67486 + Interview Questions in Secondary School in Physics

1.	find the velocity of projection of missile which has a horizontal range of 150m,if the time of flight for that range is 3sec
Answer» Topic :- Motion in plane $\maltese \: \underline{\textbf{\textsf{AnsWer}}}\:\maltese$ Time of flight (T) = 3 sec Horizontal RANGE (R) = 150 m Velocity (u) = ? It's given that, the time of flight for that range is 3 sec : $\longrightarrow\:\:\sf Time \: of \: flight = 3 \: sec \\$ $\qquad\footnotesize\bullet\:\sf Time \: of \: flight = \dfrac{2u_{y}}{g} = \dfrac{2u \sin(\theta)}{g} \\$ $\longrightarrow\:\:\sf \dfrac{2u \sin( \theta) }{g} = 3 \: sec \\$ TAKING Acceleration due gravity (g) as 10 m/s² we have : $\longrightarrow\:\:\sf \dfrac{2u \sin( \theta) }{10} = 3 \: sec \\$ $\longrightarrow\:\:\sf \dfrac{u \sin( \theta) }{5} = 3 \\$ $\longrightarrow\:\:\sf u \sin( \theta) = 3 \times 5 \\$ $\longrightarrow\:\:\sf u \sin( \theta) = 15 \qquad \:....(e {q}^{n} \: i)\\$ Now, we're also given that, horizontal range is 150M : $\dashrightarrow\:\:\sf Horizontal \: Range = 150 \: m \\$ $\qquad\footnotesize\bullet\:\sf Horizontal \: Range = \dfrac{u^2 \sin2(\theta)}{g} \\$ $\dashrightarrow\:\:\sf \dfrac{u^2 \sin2(\theta)}{g} = 150 \\$ $\qquad\footnotesize\bullet\:\sf \sin2(\theta) =2 \sin( \theta) . \cos( \theta) \\$ $\dashrightarrow\:\:\sf\dfrac{u^22 \sin( \theta).\cos( \theta)}{g} = 150 \\$ $\qquad\footnotesize\bullet\:\sf u^22 \sin( \theta).\cos( \theta) =2u \sin( \theta).u \cos( \theta) \\$ $\dashrightarrow\:\:\sf\dfrac{2u \sin( \theta). u\cos( \theta)}{g} = 150 \\$ $\dashrightarrow\:\:\sf\dfrac{2u \sin( \theta).u \cos( \theta)}{10} = 150 \\$ $\dashrightarrow\:\:\sf\dfrac{u \sin( \theta).u \cos( \theta)}{5} = 150 \\$ $\dashrightarrow\:\:\sf u \sin( \theta). u\cos( \theta)= 150 \times 5 \\$ $\dashrightarrow\:\:\sf u\sin( \theta). u\cos( \theta)= 750 \\$ $\qquad\footnotesize\bullet\:\sf Replacing \: u \sin( \theta) = 15 \: from \: equation \: (i) \: we \: have: \\$ $\dashrightarrow\:\:\sf 15. u\cos( \theta)= 750 \\$ $\dashrightarrow\:\:\sf u\cos( \theta)= \dfrac{750}{15} \\$ $\dashrightarrow\:\:\sf u\cos( \theta)= 50 \\$ Now, LET's find the angle of projection first : $:\implies \sf \dfrac{u\sin(\theta)}{u \cos (\theta)} = \dfrac{15}{50} \\$ $:\implies \sf \dfrac{\sin(\theta)}{ \cos (\theta)} = \dfrac{15}{50} \\$ $:\implies \sf \tan \theta = \dfrac{15}{50} \\$ $:\implies \sf \theta = \tan^{ - 1} \bigg(\dfrac{15}{50} \bigg) \\$ $:\implies \sf \theta = \tan^{ - 1} \bigg(0.3\bigg) \\$ $:\implies \sf \theta = 16.6 {9}^{ \circ} \\$ Now, put the value of θ = 16.69° in the eqⁿ (i) :- $\longrightarrow\:\:\sf u \sin( \theta) = 15 \\$ $\longrightarrow\:\:\sf u \sin( 16.6 {9}^{ \circ} ) = 15 \\$ $\qquad\footnotesize\bullet\:\sf \sin(16.69^{ \circ}) \approx 0.30\\$ $\longrightarrow\:\:\sf u \times 0.30 = 15 \\$ $\longrightarrow\:\:\sf u=\dfrac{15}{0.30} \\$ $\longrightarrow\:\:\sf u=\dfrac{15 \times 10}{0.30 \times 10} \\$ $\longrightarrow\:\:\sf u=\dfrac{150}{3} \\$ $\longrightarrow\:\:\sf u=\dfrac{150}{3} \\$ $\longrightarrow\:\: \underline{ \boxed{\sf u=50 {ms}^{ - 1} }} \\$

1.

find the velocity of projection of missile which has a horizontal range of 150m,if the time of flight for that range is 3sec

Answer»

Topic :- Motion in plane

$\maltese \: \underline{\textbf{\textsf{AnsWer}}}\:\maltese$

Time of flight (T) = 3 sec
Horizontal RANGE (R) = 150 m
Velocity (u) = ?

It's given that, the time of flight for that range is 3

sec :

$\longrightarrow\:\:\sf Time \: of \: flight = 3 \: sec \\$

$\qquad\footnotesize\bullet\:\sf Time \: of \: flight = \dfrac{2u_{y}}{g} = \dfrac{2u \sin(\theta)}{g} \\$

$\longrightarrow\:\:\sf \dfrac{2u \sin( \theta) }{g} = 3 \: sec \\$

TAKING Acceleration due gravity (g) as 10 m/s² we have :

$\longrightarrow\:\:\sf \dfrac{2u \sin( \theta) }{10} = 3 \: sec \\$

$\longrightarrow\:\:\sf \dfrac{u \sin( \theta) }{5} = 3 \\$

$\longrightarrow\:\:\sf u \sin( \theta) = 3 \times 5 \\$

$\longrightarrow\:\:\sf u \sin( \theta) = 15 \qquad \:....(e {q}^{n} \: i)\\$

Now, we're also given that, horizontal range is 150M :

$\dashrightarrow\:\:\sf Horizontal \: Range = 150 \: m \\$

$\qquad\footnotesize\bullet\:\sf Horizontal \: Range = \dfrac{u^2 \sin2(\theta)}{g} \\$

$\dashrightarrow\:\:\sf \dfrac{u^2 \sin2(\theta)}{g} = 150 \\$

$\qquad\footnotesize\bullet\:\sf \sin2(\theta) =2 \sin( \theta) . \cos( \theta) \\$

$\dashrightarrow\:\:\sf\dfrac{u^22 \sin( \theta).\cos( \theta)}{g} = 150 \\$

$\qquad\footnotesize\bullet\:\sf u^22 \sin( \theta).\cos( \theta) =2u \sin( \theta).u \cos( \theta) \\$

$\dashrightarrow\:\:\sf\dfrac{2u \sin( \theta). u\cos( \theta)}{g} = 150 \\$

$\dashrightarrow\:\:\sf\dfrac{2u \sin( \theta).u \cos( \theta)}{10} = 150 \\$

$\dashrightarrow\:\:\sf\dfrac{u \sin( \theta).u \cos( \theta)}{5} = 150 \\$

$\dashrightarrow\:\:\sf u \sin( \theta). u\cos( \theta)= 150 \times 5 \\$

$\dashrightarrow\:\:\sf u\sin( \theta). u\cos( \theta)= 750 \\$

$\qquad\footnotesize\bullet\:\sf Replacing \: u \sin( \theta) = 15 \: from \: equation \: (i) \: we \: have: \\$

$\dashrightarrow\:\:\sf 15. u\cos( \theta)= 750 \\$

$\dashrightarrow\:\:\sf u\cos( \theta)= \dfrac{750}{15} \\$

$\dashrightarrow\:\:\sf u\cos( \theta)= 50 \\$

Now, LET's find the angle of projection first :

$:\implies \sf \dfrac{u\sin(\theta)}{u \cos (\theta)} = \dfrac{15}{50} \\$

$:\implies \sf \dfrac{\sin(\theta)}{ \cos (\theta)} = \dfrac{15}{50} \\$

$:\implies \sf \tan \theta = \dfrac{15}{50} \\$

$:\implies \sf \theta = \tan^{ - 1} \bigg(\dfrac{15}{50} \bigg) \\$

$:\implies \sf \theta = \tan^{ - 1} \bigg(0.3\bigg) \\$

$:\implies \sf \theta = 16.6 {9}^{ \circ} \\$

Now, put the value of θ = 16.69° in the eqⁿ (i) :-

$\longrightarrow\:\:\sf u \sin( \theta) = 15 \\$

$\longrightarrow\:\:\sf u \sin( 16.6 {9}^{ \circ} ) = 15 \\$

$\qquad\footnotesize\bullet\:\sf \sin(16.69^{ \circ}) \approx 0.30\\$

$\longrightarrow\:\:\sf u \times 0.30 = 15 \\$

$\longrightarrow\:\:\sf u=\dfrac{15}{0.30} \\$

$\longrightarrow\:\:\sf u=\dfrac{15 \times 10}{0.30 \times 10} \\$

$\longrightarrow\:\:\sf u=\dfrac{150}{3} \\$

$\longrightarrow\:\: \underline{ \boxed{\sf u=50 {ms}^{ - 1} }} \\$

Discussion

2.	A current of 1A is drawn from wire in 16sec. How many electrons flowing through it
Answer» Answer: 18 ELECTRONS are FLOWING through it

2.

A current of 1A is drawn from wire in 16sec. How many electrons flowing through it

Answer»

Answer:

18 ELECTRONS are FLOWING through it

Discussion

3.	.When electrons move through a magnetic field, then change occurs in speed,mass or direction?
Answer» ANSWER: DIRECTION changes EXPLANATION: if it DOESNOT have CROSSSECTION area

3.

.When electrons move through a magnetic field, then change occurs in speed,mass or direction?

Answer»

ANSWER:

DIRECTION changes

EXPLANATION:

if it DOESNOT have CROSSSECTION area

Discussion

4.	A force is needed to keep a block of wood inside water.why
Answer» Magnitude of the buoyance force acting on the body inside the water is greayer than the WEIGHT of the body. HENCE, a force is neede to KEEP a BLOCK of wood inside water to overcome the net upward force acting on the cork

Discussion

5.	Product of mass and velocity of an object is called
Answer» Explanation: ANSWER is product of mass and VELOCITY of an OBJECT is called momentum. plz thanks me.

5.

Product of mass and velocity of an object is called

Answer»

Explanation:

ANSWER is

product of mass and VELOCITY of an OBJECT is called momentum.

plz thanks me.

Discussion

6.	Why can't we kick football sideways and it always goes straight ??????
Answer» Answer: no it's wrong Explanation: the point of FORCE depends upon that it will GO straight or it will bend it's direction if the FOOTBALL is kicked around the middle then it will go straight. but if you will kick it from CIRCUMFERENCE the it will TURN

6.

Why can't we kick football sideways and it always goes straight ??????

Answer»

Answer:

no it's wrong

Explanation:

the point of FORCE depends upon that it will GO straight or it will bend it's direction

if the FOOTBALL is kicked around the middle then it will go straight.

but if you will kick it from CIRCUMFERENCE the it will TURN

Discussion

7.	A progressive wave s represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metreand t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.
Answer» Answer: frequrncy Explanation: progressive wave s represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metre and t is in second. Calculate (a) AMPLITUDE (B) Wavelength (c) Frequency (d) Velocity of the wave.find the estimate of 555-333everything______(be) DISTURBED before the PLAY _______(COME) to an end

7.

A progressive wave s represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metreand t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.

Answer»

Answer:

frequrncy

Explanation:

progressive wave s represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metre

and t is in second.

Calculate (a) AMPLITUDE (B) Wavelength (c) Frequency (d) Velocity of the wave.find the estimate of 555-333everything______(be) DISTURBED before the PLAY _______(COME) to an end

Discussion

8.	Answer the above question
Answer» SORRY I won't be able to help u because I havent STUDIED this CHAPTER yet.

Discussion

9.	An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image
Answer» Explanation: Given that u= -15 cm f= 6 cm We NEED to find v We know the formula 1/f = 1/v + 1/u Therefore, 1/v= 1/f – 1/u Substituting the known values in the above EQUATION we get, 1/v= 1/6 + 1/15 1/v = (5+2)/30 (cm) Hence v=30/7 = 4.28cm v= 4.28cm Nature of the image: The image is formed behind the mirror and it is virtual and ERECT.

9.

An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image

Answer»

Explanation:

Given that

u= -15 cm

f= 6 cm

We NEED to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above EQUATION we get,

1/v= 1/6 + 1/15

1/v = (5+2)/30 (cm)

Hence v=30/7 = 4.28cm

v= 4.28cm

Nature of the image: The image is formed behind the mirror and it is virtual and ERECT.

Discussion

10.	Heya !!Refer the attachment Define physics ?
Answer» physics is SOMETHING which FIRST make U cry, then angry then MAD and then you start to question your existence.

Discussion

11.	A progressive wave is represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metre and t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.
Answer» Answer: sorry I don't KNOW everything______(be) disturbed before the PLAY _______(come) to an endfind the ESTIMATE of 555-333theeverything______(be) disturbed before the play _______(come) to an endeverything______(be) disturbed before the play _______(come) to an endfind the estimate of 555-333

11.

A progressive wave is represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metre and t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.

Answer»

Answer:

sorry I don't KNOW everything______(be) disturbed before the PLAY _______(come) to an endfind the ESTIMATE of 555-333theeverything______(be) disturbed before the play _______(come) to an endeverything______(be) disturbed before the play _______(come) to an endfind the estimate of 555-333

Discussion

12.	Application of thermoelectric diagram
Answer» ANSWER: A diagram indicating the CHANGE in potential difference for a fixed difference of temperature between different metals at different temperatures. It is laid out with rectangular co-ordinates. On ONE axis temperatures are laid off, generally on the axis of abscissas. On the other axis potential differences are marked

12.

Application of thermoelectric diagram

Answer»

ANSWER:

A diagram indicating the CHANGE in potential difference for a fixed difference of temperature between different metals at different temperatures. It is laid out with rectangular co-ordinates. On ONE axis temperatures are laid off, generally on the axis of abscissas. On the other axis potential differences are marked

Discussion

13.	a car traveling at speed of 5 m/s accelerate of 4 m/s find the speed of car after 5 sec and also calculate the distance covered
Answer» Answer: 162 m Explanation: here acceleration is there so speed = 5 + 4 = 9 m/s time = 5 sec we KNOW, distance = speed x time d = 9 x 18/5 x 5 d = 162 m

13.

a car traveling at speed of 5 m/s accelerate of 4 m/s find the speed of car after 5 sec and also calculate the distance covered

Answer»

Answer:

162 m

Explanation:

here acceleration is there

so speed = 5 + 4 = 9 m/s

time = 5 sec

we KNOW,

distance = speed x time

d = 9 x 18/5 x 5

d = 162 m

Discussion

14.	Writeabout differentsystem of units?
Answer» Explanation: SI unit or MKS unit(metre, kilo, sec) CGS unit(centimeters,gram,sec) FPS unit(foot,POUND ,sec) Please mark me BRAINLIEST and follow

14.

Writeabout differentsystem of units?

Answer»

Explanation:

SI unit or MKS unit(metre, kilo, sec)

CGS unit(centimeters,gram,sec)

FPS unit(foot,POUND ,sec)

Please mark me BRAINLIEST and follow

Discussion

15.	How friction charge a body?
Answer» Answer: When INSULATING MATERIALS rub against each other, they may become ELECTRICALLY charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged. Explanation: hope this HELPS uh mark me as brainlist

15.

How friction charge a body?

Answer»

Answer:

When INSULATING MATERIALS rub against each other, they may become ELECTRICALLY charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged.

Explanation:

hope this HELPS uh

mark me as brainlist

Discussion

16.	Ons.3)Due to heat pressure is
Answer» ANSWER: METAMORPHISM is your answer. PLEASE MARK the BRAINLIST

16.

Ons.3)Due to heat pressure is

Answer»

ANSWER:

METAMORPHISM is your answer.

PLEASE MARK the BRAINLIST

Discussion

17.	The effective resistance between 'A' and 'B' is :(a) (b)(c)(d)
Answer» ANSWER: A OPTION is 9900000 is your answer BRO

17.

The effective resistance between 'A' and 'B' is :(a) (b)(c)(d)

Answer»

ANSWER:

A OPTION is 9900000 is your answer BRO

Discussion

18.	A body dropped gently from a height h takes time t to reach the ground. Velocity of this body at theheight h/2 is:A) gtB) gt/2C) gt/√2D) gt/4E) gt^2/2
Answer» $\textbf{ Answer }$ a) GT $\\$ Solution :- In solving a numerical physics, please dont be CRAZY in FINDING the answers only, The more you FEEL ,the more you know Physics. $\text{ Here,. }$ As the ball is dropped gently the it must have (u=0), According to the equation of motion, ${ u^{2} - v^{2}}$ at height H/2 , distance travelled=H/2,so v² = 2gH/2=gH V=√(gH ) and DIRECTION of velocity is in the direction of acceleration due to gravity. $\tiny\sf \purple{ Hope \: it \: helps }$

18.

A body dropped gently from a height h takes time t to reach the ground. Velocity of this body at theheight h/2 is:A) gtB) gt/2C) gt/√2D) gt/4E) gt^2/2

Answer»

$\textbf{ Answer }$

a) GT

$\\$

Solution :-

In solving a numerical physics, please dont be CRAZY in FINDING the answers only, The more you FEEL ,the more you know Physics.

$\text{ Here,. }$

As the ball is dropped gently the it must have (u=0),

According to the equation of motion,

${ u^{2} - v^{2}}$

at height H/2 , distance travelled=H/2,so

v² = 2gH/2=gH

V=√(gH )

and DIRECTION of velocity is in the direction of acceleration due to gravity.

$\tiny\sf \purple{ Hope \: it \: helps }$

Discussion

19.	16) Read the following question andselect correct optionWhat are the dimensions of the quantity 1 V1/g where l-isthe length and g -is the acceleration due to gravityA) [L'T'B)[ZC)\|L'7-')D)M'T')
Answer» ANSWER: (D) M'T'This is CORRECT answer

19.

16) Read the following question andselect correct optionWhat are the dimensions of the quantity 1 V1/g where l-isthe length and g -is the acceleration due to gravityA) [L'T'B)[ZC)|L'7-')D)M'T')

Answer»

ANSWER:

(D) M'T'This is CORRECT answer

Discussion

20.	What is the effect on surrounding metal placed in a magnetic field?
Answer» Answer: MAGNETIC Field, Magnetic Field, 1) When two magnets are brought near each other, like poles repel; opposite poles attract. 2) When a MAGNET is brought near a piece of IRON, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.

20.

What is the effect on surrounding metal placed in a magnetic field?

Answer»

Answer:

MAGNETIC Field, Magnetic Field, 1) When two magnets are brought near each other, like poles repel; opposite poles attract. 2) When a MAGNET is brought near a piece of IRON, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.

Discussion

21.	. A carnot engine takes 2000 J of heat / cycle from the source and rejects 1500 J of heat / cycleto sink. If temperature of source is 600 K, what is the temperature of sink. Calculate efficiency of engine.
Answer» Explanation: EFFICIENCY is the performance of the engine.. the fraction of energy can be UTILIZED by the engine is efficiency.. In this case inlet energy is 2000j and the engine rejects 1500 J .. So total energy used by the energy is 500 j .. So Efficiency = (500/2000) = 0.25 In PERCENTAGE it is 25%..

21.

. A carnot engine takes 2000 J of heat / cycle from the source and rejects 1500 J of heat / cycleto sink. If temperature of source is 600 K, what is the temperature of sink. Calculate efficiency of engine.

Answer»

Explanation:

EFFICIENCY is the performance of the engine..

the fraction of energy can be UTILIZED by the engine is efficiency..

In this case inlet energy is 2000j and

the engine rejects 1500 J ..

So total energy used by the energy is 500 j ..

So Efficiency = (500/2000) = 0.25

In PERCENTAGE it is 25%..

Discussion

22.	Resistance is the two times of the electric current when potential difference maintaining 6v across the circuit of circular wire of length20 times of 6 meter of radius find the resistivity of the wire??
Answer» Answer: man THOUGH hydrogen is not a and even it is placed in the REACTIVITY SERIES of metals. Write the reason 5+5 +10=20 5+5 +10=20 you can check man Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20 5+5 +10=20 you can check - H - - - -- - - SUBSCRIBE to (mr. random) and (mythpat)

22.

Resistance is the two times of the electric current when potential difference maintaining 6v across the circuit of circular wire of length20 times of 6 meter of radius find the resistivity of the wire??

Answer»

Answer:

man

THOUGH hydrogen is not a and even it is placed in the REACTIVITY SERIES of metals. Write the reason 5+5 +10=20

5+5 +10=20 you can check

man

Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20

5+5 +10=20 you can check

-

H

-

--

-

SUBSCRIBE to (mr. random) and (mythpat)

Discussion

23.	Define a spherical mirror.
Answer» ANSWER: SPHERICAL mirror is a mirror that has the shape of a piece cut out of a spherical surface. There are two types of spherical mirrors: CONCAVE and convex . Explanation: MARK me as brainliest and follow

23.

Define a spherical mirror.

Answer»

ANSWER:

SPHERICAL mirror is a mirror that has the shape of a piece cut out of a spherical surface. There are two types of spherical mirrors: CONCAVE and convex .

Explanation:

MARK me as brainliest and follow

Discussion

24.	B, sini = 1₂ sing is known as
Answer» Answer: SNELL′s law:− When a ray of LIGHT passes from medium-1 to medium-2, then the RATIO of sine of angle of incidence(i) to sine of angle of refraction(r) is EQUAL to the refractive index of medium-2 (n2) RELATIVE to medium-1 (n1). sinrsini=n1n2 ⟹n1sini=n2sinr This is Snell's Law.

24.

B, sini = 1₂ sing is known as

Answer»

Answer:

SNELL′s law:− When a ray of LIGHT passes from medium-1 to medium-2, then the RATIO of sine of angle of incidence(i) to sine of angle of refraction(r) is EQUAL to the refractive index of medium-2 (n2) RELATIVE to medium-1 (n1).

sinrsini=n1n2

⟹n1sini=n2sinr

This is Snell's Law.

Discussion

25.	length of wire is 200 cm, area of the wire 20m^2 the resistance of the wire 4 ohm find the resistivity??
Answer» R = 4 l = 200CM = 2m A = 20 m^2 ρ = ? Formula is R = ρ * l / a 4 = ρ * 2 / 20 ρ = 4 * 20 / 2 ρ = 40 ohm.m

25.

length of wire is 200 cm, area of the wire 20m^2 the resistance of the wire 4 ohm find the resistivity??

Answer»

R = 4

l = 200CM = 2m

A = 20 m^2

ρ = ?

Formula is R = ρ * l / a

4 = ρ * 2 / 20

ρ = 4 * 20 / 2

ρ = 40 ohm.m

Discussion

26.	A bullet short straight up returns to its starting point in 10 sec. its initial speed was:
Answer» ANSWER: man Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20 5+5 +10=20 you can check man Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20 5+5 +10=20 you can check - h - - - -- - - subscribe to (MR. RANDOM) and (MYTHPAT)

26.

A bullet short straight up returns to its starting point in 10 sec. its initial speed was:

Answer»

ANSWER:

man

Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20

5+5 +10=20 you can check

man

Though hydrogen is not a and even it is placed in the reactivity series of metals. Write the reason 5+5 +10=20

5+5 +10=20 you can check

-

h

-

--

-

subscribe to (MR. RANDOM) and (MYTHPAT)

Discussion

27.	Derive the power in terms of voltage and current.
Answer» Answer: ok Explanation: Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or INTENSITY and R = resistance. V = voltage, electric potential DIFFERENCE Δ V or E = electromotive force (emf = voltage). Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts W Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or VOLTS E or V: volts V Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms Ω Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms ΩAmperage or current I: AMPERES, amps A

27.

Derive the power in terms of voltage and current.

Answer»

Answer:

ok

Explanation:

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or INTENSITY and R = resistance. V = voltage, electric potential DIFFERENCE Δ V or E = electromotive force (emf = voltage).

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts W

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or VOLTS E or V: volts V

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms Ω

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms ΩAmperage or current I: AMPERES, amps A

Discussion

28.	Write about metals react with acids
Answer» Answer: Acids react with most metals to form a SALT and HYDROGEN GAS. As discussed previously, metals that are more ACTIVE than acids can undergo a single displacement reaction. For example, zinc metal reacts with hydrochloric acid, producing zinc chloride and hydrogen gas.29-Dec-2020 Explanation: I hope this will help you..pls mark me as a brain liest

28.

Write about metals react with acids

Answer»

Answer:

Acids react with most metals to form a SALT and HYDROGEN GAS. As discussed previously, metals that are more ACTIVE than acids can undergo a single displacement reaction. For example, zinc metal reacts with hydrochloric acid, producing zinc chloride and hydrogen gas.29-Dec-2020

Explanation:

I hope this will help you..pls mark me as a brain liest

Discussion

29.	A wire of Resistance R is cut into five equal parts. Calculate its new resistance R’ if itis connected in (i) Series (ii) Parallel
Answer» EXPLANATION: when is in SERIES r1+r2+r3+r4+r5and when in PARALLEL 1/r1+1/r2+1/r3+1/r4+1/r5

29.

A wire of Resistance R is cut into five equal parts. Calculate its new resistance R’ if itis connected in (i) Series (ii) Parallel

Answer»

EXPLANATION:

when is in SERIES r1+r2+r3+r4+r5and when in PARALLEL 1/r1+1/r2+1/r3+1/r4+1/r5

Discussion

30.	As we go at a greater height from the surface of earth. The value of g:
Answer» The VALUE of G DECREASES

30.

As we go at a greater height from the surface of earth. The value of g:

Answer»

The VALUE of G DECREASES

Discussion

31.	If m=-1, the mirror is called a _______ mirror concave convex both concave and convex plain
Answer» ANSWER: CONCAVE MIRROR is the CORRECT answer

31.

If m=-1, the mirror is called a _______ mirror concave convex both concave and convex plain

Answer»

ANSWER:

CONCAVE MIRROR is the CORRECT answer

Discussion

32.	Vertical distance covered by an object of mass 1kg in one second is:
Answer» Answer: 57%-512+258558gtd55-/*4295-2+ 58235

32.

Vertical distance covered by an object of mass 1kg in one second is:

Answer»

Answer:

57%-512+258558gtd55-/*4295-2+ 58235

Discussion

33.	Kinetic energy is conserved in:
Answer» ANSWER: An elastic collision is a collision in which there is no net LOSS in KINETIC energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities in elastic collisions. Explanation: pls mark me a BRAINLIST

33.

Kinetic energy is conserved in:

Answer»

ANSWER:

An elastic collision is a collision in which there is no net LOSS in KINETIC energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities in elastic collisions.

Explanation:

pls mark me a BRAINLIST

Discussion

34.	A system on which no external agency exerts any force is called:
Answer» $\huge\green{\mid{\fbox{{คภรฬєг⤵}}\mid}}$ The acceleration is DIRECTLY proportional to the net FORCE; the net force equals MASS times acceleration; the acceleration in the same direction as the net force; an acceleration is PRODUCED by a net force. The NET FORCE. $\huge\fbox\red{hσpє}\huge\fbox\pink{ít}\fbox\green{hєlp}\huge\fbox\blue{yóû}$ $\huge\fbox{\red{\underline{mαrk \; mє \; вrαínlíєѕt \; plєαѕє ♥}}}$ $\large\bf{\underline\blue{❥thαnk \; чσu ♥♥}}$

34.

A system on which no external agency exerts any force is called:

Answer»

$\huge\green{\mid{\fbox{{คภรฬєг⤵}}\mid}}$

The acceleration is DIRECTLY proportional to the net FORCE; the net force equals MASS times acceleration; the acceleration in the same direction as the net force; an acceleration is PRODUCED by a net force. The NET FORCE.

$\huge\fbox\red{hσpє}\huge\fbox\pink{ít}\fbox\green{hєlp}\huge\fbox\blue{yóû}$

$\huge\fbox{\red{\underline{mαrk \; mє \; вrαínlíєѕt \; plєαѕє ♥}}}$

$\large\bf{\underline\blue{❥thαnk \; чσu ♥♥}}$

Discussion

35.	Write law of conservation of energy.
Answer» Answer: In physics and chemistry, the law of conservation of energy states that the total energy is an isolated systems remains constant,It is said to be conserved over time. For instance chemical energy is converted to kinetic energy when a stick of dinamites explodes. ____________________________ Hope it helps u♥♥ Kusum Here~♥~

35.

Write law of conservation of energy.

Answer»

Answer:

In physics and chemistry, the law of conservation of energy states that the total energy is an isolated systems remains constant,It is said to be conserved over time. For instance chemical energy is converted to kinetic energy when a stick of dinamites explodes.

____________________________

Hope it helps u♥♥

Kusum Here~♥~

Discussion

36.	Convert 373°c in degree f
Answer» 703.4 Fahrenheit thank you

36.

Convert 373°c in degree f

Answer»

703.4 Fahrenheit

thank you

Discussion

37.	A snooker ball moving with velocity v collides head on with another snooker ball of same mass atrest. If the collision is elastic the velocity of second snooker ball is:
Answer» ANSWER: Correct OPTION is C 90 o 0 o If collision is HEAD on 90 o If collision is oblique

37.

A snooker ball moving with velocity v collides head on with another snooker ball of same mass atrest. If the collision is elastic the velocity of second snooker ball is:

Answer»

ANSWER:

Correct OPTION is

C

90

o

0

o

If collision is HEAD on

90

o

If collision is oblique

Discussion

38.	For a system of N particles write down the general formula for total internal force in terms ofsummation notation How many terms the summation will have it expanded?
Answer» Answer: In mechanics, acceleration is the rate of change of the velocity of an object with respect to TIME. ACCELERATIONS are vector quantities (in that they have MAGNITUDE and direction). The orientation of an object's acceleration is given by the orientation of the net force ACTING on that object Explanation: In mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). The orientation of an object's acceleration is given by the orientation of the net force acting on that OBJEC

38.

For a system of N particles write down the general formula for total internal force in terms ofsummation notation How many terms the summation will have it expanded?

Answer»

Answer:

In mechanics, acceleration is the rate of change of the velocity of an object with respect to TIME. ACCELERATIONS are vector quantities (in that they have MAGNITUDE and direction). The orientation of an object's acceleration is given by the orientation of the net force ACTING on that object

Explanation:

In mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). The orientation of an object's acceleration is given by the orientation of the net force acting on that OBJEC

Discussion

39.	The voltage present at the output of an op-amp when its differential inputvoltage is zero is called as
Answer» Answer: Offset Voltage, (VIO) Explanation: the INPUT resistance is infinite, so no CURRENT flows into EITHER input terminal (the “current RULE”) and that the differential input offset voltage is zero (the “voltage rule”).

39.

The voltage present at the output of an op-amp when its differential inputvoltage is zero is called as

Answer»

Answer:

Offset Voltage, (VIO)

Explanation:

the INPUT resistance is infinite, so no CURRENT flows into EITHER input terminal (the “current RULE”) and that the differential input offset voltage is zero (the “voltage rule”).

Discussion

40.	In forward bais condition p- n junction offers
Answer» ANSWER: The JUNCTION offers low resistance, known as FORWARD Resistance (RF) to the flow of current through it. The magnitude of the flow of the current through the CIRCUIT depends upon the applied forward voltage.

40.

In forward bais condition p- n junction offers

Answer»

ANSWER:

The JUNCTION offers low resistance, known as FORWARD Resistance (RF) to the flow of current through it. The magnitude of the flow of the current through the CIRCUIT depends upon the applied forward voltage.

Discussion

41.	When an electron jumps from higher orbit to a lower orbit, it ……….energy. *
Answer» Answer: When electron jumps from higher orbit to lower orbit, then ENERGY is radiated in the form of ELECTROMAGNETIC radiation and these RADIATIONS are USED to record the EMISSION spectrum Energy of electron may be calculated as. E=-2π2meZ2e4n2h2.

41.

When an electron jumps from higher orbit to a lower orbit, it ……….energy. *

Answer»

Answer:

When electron jumps from higher orbit to lower orbit, then ENERGY is radiated in the form of ELECTROMAGNETIC radiation and these RADIATIONS are USED to record the EMISSION spectrum Energy of electron may be calculated as. E=-2π2meZ2e4n2h2.

Discussion

42.	a tuck starts from rest and rolls down a hill with a constant acceleration if travels a distance of 400mt in 20 seconds find its acceleration . find the force acting on it , if it's mass is 7 tonnes (1 tonne is equal to 1000kg )
Answer» ${\large{\underline{\pmb{\sf{Given...}}}}}$ ★ A tuck starts from rest and rolls down a hill with a constant acceleration ★ it travels a distance of 400m in 20 seconds ★ the MASS of the TRUCK is 7 TONNES ${\large{\underline{\pmb{\sf{To\;Find...}}}}}$ ★ The acceleration of the truck ★ The force acting on the truck ${\large{\underline{\pmb{\sf{Understanding \; the \; question...}}}}}$ ❍ Concept : As we have been said that the truck starts form rest [ it's INITIAL velocity ] with a constant acceleration and the distance travelled which is 400 m in 20 seconds and said that the mass of the truck is 7 tonnes. ★ So let's use suitable formulae in both the cases of finding the acceleration of the truck and the amount force acting upon the truck using the given statements. ${\large{\underline{\pmb{\sf{Using\; concepts...}}}}}$ ✪ Formula to find the acceleration of an object : $\tt S = ut + \dfrac{1}{2} at^{2}$ ✪ Formula to find the force : $\tt Force = Mass\times Acceleration$ ${\large{\underline{\pmb{\sf{ Solution...}}}}}$ ★ The acceleration of the truck is 2m/s^2 and the force acting upon the truck is 14,000N ${\large{\underline{\pmb{\sf{Full\; Solution...}}}}}$ ★ Firstly let's find the acceleration of the truck → Formula : $\tt S = ut + \dfrac{1}{2} at^{2}$ → Where, S denotes the distance u denotes initial velocity t denotes time a denotes acceleration → Here, S = 400m u = 0m/s^2 t = 20 s ~ Now let' substitute the values in the above mentioned formulae and find the required solution . ➟ S = ut + 1/2 × a × t × t ➟ 400 = 0 × 20 + 1/2 × a × 20 × 20 ➟ 400 = 0 × 20 + 1/2 × 400a ➟ 400 = 0 × 20 + 200a ➟ 400 = 0 + 200a ➟ 400 = 200a ➟ a = 400/200 ➟ a = 2m/s^2 Henceforth the acceleration of the truck is 2m/s^2 ~As we have found the acceleration now, let's find the force acting upon the truck. → Formula : $\tt Force = Mass \times Acceleration$ . → Here, Mass = 7 tonnes Acceleration = 2m/s^2 ~ As we know that when we evaluate something we'll have to make sure that they belong to the same unit. now as the mass in the unit of tonnes let's convert it into S.I system ( kilograms ) ${\bf{\red{ hint : }}}$ 1 ton = 1000 kg ★ So, 7 tonnes = 7 × 1000kg = 7000kg ~Now, let;s substitute the values in the formula and find the force acting upon. ➟ F = M × A ➟ F = 7000 × 2 ➟ F = 14000N Henceforth the force acting upon the truck is 14000 newton ${\underline{\large{\pmb{\sf{Additional \; Info...}}}}}$ ${\underline{\underline{\sf{\bigstar{Other \; formula \; to\; find \; acceleration :}}}}}$ ✪ Formula : $\tt a = \dfrac{u-v}{t}$ ${\underline{\underline{\sf{\bigstar{Other \; formula \; to\; find \; force :}}}}}$ ✪ Formula : $\tt Force = Pressure \times Area$ ${\underline{\underline{\sf{\bigstar{Newton's \; law \; of \; gravitation :}}}}}$ $\setlength{\unitlength}{7mm} \begin{picture}(6,6)\thicklines\put(2,2){\circle{14}}\put(8,2){\circle{14}} \put(2,2){\circle{0.15}} \put(8,2){\circle{0.15}} \put(2,2){\line(1,0){6}} \put(4,2){\line( - 1,1){0.5}} \put(6,2){\line(1,1){0.5}} \put(4,2){\line( - 1, - 1){0.5}} \put(6,2){\line( 1, -1){0.5}} \put(4.5,0.7){\vector( - 1,0){2.7}} \put(5.4,0.7){\vector(1,0){2.8}}\put(4.75,0.6){$ \bf d $}\put( 3.3, - 1){ \framebox{$ \bf F = \displaystyle \dfrac{G Mm }{ d^2} $}}\end{picture}$ * Note : view the answer from web if any difficulty in viewing from the app See this question at : brainly.in/question/39482821

42.

a tuck starts from rest and rolls down a hill with a constant acceleration if travels a distance of 400mt in 20 seconds find its acceleration . find the force acting on it , if it's mass is 7 tonnes (1 tonne is equal to 1000kg )

Answer»

${\large{\underline{\pmb{\sf{Given...}}}}}$

★ A tuck starts from rest and rolls down a hill with a constant acceleration

★ it travels a distance of 400m in 20 seconds

★ the MASS of the TRUCK is 7 TONNES

${\large{\underline{\pmb{\sf{To\;Find...}}}}}$

★ The acceleration of the truck

★ The force acting on the truck

${\large{\underline{\pmb{\sf{Understanding \; the \; question...}}}}}$

❍ Concept : As we have been said that the truck starts form rest [ it's INITIAL velocity ] with a constant acceleration and the distance travelled which is 400 m in 20 seconds and said that the mass of the truck is 7 tonnes.

★ So let's use suitable formulae in both the cases of finding the acceleration of the truck and the amount force acting upon the truck using the given statements.

${\large{\underline{\pmb{\sf{Using\; concepts...}}}}}$

✪ Formula to find the acceleration of an object :

$\tt S = ut + \dfrac{1}{2} at^{2}$

✪ Formula to find the force :

$\tt Force = Mass\times Acceleration$

${\large{\underline{\pmb{\sf{ Solution...}}}}}$

★ The acceleration of the truck is 2m/s^2 and the force acting upon the truck is 14,000N

${\large{\underline{\pmb{\sf{Full\; Solution...}}}}}$

★ Firstly let's find the acceleration of the truck

→ Formula :

$\tt S = ut + \dfrac{1}{2} at^{2}$

→ Where,

S denotes the distance
u denotes initial velocity
t denotes time
a denotes acceleration

→ Here,

S = 400m
u = 0m/s^2
t = 20 s

~ Now let' substitute the values in the above mentioned formulae and find the required solution .

➟ S = ut + 1/2 × a × t × t

➟ 400 = 0 × 20 + 1/2 × a × 20 × 20

➟ 400 = 0 × 20 + 1/2 × 400a

➟ 400 = 0 × 20 + 200a

➟ 400 = 0 + 200a

➟ 400 = 200a

➟ a = 400/200

➟ a = 2m/s^2

Henceforth the acceleration of the truck is 2m/s^2

~As we have found the acceleration now, let's find the force acting upon the truck.

→ Formula :

$\tt Force = Mass \times Acceleration$ .

→ Here,

Mass = 7 tonnes
Acceleration = 2m/s^2

~ As we know that when we evaluate something we'll have to make sure that they belong to the same unit. now as the mass in the unit of tonnes let's convert it into S.I system ( kilograms )

${\bf{\red{ hint : }}}$ 1 ton = 1000 kg

★ So, 7 tonnes = 7 × 1000kg = 7000kg

~Now, let;s substitute the values in the formula and find the force acting upon.

➟ F = M × A

➟ F = 7000 × 2

➟ F = 14000N

Henceforth the force acting upon the truck is 14000 newton

${\underline{\large{\pmb{\sf{Additional \; Info...}}}}}$

${\underline{\underline{\sf{\bigstar{Other \; formula \; to\; find \; acceleration :}}}}}$

✪ Formula :

$\tt a = \dfrac{u-v}{t}$

${\underline{\underline{\sf{\bigstar{Other \; formula \; to\; find \; force :}}}}}$

✪ Formula :

$\tt Force = Pressure \times Area$

${\underline{\underline{\sf{\bigstar{Newton's \; law \; of \; gravitation :}}}}}$

$\setlength{\unitlength}{7mm} \begin{picture}(6,6)\thicklines\put(2,2){\circle{14}}\put(8,2){\circle{14}} \put(2,2){\circle*{0.15}} \put(8,2){\circle*{0.15}} \put(2,2){\line(1,0){6}} \put(4,2){\line( - 1,1){0.5}} \put(6,2){\line(1,1){0.5}} \put(4,2){\line( - 1, - 1){0.5}} \put(6,2){\line( 1, -1){0.5}} \put(4.5,0.7){\vector( - 1,0){2.7}} \put(5.4,0.7){\vector(1,0){2.8}}\put(4.75,0.6){$ \bf d $}\put( 3.3, - 1){ \framebox{$ \bf F = \displaystyle \dfrac{G Mm }{ d^2} $}}\end{picture}$

* Note : view the answer from web if any difficulty in viewing from the app

See this question at : brainly.in/question/39482821

Discussion

43.	सर पर
Answer» EXPLANATION: gzohsoysoysohsoysoysoysoysoys

43.

सर पर

Answer»

EXPLANATION:

gzohsoysoysohsoysoysoysoysoys

Discussion

44.	State what is meant by a field line (line of force) in an electric field.
Answer» Answer: An electric line of FORCE is an imaginary CONTINUOUS line or curve DRAWN in an electric field such that TANGENT to it at any point gives the direction of the electric force at that point. the direction of a line of force is the direction along which a small free positive charge will move along the line. Explanation: please GIVE thank and please mark as brilliant

44.

State what is meant by a field line (line of force) in an electric field.

Answer»

Answer:

An electric line of FORCE is an imaginary CONTINUOUS line or curve DRAWN in an electric field such that TANGENT to it at any point gives the direction of the electric force at that point. the direction of a line of force is the direction along which a small free positive charge will move along the line.

Explanation:

please GIVE thank and please mark as brilliant

Discussion

45.	Types of oxygen cylinder used in hospital
Answer» Answer: There are 2 types of medical products that provide oxygen GAS in ACCORDANCE with health. These are oxygen cylinders and oxygen concentrators. The WAY of use in both types of devices is similar. Oxygen cylinders are REFILLABLE, while oxygen concentrators do not need REFILLING.

45.

Types of oxygen cylinder used in hospital

Answer»

Answer:

There are 2 types of medical products that provide oxygen GAS in ACCORDANCE with health. These are oxygen cylinders and oxygen concentrators. The WAY of use in both types of devices is similar. Oxygen cylinders are REFILLABLE, while oxygen concentrators do not need REFILLING.

Discussion

46.	The field lunes for two point charges are shown in figure
Answer» EXPLANATION: Figure SHOWS the electirc field lines for TWO point charges separated by a distance. ... As the number of lines leaving q1 is twice the number of field lines TERMINATING on q2, therefore, MAGNITUDE of q2,i. e.,q1∣q2=2.

46.

The field lunes for two point charges are shown in figure

Answer»

EXPLANATION:

Figure SHOWS the electirc field lines for TWO point charges separated by a distance. ... As the number of lines leaving q1 is twice the number of field lines TERMINATING on q2, therefore, MAGNITUDE of q2,i. e.,q1∣q2=2.

Discussion

47.	Percentage change in distance is 4. Find % change in Coulomb’s Force.
Answer» Answer: In Coulomb’s Law, F = kq1Q2/d^2 where F is the electric force, k is a constant, q1 and q2 are the two charges and d^2 is the square of the distance between the two charges, let this ORIGINAL value equals to 100%. If d is QUADRUPLED, (4d)^2 becomes 16 d^2. Plugging in this to Coulomb’s law its value related to the electric force is F = (1/16) d^2. The enclosed number (1/16) in PERCENT is 6.25%. The percentage change in coulomb force is therefore 100% - 6.25% or 93.75%.

47.

Percentage change in distance is 4. Find % change in Coulomb’s Force.

Answer»

Answer:

In Coulomb’s Law, F = k*q1*Q2/d^2 where F is the electric force, k is a constant, q1 and q2 are the two charges and d^2 is the square of the distance between the two charges, let this ORIGINAL value equals to 100%.

If d is QUADRUPLED, (4d)^2 becomes 16 d^2. Plugging in this to Coulomb’s law its value related to the electric force is F = (1/16) d^2. The enclosed number (1/16) in PERCENT is 6.25%. The percentage change in coulomb force is therefore 100% - 6.25% or 93.75%.

Discussion

48.	Threading on tyre ______ friction1. increase2. decrease3. increase as well as decrease 4. doubles hello everyonepls answer quickly
Answer» ANSWER: OPTION (1) IS THE RIGHT ANSWER. INCREASE. Explanation: I HOPE YOU UNDERSTAND NOW.

48.

Threading on tyre ______ friction1. increase2. decrease3. increase as well as decrease 4. doubles hello everyonepls answer quickly

Answer»

ANSWER:

OPTION (1) IS THE RIGHT ANSWER.

INCREASE.

Explanation:

I HOPE YOU UNDERSTAND NOW.

Discussion

49.	What are the characteristics of matter?What are the states of matter?
Answer» $What\:are\:the\:characteristics\:of\:matter?$ Matter is everything around you which is made up of PARTICLES. It has MASS and occupies space. Mass is a PHYSICAL quantity which expresses the amount of stuff in an object. The space inside the container that is occupied by matter is its volume. $What\:are\:the\:states\:of\:matter?$ In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in EVERYDAY life: solid, liquid, gas, and plasma.

49.

What are the characteristics of matter?What are the states of matter?

Answer»

$What\:are\:the\:characteristics\:of\:matter?$

Matter is everything around you which is made up of PARTICLES. It has MASS and occupies space. Mass is a PHYSICAL quantity which expresses the amount of stuff in an object. The space inside the container that is occupied by matter is its volume.

$What\:are\:the\:states\:of\:matter?$

In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in EVERYDAY life: solid, liquid, gas, and plasma.

Discussion

50.	Tivity 3 When a force is applied on a body of mass 10 kg for a period of 4 s, the velocity of the bodychanges from 6 m/s to 8 m/s.a) What is the initial momentum of the body? answerplease
Answer» ANSWER: fggg Explanation: xvgdhi ND ty uc CH ivg

50.

Tivity 3 When a force is applied on a body of mass 10 kg for a period of 4 s, the velocity of the bodychanges from 6 m/s to 8 m/s.a) What is the initial momentum of the body? answerplease

Answer»

ANSWER:

fggg

Explanation:

xvgdhi ND ty uc CH ivg

Discussion

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The field lunes for two point charges are shown in figure​

Percentage change in distance is 4. Find % change in Coulomb’s Force.

Threading on tyre ______ friction1. increase2. decrease3. increase as well as decrease 4. doubles hello everyonepls answer quickly ​

What are the characteristics of matter?What are the states of matter?​

Tivity 3 When a force is applied on a body of mass 10 kg for a period of 4 s, the velocity of the bodychanges from 6 m/s to 8 m/s.a) What is the initial momentum of the body? answerplease​

find the velocity of projection of missile which has a horizontal range of 150m,if the time of flight for that range is 3sec

A current of 1A is drawn from wire in 16sec. How many electrons flowing through it

.When electrons move through a magnetic field, then change occurs in speed,mass or direction?

A force is needed to keep a block of wood inside water.why

Product of mass and velocity of an object is called

Why can't we kick football sideways and it always goes straight ??????

A progressive wave s represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metreand t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.

An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image

Heya !!Refer the attachment Define physics ?

A progressive wave is represented by the equation Y=6sin(80rt - 0.5r×) where x, y are in metre and t is in second. Calculate (a) Amplitude (b) Wavelength (c) Frequency (d) Velocity of the wave.

Application of thermoelectric diagram

a car traveling at speed of 5 m/s accelerate of 4 m/s find the speed of car after 5 sec and also calculate the distance covered

Writeabout differentsystem of units?

Ons.3)Due to heat pressure is

The effective resistance between 'A' and 'B' is :(a) (b)(c)(d)

A body dropped gently from a height h takes time t to reach the ground. Velocity of this body at theheight h/2 is:A) gtB) gt/2C) gt/√2D) gt/4E) gt^2/2

16) Read the following question andselect correct optionWhat are the dimensions of the quantity 1 V1/g where l-isthe length and g -is the acceleration due to gravityA) [L'T'B)[ZC)|L'7-')D)M'T')

What is the effect on surrounding metal placed in a magnetic field?

. A carnot engine takes 2000 J of heat / cycle from the source and rejects 1500 J of heat / cycleto sink. If temperature of source is 600 K, what is the temperature of sink. Calculate efficiency of engine.

Resistance is the two times of the electric current when potential difference maintaining 6v across the circuit of circular wire of length20 times of 6 meter of radius find the resistivity of the wire??

Define a spherical mirror.

B, sini = 1₂ sing is known as

length of wire is 200 cm, area of the wire 20m^2 the resistance of the wire 4 ohm find the resistivity??

Derive the power in terms of voltage and current.

Write about metals react with acids

A wire of Resistance R is cut into five equal parts. Calculate its new resistance R’ if itis connected in (i) Series (ii) Parallel

If m=-1, the mirror is called a _______ mirror concave convex both concave and convex plain

Write law of conservation of energy.

Convert 373°c in degree f

For a system of N particles write down the general formula for total internal force in terms ofsummation notation How many terms the summation will have it expanded?

The voltage present at the output of an op-amp when its differential inputvoltage is zero is called as

In forward bais condition p- n junction offers

When an electron jumps from higher orbit to a lower orbit, it ……….energy. *

a tuck starts from rest and rolls down a hill with a constant acceleration if travels a distance of 400mt in 20 seconds find its acceleration . find the force acting on it , if it's mass is 7 tonnes (1 tonne is equal to 1000kg )

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Types of oxygen cylinder used in hospital

The field lunes for two point charges are shown in figure

Threading on tyre ______ friction1. increase2. decrease3. increase as well as decrease 4. doubles hello everyonepls answer quickly

What are the characteristics of matter?What are the states of matter?

Tivity 3 When a force is applied on a body of mass 10 kg for a period of 4 s, the velocity of the bodychanges from 6 m/s to 8 m/s.a) What is the initial momentum of the body? answerplease