67486 + Interview Questions in Secondary School in Physics

1.	State formula of Biot Savart law without vectors.
Answer» Answer: CHANGE management Explanation: PLEASE MARK BRAINLIESTT dear ❣️❣️

1.

State formula of Biot Savart law without vectors.

Answer»

Answer:

CHANGE management

Explanation:

PLEASE MARK BRAINLIESTT dear ❣️❣️

Discussion

2.	24કારકરવાના તાર (Heating//// નિક્કોમના બનેલા એકElement) ને 230 V ના ઉદગમ સાથે જોડતાં પ્રારંભમાં તે3,2A પ્રવાહ ખેંચે છે કે જે અમુક સેકન્ડ બાદ 2.8 A જેટલો.સ્થાયી થાય છે. જો ઓરડાનું તાપમાન 27.0 °C જેટલું હોય !તો ગરમ કરતાં તારનું સ્થાયી તાપમાન કેટલું હશે ?'સંકળાયેલ તાપમાનનાં ગાળા માટે નિક્રોમના આવરોધનાતાપમાન ગુણાંકનું સરેરાશ મૂલ્ય 1.70 x 101 °C1 છે.
Answer» Answer: Gujarati bolo CHO TEME HI hu pan GUJRATI BOLU chu

2.

24કારકરવાના તાર (Heating//// નિક્કોમના બનેલા એકElement) ને 230 V ના ઉદગમ સાથે જોડતાં પ્રારંભમાં તે3,2A પ્રવાહ ખેંચે છે કે જે અમુક સેકન્ડ બાદ 2.8 A જેટલો.સ્થાયી થાય છે. જો ઓરડાનું તાપમાન 27.0 °C જેટલું હોય !તો ગરમ કરતાં તારનું સ્થાયી તાપમાન કેટલું હશે ?'સંકળાયેલ તાપમાનનાં ગાળા માટે નિક્રોમના આવરોધનાતાપમાન ગુણાંકનું સરેરાશ મૂલ્ય 1.70 x 101 °C1 છે.

Answer»

Answer:

Gujarati bolo CHO TEME HI hu pan GUJRATI BOLU chu

Discussion

3.	Flexible string of length 1 m & mass 1 gm is stretched by a tension t. the string is found to vibrate in three segments at a frequency of 612 hz. calculate the tension in the string.
Answer» Answer: FLEXIBLE string of length 1 m & mass 1 gm is stretched by a TENSION t. the string is found to VIBRATE in three segments at a FREQUENCY of 612 hz. calculate the tension in the string. Explanation: hope it didn't hlp

3.

Flexible string of length 1 m & mass 1 gm is stretched by a tension t. the string is found to vibrate in three segments at a frequency of 612 hz. calculate the tension in the string.

Answer»

Answer:

FLEXIBLE string of length 1 m & mass 1 gm is stretched by a TENSION t. the string is found to VIBRATE in three segments at a FREQUENCY of 612 hz. calculate the tension in the string.

Explanation:

hope it didn't hlp

Discussion

4.	Explain how oxidation corrosion rancidity applies scientific concepts in daily life.
Answer» Answer: (a) Corrosion is a natural process, which converts a refined metal to a more stable form, such as its oxide or HYDROXIDE. It is the gradual destruction of metals by chemical reaction with their environment. Rusting, the formation of iron oxides is a well-known EXAMPLE of electrochemical corrosion. (b) Rancidity REFERS to the spoilage of food in such a way that it becomes UNDESIRABLE and unsafe for CONSUMPTION. It is the hydrolysis or autoxidation of fats into short-chain aldehydes and ketones which are objectionable in taste and odour. When rancidity occurs in food, undesirable odours and flavours can result. In some cases, however, the flavours can be desirable (as in aged cheeses). Explanation:

4.

Explain how oxidation corrosion rancidity applies scientific concepts in daily life.

Answer»

Answer:

(a) Corrosion is a natural process, which converts a refined metal to a more stable form, such as its oxide or HYDROXIDE. It is the gradual destruction of metals by chemical reaction with their environment.

Rusting, the formation of iron oxides is a well-known EXAMPLE of electrochemical corrosion.

(b) Rancidity REFERS to the spoilage of food in such a way that it becomes UNDESIRABLE and unsafe for CONSUMPTION. It is the hydrolysis or autoxidation of fats into short-chain aldehydes and ketones which are objectionable in taste and odour.

When rancidity occurs in food, undesirable odours and flavours can result. In some cases, however, the flavours can be desirable (as in aged cheeses).

Explanation:

Discussion

5.	Charges q and -q are placed at some distance what is the locus of points in the plane of charges where potential is zero
Answer» Answer: setattr() is used to ASSIGN the object attribute its value. Apart from ways to assign values to class variables, through CONSTRUCTORS and object functions, this method gives you an alternative WAY to assign value. Parameters : OBJ : Object WHOSE which attribute is to be assigned.

5.

Charges q and -q are placed at some distance what is the locus of points in the plane of charges where potential is zero

Answer»

Answer:

setattr() is used to ASSIGN the object attribute its value. Apart from ways to assign values to class variables, through CONSTRUCTORS and object functions, this method gives you an alternative WAY to assign value. Parameters : OBJ : Object WHOSE which attribute is to be assigned.

Discussion

6.	Four point charges Q, 2Q,3Q and 4Q are placed at the vertices of a square of side a in order . Calculate magnitude and direction of electeic field at the point of intersection of diagonals
Answer» Answer: Enet= 4kQ/a^2√2 and direction is towards the side of charge Q and 2Q Explanation: question is asking to find the electric field at the center of the square. the formula for electric field is k q / SEPARATION ^2 here k is 9*10^9 separation = a/√2 electric field for Q = kQ/(a/√2)^2 = 2kQ/a^2 electric field for 2Q = 4kQ/a^2 electric field for 3Q = 6kQ/a^2 electric field for 4Q = 8kQ/a^2 now, charge Q and 3Q lies on the same diagonal and direction of electric field of QAND 3Q are opposite to each other so we can CANCEL electric field of Q nad 3Q that is remaining electric field = 4kQ/a^2 and direction is towards Q charge. similarly, we can cancel electric field of 4Q and 2Q so remaining charge = 4kQ/a^2 and direction is towards 2Q.... now you can see that there are two vector one is towards Q and other is towards 2Q and the angle between them is 90 DEGREE and both vector are of equal magnitude and that is 4kQ/a^2 ∴ electric field net = √ (4kQ/a^2)^2 + (4kQ/a^2)^2 = √2(4kQ/a^2)^2 = 4kQ/a^2√2 and direction is towards the side of Qand 2Q charge hope you understood it.......................

6.

Four point charges Q, 2Q,3Q and 4Q are placed at the vertices of a square of side a in order . Calculate magnitude and direction of electeic field at the point of intersection of diagonals

Answer»

Answer:

Enet= 4kQ/a^2√2 and direction is towards the side of charge Q and 2Q

Explanation: question is asking to find the electric field at the center of the square.

the formula for electric field is k q / SEPARATION ^2

here k is 9*10^9

separation = a/√2

electric field for Q = kQ/(a/√2)^2

= 2kQ/a^2

electric field for 2Q = 4kQ/a^2

electric field for 3Q = 6kQ/a^2

electric field for 4Q = 8kQ/a^2

now, charge Q and 3Q lies on the same diagonal

and direction of electric field of QAND 3Q are opposite to each other

so we can CANCEL electric field of Q nad 3Q that is remaining electric field = 4kQ/a^2 and direction is towards Q charge.

similarly, we can cancel electric field of 4Q and 2Q

so remaining charge = 4kQ/a^2 and direction is towards 2Q....

now you can see that there are two vector one is towards Q and other is towards 2Q and the angle between them is 90 DEGREE and both vector are of equal magnitude and that is 4kQ/a^2

∴ electric field net = √ (4kQ/a^2)^2 + (4kQ/a^2)^2

= √2(4kQ/a^2)^2

= 4kQ/a^2√2 and direction is towards the side of Qand 2Q charge

hope you understood it.......................

Discussion

7.	Why a glass plate appears green when seen in Green light
Answer» Answer: A SURFACE appear to be a particular color because it absorb the all other spectrum and reflect the color which we see. So a SLAB appear GREEN because it absorb all other color and reflect only green color. So when green LIGHT FALLS on glass slab it will appear green Explanation:

7.

Why a glass plate appears green when seen in Green light

Answer»

Answer:

A SURFACE appear to be a particular color because it absorb the all other spectrum and reflect the color which we see. So a SLAB appear GREEN because it absorb all other color and reflect only green color. So when green LIGHT FALLS on glass slab it will appear green

Explanation:

Discussion

8.	Define modulation and demidulaction
Answer» Answer: kyeydddkdmoux SA tu CX V rawa dc s ki yg bg ES GB tB in UH

8.

Define modulation and demidulaction

Answer»

Answer:

kyeydddkdmoux SA tu CX V rawa dc s ki yg bg ES GB tB in UH

Discussion

9.	The teacher dash profitability use computer all teaching aids tell model
Answer» ANSWER: used to produce fibre from plants LIKE jute, flax, hemp stalks, and also coil from coconut husks. The SHORT and long FIBRES obtained after retting are used widely to manufacture PAPER, ropes, and wallboards.

9.

The teacher dash profitability use computer all teaching aids tell model

Answer»

ANSWER:

used to produce fibre from plants LIKE jute, flax, hemp stalks, and also coil from coconut husks. The SHORT and long FIBRES obtained after retting are used widely to manufacture PAPER, ropes, and wallboards.

Discussion

10.	Acceleration question refer to the attachment Plz answer step by step asap urgent! ...I will mark you brainliest
Answer» Answer: EXPLANATION: HMM..... look the force of 5N will not be taken into CONSIDERATION. And now NEXT, the A=F/M A=10-6/2 A=4/2 A=2m/s²

10.

Acceleration question refer to the attachment Plz answer step by step asap urgent! ...I will mark you brainliest

Answer»

Answer:

EXPLANATION:

HMM..... look the force of 5N will not be taken into CONSIDERATION. And now NEXT,

the A=F/M

A=10-6/2

A=4/2

A=2m/s²

Discussion

11.	two particles are placed at some distance .If the mass of each of the two particles is doubled keeping the distance between them unchanged the value of gravitational force between them will be
Answer» Answer: Your Answer is..... Explanation: The FORCE of gravitational attraction between the TWO bodies of mass (M) and (m) is F=G r 2 Mm . Now, If masses of both objects are halved WITHOUT changing distance between them or M=2M and 2m Now, F=G r 2 2M×2m =4G r 2 Mm . Thus, force BECOMES four times as we increase the masses to double without altering the distances.

11.

two particles are placed at some distance .If the mass of each of the two particles is doubled keeping the distance between them unchanged the value of gravitational force between them will be

Answer»

Answer:

Your Answer is.....

Explanation:

The FORCE of gravitational attraction between the TWO bodies of mass (M) and (m) is F=G

r

2

Mm

.

Now, If masses of both objects are halved WITHOUT changing distance between them or M=2M and 2m

Now, F=G

r

2

2M×2m

=4G

r

2

Mm

.

Thus, force BECOMES four times as we increase the masses to double without altering the distances.

Discussion

12.	Describe brifely about characteristics of sound wave
Answer» Answer: SOUND wave can be described by FIVE characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength. That is it is the LENGTH of one COMPLETE wave.

12.

Describe brifely about characteristics of sound wave

Answer»

Answer:

SOUND wave can be described by FIVE characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength. That is it is the LENGTH of one COMPLETE wave.

Discussion

13.	On shaking any of the carbonated cold drink (Limca or Coke) some bubbles appears and later it disappears also Give reason of appearance and disappearance of bubbles?
Answer» The BUBBLES appear due to a GAS CALLED carbon dioxide dissolved in them. The gas and the liquid ( and everything else) are made up of tiny bit of stuff called molecules. The science SAYS that there is only a certain amount of carbon dioxide and once it is gone , the bubbles will stop. hope this helps you. Plz mark me as brainliest.

13.

On shaking any of the carbonated cold drink (Limca or Coke) some bubbles appears and later it disappears also Give reason of appearance and disappearance of bubbles?

Answer»

The BUBBLES appear due to a GAS CALLED carbon dioxide dissolved in them. The gas and the liquid ( and everything else) are made up of tiny bit of stuff called molecules.

The science SAYS that there is only a certain amount of carbon dioxide and once it is gone , the bubbles will stop.

hope this helps you.

Plz mark me as brainliest.

Discussion

14.	25. If \|A+B\| = \|Ā\| +\B], then angle between A and B willbe(a) 90°(c) 0°(b) 120(d) 60°
Answer» ANSWER: this is the answer GIVEN in the IMAGE

14.

25. If |A+B| = |Ā| +\B], then angle between A and B willbe(a) 90°(c) 0°(b) 120(d) 60°

Answer»

ANSWER:

this is the answer GIVEN in the IMAGE

Discussion

15.	A car starts from rest and acquire on velocity of 54km/hr in 2min.find acceleration.and distance travelled
Answer» ✬ Distance = 900 m ✬ ✬ Acceleration = 0.125 m/s² ✬ Explanation: Given: A car tarted from rest i.e Initial VELOCITY is 0. Final velocity of car is 54 km/hr Time taken is 2 minutes. To Find: What is the ACCELERATION and Distance covered by car ? Formula to be used: v = u + at (for acceleration) s = ut + 1/2at² ( for distance ) Solution: First CHANGE the units in m/s to make units same. ➯ 1 minutes = 60 SECONDS ➯ 2 minutes = 2(60) = 120 seconds. Multiply with 5/18 to change km/h to m/s. ➯ Final velocity = 54(5/18) ➯ v = 15 m/s. Now, put the values on formula. $\implies{\rm }$ v = u + at $\implies{\rm }$ 15 = 0 + a $\times$ 120 $\implies{\rm }$ 15 = 120a $\implies{\rm }$ 15/120 = a $\implies{\rm }$ 0.125 m/s² = a So, the acceleration of car is 0.125 m/s². __________________________ Using second formula for finding distance $\implies{\rm }$ s = ut + 1/2at² $\implies{\rm }$ s = 0 $\times$ 120 + 1/2 $\times$ 0.125 $\times$ 120² $\implies{\rm }$ s = 0.125/2 $\times$ 14400 $\implies{\rm }$ s = 0.125 $\times$ 7200 $\implies{\rm }$ s = 900 m Hence, the distance covered by car is 900 m.

15.

A car starts from rest and acquire on velocity of 54km/hr in 2min.find acceleration.and distance travelled

Answer»

✬ Distance = 900 m ✬

✬ Acceleration = 0.125 m/s² ✬

Explanation:

Given:

A car tarted from rest i.e Initial VELOCITY is 0.
Final velocity of car is 54 km/hr
Time taken is 2 minutes.

To Find:

What is the ACCELERATION and Distance covered by car ?

Formula to be used:

v = u + at (for acceleration)
s = ut + 1/2at² ( for distance )

Solution: First CHANGE the units in m/s to make units same.

➯ 1 minutes = 60 SECONDS

➯ 2 minutes = 2(60) = 120 seconds.

Multiply with 5/18 to change km/h to m/s.

➯ Final velocity = 54(5/18)

➯ v = 15 m/s.

Now, put the values on formula.

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 15 = 0 + a $\times$ 120

$\implies{\rm }$ 15 = 120a

$\implies{\rm }$ 15/120 = a

$\implies{\rm }$ 0.125 m/s² = a

So, the acceleration of car is 0.125 m/s².

__________________________

Using second formula for finding distance

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 $\times$ 120 + 1/2 $\times$ 0.125 $\times$ 120²

$\implies{\rm }$ s = 0.125/2 $\times$ 14400

$\implies{\rm }$ s = 0.125 $\times$ 7200

$\implies{\rm }$ s = 900 m

Hence, the distance covered by car is 900 m.

Discussion

16.	At maximum height velocity becomes
Answer» Answer: So at MAXIMUM height velocity becomes zero. then acceleration still acting on OBJECT and there is no balancing FORCE at maximum height which can HOLD the object at max height.

16.

At maximum height velocity becomes

Answer»

Answer:

So at MAXIMUM height velocity becomes zero. then acceleration still acting on OBJECT and there is no balancing FORCE at maximum height which can HOLD the object at max height.

Discussion

17.	Ek belnakar datu tambe ki Chad ki lambai 1cm or radius 2.0mm h cad ke sure pr120 volt vibvantr aaropit krne or cad me pirvahit data ka ma'am Kya hoga
Answer» Answer: EK belnakar datu tambe ki Chad ki LAMBAI 1cm or radius 2.0mm h cad ke sure pr120 volt vibvantr aaropit krne or cad me pirvahit DATA ka ma'am Kya HOGA

17.

Ek belnakar datu tambe ki Chad ki lambai 1cm or radius 2.0mm h cad ke sure pr120 volt vibvantr aaropit krne or cad me pirvahit data ka ma'am Kya hoga

Answer»

Answer:

EK belnakar datu tambe ki Chad ki LAMBAI 1cm or radius 2.0mm h cad ke sure pr120 volt vibvantr aaropit krne or cad me pirvahit DATA ka ma'am Kya HOGA

Discussion

18.	Two bodies of masses m and 4m are moving at equal momenta. Then ratio of their kinetic energies will be?
Answer» ANSWER: KINETIC ENERGY will be PASSED

18.

Two bodies of masses m and 4m are moving at equal momenta. Then ratio of their kinetic energies will be?

Answer»

ANSWER:

KINETIC ENERGY will be PASSED

Discussion

19.	Name the Country which follow one person, one vote, one value principle.
Answer» ANSWER: CAMBODIA............

19.

Name the Country which follow one person, one vote, one value principle.

Answer»

ANSWER:

CAMBODIA............

Discussion

20.	An object 15cm from cancave mirror of focal length 25cm what is the position of the image?If the object is 2cm high . what is the height of the image
Answer» $\large\bf\underline {To \: find:-}$ We need to find the position of the IMAGE, and the HEIGHT of the image. $\huge\bf\underline{Solution:-}$ $\bf\underline{\red{Given:-}}$ ● object distance (u) = - 15cm ● Focal length (f) = - 25cm ● size of object (h) = 2cm ━━━━━━━━━━━━━━━━━━━ ▶ By using mirror Formula :- $\: \: \: \: \large\underline{ \boxed{ \red{ \bold{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}}}$ ➳ 1/v = 1/f - 1/u ➳ 1/v = 1/(-25) -1/(-15) ➳ 1/v = - 1/25 + 1/15 ➳ 1/v = (-3 + 5)/75 ➳ 1/v = 2/75 ➳ 2V = 75 ➳ v = 75/2 ➳ v = 37.5 cm And , $\red{\bf\:Magnification = h'/h = - v/u}$ ⪼ h'/2 = -37.5/-15 ⪼ h'/2 = 375/150 ⪼ h'/2 = 25/10 ⪼ h'/2 = 5/2 ⪼ 2H' = 10 ⪼ h' = 10/2 ⪼ h' = 5cm Hence, ▶ Image distance (v) = 37.5cm ▶ Object height (h) = 5cm ━━━━━━━━━━━━━━━━━━━━━━━━━

20.

An object 15cm from cancave mirror of focal length 25cm what is the position of the image?If the object is 2cm high . what is the height of the image

Answer»

$\large\bf\underline {To \: find:-}$

We need to find the position of the IMAGE, and the HEIGHT of the image.

$\huge\bf\underline{Solution:-}$

$\bf\underline{\red{Given:-}}$

● object distance (u) = - 15cm

● Focal length (f) = - 25cm

● size of object (h) = 2cm

━━━━━━━━━━━━━━━━━━━

▶ By using mirror Formula :-

$\: \: \: \: \large\underline{ \boxed{ \red{ \bold{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}}}$

➳ 1/v = 1/f - 1/u

➳ 1/v = 1/(-25) -1/(-15)

➳ 1/v = - 1/25 + 1/15

➳ 1/v = (-3 + 5)/75

➳ 1/v = 2/75

➳ 2V = 75

➳ v = 75/2

➳ v = 37.5 cm

And ,

$\red{\bf\:Magnification = h'/h = - v/u}$

⪼ h'/2 = -37.5/-15

⪼ h'/2 = 375/150

⪼ h'/2 = 25/10

⪼ h'/2 = 5/2

⪼ 2H' = 10

⪼ h' = 10/2

⪼ h' = 5cm

Hence,

▶ Image distance (v) = 37.5cm
▶ Object height (h) = 5cm

━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

21.	A ray of orange light and blue light are incident through water in a beaker at the same time. In which light reaches the bottom of the beaker first and why?
Answer» ANSWER: ai3ii9eoeen 4 5 tm Explanation: 123456789

21.

A ray of orange light and blue light are incident through water in a beaker at the same time. In which light reaches the bottom of the beaker first and why?

Answer»

ANSWER:

ai3ii9eoeen 4 5 tm

Explanation:

123456789

Discussion

22.	How is electric potential created.
Answer» Explanation: As COMBINATION of proton and Neutron gives+ve charge.Like GRAVITATIONAL force, which attract (proton+neutron) having force which attract electrons. When+ve charge and-ve charge collected on TWO side of bettery, it creates POTENTIAL difference between two SIDES that is voltage. Mark As Brainliest

22.

How is electric potential created.

Answer»

Explanation:

As COMBINATION of proton and Neutron gives+ve charge.Like GRAVITATIONAL force, which attract (proton+neutron) having force which attract electrons. When+ve charge and-ve charge collected on TWO side of bettery, it creates POTENTIAL difference between two SIDES that is voltage.

Mark As Brainliest

Discussion

23.	The slope of a-t graph is give
Answer» EXPLANATION: a÷t=v change in VELOCITY

23.

The slope of a-t graph is give

Answer»

EXPLANATION:

a÷t=v

change in VELOCITY

Discussion

24.	Six charges each equal to +Q are placed at corners of regular hexagon of side (l) the electric potential and electric field at point p where diagonals intersect are
Answer» Explanation: The electric potential at the INTERSECTION of the DIAGONALS PP is the SUM of the electric potentials from all the POINT charges. As a regular hexagon is composed of EQUILATERAL triangles all these point charges have the distance xx from the point PP. VE(P)=14πϵ0(6Qx)=3Q2πϵ0xVE(P)=14πϵ0(6Qx)=3Q2πϵ0x.

24.

Six charges each equal to +Q are placed at corners of regular hexagon of side (l) the electric potential and electric field at point p where diagonals intersect are

Answer»

Explanation:

The electric potential at the INTERSECTION of the DIAGONALS PP is the SUM of the electric potentials from all the POINT charges. As a regular hexagon is composed of EQUILATERAL triangles all these point charges have the distance xx from the point PP.

VE(P)=14πϵ0(6Qx)=3Q2πϵ0xVE(P)=14πϵ0(6Qx)=3Q2πϵ0x.

Discussion

25.	If the uncertainty in position of an electron is 4 x 10^(-10) m, the uncertainty in its momentum
Answer» Answer: 5×10^-5 kgm/s Explanation: $according \: to \: principle \: of \: <klux>UNCERTAINTY</klux> \: \\ ∆ x ∆ p \geqslant \frac{h}{4\pim}$ where, ∆x= uncertainty in position ∆p= uncertainty in momentum h= Planck's constant m=MASS(here,mass of electron) THEREFORE, uncertainty in momentum,∆p is GIVEN by, $\alpha p = \frac{h}{ \alpha x4\pim} \\ = \frac{6.626 \times {10}^{ - 34} }{4 \times 3.14 \times 9.1 \times {10}^{ - 31} } \\ = 5 \times {10}^{ - 5}$

25.

If the uncertainty in position of an electron is 4 x 10^(-10) m, the uncertainty in its momentum

Answer»

Answer:

5×10^-5 kgm/s

Explanation:

$according \: to \: principle \: of \: <klux>UNCERTAINTY</klux> \: \\ ∆ x ∆ p \geqslant \frac{h}{4\pim}$

where,

∆x= uncertainty in position
∆p= uncertainty in momentum
h= Planck's constant
m=MASS(here,mass of electron)

THEREFORE,

uncertainty in momentum,∆p is GIVEN by,

$\alpha p = \frac{h}{ \alpha x4\pim} \\ = \frac{6.626 \times {10}^{ - 34} }{4 \times 3.14 \times 9.1 \times {10}^{ - 31} } \\ = 5 \times {10}^{ - 5}$

Discussion

26.	Guys logo ko thoughts bole toh dimaak kharab hota hai
Answer» $\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \$ YAA ABSOLUTELY RIGHT

26.

Guys logo ko thoughts bole toh dimaak kharab hota hai

Answer»

$\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \$

YAA ABSOLUTELY RIGHT

Discussion

27.	The following readings were obtained when measuring the density of a stone. Mass of stone=25g,volume of water =25cm and volume of water and stone=35cm. What is density of the stone?
Answer» Answer: 2.5 g/CM Explanation: as density=mass/volume volume of STONE is 10 cm as 35-25=10

27.

The following readings were obtained when measuring the density of a stone. Mass of stone=25g,volume of water =25cm and volume of water and stone=35cm. What is density of the stone?

Answer»

Answer:

2.5 g/CM

Explanation:

as density=mass/volume

volume of STONE is 10 cm

as 35-25=10

Discussion

28.	How to caculate magnitude of a vector
Answer» Explanation: The magnitude of a VECTOR →PQ is the distance between the initial point P and the END point Q . In symbols the magnitude of →PQ is written as \| →PQ \| . If the COORDINATES of the initial point and the end point of a vector is given, the Distance Formula can be used to FIND its magnitude. *hope* *that* it *was* *HELPFUL* *for* *you*

28.

How to caculate magnitude of a vector

Answer»

Explanation:

The magnitude of a VECTOR →PQ is the distance between the initial point P and the END point Q . In symbols the magnitude of →PQ is written as | →PQ | . If the COORDINATES of the initial point and the end point of a vector is given, the Distance Formula can be used to FIND its magnitude.

hope that it was HELPFUL for you

Discussion

29.	Define refractive index using speed of light...
Answer» Answer: The refractive index of a substance is a MEASURE of the amount of bending after a BOUNDARY. It is calculated using this equation: refractive index = speed of LIGHT in a VACUUM/speed of light in the medium. The speed of light in a vacuum is 300 000 000 m/s (3 × 108 m/s). Hope it will be helpful ✌️

29.

Define refractive index using speed of light...

Answer»

Answer:

The refractive index of a substance is a MEASURE of the amount of bending after a BOUNDARY.

It is calculated using this equation: refractive index = speed of LIGHT in a VACUUM/speed of light in the medium.

The speed of light in a vacuum is 300 000 000 m/s (3 × 108 m/s).

Hope it will be helpful ✌️

Discussion

30.	a metall ball is heated to 100c and dropped into large block of ice af 0c .. if 10g of ice melts ,thermal capacity of the ball in cal C
Answer» EXPLANATION: the ANSWER is 16.67 is the answer

30.

a metall ball is heated to 100c and dropped into large block of ice af 0c .. if 10g of ice melts ,thermal capacity of the ball in cal C

Answer»

EXPLANATION:

the ANSWER is 16.67 is the answer

Discussion

31.	What is monochromatic and dichromatic light ?
Answer» The light CONSISTS a single wavelength is called monochromatic light and the light consists a broad range of wavelengths is called POLYCHROMATIC light. As for example the white light is polychromatic because it's COMBINATION of DIFFERENT wavelengths, blue or red or any coloured lights are monochromatic.

Discussion

32.	. A body of mass 10 kg and velocity 10 m/s collides with a stationary body of mass 5 kg. After collision, both bodies stick to each other. The common velocity would be
Answer» Answer: 20/3 add me BRAINLEAST

32.

. A body of mass 10 kg and velocity 10 m/s collides with a stationary body of mass 5 kg. After collision, both bodies stick to each other. The common velocity would be

Answer»

Answer:

20/3

add me BRAINLEAST

Discussion

33.	Advantages and disadvantages of artificial methods of vegetative propagation
Answer» Answer: Advantages of vegetative propagation Quicker and more certain. Produces IDENTICAL quality as the parent. Plants that do not have viable seed, can be reproduced. Flowers produced are of superior quality. Desirable CHARACTER of fruit can be maintained. Disadvantages of vegetative reproduction Does not produce new variety. Leads to overcrowding AROUND the parent plant. Very little possibility of dispersal. Explanation:

33.

Advantages and disadvantages of artificial methods of vegetative propagation

Answer»

Answer:

Advantages of vegetative propagation

Quicker and more certain.

Produces IDENTICAL quality as the parent.

Plants that do not have viable seed, can be reproduced.

Flowers produced are of superior quality.

Desirable CHARACTER of fruit can be maintained.

Disadvantages of vegetative reproduction

Does not produce new variety.

Leads to overcrowding AROUND the parent plant.

Very little possibility of dispersal.

Explanation:

Discussion

34.	How is light year related to its SI unit?
Answer» ANSWER: the SI UNIT what is Explanation: DIFFICULT difficult

34.

How is light year related to its SI unit?

Answer»

ANSWER:

the SI UNIT what is

Explanation:

DIFFICULT difficult

Discussion

35.	If two forces each of magnitude f are acting at 90 degree with eachother ten magnitude of their
Answer» ANSWER: I can't UNDERSTAND your QUESTION

35.

If two forces each of magnitude f are acting at 90 degree with eachother ten magnitude of their

Answer»

ANSWER:

I can't UNDERSTAND your QUESTION

Discussion

36.	Kisi motor pump ki Samarth 2 kilowatt Hai is pump dwara 10 metre unchai par sthit Tanki Mein Prati minut Kitna Jal chadhaya Ja sakta hai
Answer» Kisi motor PUMP ki SAMARTH 2 kilowatt Hai is pump dwara 10 METRE unchai par sthit Tanki Mein Prati minut Kitna Jal chadhaya Ja sakta hai

Discussion

37.	A positively charged Alpha particle is projected towards west is deflected towards not by a magnetic field the direction of the magnetic field is(a) towards south (b)toward East (c)downward (d)uupwardexplain...,....................
Answer» by applying FLEMING's LEFT HAND rule , the answer WOULD be option b)towards east.

Discussion

38.	the ratio of forces between two small conducting sphere charged to constant potentials in (a) air (b) medium of k=2 is
Answer» EXPLANATION: f=9×10^9×q1q2÷r^2 f=(1÷4π×££r)×q1q2÷r2

38.

the ratio of forces between two small conducting sphere charged to constant potentials in (a) air (b) medium of k=2 is

Answer»

EXPLANATION:

f=9×10^9×q1q2÷r^2

f=(1÷4π×££r)×q1q2÷r2

Discussion

39.	We use tungsten wire in the filaments of bulbs because
Answer» Answer: TUNGSTEN is used for making the filaments of electric bulbs because it has a very high melting point. Due to its very high melting point, the tungsten FILAMENT can be kept white hot WITHOUT melting away. Also, tungsten has high flexibility and LOW rate of evaporation at high temperature.

39.

We use tungsten wire in the filaments of bulbs because

Answer»

Answer:

TUNGSTEN is used for making the filaments of electric bulbs because it has a very high melting point. Due to its very high melting point, the tungsten FILAMENT can be kept white hot WITHOUT melting away. Also, tungsten has high flexibility and LOW rate of evaporation at high temperature.

Discussion

40.	The potential difference between A and B is:
Answer» SOLUTION in photo. aur questions ke liye FOLLOW KRO aur messages SEND kro

40.

The potential difference between A and B is:

Answer»

SOLUTION in photo.

aur questions ke liye FOLLOW KRO aur messages SEND kro

Discussion

41.	Numericals:1. The wavelength of light of a particular colours5800 Å. Express it in (a) nanometre and (b) metre.nice ans will be brainiest
Answer» Answer: 1Angstrom=10^-10m *1nm=10^-9m* 5800A°=5800×10^-10m =580×10^-9m=580nm =58×10^-8m Explanation: *Hop*e it HELPS you FRND...

41.

Numericals:1. The wavelength of light of a particular colours5800 Å. Express it in (a) nanometre and (b) metre.nice ans will be brainiest

Answer»

Answer:

1Angstrom=10^-10m

1nm=10^-9m

5800A°=5800×10^-10m

=580×10^-9m=580nm

=58×10^-8m

Explanation:

Hope it HELPS you FRND...

Discussion

42.	Here's Uh Question'' Stressed out '' song is composed by?____No spam❎
Answer» Tyler Joseph "STRESSED Out" was WRITTEN by Joseph from the perspective of the character Blurryface rather than some IMPERSONAL third-person narrator. His LYRICISM is FILLED with couplets and one-line rhyme schemes pertaining to definitive generational concerns. Tyler Joseph was in his mid-20s at time of the single's release.

42.

Here's Uh Question'' Stressed out '' song is composed by?____No spam❎

Answer»

Tyler Joseph

"STRESSED Out" was WRITTEN by Joseph from the perspective of the character Blurryface rather than some IMPERSONAL third-person narrator. His LYRICISM is FILLED with couplets and one-line rhyme schemes pertaining to definitive generational concerns. Tyler Joseph was in his mid-20s at time of the single's release.

Discussion

43.	Ncert class 9. chapter 8 - motion. 3) A train starting from a railway and moving with uniform acceleration attains a speed 40 km/h in 10 mins. Find its acceleration. the ans is 0.0185. ...and I used the formula [a= v-u/t] and my result is 0.185...i am not getting the zero...pls help me..if anybody can .
Answer» Given : ➳ Initial velocity = zero ➳ FINAL velocity = 40kmph ➳ Time interval = 10min To Find : ➨ Acceleration of train. Concept : ➢ Acceleration is DEFINED as the rate of change in velocity. ➢ It is a vector quantity having both magnitude as well as direction. ➢ It can be positive, negative or zero. ➢ SI unit : m/s² ✴ FIRST equation of kinematics : $\bigstar\:\underline{\boxed{\tt{v=u+at}}}$ Conversion : ➠ 1kmph = 5/18mps ➠ 40kmph = 40 × 5/18 = 11.11mps ➠ 10min = 10 × 60 = 600s Calculation : $\longrightarrow\tt\:v=u+at\\ \\ \longrightarrow\bf\:a=\dfrac{v-u}{t}\\ \\ \longrightarrow\tt\:a=\dfrac{11.11-0}{600}\\ \\ \longrightarrow\underline{\boxed{\tt{a=0.0185\:ms^{-2}}}}$

43.

Ncert class 9. chapter 8 - motion. 3) A train starting from a railway and moving with uniform acceleration attains a speed 40 km/h in 10 mins. Find its acceleration. the ans is 0.0185. ...and I used the formula [a= v-u/t] and my result is 0.185...i am not getting the zero...pls help me..if anybody can .

Answer»

Given :

➳ Initial velocity = zero

➳ FINAL velocity = 40kmph

➳ Time interval = 10min

To Find :

➨ Acceleration of train.

Concept :

➢ Acceleration is DEFINED as the rate of change in velocity.

➢ It is a vector quantity having both magnitude as well as direction.

➢ It can be positive, negative or zero.

➢ SI unit : m/s²

✴ FIRST equation of kinematics :

$\bigstar\:\underline{\boxed{\tt{v=u+at}}}$

Conversion :

➠ 1kmph = 5/18mps

➠ 40kmph = 40 × 5/18 = 11.11mps

➠ 10min = 10 × 60 = 600s

Calculation :

$\longrightarrow\tt\:v=u+at\\ \\ \longrightarrow\bf\:a=\dfrac{v-u}{t}\\ \\ \longrightarrow\tt\:a=\dfrac{11.11-0}{600}\\ \\ \longrightarrow\underline{\boxed{\tt{a=0.0185\:ms^{-2}}}}$

Discussion

44.	a ball is kicked at an angle of 30 with the vertical. if the horizontal component of velocity is 19.6 m/s.find the maximum height and vertical range
Answer» ANSWER: MAXIMUM HEIGHT= 5m Maximum RANGE= 20√3

44.

a ball is kicked at an angle of 30 with the vertical. if the horizontal component of velocity is 19.6 m/s.find the maximum height and vertical range

Answer»

ANSWER:

MAXIMUM HEIGHT= 5m

Maximum RANGE= 20√3

Discussion

45.	Why are there only seven colors in white light?
Answer» ANSWER: You must have seen when light passes through a prism it disperse and the PHENOMENON is called dispersion and we see the spectrum of seven Colors but it has got all the RADIATION but our eyes can see only those frequencies and hence only 7 colors.

45.

Why are there only seven colors in white light?

Answer»

ANSWER:

You must have seen when light passes through a prism it disperse and the PHENOMENON is called dispersion and we see the spectrum of seven Colors but it has got all the RADIATION but our eyes can see only those frequencies and hence only 7 colors.

Discussion

46.	How many electrons per second pass through a section of wire carrying a charge of 0.7a
Answer» Answer: when a current of 1 ampere is FLOWING through a CONDUCTOR it MEANS 6.25 into 10 to the power 18 electrons pass per second across the cross-section of the conductor... then, in 0.7A=6.2510^18/0.7 electrons... I hope* it *will* *BENEFIT* *you* *buddy* *please* *follow* me or *like* my *answer* at *least* ....

46.

How many electrons per second pass through a section of wire carrying a charge of 0.7a

Answer»

Answer:

when a current of 1 ampere is FLOWING through a CONDUCTOR it MEANS 6.25 into 10 to the power 18 electrons pass per second across the cross-section of the conductor...

then, in 0.7A=6.25*10^18/0.7 electrons...

I hope it will BENEFIT you buddy please follow me or like my answer at least ....

Discussion

47.	If the radius of circle is doubled, then centripetal force becomes
Answer» ANSWER: Become 1/2 of the ORIGINAL value. Explanation: As we know that F is RELATED inversely with the r. So if r increase and become double them F become 1/2.

47.

If the radius of circle is doubled, then centripetal force becomes

Answer»

ANSWER:

Become 1/2 of the ORIGINAL value.

Explanation:

As we know that F is RELATED inversely with the r.

So if r increase and become double them F become 1/2.

Discussion

48.	एक्क आरोग व्यक्ति पति मिनट पिक्चर कि नहीं सा लेना है
Answer» Answer: If image of POINT A(2,3) in y-asis be B and the image of B in x-acis be C and image of C in y-axis be D then area of quadrilateral ABCD is. (A) 4 (B)6 (C) 24 (D) 18Vinu GAVE a loan of Rs. 200 to Harish and recovered it at the rate of Rs. 14 per month for twenty months. The rate of simple interest charged is: A) 26% B)24% C)16% D)12%

48.

एक्क आरोग व्यक्ति पति मिनट पिक्चर कि नहीं सा लेना है

Answer»

Answer:

If image of POINT A(2,3) in y-asis be B and the image of B in x-acis be C and image of C in

y-axis be D then area of quadrilateral ABCD is.

(A) 4

(B)6

(C) 24

(D) 18Vinu GAVE a loan of Rs. 200 to Harish and recovered it at the rate of Rs. 14 per month for

twenty months. The rate of simple interest charged is:

A) 26%

B)24%

C)16%

D)12%

Discussion

49.	To identify the charge we use
Answer» ANSWER to DETERMINE the charge on an object, determine the no. of excess protons on excess electrons. multiple the excess by charge of an electron or the charge of a PROTON -1.6×10¹⁹C. finally, ADJUST the sign of the object to + or -7. HOPE IT HELPS YOU

49.

To identify the charge we use

Answer»

ANSWER

to DETERMINE the charge on an object, determine the no. of excess protons on excess electrons. multiple the excess by charge of an electron or the charge of a PROTON -1.6×10¹⁹C. finally, ADJUST the sign of the object to + or -7.

HOPE IT HELPS YOU

Discussion

50.	Which one of these is true about motion?
Answer» ANSWER: where are the OPTIONS BRO....

50.

Which one of these is true about motion?

Answer»

ANSWER:

where are the OPTIONS BRO....

Discussion

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