Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is theTIREXPLAIN IT​

Answer»

BUT CAN YOU WRITE THE QUESTION PROPERLY....

2.

Define electron beam.​

Answer»

Electron beam (EB) welding is a fusion welding process whereby electrons are generated by an electron GUN and accelerated to HIGH speeds using ELECTRICAL fields. This high SPEED stream of electrons is tightly FOCUSED using magnetic fields and applied to the materials to be joined.

3.

In the demonstration of a stunt, two solid balls of equal density and radii rand 2, are placed with the centre of the larger one above the middle of a cart of mass M = 6 kg andlength L = 3 m. The mass of the smaller ball is m = 1 kg. The balls are made to roll,without slipping in such a way that a straight line connecting their centres remains ata constant angle 0) = 53° to the horizontal. The cart is pulled by a horizontal force. Findthetimetaken for the balls to fall of the edge of the cart, in seconds(Take g = 10 m/s)​

Answer»

tion:Given,Two balls, each of radius R and of equal mass and density, are placed in contact.Step-1:FIND the Distance between the centre of two ballsDistance between the centre of two balls = SUM of their Radii.Distance between the centre of two balls =R+R=2R.Step-2:Express the Mass of a ball as product of Density and Volume.(This would be same for other ball ,given that two balls have equal mass)Since, the shape of the ball is Sphere.Volume of the ball V=34πR3So,Mass of the ball m=ρ×34πR3Step-3:Find the force of gravitation between the two balls.According to Newton's LAW of Universal GravitationF=r2GMmWhere,F= Gravitational Force between two objects.G= Gravitational constantM= Mass of the first objectm= Mass of the SECOND objectr= Distance between objectsHere,.M=m=ρ×34πR3Substituting Values⟹F=(2R)2Gm2⟹F=4R2G(ρ×34πR3)2⟹F=G×ρ2×(34)2×41×R2

4.

Judge the equivalent resistance when the following are connected in parallel a) 1 home andb) 1000000homes​

Answer» JUDGE the equivalent resistance when the following are CONNECTED in PARALLELA) 1 home andb) 1000000homesExplanation:judge the equivalent resistance when the following are connected in parallela) 1 home andb) 1000000homes
5.

स्प्रिंग पर 2 केजी 5 केजी 7 केजी का mass hi tho claculate in all strings (G=10m/s) ​

Answer»

T in all STRINGS are20N, 50N, 70N RESPECTIVELY

6.

Q1. has air weight ?​

Answer»

yesair is the EARTH's ATMOSPHERE. it's a MIXTURE of several gases and elements.it has MASS and weight as it is a MATTER.

7.

15. State and prove Newton's second law of motion.​

Answer»

hii I think that it helps youExplanation:Newton's SECOND law of motion states that the acceleration of a SYSTEM is directly PROPORTIONAL to and in the same direction as the NET external force acting on the system, and inversely proportional to its mass. In equation form, Newton's second law of motion is a=Fnetm a = F net m .

8.

Why are artificial magnets preferred to natural magnets ?​

Answer»

ial magnets are preferred over NATURAL magnets because natural magnets are WEAK and OFTEN irregular in SHAPE, they can readily be magnetised and demagnetised by turning the current on or off in the coil.

9.

Railway tracks expand in winters and contract in summers. True or False

Answer»

FalseExplanation:RAILWAY tracks expand in summer and contract in WINTER .HOPE it helps :-)

10.

Define centre of mass​

Answer» ICS, the CENTER of mass of a distribution of mass in SPACE is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force MAY be applied to cause a linear acceleration without an ANGULAR acceleration.
11.

In a spring mass vibrating system, the natural frequency of vibration is 3.56 Hz. When the amount of the suspended mass is increased by 5 kg, the natural frequency is lowered to 2.9 Hz. Determine the original unknown mass and the spring constant​

Answer»

tion:HIGH school and WORK on the way to the gym and then I will be there for you to be a GOOD day at work and I have to be a good day at work and I have to be a good day at work and I have to be a good day at work and I have to

12.

शब प्रश्न १. खालील वाक्यांतील क्रियाविशेषण अव्यये ओळखा. (sentences.)(१) रेषा काढत हातभर पुढे सरकल्यावर मागे वळून पाहावे.​

Answer»

क्रियाविशेषण अव्यये:(१) पुढे 2) मागे

13.

what voltage must be applied to an x ray tube for it to emit x rays with a minimum wavelength of 30pm

Answer» PLEASE MY SWEET FRIEND EXPLAIN YOUR QUESTION CLEARLY.
14.

What are the use of Bleaching Powder ?​

Answer»

Uses of Bleaching PowderIt is USED for bleaching dirty clothes in the laundry, as a bleaching agent for COTTON and linen in the TEXTILE industry. It is a strong OXIDIZING agent, hence used as an oxidizer in many industries. It is used as a disinfectant which is used for disinfecting water to make potable water.

15.

How can you say that temperatureis the measure of thermal equilibrium​

Answer»

rmal ENERGY will flow in that DIRECTION until the two objects are at the same temperature. When the two systems in contact are at the same temperature, we say they are in THERMAL EQUILIBRIUM.

16.

Which of following is the defect in which a person cannot see the distant objects clearly​

Answer»

is the DEFECT in which a PERSON cannot SEE the DISTANT objects clearly.

17.

Calculate the amount of energy needed to raise the temperature of 3.0 kg of steel from 20 °C to 120 °C. Thespecific heat capacity of steel is 490 J kg-1 K-1. please answer with a step by step with your answer and with all formulas filled in.​

Answer»

ss(M) = 3kgchange in TEMPERATURE(ΔT)= 120K-20K                                      = 100*C                                    c= 490 J Kg-1 K-1                                   Q= McΔT                                  490 × 3 × 100                                  147000 J Ans.Hence 14700 J of HEAT energy needed to raise the temperature of 3 kg of steel from 20K to 120K (or in degree celsius one and the same THING)

18.

Give the genotype and phenotype ratio for F1 and F2 generation according to second law of Mendel

Answer»

Every member of the F1 GENERATION is HETEROZYGOUS and the phenotype of the F1 generation expresses the dominant trait. Crossing two members of the F1 generation produces the second filial (F2) generation. ... This predicted 3:1 phenotypic ratio ASSUMES Mendelian inheritance.

19.

Log of 0.62 pls explain​

Answer» ISKA fraction batana hai toh 62/100 EXPLANATION:HOPE this helps you
20.

If the coefficient of kinetic friction between the 75 kg crate shown in Figure 1 and the ground is µk = 0.3, determine the distance the crate travels and its velocity when t = 3 s. The crate starts from rest, and P = 200 N. Show the free body diagram with your answer. P has an angle of 30 degrees and the direction of P is to the right.

Answer»

t's this yaargive UR NUMBER I WANT to MAKE FRIENDSHIP with you

21.

Match the following. Column A(a) Lubricants(b) Liquid pressure(c) Loudness of sound(d) Ultrasonic sound(e) Pure waterColumn B1. Increases with depth2. Reduce the friction a3. Produced by bats4. Insulator of electricity5. Increases with its intensity​

Answer»

he following.Column A(a) Lubricants(b) Liquid pressure(c) LOUDNESS of sound(d) Ultrasonic sound(E) Pure waterColumn B1. Increases with depth2. REDUCE the friction a3. PRODUCED by bats4. Insulator of electricity5. Increases with its intensityExplanation:match the following.Column A(a) Lubricants(b) Liquid pressure(c) Loudness of sound(d) Ultrasonic sound(e) Pure waterColumn B1. Increases with depth2. Reduce the friction a3. Produced by bats4. Insulator of electricity5. Increases with its INTENSITY

22.

How do we change an open circuit to a closed circuit?

Answer»

it can be OPENED or CLOSED with the HELP of SWITCH.

23.

The leakage current in a po juuction is of the order of (A) MA(B) mA(C) KA(D) Aintringir semirundutor has​

Answer»

The ANSWER is (A) MA this CORRECT answer PLZ me FOLLOW

24.

A runner starts a race and in 1.25s has a velocity of 5.0m/s [E]. Determine the acceleration of the runner

Answer»

4m/s^2Explanation:initial velocity = 0m/sfinal velocity = 5m/stime = 1.25sby FIRST equation of motion,v= u+ atlet the ACCELERATION be A5 = 1.25 aa = 5/1.25 = 500/125 = 4A = 4m/s^2

25.

Explain magnetic field due to a current through a circular loop​

Answer»

The magnetic field around a STRAIGHT CURRENT carrying CONDUCTOR or wire can be increased by bending the wire into circular loop. ... Each small section of current carrying wire CONTRIBUTES to magnetic field lines. At the CENTRE of circular wire,field lines become straight and perpendicular to the plane of coil.

26.

Please help me to find answer​

Answer»

now SORRY sorry sorry sorry sorry sorry sorry sorry sorry

27.

What were the brutalities held during the Nazi Period?Meli koi feelings noi h kya 乁( •_• )ㄏ​

Answer»

tion:During World War II, the GERMANS' combined armed forces (Heer, Kriegsmarine and Luftwaffe) committed systematic war CRIMES, including massacres, mass rap e, LOOTING, the exploitation of FORCED labor, the murder of three MILLION Soviet prisoners of war, and participated in the extermination of Jews.

28.

What is a circuit and workdone?​

Answer»

An electrical circuit is simply an energy transformation tool. Energy is PROVIDED to the circuit by an electrochemical cell, BATTERY, generator or other electrical energy source. ... The work done on the CHARGE is equivalent to the electrical potential energy CHANGE of the charge

29.

A)Draw a distance time graph for the bus .b)What would be the nature of motion of the bus?​

Answer»

ravels along a STRAIGHT PATH and also some times along CURVED path its motion is rectilinear motion or simply linear motion. A BUS moves along straight line so we can we one DIMENSIONAL motion's equation to calculate any dimension regarding its motion.

30.

Which are the bad conductor is out the ​

Answer»

non metals are bad CONDUCTOR EXPLANATION:PLS like

31.

A diver decreases the speed of a car from 30m/s to 20m/s in 10 second. Find acceleration. ​

Answer» TION:ACCELERATION =( v-u)/t =( 20-30)/10= -10/10= -1m/s²
32.

The substance having a density of 0.8g/cm3 has a mass of 64 gram . What is it volume???​

Answer»

Here the density = 0.8g/cm³And MASS = 64gAs you know density =mass /VOLUMETO find volumeSo, ... is the correct answer please thank my all question and follow

33.

Write symbols and state functions of each of the following components (I) resistance(I) open switch​

Answer»

this is the answerExplanation:WRITE SYMBOLS and STATE functions of each of the following components(I) RESISTANCE(I) open switch

34.

Pwedi poh mangligaw sa mga babae​

Answer»

what R U SAYING i didn't UNDERSTAND ^-^!

35.

A body initially travelling a 10m/s is given a retardation of 2m/s for 3s find its final velocity​

Answer»

The required final velocity is 4 m/sExplanation:Given :A BODY initially travelling at 10 m/s is given a RETARDATION of 2 m/s² for 3 sTo find :the final velocitySolution :Using the first equation of MOTION, v = u + atwherev denotes the final velocityu denotes the initial velocitya denotes the accelerationt denotes the timeSubstitute, u = 10 m/sa = -2 m/s² (retardation) t = 3 sv = 10 + (-2)(3)v = 10 - 6V = 4 m/sTherefore,the required final velocity is 4 m/s

36.

Explani about anytwo sesexculmöbles of reprodotlon whith examples ​

Answer» CTION and manuvalmark me as BRIANLIST ❤️❤️ PLS
37.

Explain the formation of image by a plane mirror with the help of ray diagram for a point sized object ​

Answer»

For the ray starting from point A and travelling in a horizontal direction towards point E, the ANGLE of INCIDENCE is 0 and hence it retraces its path. Similarly, the ray starting from A and travelling towards point C follows the law of reflection. When these rays are produced backwards they appear to meet at a point E and D. Now this image is known as a virtual image. What is the difference between real and virtual IMAGES? In real image, the rays of light actually meet after reflection while in a virtual image it APPEARS to meet but not actually meet. A real image can be obtained on screen but not a virtual image.Explanation:mark me as brainleist

38.

What is constant acceleration and zero acceleration..! ​

Answer» ANT acceleration MEANS that the acceleration does not CHANGE. Some would say that if the acceleration is zero then the acceleration does not change and so ONE can say that the acceleration is constant.HOPE IT HELPS U ✌✌✌...
39.

Light of frequency 7.21 x 10^4 Hz is incident on a metal surface. The cut-off wavelength for photoelectric emission from the metal surface is 540 nm. Determine the maxim n speed of thephotoelectrons emitted from the surface. (Given: h= 6.63 x 10-34 Js, mass of an electron = 9.1 x 10-31kg).​

Answer» EXPLANATION:Given frequency of LIGHT= 7.21*10^4 Hzcut off WAVELENGTH= 540 nmKE(max)= 1/2mv^2= h(v-v0)v0= v- MV^2/2hV0= 7.21- 9.1*10^-31 * (3*10^8)^2/2(6.63*10^-34)V0= 4.74* 10^14 HzNote: in the given question, speed should be given , and we NEED to find threshold frequency.
40.

The sum of multiple forces acting on one object is called

Answer»

ᴛʜᴇ sᴜᴍ ᴏғ ᴍᴜʟᴛɪᴘʟᴇ ғᴏʀᴄᴇs ᴀᴄᴛɪɴɢ ᴏɴ ᴏɴᴇ ᴏʙᴊᴇᴄᴛ ɪs ᴄᴀʟʟᴇᴅ ɴᴇᴛ ғᴏʀᴄᴇ.

41.

A car travels with a constant velocity of 45km/hr for 20s. what distance does it cover in this time​

Answer» DISTANCE COVERED in this TIME is 250 m
42.

The length of a running track is measured and given as 400m,find the percentage error if the length is measured to 1 significant figure

Answer» WER of this QUESTION is
43.

The mass of the boy is 35 kilograms. What is the force of friction that slowed him down? Use the equation for Newton’s second law, F = ma.

Answer»

F=ma35Explanation:

44.

A n s. t h i s . . . . . . . . ​

Answer»

100/1=100m WAVE LENGTH

45.

If the magnitude (M) of silicon is 4.5×10 A/M and magnetic field strength (H) is 1500A/M, calculate its magnetic sussability​

Answer» SILICON KA at.. MASS YAD HAI or at.. no..
46.

A of1000 kg travelling at108 kmh uniformly brought to restdistance of 40m Find (a) theoccelerations (b) the averageondagecvetbreaking force?​

Answer»

mzjznzjz.. jjkzkzkzhzjzjzjnz. znzhznzExplanation:hshduhsbxjxj

47.

What is the amount of charge possessed by 1 kg of electrons ?(1) 1.76 x 1011 C(2) 1.76 x 10-9 C(3) 1.76 x 10-7 C(4) 1.76 x 10-5 C​

Answer» 1.76× 1011 CEXPLANATION:NUMBER 1 is your ANSWER
48.

What type of treatment of leaky rocks are used when conditions are Fault zone,joints and dykes?​

Answer»

Joints and faults are types of FRACTURES. A JOINT is a fracture along which no movement has taken place, usually caused by tensional FORCES. A FAULT is a fracture or BREAK in the rock along which movement has taken place.

49.

Please answer the attachment question?​

Answer»

This is an CIRCUIT CONNECTED to the AMMETER or AMPERE

50.

Bones of a person are fractured in an accident why​

Answer»

he breaks are TYPICALLY caused by the force of the crash, the BODY being hit with external objects, being thrown forward or backward in an unnatural way, having the limbs and bones twisted or bent UNNATURALLY, being thrown from the CAR or by being CRUSHED in the crash.