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h = 125 mExplanation:Hello Friend, LETS say that the stone is in motion for ' t ' seconds.Distance covered by the stone in first 4 seconds:u = 0 , t =4 , a = 10s = 1/2 x 10 x 16 = 80 mIn last two seconds:The stone would already have some velocity DUE to it's drop from intitial position. Let us find this velocity:t = t -2 (since only two seconds are left in motion) , u = 0 , a =10v = 10(t-2)The stone would have a velocity of 10 (t-2) two seconds before it hits the ground.So,u = 10(t-2) , a = 10 , t =2 (as it is given only two seconds are left in motion) ,         s = 80 (as it is given distance covered in first 4 seconds is equal to this distance)80 = 10(t-2)2 + 5(4) => 80 = 20t - 40 + 20 => t = 5 secondsTherefore the stone is in motion for 5 seconds.IN the questions, they demand us to find h.h = 1/2 x 10 x (25)Therefore h = 125 m Dear friends, I have directly applied equations of motions here. Please understand it, I used only s = ut + 1/2 at^2 and v = u + at , nothing else.If you LIKE the answer please mark me as brainliest and also give me thanks.

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RAM, which stands for random ACCESS memory, and ROM, which stands for read-only memory, are both present in your computer. RAM is volatile memory that temporarily STORES the files you are working on. ROM is non-volatile memory that permanently stores INSTRUCTIONS for your computer

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33.75 mExplanation:We know MAX height = u^2 sin^2thetha / 2G (thetha is the angle MADE with the horizontal)------    Here, H = 900 X (3/4) / 20 = 135/4 = 33.75Please mark me as brainliest and follow me if you like the answer.

Explanation:one must find out the time taken by the body sent upward to meet the top body (as if the body was not dropped) so if you divide the height 200m by the velocity 50m/s then one gets 4 sec. if you do all EQUATIONS as done by another responder for accelerated motion ultimately you will get the same answer. you can ask why you are getting the CORRECT time interval even if g was put off. it so happens that the acceleration produced each sec to the top body (dropped)is also a DECELERATION produced to the velocity of bottom particle, so net EFFECT of g gets adjusted. now to find where they will meet -the top one will travel a distance in 4 sec d= (1/2) g . t^2 = (1/2) x 9.8 x 16 = 78.4 meters from the top ; so from the bottom the distance would be d’= 200–78.4 = 121.6 m

dyn/cm² – Dyne per Square Centimetre Pressure Unit Dyne per Square Centimeter is ONE of the smallest pressure units and is derived from the CGS unit for force where 1 dyne equals 1 gram accelerated by 1 centimeter per second per second. 1 Dyne per Square Centimetre equals 0.1 pascals. The dyn/cm^2 is mainly used for pressures associated with the measurement of shear stress and is strongly linked to the measurement of surface tension where dyne/cm is a commonly used unit. You will find conversion values for 1 dyn/cm2 into other pressure units in the table below. To find the number of dynes/cm2 that other pressure units convert into, please CLICK on the appropriate link from the choices below. For calculating SEVERAL values of dynes/cm2 we SUGGEST you use our pressure unit CONVERTER to save time.Explanation:

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म्नलिखित है:माना कि बाट 5 इकाई, 2 इकाई, 2 इकाई तथा 1 इकाई के हैंहमारे पास 2 इकाई के 2 बाट तथा 5 इकाई और 1 इकाई के 1-1 बाट हैंयदि हमें 3 इकाई का बाट चाहिए तो3  = 2 + 1यदि हमें 4 इकाई का बाट चाहिए तो4  = 2 + 2यदि हमें 6 इकाई का बाट चाहिए तो6  = 5 + 1यदि हमें 7 इकाई का बाट चाहिए तो7  = 5 + 2यदि हमें 8 इकाई का बाट चाहिए तो8  = 5 + 2 + 1यदि हमें 9 इकाई का बाट चाहिए तो9  = 5 + 2 + 2यदि हमें 10 इकाई का बाट चाहिए तो10  = 5 + 2 + 2 + 1इस प्रकार हम एक से दस तक सभी इकाई के बाटों का निर्माण कर सकते हैं|हालांकि 5:2:2:1 के अलावा भी अनुपात हैं जिनसे 1-10 तक के इकाई के बाटों का निर्माण किया जा सकता हैपरंतु 5 इकाई का बाट अधिक उपयोगी होने के कारण यह अनुपात 5:2:2:1 ही लिया जाता है|आशा है यह उत्तर आपकी सहायता करेगा|और जानिये:इसी प्रकार के प्रश्नbrainly.in/question/20560081

One gauss is defined as one MAXWELL per SQUARE centimeter. The cgs SYSTEM has been SUPERSEDED by the International System of Units (SI), which uses the tesla (symbol T) as the unit of magnetic flux density. One gauss equals 1×10−4 tesla (100 μT), so 1 tesla = 10,000 gauss.

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I HOPE it is helpful to youparticle start motion from rest according to formula θ=(t4/60)- (t/4). Then the ANGULAR VELOCITY and angular ACCELERATION at time t=10s.

Harminder DuaExplanation:The feature is named for its discoverer, Harminder Dua, a PROFESSOR of OPHTHALMOLOGY and visual SCIENCES at the UNIVERSITY of Nottingham.Hope this ANSWER is helpful for you.Thank you.PLEASE MARK ME BRAINLIEST

Ampere's circuital law STATES that line integral of magnetic field around any closed loop is equal to μ o times the electric current FLOWING through the cross-section area enclosed by that loop.Mathematically, ∮B.dl=μILet the current flowing in the solenoid having number of turns per unit length N be I.Magnitude of magnetic field inside the solenoid is B while at outside is zero.Now ∮ loop B.dl=∫B ab .L+∫B bc .L ′ +∫B cd .L+∫B da .L ′ The value of first term ∫B ab .L=BLThe second and fourth term are zero because ANGLE between magnetic field and the length loop is 90 o .The third term is also zero as the value of magnetic field outside the solenoid is zero.Total current flowing through the loop I total =(nL)IFrom Ampere's circuital law, we get BL=μ o (nLI) ⟹ B=μ o nI

y=(X+1)(x+2) 2 DXDY =(x+1) dxd (x+2) 2 +(x+2) 2 dxd (x+1) [APPLY product Rule of differentiable][ dxd f(x)⋅g(x)= dxd f(x).q(x)+ dxd g(x)]=(x+1)⋅2(x+2)+(x+2) 2 ⋅1=(x+2)[2(x+1)+x+2]=(x+2)[2x+2+x+2]=(x+2)[3x+4]=(x+2)(3x+4).

Mass of a BODY = 1 kg. Initial velocity, u = 10 m/s.Final velocity, V = 0 m/s.Distance = 5 m. TO FIND : FORCE experienced by the object. FORMULA : SOLUTION : A body of mass 1 kg is moving with a speed of 10 m/s. So, Object travels 10 m in 1 sec. We know that, Now, The force experienced by the body is 20 N.

The SI is made up of 7 base units that DEFINE the 22 DERIVED units with special names and symbols.Explanation:Hope it helps

sun A ray A beam OPAQUE medium.fireflies or lightning bugsExplanation:and I don't UNDERSTAND the A B c d SORRY

Osmosis is the MOVEMENT of a solvent across a SEMIPERMEABLE membrane toward a higher concentration of SOLUTE (lower concentration of solvent). In biological SYSTEMS, the solvent is TYPICALLY water, but osmosis can occur in other liquids, supercritical liquids, and even gases.

it's not DEFRACTION it is REFRACTION

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50° Is The answer of This QuestionExplanation:Please MARK As BRAINLIESTI can FOLLOW You But You Before me Mark As Brainliest

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Mass of solid= 72 g volume of the solid = FINAL volume - Initial volume = 42 - 24ml. = 18 ml DENSITY of the solid = Mass / Volume =( 72/18) g/ml. = 4 g/ml

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The ANSWER of this QUESTION is B

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during neutralization reaction of ACID and base the products formed are SALT + WATER.....Explanation:hope this will help U.....

PhononExplanation:An exact amount of ENERGY ħω must be SUPPLIED to the HARMONIC oscillator lattice to push it to the NEXT energy level.

si UNIT of pressurefor pressure, the si system's basic unit is PASCAL (PA), which is n/m² (newton per square meter, while newton is kgm/s²). pascal is a very SMALL pressure unit and for example the STANDARD atmospheric pressure is 101325 pa absolute.

An electric current is the RATE of FLOW of electric charge past a POINT or region. An electric current is said to exist when there is a NET flow of electric charge through a region. Electric charge is carried by charged particles, so an electric current is a flow of charged particlesExplanation:Hope it helps

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tion:The dialyzer, or filter, has two PARTS, one for your BLOOD and one for a washing fluid called DIALYSATE. ... Smaller waste PRODUCTS in the blood, such as urea, creatinine, potassium and extra fluid pass through the membrane and are WASHED away.

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tion:please follow mehere's the answer dearThe DISTANCE covered by an object in a unit of TIME is CALLED the speed of the object. The formula for speed can be written as the total distance covered divided by the total time TAKEN. Thus, speed equals total distance covered divided by the total time taken to COVER the distance.