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that:-f = GMm/ (eq 1)acc. to questionG3Mm/3(GMm/)3F (said above in eq 1)THEREFORE force increases by 3 TIMES....

netic field PRODUCED by a current PASSING through the coil REACTS with the magnetic field of the PERMANENT

k you Escape velocityIn physics, escape VELOCITY is the MINIMUM SPEED needed for a free object to escape from the gravitational influence of a MASSIVE BODY. The escape velocity from Earth is about 11.186 km/s at the surface.

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ated all rreay but FORGOT EVERYTHING

larization is the degree to which the SPIN, i.e., the intrinsic angular MOMENTUM of elementary PARTICLES, is aligned with a given DIRECTION. This property may pertain to the spin, hence to the magnetic moment, of conduction electrons in ferromagnetic METALS, such as iron, giving rise to spin-polarized currents.

a case, 1/R=0 and thegravitational potential energy will be equal to. U i = ( G M m ) / r. This UI is CALLED the gravitational potential.Gravitational potential is the WORK done to bring a unit MASS m to a position r from infinity without allowing it to accelerate under the INFLUENCE of another charge M.hope this help u

The possibel CASES are as follows:R1=20cm 'R2= 30cm n=1.5 LENS MAKERS fromula : 1/F= (n-1) [1/R1-1/R2] For Double Convex lens :R1=+20cm R2= - 30cm1/f= (1.5-1)[1/20+1/30]=0.5 x [ 3+2/60]=0.5 x 5/60= 5X5/ 10 x 60=1/24f= 24cmFor Double concave lens :R1= - 20cm R2=+30cm1/f =(1.5-1)[-1/20 -1/30]=0.5x [ -3-2/60]f= -24cmFor Concave Convex : R1= +20cm R2= +30 1/f= 0.5[ 1/20-1/30] = 0.5 x [ 3-2/60] =5/10x60 f= 120cm For concave concave lens : R1= -20cm R2= - 30cm 1/f = 0.5x[ -1/20+1/30] = 0.5 [ -3+2/60] f= -1 20cm

ur fingers towards the DIRECTION of LOOP....i.e., clockwise in the above case.the thumb pointing gives the direction of magnetic field...if thumb points inward that means that the magnetic field will be inside the loop and if the thumb points outwards then magnetic field will be outside loop....HAPPY helping MATE..

e here is your...Electrolysis is the passing of a direct electric CURRENT through an IONIC substance that is either molten or dissolved in a suitable solvent, PRODUCING chemical reactions at the ELECTRODES and a separation of the materials.hope so answer will HELP...

vehicles have better mobility over rough terrain than those with wheels. ... Tracksare much less likely to get STUCK in soft GROUND, mud, or snow SINCE they distribute the weight of the VEHICLE over a larger contact area, decreasing its ground PRESSURE...mark me as brainliest if u like plzzz

operties of IMAGES formed by the given convex mirror are :  1 . Image is always erect  2. SMALL in size  3. VIRTUAL  4. Always form BEHIND the mirror  between focus and pole

0pa=F/0.0013F=0.455 N

inclination change is an orbital maneuver aimed at CHANGING the inclination of an ORBITING body's orbit. This maneuver is also known as an orbital plane change as the plane of the orbit is tipped. This maneuver requires a change in the orbital velocity vector (delta v) at the orbital nodes (i.e. the point where the initial and desired orbits intersect, the line of orbital nodes is defined by the intersection of the two orbital planes). In general, inclination changes can take a very large amount of delta v to perform, and most mission planners TRY to avoid them whenever possible to CONSERVE fuel. This is typically achieved by launching a spacecraft directly into the desired inclination, or as close to it as possible so as to minimize any inclination change required over the DURATION of the spacecraft life. Planetary flybys are the most efficient way to achieve large inclination changes, but they are only effective for interplanetary missions

body is an idealized physical body that absorbs all incident electromagnetic RADIATION,regradeless of FREQUENCY or ANGLE of INCIDENCE. I REALLY there is no perfect black body that is exist

Gonzales is absolutely correct, your stretched wire will have 4 times the resistance. Here is the math for this as presented when previously asked where the starting wire had 50 ohms resistance. LET us take a material that has a RESISTIVITY of 392.7 rho. This is the P that resistivity is measured in. This means that a 1 meter cube would MEASURE 1 ohm from side to side. Further let us imagine a wire of this high resistance material being 10 mm in diameter and having a length of 10 mm. Like this: Now we stretch this material to twice its length but the volume remains the same. Now our material looks like this: No, the diameter does not halve, it is the volume that stays the same. You may do the math for that bit. Using the formula for resistance, R, for this material’s resistivity on the original material for your 50 ohms as stated in your question: Where l=length A=Cross Sectional Area. Our stretched material, using the same formula, is:

are used to make TIGHT SEAL on the doors to refrigerator and FREEZERS . They power speakers in earphones,stereos and television.Magnets are used to store DATA in computers.

ac NEWTON (January 4, 1643- March 31, 1727 or in old style: December 25, 1642- March 20, 1727 ) was an English physicist mathematician, ASTRONOMER, alchemist ,inventor, THEOLOGIAN and natural philosopher .he is often regarded as the most influential SCIENTIST in history and is most famous for discovering the law of gravity.

ntiate the velocity EQUATION we GET some VALUE then we can find the REALATION

n between MOMENTUM and kinetic energySometimes it's DESIRABLE to express the kinetic ENERGY of a particle in terms of the momentum. That's easy enough. Since and the kinetic energy  soNote that if a massive particle and a light particle have the same momentum, the light one will have a LOT more kinetic energy. If a light particle and a heavy one have the same velocity, the heavy one has more kinetic energy.

of metre scale= 80gfulcrum= 70cmlet 60g be suspended at ycmsum of CLOCKWISE moment= SUN of anticlockwise moment60 x y = 80 x [70-50]60y = 1600y = 26.67cmthe mass of 60g must be placed at a distance 26.67 CM away from the fulcrum ______________________________________________0                                               50             70                  y          100                                                   l                                      l                                                 80g                                60g

ncave lens the position of the object does not matter.No matter where you PLACE the object the IMAGE will ALWAYS FORM between the optical centre and the focus and the image is always DIMINISHED. Therefore it is not possible for a concave lens with focal length 3cm to form an image at 10cm from the lens.Hope this helps.

diagram.we need to find the acceleration of the pendulum at any position that makes an angle Ф with the vertical at the point of support.pendulum length = L.  mass = m.  Le the tension force in the string connected to the pendulum bob be = T. The pendulum is released from position A.  It moves along the circular ARC APG.  At P the direction of movement of pendulum bob is along PF.The pendulum at position P does not move along  OP or PC.  Hence, the forces in this direction are balanced.  The bob moves along PF.         T = m g Cos Ф     - m g Sin Ф = net force acting on the bob at P.      a_t = linear instantaneous acceleration along the tangent to the arc  along PF            = Force/ mass = - g sin ФAs the pendulum is moving in a circular arc, there is a centripetal force on the bob of the pendulum.   Hence there is a centripetal acceleration resulting from it.           a_r = v² / L,    v = tangential instantaneous velocity.In the ideal simple pendulum, there is no loss of energy and the force that gives potential energy is the gravitational force.    change in P.E. of the bob when drops from A to P   =  m g BP = m g L Sin Ф   So KE of bob at P = m g L Sin Ф       1/2  m v² = m g L Sin Ф               v² = (2 g L Sin Ф)       Radial centripetal acceleration along PO = 2 g Sin Ф The net acceleration of the bob = √(a_r² + a_t²)                              a    = √[ (-g SinФ)² + (2gSinФ)² ]     magnitude   a = √5 g SinФ   Its direction is given by:  α with the tangential PF, SAY.       then according to the addition of vectors:                  tan α = (2g SinФ) / [g SinФ + 2g SinФ Cos 90°)                           = 2           so α = tan⁻¹ 2 = 63.43°  with PF.   So the angle between the two accelerations is always 90° and the angle between the resultant and each component of acceleration is always 63.43°  or (90° - 63.43°).  Thus, the resultant acceleration has magnitude √5gSinФ   and is horizontal when α = Ф = 63.43° and that is when the pendulum makes an angle 63.43° with the vertical.======================   the resulting acceleration of the accelerations along PO and PF will be horizontal if their vertical components along PB and PD cancel each other.     component of tangential acceleration a_t along PD =- g sin Ф * sin Ф     component of radial acceleration along PB = 2 g Sin Ф * Cos Ф             Hence, they cancel, if SinФ = 2 Cos Ф   ie.,  Tan Ф = 2    =>    Ф = 63.43 degrees with the vertical OG.   In that case the acceleration will be along PE.Read more on Brainly.in - brainly.in/question/92872#readmore

rt RATE is periodic as when we are at rest it BEATS with same rhythm.When we do any exercise or BECOME excited or do any work DUE to which there is an increase in the metabolism then also heart beats with same rhythm. It is true that when we run or do any exercise heart beats faster but then also it is periodic.So,BEATING of heart is periodic.

st is a type of FORCE USE this formula ↓F=maM=20000kg a=5m/s2Substituting values :- we GET ;F= 20000*5Therefore, Thrust =100000N

on and 10^23 MARS

e❤❤here's ua answer : As the electrons collide or VIBRATE, heat energy is GENERATED depending on the resistance of the conductor. This overall EFFECT is called heating effect of electrical current. This what causes the bulb to glow as the tungsten filament, which as a very high resistance, heats up as current passes through it.OR:Heating effect of electric current is responsible for the bulb to glow in an electric circuit. Due to heating effect, the filament of the bulb gets heated to a high temperature and it starts glowing. HOPE it helps uhByE

ssearchHOMEWORK HELP > SCIENCEWhy do liquids expand more than solids and gases expand more than liquids? Please, please, please help!! Is it because to start with the particles in a liquid are more spread out so when HEAT is...Why do liquids expand more than solids and gases expand more than liquids? Please, please, please help!!Is it because to start with the particles in a liquid are more spread out so when heat is added to them they expand even more?  Please help... got a test.print Print document PDF list CiteExpert AnswersBANDMANJOE | CERTIFIED EDUCATORThe molecules of a solid are arranged in a TIGHTLY-packed, ordered lattice.  The molecules experience some motion, but not much.  It would be fair to say they have a greater attraction between themselves than do the molecules of liquids or gases.  This is what gives matter classified as a solid its physical characteristics of being "solid":  its molecules don't separate from each other.  Liquids, on the other hand, have some attraction for each other, but their molecules are not arranged in the tightly constructed lattice solids have.  A liquid's molecules will have a definite volume, but will assume the shape of the container they occupy.  This is in direct contrast to the molecules of a solid which has both definite volume and definite shape.  The molecules of a gas have no attraction between them whatsoever.  Gases have neither definite volume nor definite shape.  So, SEEING the differences between the molecules of solids, liquids, and gases as they occur normally, when you add heat to the mix, it accentuates the properties that already exist  The solids molecules will expand a little, but remain relatively close TOGETHER, while the liquids molecules will expand even more sohope it help

×10 RAISED to minus8 (Dyncm)SQUARE / (G) square

per wire which are insulated with insulators LIKE RUBBER are CALLED insulated copper wire HOPE IT HELPS!!!

mical Telescope: Magnifying power of astronomical telescope in normal adjustment is defined as the RATIO of the angle subtended at the eye by the FINAL image to the angle subtended at the eye, by the object DIRECTLY, when the final image and the object both lie at infinite distance from the eye.Magnifying power, m = β/α   (1) As angles α and β are small, therefore, α ≈ tanα and β ≈ tanβ. where C1B' = f0 focal length of objective lens, C2B' = - fe  focal length of eye lens. Negative sign of m indicates that final image is INVERTED. The diameter of objective is kept large to increase (i) intensity of image, (ii) resolving power of telescope.

c Moment Formula: Calculation for a Bar Magnet(a) If a magnet of length l and magnetic moment M gets bent in the form of a semicircular, then its new magnetic SEE moment will be M’ = 2M/π(b) The magnetic moment of a given electron because of its orbital motion is 1μB. But due to its spin motion, it will be μB /2.i.e. Morbital = and Mspin = s Here μB = Bohr magneton(i) The value of Bohr magneton μB = eh / 4πm(ii) μB = 0.93 × 10–23 Amp-m2(c) Other formulae for magnetic moments:(i) M = ni R2(ii) M = eVr/2 = er2ω/2 = er22πf/2 = er2π/T(iii) e/mJ(iv) M = nωB(d) How can we calculate RESULTANT magnetic moment? (i) When two bar MAGNETS are lying mutually perpendicular to each other, thenM = √M12 + M22 = √2mplWhen two coils with a radius of r and carrying current I each, are lying concentrically with their planes at right angles to each other, thenM = √M12 + M22 = √2iπr2 if M1 = M2Illustration: A square loop OABCO of side l carries a current i. Now, find the magnetic moment of the loop.Solution: Magnetic moment of the loop can be written as,M = i (BC x CO), where the letters in bold denote the vectorsBC = -lkThis was our article on magnetic moment formula.

s FILTERS are used primarily in wireless transmitters and RECEIVERS. The main functions of such filter in a transmitter is to limit the bandwidth of the output signal to the MINIMUM NECESSARY to convey data at the desired speed and in the desired form.

artment has developed excellent facilities for clinical CARE and has fully developed facilities for adult and pediatric interventions INCLUDING coronary interventions, valvuloplasty, device closure of congenital shunts and electrophysiology services (including radiofrequency ablation, pacemaker, bi-ventricular pacemaker and cardioverter defibrillator implantation). Laboratory testing facilities include treadmill testing, holter recording, echocardiography (including transthoracic, TRANSESOPHAGEAL, 3-D and fetal echocardiography), Tilt testing for syncope and electrophysiology testing including CARTO system mapping. The department has done pioneering work in the FIELD of rheumatic fever and rheumatic heart disease including JUVENILE mitral stenosis, coronary artery disease including angioplasties, arrhythmias, cardiomyopathies and congenital heart diseases.