rightarrow{m = \frac{3.06}{1000} \: g m}$

$\rightarrow\rm\small{Volume = \frac {3.06}{1000 } {(0.9)} \: }$

$\rm\rightarrow \: \frac{306 \times\cancel {10} }{ \cancel{1000} \times 9}$

$\rightarrow\rm \small\frac{\cancel{30}}{ \cancel{900}}$

$\dashrightarrow\rm\small\fbox\green{ Volume = 3 m }$

___________________________

#SHIVAM

@Shivam

#Qualityanswer

Discussion

992.	Which of these is most likely to react with metala-waterb-liquid soapc-vegetable oild-hydrochloric acid
Answer» ANSWER: I SUPPOSE... HYDROCHLORIC ACID..HEHEHE!!

992.

Which of these is most likely to react with metala-waterb-liquid soapc-vegetable oild-hydrochloric acid

Answer»

ANSWER:

I SUPPOSE... HYDROCHLORIC ACID..HEHEHE!!

Discussion

993.	Hlo dear friendsplz answer in very long answerexplain pressure in liquids with an example?
Answer» Answer: $\huge\red{A}\pink[N]\orange{S}\green{W}\blue{E}\gray{R}$ Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit AREA. The basic formula for pressure is F/A (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure. While sipping beverages from a STRAW, have you noticed that you actually suck the air out of the straw? While you sip the beverage, you’re actually applying ‘Pressure’. The AMOUNT of force exerted (thrust) on a surface per unit area is defined as ‘Pressure’. It can also be defined as the RATIO of the force to the area (over which the force is acting). Formula and Unit of Pressure Pressure (P) = Thrust/ Area The SI unit is ‘pascals (Pa)’. 1 Pa = 1N/m2 Example: It is easier to hammer a SHARP pin than to hammer a blunt pin. This is because the area at the end of the sharp pin is smaller than the area at the end of a blunt pin. This leads to an increase in pressure leading to hammer the sharp pin easily.

993.

Hlo dear friendsplz answer in very long answerexplain pressure in liquids with an example?

Answer»

Answer:

$\huge\red{A}\pink[N]\orange{S}\green{W}\blue{E}\gray{R}$

Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit AREA. The basic formula for pressure is F/A (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure. While sipping beverages from a STRAW, have you noticed that you actually suck the air out of the straw? While you sip the beverage, you’re actually applying ‘Pressure’.

The AMOUNT of force exerted (thrust) on a surface per unit area is defined as ‘Pressure’. It can also be defined as the RATIO of the force to the area (over which the force is acting).

Formula and Unit of Pressure

Pressure (P) = Thrust/ Area

The SI unit is ‘pascals (Pa)’. 1 Pa = 1N/m2

Example: It is easier to hammer a SHARP pin than to hammer a blunt pin. This is because the area at the end of the sharp pin is smaller than the area at the end of a blunt pin. This leads to an increase in pressure leading to hammer the sharp pin easily.

Discussion

994.	A train travels in a straight line at a constant speed of 60 km/h for a particular distance d and then travels another distance equal to 2d in the same direction at a constant speed of 80 km/hr in the same direction as it was in the it was previously going a) What is the average speed of the train during the whole journey
Answer» Explanation: Let distance from A to B=x km= distance from B to A. TIME TAKEN by TRAIN from A to B = 60 x HR Time taken by train from B to A = 80 x hr Total time taken by train = 60 x + 80 x = 240 7x hr average speed= total time total distance = 240 7x 2X = 7 480 km h −1

994.

A train travels in a straight line at a constant speed of 60 km/h for a particular distance d and then travels another distance equal to 2d in the same direction at a constant speed of 80 km/hr in the same direction as it was in the it was previously going a) What is the average speed of the train during the whole journey

Answer»

Explanation:

Let distance from A to B=x km= distance from B to A.

TIME TAKEN by TRAIN from A to B =

60

x

HR

Time taken by train from B to A =

80

x

hr

Total time taken by train =

60

x

+

80

x

=

240

7x

hr

average speed=

total time

total distance

=

240

7x

2X

=

7

480

km h

−1

Discussion

995.	24. Which of the following statements is true: (a) Heat can be converted completely into work (c) Both work and heat are inter-convertible (b) Work can be converted completely into heat (d) Neither heat nor work is inter convertible
Answer» Answer: 1. FALSE 2. TRUE 3. true 4. false

995.

24. Which of the following statements is true: (a) Heat can be converted completely into work (c) Both work and heat are inter-convertible (b) Work can be converted completely into heat (d) Neither heat nor work is inter convertible

Answer»

Answer:

1. FALSE

2. TRUE

3. true

4. false

Discussion

996.	Solve the question in the given attachment
Answer» 1) We have, $\begin{gathered}\vec{F}=ai+3j+6k\\ \\ \vec{r}=2i-6j-12k\end{gathered}$ ANGULAR momentum about ORIGIN is conserved when torque about origin is 0. That is, $\begin{gathered}\vec{r} \times \vec{F}=\vec{0}\\ \\= > \begin{vmatrix}i&j&k\\a&3&6\\2&-6&-12\end{vmatrix}=0\\ \\= > i*0+j(12+12a)+k(-6a-6)=0\\ \\= > 12+12a=0,-6a-6=0\\ \\= > \boxed{a=-1}\end{gathered}$ Hence, VALUE of a is -1.

996.

Solve the question in the given attachment

Answer»

1) We have,

$\begin{gathered}\vec{F}=ai+3j+6k\\ \\ \vec{r}=2i-6j-12k\end{gathered}$

ANGULAR momentum about ORIGIN is conserved when torque about origin is 0.

That is,

$\begin{gathered}\vec{r} \times \vec{F}=\vec{0}\\ \\= > \begin{vmatrix}i&j&k\\a&3&6\\2&-6&-12\end{vmatrix}=0\\ \\= > i*0+j(12+12a)+k(-6a-6)=0\\ \\= > 12+12a=0,-6a-6=0\\ \\= > \boxed{a=-1}\end{gathered}$

Hence, VALUE of a is -1.

Discussion

997.	Sthir avshaon ke karan utapan electric field ka naam likhye
Answer» ANSWER: correct Explanation: some we are not ajusted in the same WAY

997.

Sthir avshaon ke karan utapan electric field ka naam likhye

Answer»

ANSWER:

correct

Explanation:

some we are not ajusted in the same WAY

Discussion

998.	The distance of the object from the plane mirror is 12.5 m . So the distance between the object and its image is
Answer» Explanation: problem is SOLVED in picture do LIKE and Mark if you are SATISFIED

998.

The distance of the object from the plane mirror is 12.5 m . So the distance between the object and its image is

Answer»

Explanation:

problem is SOLVED in picture

do LIKE and Mark if you are SATISFIED

Discussion

999.	Who discovered that there is electricity in lightning?I will choose the Correct answer without searching.As Brainliest.
Answer»

Discussion

1000.	The sound from a single source can reach point o by two different paths. One path is 20 m
Answer» Explanation: minimum FREQUENCY = 170 Hz Explanation: given data One path long = 20 m second path long = 21 m speed of SOUND = 340 m/s

1000.

The sound from a single source can reach point o by two different paths. One path is 20 m

Answer»

Explanation:

minimum FREQUENCY = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of SOUND = 340 m/s

Discussion

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