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TE !!!HOPE THIS HELPS YOU ...Derivation for the FORMULA for the resultant resistance when the resistors are in the parallel combination .CONSIDER 2 resistors R1 and R2 to be connected n parallel combination.                     Two resistors are said to be in the parallel combination when the both of the ends of the resistors are collected and tied together to have the resistors with common potential difference.We know that ,                                                                                                From Ohm's Law ,      V = IR                                                                            Then for parallel combination let R(p) be resultant resistance of parallel combination, and I be resultant current.                                                                                                  So, V = IR(p) or I = V/R(p) _________________[ 1]Since in parallel combination the potential difference will be the same ,let it be considered as V .Let current through resistors R1 and R2 be I1 and I2 respectively.               Then,                                                                                                                        => I = I1 + I2 _________________[2]Then, substituting equation [ 2] in equation [ 1]  .=> I1 + I2 = V/R1 + V/R2=> I = V [ 1/R1 + 1/R2 ]From equation [ 1] putting , I = V/R(p)=> V/R(p) =  V [ 1/R1 + 1/R2 ]=> 1/R(p) = 1/R1 + 1/R2Hence , the resultant resistance for resistors in parallel can be GIVEN by the equation 1/R(p) = 1/R1 + 1/R2THANK YOU FOR THE WONDERFUL QUESTION ...#bebrainly

he right circumstances LIGHT can be used to push electrons, freeing them from the surface of a solid. This process is called the photoelectric effect(or photoelectric emission or photoemission), a material that can exhibit this phenomena is said to be photoemissive, and the ejected electrons are called photoelectrons; but there is nothing that would distinguish them from other electrons. All electrons are identical to one another in MASS, charge, spin, and magnetic moment.The photoelectric effect was first observed in 1887 by Heinrich Hertz during experiments with a spark GAP generator (the earliest device that could be called a radio). In these experiments, SPARKS generated between two small metal spheres in a transmitter induce sparks that jump between between two different metal spheres in a receiver. Compared to later radio devices, the spark gap generator was notoriously difficult to work with. The air gap would often have to be SMALLER than a millimeter for a the receiver to reliably reproduce the spark of the transmitter. Hertz found that he could increase the sensitivity of his spark gap device by illuminating it with visible or ultraviolet light. Later studies by J.J. Thomson showed that this increased sensitivity was the result of light pushing on electrons — a particle that he discovered in 1897.

aves can propagate over the horizon when the LOWER atmosphere of the earth bends, scatters, and/or reflects the electromagnetic fields. These EFFECTS are collectively known as tropospheric propagation, or tropo for short. Tropospheric propagation can affect wirelesscommunications, sometimes enhancing the usable range, but also compounding interference problems.The most well-known form of tropo is called bending. Air reduces radio-wave propagation speed compared with the speed in a vacuum. The greater the air density, the more the air slows the waves, and thus the greater is the index of refraction. The density and index of refraction are highest near the surface, and steadily decrease with altitude. This produces a tendency for radio waves at very-high frequencies (VHF, 30 to 300 MHz) and ultra-high frequencies (UHF, 300 MHz to 3 GHz) to be refracted toward the surface. A wave beamed HORIZONTALLY can follow the curvature of the earth for hundreds of miles.The lower atmosphere scatters electromagnetic radiation over a vast range, including radio WAVELENGTHS. This effect is known as tropospheric scatter, or troposcatter. In general, troposcatter is most pronounced at UHF and microwave radio frequencies (300 MHz and above). A radio wave beamed slightly above the horizon can be scattered at altitudes up to several miles, making over-the-horizon communication possible. The greatest communications range can be realized over FLAT land or over water. Scattered waves are weak, so high-power transmitters and sensitive receivers are necessary.Hope it help.

on Moon BECOMES the WEIGHT on EARTH.Weight on Earth = 30 N Weight on Moon = 1/6 × 30=

c field is the negative gradient of the scalar potential. Thenegative sign came as a result because the potential DIFFERENCE is thework done PER UNIT CHARGE against the electrostatic force to move a charge from a to b. However, this EQUATION is valid only for static electrostatic fields

energy=(1/2)m(v^2)m=massv=velocitythis is for LINEAR motions .If we consider about angular motions, it becomeskinetic energy=(1/2)*moment of INERTIA*(angular velocity^2)angular velocity=linear velocity/radius of the MOTION

ivity of intrinsic SEMICONDUCTOR is due to their own internal charge CARRIERS. The bonding between between two ELECTRONS of two neighboring atoms is covalent, therefor at NTP, there is no free charge carrier for CONDUCTION.

y consumes 12KG LPG in 30 days .then, the family consumes LPG in a day = 12/30 KG = 0.4 kg .a/c to question, The CALORIFIC value of LPG = 50J/kg you should understand that, calorific value means the MEASUREMENT of heat PRODUCED by specific amount of fuel or food . this is usually expression in joule per kg. so, the average energy consumed per day = calorific value of LPG × amount of LPG consumed in a day = 50 × 0.4 J = 20J hence, 20J energy consumed per day.

charged particle enters a magnetic FIELD, it experience Lorentz force given by: dpdt=qv⃗ c×B⃗ dpdt=qv→c×B→Since the force is CROSS product of particle’s velocity and magnetic field, it will be perpendicular to the DIRECTION of motion — the force does no work on the charge particle. Thus, the kinetic energy is unchanged—speed of the particle remains the same. The only thing it can change is the direction of the motion.You can find the radius and time period of the CIRCULAR motion by EQUATING the above expression of mechanical force with the centripetal force give by: Fc=mv2r.

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distance from the mirror, u = -40cm FOCAL length of concave mirror , f = -50cmuse formula, 1/v + 1/u = 1/f or, 1/v + 1/-40 = 1/-50 or, 1/v = 1/-50 + 1/40 or, 1/v = (-4 + 5)/200 = 1/200 v = 200cmhence, position of IMAGE from the pole of mirror is 200CM . we know, magnification = -v/uheight of image/height of object = -v/u height of image/4cm = -200cm/-40cm height of image/4cm = 5height of image = 20cm

R,2R+2R=4R1/4R+1/4R=2/4RR=2R....

of copper = 9 × 10³ kg/m³ first, we have to find number of ATOMS per unit volume. atomic weight of copper = 63g/mol = 63 × 10^-3 kg/mol volume of 1 mole of copper = mass of 1 mole of copper/density of 1 mole of copper = 63 × 10^-3/9 × 10³ = 7 × 10^-6 m³ number of electrons in 1 mole of copper = 29 × 6.023 × 10²³ so, number of electrons per unit volume = 6.023 × 10²³/7 × 10^-6 = 8.6 × 10^28 /m³ now use FORMULA, here, i = 1.1 A , n = 24.95 × 10^29/m³ e = 1.6 × 10^-19 C and A = π(1/2 × 10^-3)² so, vd = 1.1/{8.6 × 10^28 × 1.6 × 10^-19 × 3.14 × 1/4 × 10^-6 } = 4.4/{24.95 × 1.6 × 3.14 × 10³} = 0.1 × 10^-3 m/s HENCE, drift velocity = 10^-4 m/s

refractive INDEX varies with wavelength, so will the refraction angle as light goes from one material to another. Dispersion also causes the focal LENGTH of lenses to be wavelength dependent. ... For VISIBLE light normal dispersion MEANS that the refractive index is higher for BLUE light than for red.

ion through a rectangular glass slab. ... In the FIGURE i is the angle of incidence, R is the angle of refraction and e is the angle of EMERGENCE. Angle of incidence and angle of emergence are EQUAL as emergent ray and incident ray are parallel to each other.

s law of cooling states that the rate of heat loss of a body is directly proportional to the difference in the temperatures between the body and its surroundings provided the temperature difference is small and the nature of radiating surface remains same. As such, it is equivalent to a statement that the heat transfer coefficient, which mediates between heat losses and temperature differences, is a constant. This condition is generally TRUE in thermal conduction (where it is guaranteed by Fourier's law), but it is often only approximately true in conditions of convective heat transfer, where a number of physical processes MAKE effective heat transfer coefficients somewhat dependent on temperature differences. Finally, in the case of heat transfer by thermal radiation, Newton's law of cooling is not true.Sir Isaac Newton did not ORIGINALLY state his law in the above form in 1701, when it was originally formulated. Rather, using today's terms, Newton NOTED after some mathematical manipulation that the rate of temperature change of a body is proportional to the difference in temperatures between the body and its surroundings. This final simplest VERSION of the law given by Newton himself, was partly due to confusion in Newton's time between the concepts of heat and temperature, which would not be fully disentangled until much later.[1]When stated in terms of temperature differences, Newton's law (with several further simplifying assumptions, such as a low Biot number and temperature-independent heat capacity) results in a simple differential equation for temperature-difference as a function of time. This equation has a solution that specifies a simple negative exponential rate of temperature-difference decrease, over time. This characteristic time function for temperature-difference behavior, is also associated with Newton's law of cooling.

ticular TEMPERATURE at which liquid starts BOILING at NORMAL ATMOSPHERIC PRESSURE

काय (सिस्टम) की कार्य करने की क्षमता को उर्जा कहते हैं। किसी संकाय पर काम करके या उसके द्वारा काम कराकर ही उसकी उर्जा को बदला जा सकता है क्योंकि उर्जा वह राशि है जो संरक्षित (कंजर्व्ड) होती है। उर्जा तरह-तरह के रूपों में पायी जाती है और भिन्न-भिन्न प्रकार की उर्जा का परस्पर परिवर्तन किया जा सकता है। किसी प्रकार की उर्जा कहीं उपयोगी है तो किसी प्रकार की कहीं और। उदाहरण के लिये कोयले में संचित रासायनिक उर्जा को जलाकर उससे उष्मीय उर्जा प्राप्त की जा सकती है। इस उष्मा से पानी को उबालकर वाष्प बनाकर उससे वाष्प टरबाइन चलाकर इसे यांत्रिक उर्जा में बदला जा सकता है। इस टरबाइन से कोई विद्युत जनित्र चलाकर इस यांत्रिक उर्जा को विद्युत उर्जा में बदला जा सकता है। इस विद्युत उर्जा से प्रकाश बल्ब जलाकर प्रकाश उर्जा प्राप्त की जा सकती है।

y Binding energy is the TOTAL amount of energy required by a SATELLITE to go from its ORBIT to infinity.binding energy = - total energy of satellite in its orbit. = = -T.E = -(K.E + P.E) we know, P.E is given by, P.E = -GMm/r and K.E is given by , K.E = 1/2mv² but we know, centripetal force = gravitational force [ in CIRCULAR orbit at equilibrium]so, mv²/r = GMm/r² so, mv² = GMm/r or, K.E = 1/2mv² = GMm/2r so, T.E = K.E + P.E = GMm/2r - GMm/r = -GMm/2r hence, binding energy of satellite =-(- GMm/2r)= GMm/2r, where M is mass of earth , m is mass of satellite and r is the radius of satellite.

convert ELECTRICITY into other forms, most of the energy is CONVERTED to useful work. But some of it is converted into heat energy.This is the heating effect of current. It is commonly known as resistive heating. It was FIRST OBSERVED by James Joule. We put this in phenomenon in a useful way. The Iron box and heater work on this principle.

entum (p) of an object is found by MULTIPLYING the OBJECTS MASS (m) in kilograms (kg) by it’s velocity in metres per second (ms-1). MOMENTUM = mass x velocity p=mv Momentum image 1 Momentum is a vector and it’s unit is the kilogram metre per second (kgms-1). Example; A car of mass 2000 kg is TRAVELLING at 32 ms-1. What is its momentum? momentum calc 4 Newton’s Second Law  – link to Newton’s laws. The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force. The resultant force is equal to the rate of change of momentum. rate of change of momentum 2 Impulse If we multiply the force acting on an object by the time it is acting for this is called the impulse of a force. Impulse is a vector and its unit is the kilogram metre per second (kgms-1) or the newton second (Ns). Impulse Impluse So we can see that  impulse is equal to the change in momentum.

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is given ase=v*I*ttake the time in secondafter that the SI UNIT of ENERGY is KWH

e.....❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️Physics extends well into your everyday life, DESCRIBING the MOTION, forces and energy of ordinary experience. In actions such as walking, driving a car or using a phone, physics is at work. For everydayliving, all the technologies you might take for granted exploit the rules of physics.hope it helps U ....❤️❤️❤️❤️❤️❤️❤️pls FOLLOW me

l is who that GIVES rise to their youngones INSIDE mother and don't lay eggs PRODUCE MILK

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ata: Mass of wagon (m) = 3000 kg Position (Δx)= 10 pm = 10 ×10-12m = 10-11m Planck's constant = 6.63 x10-34 Js Βy UNCERTAINTY principle, ∆v = h/ 4π (m∆x) = 6.626 X10-34 / 4x3.14 (3000 x 10 -11) = 1.76 X 10 -27 m/sHave a gud day!!!!

Summer, sound travels faster during the summer.Sound travels outwards from the source in all directions. So there you have it sound does travel faster in warm air BUT it may appear to travel farther in cold air. …if the air close to the GROUND is colder than the air above it then sound waves TRAVELLING upwards will be BENT downwards. This is called Refraction.

, elastic modulus is the ratio of stress to strain, stress is the LOAD applied per unit area and strain is change in length of material per unit length. E.g., elastic modulus = FL/A∆Lwhere F is load applied on bar. ∆L is increase in length of bar due to applied load, L is original length of bar and A is CROSS sectional area.here, L = l, A = a , F = p and elastic modulus = ESO, e = Pl/a∆Lor, ∆L = pl/ae hence, increase in length of the bar = pl/ae

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the ENERGY in kilowatt HOUR, we will use a FOMULA for the CALCULATION of KWH.Energy in kWh = = = 0.12kWh.Thanks for asking.All the best.

ne =FORCE *displacement VELOCITY =displacement ÷timetherefore, displacement = velocity *timehere,velocity =5m/s. time=2min = 120secondsforce=2.5*10^6hence....work DONE = 2.5*10^6 × 5m/s × 120 sec = 1500*10^6 J

s a clock with a “seconds” hand Action The STUDENTS observe the clock and calculate the angular VELOCITY of the three hands. They may also calculate the linear velocity of the hands if the radius is measurable (if the clock is not mounted high up on a wall). The Physics The angular velocity is independent of the clock size, however for LARGER clocks the linear velocity of the pointers at the end of the hands will be greater. The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds, so ω = π/30 rad.s-1 = 0.03 rad.s-1. The minute takes one hour = 60 s/min × 60 min = 3600 s to go around, so ω = 2π / 3600 rad.s-1 = 1.7 × 10-3 rad.s-1. The hour hand takes 12 hours = 12 hours × 60 min/hour × 60 s/min = 43200 s to do 2π radians, so ω = 2π rad/43200 s = 1.5 × 10-4 rad.s-1. Accompanying sheet Clocks What is the angular velocity of the second hand? What are the angular velocities of the minute and hour hands? Does it matter how big the clock is? Does the length of the hands make a difference to their linear velocity?

st have to learn d elements acc. to d periodic table to know d atomic no. of any element. to compute it's electronic configuration, arrange d no. of electrons in d ENERGY shells. d no. of electrons can DETERMINED by jus lukin at its corresponding atomic no. let's see d electronic configuration of Al, Mg, Ca, n C k. L. m. n Al. 2. 8. 3 Mg. 2. 8. 2 Ca. 2. 8. 8. 2 C. 2. 4