67486 + Interview Questions in Secondary School in Physics

1.	In the experiment of refraction through a glass slab, the angle of incidence should be less than 90•.Why
Answer» Answer: hey here is ur answer pls MARK it as brainliest Explanation: so angle of incidence must be less than 90 degree because angle of incidence doesn't passes through any DEVIATION ie it is not PERPENDICULAR moreover if angle of incidence is 90 then angle of refraction must also be 90 which is just impossible because according to SNELLS law i=r thus it said that

1.

In the experiment of refraction through a glass slab, the angle of incidence should be less than 90•.Why

Answer»

Answer:

hey here is ur answer

pls MARK it as brainliest

Explanation:

so angle of incidence must be less than 90 degree because angle of incidence doesn't passes through any DEVIATION

ie it is not PERPENDICULAR

moreover if angle of incidence is 90

then angle of refraction must also be 90

which is just impossible

because according to SNELLS law i=r

thus it said that

Discussion

2.	If you were to classify a newly discovered animal, what would you want to know first?Does it have vascular tissue?Does it have hair?Does it have a backbone?Does it live on land or in the sea?plsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss answer correctly
Answer» ANSWER: Explanation: I would check that does it have HAIR or not because hair provides info about the DNA which can help me if that specific animal has evolved from DNA of any other animal.. Hope it HELPED you. Mark BRAINLIEST is it did.

2.

If you were to classify a newly discovered animal, what would you want to know first?Does it have vascular tissue?Does it have hair?Does it have a backbone?Does it live on land or in the sea?plsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss answer correctly

Answer»

ANSWER:

Explanation:

I would check that does it have HAIR or not because hair provides info about the DNA which can help me if that specific animal has evolved from DNA of any other animal..

Hope it HELPED you.

Mark BRAINLIEST is it did.

Discussion

3.	An object has moved through adistance. Can it have zerodisplacement? If yes, SupportyOur answer with an example.
Answer» Answer: OBJECT can have ZERO displacement if it travels in a CIRCLE and come BACK to its original place but the distance TRAVELLED can never be zero

3.

An object has moved through adistance. Can it have zerodisplacement? If yes, SupportyOur answer with an example.

Answer»

Answer:

OBJECT can have ZERO displacement if it travels in a CIRCLE and come BACK to its original place but the distance TRAVELLED can never be zero

Discussion

4.	Please help me in Biology exam please i want fast answer please
Answer» ANSWER: It is exam. Explanation:LEARN and do it by yourself.

4.

Please help me in Biology exam please i want fast answer please

Answer»

ANSWER:

It is exam.

Explanation:LEARN and do it by yourself.

Discussion

5.	an object starting from rest travels with an acceleration of 5 metre per second square.what will be its velocity after 3 seconds?
Answer» ANSWER: Initial velocity (U) = 0 m/s. Acceleration (a) = 5 m/s² Time INTERVAL (t) = 3 s.

5.

an object starting from rest travels with an acceleration of 5 metre per second square.what will be its velocity after 3 seconds?

Answer»

ANSWER:

Initial velocity (U) = 0 m/s. Acceleration (a) = 5 m/s² Time INTERVAL (t) = 3 s.

Discussion

6.	Integral of (x² - 1/x²)dx
Answer» ANSWER: jjghgjkkokkuygffgjkgcx

6.

Integral of (x² - 1/x²)dx

Answer»

ANSWER:

jjghgjkkokkuygffgjkgcx

Discussion

7.	Please answer these...plz all the 3 parts
Answer» ANSWER: a is EQUAL to2m/s v is equal to 8m/s

7.

Please answer these...plz all the 3 parts

Answer»

ANSWER:

a is EQUAL to2m/s

v is equal to 8m/s

Discussion

8.	Wh machineat is the difference betwee a simply machine and a complex
Answer» Answer: Simple Machine: Any of various devices that FUNCTION in a manner basic to any machine, such as a lever, pulley, wedge, screw, or inclined plane. Complex Machine: A DEVICE consisting of two or more simple machines WORKING TOGETHER. ... A wedge is driven or forced between objects to split, lift, or make them stronger

8.

Wh machineat is the difference betwee a simply machine and a complex

Answer»

Answer:

Simple Machine: Any of various devices that FUNCTION in a manner basic to any machine, such as a lever, pulley, wedge, screw, or inclined plane. Complex Machine: A DEVICE consisting of two or more simple machines WORKING TOGETHER. ... A wedge is driven or forced between objects to split, lift, or make them stronger

Discussion

9.	Mass of a certain body is 10kg and volume is 2m^3. Find its density.
Answer» Answer: 1.2 Explanation: density=mass/volume density=10/8 density=1.2kg/m^3

9.

Mass of a certain body is 10kg and volume is 2m^3. Find its density.

Answer»

Answer:

1.2

Explanation:

density=mass/volume

density=10/8

density=1.2kg/m^3

Discussion

10.	gawain sa pagkatuto bilang 3 pagmasdan anf iyong paligid o komunidad na kinabibilangan magbigay ng hanggang tatlong uri ng kagamitan o makinarya na makikita mo na nakapagpapabilis ng trabaho.i paliwanag ang bawat kahalagahan ng piniling kagamitan o makinarya
Answer» Answer: NA kinabibilangan MAGBIGAY ng HANGGANG tatlong uri ng kagamitan o makinarya na makikita mo na nakapagpapabilis ng trabaho.i paliwanag ang bawat KAHALAGAHAN ng piniling

10.

gawain sa pagkatuto bilang 3 pagmasdan anf iyong paligid o komunidad na kinabibilangan magbigay ng hanggang tatlong uri ng kagamitan o makinarya na makikita mo na nakapagpapabilis ng trabaho.i paliwanag ang bawat kahalagahan ng piniling kagamitan o makinarya

Answer»

Answer:

NA kinabibilangan MAGBIGAY ng HANGGANG tatlong uri ng kagamitan o makinarya na makikita mo na nakapagpapabilis ng trabaho.i paliwanag ang bawat KAHALAGAHAN ng piniling

Discussion

11.	What is a Bermuda triangle
Answer» $\huge\red{\mid{\fbox{\tt{ᴀɴsᴡᴇʀ }}\mid}}$ ᴛʜᴇ ʙᴇʀᴍᴜᴅᴀ ᴛʀɪᴀɴɢʟᴇ ɪs ᴀ ʀᴇɢɪᴏɴ ɪɴ ᴛʜᴇ ᴡᴇsᴛᴇʀɴ ᴘᴀʀᴛ ᴏғ ᴛʜᴇ ɴᴏʀᴛʜ ᴀᴛʟᴀɴᴛɪᴄ ᴏᴄᴇᴀɴ ɪɴ ᴡʜɪᴄʜ sʜɪᴘs, ᴘʟᴀɴᴇs, ᴀɴᴅ ᴘᴇᴏᴘʟᴇ ᴀʀᴇ ᴀʟʟᴇɢᴇᴅ ᴛᴏ ʜᴀᴠᴇ ᴍʏsᴛᴇʀɪᴏᴜsʟʏ ᴠᴀɴɪsʜᴇᴅ.

11.

What is a Bermuda triangle

Answer»

$\huge\red{\mid{\fbox{\tt{ᴀɴsᴡᴇʀ }}\mid}}$

ᴛʜᴇ ʙᴇʀᴍᴜᴅᴀ ᴛʀɪᴀɴɢʟᴇ ɪs ᴀ ʀᴇɢɪᴏɴ ɪɴ ᴛʜᴇ ᴡᴇsᴛᴇʀɴ ᴘᴀʀᴛ ᴏғ ᴛʜᴇ ɴᴏʀᴛʜ ᴀᴛʟᴀɴᴛɪᴄ ᴏᴄᴇᴀɴ ɪɴ ᴡʜɪᴄʜ sʜɪᴘs, ᴘʟᴀɴᴇs, ᴀɴᴅ ᴘᴇᴏᴘʟᴇ ᴀʀᴇ ᴀʟʟᴇɢᴇᴅ ᴛᴏ ʜᴀᴠᴇ ᴍʏsᴛᴇʀɪᴏᴜsʟʏ ᴠᴀɴɪsʜᴇᴅ.

Discussion

12.	Soham is moving in his car with a velocity of 90 km/h. How much distance will be covered ini. One minuteii. one second
Answer» Answer: (i) Given, Velocity = 90km/HR Time = 1 min or 1/60 hr Then , DISTANCE= V×T 90×1/60 Distance= 2/3km (ii) On the base of first do the second ONE yourself

12.

Soham is moving in his car with a velocity of 90 km/h. How much distance will be covered ini. One minuteii. one second

Answer»

Answer:

(i) Given,

Velocity = 90km/HR

Time = 1 min or 1/60 hr

Then ,

DISTANCE= V×T

90×1/60

Distance= 2/3km

(ii) On the base of first do the second ONE yourself

Discussion

13.	Derive an expression for time period of a string
Answer» T = √[M0 L1 T0] × [M0 L1 T-2]-1 = √[T2] = [M0 L0 T1]. Therefore, the TIME period is dimensionally REPRESENTED as [M0 L0 T1].

13.

Derive an expression for time period of a string

Answer»

T = √[M0 L1 T0] × [M0 L1 T-2]-1 = √[T2] = [M0 L0 T1]. Therefore, the TIME period is dimensionally REPRESENTED as [M0 L0 T1].

Discussion

14.	Mass of object increase k.E be
Answer» ANSWER: YES MASS of OBJECT INCREASE

14.

Mass of object increase k.E be

Answer»

ANSWER:

YES MASS of OBJECT INCREASE

Discussion

15.	Derive first law of Newton.Correct answer please
Answer» Newton's FIRST law states that a body stays at rest if it is at rest and moves with a constant VELOCITY unit if a net force is applied on it. Newton's second law states that the net force applied on the body is equal to the RATE of change in its momentum. That is, when F = 0, V = u for whatever time, t is TAKEN. I hope it will help you. Have a great day.

15.

Derive first law of Newton.Correct answer please

Answer»

Newton's FIRST law states that a body stays at rest if it is at rest and moves with a constant VELOCITY unit if a net force is applied on it. Newton's second law states that the net force applied on the body is equal to the RATE of change in its momentum. That is, when F = 0, V = u for whatever time, t is TAKEN.

I hope it will help you.

Have a great day.

Discussion

16.	What is linear motion ?
Answer» Answer: LINEAR MOTION, also CALLED rectilinear motion, is one-dimensional motion along a straight line, and can therefore be described mathematically USING only one spatial DIMENSION.

16.

What is linear motion ?

Answer»

Answer:

LINEAR MOTION, also CALLED rectilinear motion, is one-dimensional motion along a straight line, and can therefore be described mathematically USING only one spatial DIMENSION.

Discussion

17.	If density of earth becomes uniform then how will if effect rotation of earth ?
Answer» Answer: Earth rotates once about its axis of rotation in 1 day and moves around Sun in 365 DAYS. Since Earth and a particle on Earth both move together with a constant speed around Sun, there is no effect in the measured acceleration due to gravity on the account of Earth’s translational motion. The curved PATH around Sun can be approximated to be linear for distances under consideration. Hence, Earth can serve as inertial frame of reference for the application of Newton’s law of motion, irrespective of its translational motion. However, consideration of rotation of Earth about its axis changes the nature of Earth’s reference. It is no more an inertial frame. A particle at a point, “P”, is rotating about the axis of rotation. Clearly, a provision for the centripetal force should exist to meet the requirement of circular motion. We should emphasize here that centripetal force is not an additional force by itself, but is a requirement of circular motion, which should be met with by the forces operating on the particle. Here, gravitational force meets this requirement and, therefore, gets modified to that extent. Here, we shall restrict our consideration specifically to the effect of rotation. We will ignore other factors that AFFECT gravitational acceleration. This MEANS that we CONSIDER Earth is a solid uniform sphere. If it is so then, measured value of acceleration is equal to reference gravitational acceleration ( g0 ) as modified by rotation.Earth rotates once about its axis of rotation in 1 day and moves around Sun in 365 days. Since Earth and a particle on Earth both move together with a constant speed around Sun, there is no effect in the measured acceleration due to gravity on the account of Earth’s translational motion. The curved path around Sun can be approximated to be linear for distances under consideration. Hence, Earth can serve as inertial frame of reference for the application of Newton’s law of motion, irrespective of its translational motion. However, consideration of rotation of Earth about its axis changes the nature of Earth’s reference. It is no more an inertial frame. A particle at a point, “P”, is rotating about the axis of rotation. Clearly, a provision for the centripetal force should exist to meet the requirement of circular motion. We should emphasize here that centripetal force is not an additional force by itself, but is a requirement of circular motion, which should be met with by the forces operating on the particle. Here, gravitational force meets this requirement and, therefore, gets modified to that extent. Here, we shall restrict our consideration specifically to the effect of rotation. We will ignore other factors that affect gravitational acceleration. This means that we consider Earth is a solid uniform sphere. If it is so then, measured value of acceleration is equal to reference gravitational acceleration ( g0 ) as modified by rotation.

17.

If density of earth becomes uniform then how will if effect rotation of earth ?

Answer»

Answer:

Earth rotates once about its axis of rotation in 1 day and moves around Sun in 365 DAYS. Since Earth and a particle on Earth both move together with a constant speed around Sun, there is no effect in the measured acceleration due to gravity on the account of Earth’s translational motion. The curved PATH around Sun can be approximated to be linear for distances under consideration. Hence, Earth can serve as inertial frame of reference for the application of Newton’s law of motion, irrespective of its translational motion.

However, consideration of rotation of Earth about its axis changes the nature of Earth’s reference. It is no more an inertial frame. A particle at a point, “P”, is rotating about the axis of rotation. Clearly, a provision for the centripetal force should exist to meet the requirement of circular motion. We should emphasize here that centripetal force is not an additional force by itself, but is a requirement of circular motion, which should be met with by the forces operating on the particle. Here, gravitational force meets this requirement and, therefore, gets modified to that extent.

Here, we shall restrict our consideration specifically to the effect of rotation. We will ignore other factors that AFFECT gravitational acceleration. This MEANS that we CONSIDER Earth is a solid uniform sphere. If it is so then, measured value of acceleration is equal to reference gravitational acceleration ( g0 ) as modified by rotation.Earth rotates once about its axis of rotation in 1 day and moves around Sun in 365 days. Since Earth and a particle on Earth both move together with a constant speed around Sun, there is no effect in the measured acceleration due to gravity on the account of Earth’s translational motion. The curved path around Sun can be approximated to be linear for distances under consideration. Hence, Earth can serve as inertial frame of reference for the application of Newton’s law of motion, irrespective of its translational motion.

However, consideration of rotation of Earth about its axis changes the nature of Earth’s reference. It is no more an inertial frame. A particle at a point, “P”, is rotating about the axis of rotation. Clearly, a provision for the centripetal force should exist to meet the requirement of circular motion. We should emphasize here that centripetal force is not an additional force by itself, but is a requirement of circular motion, which should be met with by the forces operating on the particle. Here, gravitational force meets this requirement and, therefore, gets modified to that extent.

Here, we shall restrict our consideration specifically to the effect of rotation. We will ignore other factors that affect gravitational acceleration. This means that we consider Earth is a solid uniform sphere. If it is so then, measured value of acceleration is equal to reference gravitational acceleration ( g0 ) as modified by rotation.

Discussion

18.	Two masses m1 and m2 are attached to the end of a string which passes over a pulley attached to the top of an inclined plane .the angle of inclination of the plane theta .if m1=10kg , m2=5kg, theta =30 .then what is the tension in the string?a.100N b.50N c.25N d.zero
Answer» In the FIGURE, from the FBD of the 10 kg mass, when we CONSIDER the forces PARALLEL to the surface of the plane, we get, $\sf{\longrightarrow T-50=10a\quad\quad\dots(1)}$ Here 10a is the net force acting on the 10 kg mass, where a is the net ACCELERATION of the system. From the FBD of the 5 kg mass, when we consider the vertical forces, we get, $\sf{\longrightarrow 50-T=5a\quad\quad\dots(2)}$ Here 5a is the net force. Adding (1) and (2), $\sf{\longrightarrow T-50+50-T=10a+5a}$ $\sf{\longrightarrow15a=0}$ $\sf{\longrightarrow a=0}$ Then (1) becomes, $\sf{\longrightarrow T-50=0}$ $\sf{\longrightarrow\underline{\underline{T=50\ N}}}$ Hence (b) is the answer.

18.

Two masses m1 and m2 are attached to the end of a string which passes over a pulley attached to the top of an inclined plane .the angle of inclination of the plane theta .if m1=10kg , m2=5kg, theta =30 .then what is the tension in the string?a.100N b.50N c.25N d.zero

Answer»

In the FIGURE, from the FBD of the 10 kg mass, when we CONSIDER the forces PARALLEL to the surface of the plane, we get,

$\sf{\longrightarrow T-50=10a\quad\quad\dots(1)}$

Here 10a is the net force acting on the 10 kg mass, where a is the net ACCELERATION of the system.

From the FBD of the 5 kg mass, when we consider the vertical forces, we get,

$\sf{\longrightarrow 50-T=5a\quad\quad\dots(2)}$

Here 5a is the net force.

Adding (1) and (2),

$\sf{\longrightarrow T-50+50-T=10a+5a}$

$\sf{\longrightarrow15a=0}$

$\sf{\longrightarrow a=0}$

Then (1) becomes,

$\sf{\longrightarrow T-50=0}$

$\sf{\longrightarrow\underline{\underline{T=50\ N}}}$

Hence (b) is the answer.

Discussion

19.	The mass of the planet Saturn is 568.2×10^24 kg. Express this mass in terms of solar mass. 1 solar mass = 2*10^30 kg
Answer» Answer: 284.1 * 10^-6 SOLAR mass Explanation:

19.

The mass of the planet Saturn is 568.2×10^24 kg. Express this mass in terms of solar mass. 1 solar mass = 2*10^30 kg

Answer»

Answer:

284.1 * 10^-6 SOLAR mass

Explanation:

Discussion

20.	The frequency of a given region of the electromagnetic spectrum ranges from 3 × 1016 − 3 × 1019 hertz. Which type of wave is found in this region?A. x-raysB. ultraviolet raysC. infrared wavesD. radio waves
Answer» ANSWER: D iscmmsmkwkekwkdmdndkskkd

20.

The frequency of a given region of the electromagnetic spectrum ranges from 3 × 1016 − 3 × 1019 hertz. Which type of wave is found in this region?A. x-raysB. ultraviolet raysC. infrared wavesD. radio waves

Answer»

ANSWER:

D iscmmsmkwkekwkdmdndkskkd

Discussion

21.	A ballon filled with hydragon r ises in air give reason
Answer» Answer: A balloon FILLED with hydrogen rises to a certain HEIGHT and more weight of AIR is displaced than the weight of balloon. But as it rises higher, the density of air decreases and UPTHRUST becomes less and ultimately upthrust becomes equal to the weight of balloon and it stops riding further.

21.

A ballon filled with hydragon r ises in air give reason

Answer»

Answer:

A balloon FILLED with hydrogen rises to a certain HEIGHT and more weight of AIR is displaced than the weight of balloon. But as it rises higher, the density of air decreases and UPTHRUST becomes less and ultimately upthrust becomes equal to the weight of balloon and it stops riding further.

Discussion

22.	Two sound waves traveling in the same medium interfere with each other. The compression of one wave falls on the compression of the other wave. What can you say about the resultant sound?A. The resultant sound will be louder than the individual sound waves.B. The resultant sound will be lower than the individual sound waves.C. The resultant sound will have the same loudness as the individual sound waves.D. The resultant sound will not be heard at all.
Answer» ANSWER: I THINK that OPTION C is the WRITE answer

22.

Two sound waves traveling in the same medium interfere with each other. The compression of one wave falls on the compression of the other wave. What can you say about the resultant sound?A. The resultant sound will be louder than the individual sound waves.B. The resultant sound will be lower than the individual sound waves.C. The resultant sound will have the same loudness as the individual sound waves.D. The resultant sound will not be heard at all.

Answer»

ANSWER:

I THINK that OPTION C is the WRITE answer

Discussion

23.	1) Draw a ray diagram for which an enlarged real and inverted image is formed by concave mirror
Answer» HOPE it helps you plz make my ANSWER as brilliant

23.

1) Draw a ray diagram for which an enlarged real and inverted image is formed by concave mirror

Answer»

HOPE it helps you

plz make my ANSWER as brilliant

Discussion

24.	Body is& PhysicarNece ton's 1st lawstates that "It amitially at test it will continue to be atrest and initiallyinitially moving then itcontinuemation with constantvelocitye. it F =0 thenthen ã o fif ā=0then athis law Valid in all Frames ofre Frences ?-s
Answer» EXPLANATION: The laws of PHYSICS are same in all inertial frames of references. In fact, if it we find a "law" which is not so, we believe it is not a FUNDAMENTAL law. Had the laws been different, there WOULD be no GUARANTEE that the ball would fall back. But, of course that is not true.

24.

Body is& PhysicarNece ton's 1st lawstates that "It amitially at test it will continue to be atrest and initiallyinitially moving then itcontinuemation with constantvelocitye. it F =0 thenthen ã o fif ā=0then athis law Valid in all Frames ofre Frences ?-s

Answer»

EXPLANATION:

The laws of PHYSICS are same in all inertial frames of references. In fact, if it we find a "law" which is not so, we believe it is not a FUNDAMENTAL law. Had the laws been different, there WOULD be no GUARANTEE that the ball would fall back. But, of course that is not true.

Discussion

25.	derive an expression for speed of longitudinal wave based on newtons assumption. also give laplaces correction for the same
Answer» ANSWER: ok Explanation:

25.

derive an expression for speed of longitudinal wave based on newtons assumption. also give laplaces correction for the same

Answer»

ANSWER:

ok

Explanation:

Discussion

26.	Which type of wall would make the best soundproofing for room?A. 1.0 centimeter thick glassB. two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between themC. two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between themD. 1.0 centimeter thick steel
Answer» Answer: Type X drywall is meant for fire-resistance, but since it's denser than standard drywall, it also stops sound better, especially when used with resilient CHANNEL. ACOUSTICAL sealant is available at drywall SUPPLIERS, but silicone CAULK found at home centers is also a good CHOICE for sound proof caulk.

26.

Which type of wall would make the best soundproofing for room?A. 1.0 centimeter thick glassB. two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between themC. two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between themD. 1.0 centimeter thick steel

Answer»

Answer:

Type X drywall is meant for fire-resistance, but since it's denser than standard drywall, it also stops sound better, especially when used with resilient CHANNEL. ACOUSTICAL sealant is available at drywall SUPPLIERS, but silicone CAULK found at home centers is also a good CHOICE for sound proof caulk.

Discussion

27.	PLEASE HELP!!! Which statement best explains that sound waves are pressure waves?A. Sound waves have regions of compressions and rarefactions.B. Sound waves cannot propagate through metals.C. Sound waves move perpendicular to the medium particles.D. Sound waves cannot propagate through water.
Answer» Answer: A. SOUND WAVES have regions of COMPRESSIONS and RAREFACTIONS.

27.

PLEASE HELP!!! Which statement best explains that sound waves are pressure waves?A. Sound waves have regions of compressions and rarefactions.B. Sound waves cannot propagate through metals.C. Sound waves move perpendicular to the medium particles.D. Sound waves cannot propagate through water.

Answer»

Answer:

A. SOUND WAVES have regions of COMPRESSIONS and RAREFACTIONS.

Discussion

28.	Solve this please ✿ Help me✅✿ No spam ☺️✿ Thank You✨✿ ❤️
Answer» ANSWER: QUESTION 63) a) Uniform MOTION b) rest c) Don't know.Sorry. d) ACCELERATORY Motion

28.

Solve this please ✿ Help me✅✿ No spam ☺️✿ Thank You✨✿ ❤️

Answer»

ANSWER:

QUESTION 63)

a) Uniform MOTION

b) rest

c) Don't know.Sorry.

d) ACCELERATORY Motion

Discussion

29.	A velocity-time graph to represent an object traveling with uniform velocity
Answer» Velocity-TIME graph of an object MOVING with uniform velocity. The slope of a Velocity–time graph of an object moving in rectilinear motion with uniform velocity is straight LINE and PARALLEL to x-axis when velocity is taken along y-axis and time is taken along x-axis. i hope this answer help you mark as brainlist thank you ❤

29.

A velocity-time graph to represent an object traveling with uniform velocity

Answer»

Velocity-TIME graph of an object MOVING with uniform velocity. The slope of a Velocity–time graph of an object moving in rectilinear motion with uniform velocity is straight LINE and PARALLEL to x-axis when velocity is taken along y-axis and time is taken along x-axis.

i hope this answer help you

mark as brainlist

thank you ❤

Discussion

30.	Define velocity and average velocity__________________Hii koi onli.ne hai kya ?
Answer» ANSWER: The velocity of an object is the rate of change of its position with RESPECT to a frame of REFERENCE, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion. Other units: mph, ft/s In SI BASE units: m/s Dimension: L T−1

30.

Define velocity and average velocity__________________Hii koi onli.ne hai kya ?

Answer»

ANSWER:

The velocity of an object is the rate of change of its position with RESPECT to a frame of REFERENCE, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion.

Other units: mph, ft/s

In SI BASE units: m/s

Dimension: L T−1

Discussion

31.	The force applied on a nail by a hammer is 1 N. The ends of the nail are 20 m^2 and 0.2 m^2. What are the force and pressure at the tip of the nail?
Answer» Explanation: PRESSURE = FORCE ÷ area 1N ÷ 20m² pressure = 0.05 at the tip of the NAIL means in 1 nail pressure = force ÷ area 1N ÷ 0.2m² pressure = 5 at the tip of the nail means in 1 nail

31.

The force applied on a nail by a hammer is 1 N. The ends of the nail are 20 m^2 and 0.2 m^2. What are the force and pressure at the tip of the nail?

Answer»

Explanation:

PRESSURE = FORCE ÷ area

1N ÷ 20m²

pressure = 0.05 at the tip of the NAIL means in 1 nail

pressure = force ÷ area

1N ÷ 0.2m²

pressure = 5 at the tip of the nail means in 1 nail

Discussion

32.	How much force is needed to pull an object of mass 40kg in vertically upward direction with acceleration of 2.2meter per second square
Answer» EXPLANATION: here is your answer please MARK me as BRAINLIEST

32.

How much force is needed to pull an object of mass 40kg in vertically upward direction with acceleration of 2.2meter per second square

Answer»

EXPLANATION:

here is your answer

please MARK me as BRAINLIEST

Discussion

33.	A bar magnet of mass 120 g, in the form of a rectangular parallelepiped, has dimensions1= 40 mm, b= 10 mm and h= 80 mm. With the dimension h vertical, the magnet performsangular oscillations in the plane of a magnetic field with period i s. If its magnetic momentis 3.4 A m?, determine the influencing magnetic field.
Answer» ANSWER: The moment of inertia of the magnet about the AXIS of rotation is . We have, … (i) or, T ...(ii) Dividing by equation (i), or, EXPLANATION: *This* *answer* *HELPFUL* *for* u *MARK* *has* *brainlist* or follow me *please* *Thanks*

33.

A bar magnet of mass 120 g, in the form of a rectangular parallelepiped, has dimensions1= 40 mm, b= 10 mm and h= 80 mm. With the dimension h vertical, the magnet performsangular oscillations in the plane of a magnetic field with period i s. If its magnetic momentis 3.4 A m?, determine the influencing magnetic field.

Answer»

ANSWER:

The moment of inertia of the magnet about the AXIS of rotation is

.
We have,

… (i)
or,

T

...(ii)
Dividing by equation (i),

or,

EXPLANATION:

This answer HELPFUL for u

MARK has brainlist or follow me please

Thanks

Discussion

34.	Derive Newton's formula using convex lens in detail and proper explanation.
Answer» Explanation: Lens maker's formula relates the focal length, RADII of curvature of the curved surfaces, and the REFRACTIVE INDEX of the transparent material. The formula is used to construct lenses with DESIRED focal lengths

34.

Derive Newton's formula using convex lens in detail and proper explanation.

Answer»

Explanation:

Lens maker's formula relates the focal length, RADII of curvature of the curved surfaces, and the REFRACTIVE INDEX of the transparent material. The formula is used to construct lenses with DESIRED focal lengths

Discussion

35.	Differences between types of energy and forms of energy
Answer» Answer: POTENTIAL ENERGY comes in forms that are stored, including - Chemical, Gravitational and Nuclear. Kinetic energy forms are doing work - Like ELECTRICAL, heat, LIGHT, motion and sound. Difference between them both are, Potential energy can be stored and Kinetic energy is already doing work and can't be stored. hope it helps u:)

35.

Differences between types of energy and forms of energy

Answer»

Answer:

POTENTIAL ENERGY comes in forms that are stored, including - Chemical, Gravitational and Nuclear. Kinetic energy forms are doing work - Like ELECTRICAL, heat, LIGHT, motion and sound. Difference between them both are, Potential energy can be stored and Kinetic energy is already doing work and can't be stored.

hope it helps u:)

Discussion

36.	What are the applications of resistivity of conductors in daily life on heating elements and electrical wiring at home (fuse and connecting wires)?
Answer» ANSWER: Insulators work as protectors. They may protect heat, sound and the passage of electricity. THERMAL insulators, sound insulators and electrical insulators are used for various reasons, from keeping houses WARM to protecting electrical WIRES and SOUNDPROOFING rooms.

36.

What are the applications of resistivity of conductors in daily life on heating elements and electrical wiring at home (fuse and connecting wires)?

Answer»

ANSWER:

Insulators work as protectors. They may protect heat, sound and the passage of electricity. THERMAL insulators, sound insulators and electrical insulators are used for various reasons, from keeping houses WARM to protecting electrical WIRES and SOUNDPROOFING rooms.

Discussion

37.	A battery of e.m.f. 2000 V is connected in series with an inductance of 10 mH, acapacitor of capacity 0.05 microfarad and a resistance 100 ohm. Is the circuitoscilatory. If it is oscillatory, find the frequency of oscillation.
Answer» ANSWER: Explana TION :

37.

A battery of e.m.f. 2000 V is connected in series with an inductance of 10 mH, acapacitor of capacity 0.05 microfarad and a resistance 100 ohm. Is the circuitoscilatory. If it is oscillatory, find the frequency of oscillation.

Answer»

ANSWER:

Explana TION :

Discussion

38.	A) The mean speed of the molecules of an ideal gas is 2.0 x 103 ms. The radiusof a gas molecule is 1.5 x 10-10m. Calculate the (i) collision frequency, and(ii) mean free path. It is given that n = 4 x 1024 m-3
Answer» Given : The MEAN speed of the molecules of an ideal gas is $<klux>2</klux>.0 \times 10^3$ ms. i.e V = $2.0 \times 10^3$ The radius of a gas molecule is $1.5 \times 10^{-10}$ m. i.e. r = $n = 4 \times 10^{24} m^3$ To find: 1) Collision frequency gas of molecules of an ideal gas? 2) mean free path of an ideal gas? Step to step explanation: 1) The collision frequency gas of molecules of an ideal : $\displaystyle {z= 4\pi r^2nv}$ z = 4 × 3.14 × $1.5 \times 10^{-10}$ × $1.5 \times 10^{-10}$ × $4 \times 10^{24}$ × $2.0 \times 10^3$ z = 2.26 × $\mahbf {10^9}$ $\mathbf hz$ 2) The mean free path of an ideal gas : $\displaystyle \lambda = \frac{1}{4\pi r^2n}$ $\displaystyle \lambda = \frac{1}{4 \times \pi \times 1.5 \times 10^{-10} \times 1.5 \times 10^{-10} \times 4 \times 10^{24} }$ λ = 0.88 × $\displaystyle 10^{-6}$ m

38.

A) The mean speed of the molecules of an ideal gas is 2.0 x 103 ms. The radiusof a gas molecule is 1.5 x 10-10m. Calculate the (i) collision frequency, and(ii) mean free path. It is given that n = 4 x 1024 m-3

Answer»

Given :

The MEAN speed of the molecules of an ideal gas is $<klux>2</klux>.0 \times 10^3$ ms.

i.e V = $2.0 \times 10^3$

The radius of a gas molecule is $1.5 \times 10^{-10}$ m.

i.e. r =

$n = 4 \times 10^{24} m^3$

To find:

1) Collision frequency gas of molecules of an ideal gas?

2) mean free path of an ideal gas?

Step to step explanation:

1) The collision frequency gas of molecules of an ideal :

$\displaystyle {z= 4\pi r^2nv}$

z = 4 × 3.14 × $1.5 \times 10^{-10}$ × $1.5 \times 10^{-10}$ × $4 \times 10^{24}$ × $2.0 \times 10^3$

z = 2.26 × $\mahbf {10^9}$ $\mathbf hz$

2) The mean free path of an ideal gas :

$\displaystyle \lambda = \frac{1}{4\pi r^2n}$

$\displaystyle \lambda = \frac{1}{4 \times \pi \times 1.5 \times 10^{-10} \times 1.5 \times 10^{-10} \times 4 \times 10^{24} }$

λ = 0.88 × $\displaystyle 10^{-6}$ m

Discussion

39.	See the attached doc.
Answer» ANSWER: R=rhol/a R=310^-4l/pie r^2 R=310^-4l/pie(10^-3)^2 2=3l/pie l=6pies

39.

See the attached doc.

Answer»

ANSWER:

R=rho*l/a

R=3*10^-4*l/pie r^2

R=3*10^-4*l/pie(10^-3)^2

2=3*l/pie

l=6pies

Discussion

40.	Lightwaves travel from the air into a lens made of glass. Their velocity decreases as they enter the glass. How does this affect the frequency and wavelength of the lightwaves?A. Their frequency stays the same and their wavelength increases.B. Their frequency stays the same and their wavelength decreases.C. Their frequency increases and their wavelength decreases.D. Their frequency decreases and their wavelength increases.
Answer» ANSWER: B) their FREQUENCY stays the same and their wavelength decrease Explanation: because VELOCITY of LIGHT is directly proportional to the wavelength of light. so when velocity decrease then the wavelength also decrease. thank you.

40.

Lightwaves travel from the air into a lens made of glass. Their velocity decreases as they enter the glass. How does this affect the frequency and wavelength of the lightwaves?A. Their frequency stays the same and their wavelength increases.B. Their frequency stays the same and their wavelength decreases.C. Their frequency increases and their wavelength decreases.D. Their frequency decreases and their wavelength increases.

Answer»

ANSWER:

B) their FREQUENCY stays the same and their wavelength decrease

Explanation:

because VELOCITY of LIGHT is directly proportional to the wavelength of light. so when velocity decrease then the wavelength also decrease.

thank you.

Discussion

41.	A. Fill in the blanks with suitable words.1. Density of iron is dess than thedensity of water.
Answer» ANSWER: DENSITY of IRON is dess than the density of water.

41.

A. Fill in the blanks with suitable words.1. Density of iron is dess than thedensity of water.

Answer»

ANSWER:

DENSITY of IRON is dess than the

density of water.

Discussion

42.	27 °c উষ্ণতায় ও 570 mm পারদস্তম্ভের চাপে 2.2 g কার্বন ডাই অক্সাইডের আয়তন
Answer» Answer: 27 °c উষ্ণতায় ও 570 MM ... চাপে 2.2 G কার্বন ডাই অক্সাইডের আয়তন

42.

27 °c উষ্ণতায় ও 570 mm পারদস্তম্ভের চাপে 2.2 g কার্বন ডাই অক্সাইডের আয়তন

Answer»

Answer:

27 °c উষ্ণতায় ও 570 MM ... চাপে 2.2 G কার্বন ডাই অক্সাইডের আয়তন

Discussion

43.	) Explain the relation between the e.m.f of a cell (E) and the potential difference between its terminals (V)
Answer» Answer: UC if if to us if to Oz so if so is at St in HI ya to gaucho in in in in on on in was EX tv in in on pl pl in on Rd ea was ex av week wo woo woo woo woo woo woo woo woo woo dip so all FL dj CM

43.

) Explain the relation between the e.m.f of a cell (E) and the potential difference between its terminals (V)

Answer»

Answer:

UC if if to us if to Oz so if so is at St in HI ya to gaucho in in in in on on in was EX tv in in on pl pl in on Rd ea was ex av week wo woo woo woo woo woo woo woo woo woo dip so all FL dj CM

Discussion

44.	A force of 200N is applied on a 10kg box across a frictionless surface.A. What is the acceleration of the box?B. If the box accelerates from rest, what will its final speed be after 8 seconds?C. How long will it take the box to reach a speed of 500m/s if it continues to accelerate at this rate?
Answer» ANSWER: ACCELERATION of BOX 4MS`2

44.

A force of 200N is applied on a 10kg box across a frictionless surface.A. What is the acceleration of the box?B. If the box accelerates from rest, what will its final speed be after 8 seconds?C. How long will it take the box to reach a speed of 500m/s if it continues to accelerate at this rate?

Answer»

ANSWER:

ACCELERATION of BOX 4MS`2

Discussion

45.	Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?A. visible light, gamma rays, infrared rays, x-rays, ultraviolet raysB. infrared rays, visible light, ultraviolet rays, x-rays, gamma raysC. gamma rays, x-rays, ultraviolet rays, visible light, infrared raysD. ultraviolet rays, visible light, gamma rays, x-rays, infrared rays
Answer» Answer: INFRARED rays, VISIBLE LIGHT, ultraviolet rays, x-rays, GAMMA rays

45.

Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?A. visible light, gamma rays, infrared rays, x-rays, ultraviolet raysB. infrared rays, visible light, ultraviolet rays, x-rays, gamma raysC. gamma rays, x-rays, ultraviolet rays, visible light, infrared raysD. ultraviolet rays, visible light, gamma rays, x-rays, infrared rays

Answer»

Answer:

INFRARED rays, VISIBLE LIGHT, ultraviolet rays, x-rays, GAMMA rays

Discussion

46.	Consider the charges q,q,-q lies at the vertices of an equilateral triangle.what is the force on it's charge
Answer» Answer: hi Explanation: CONSIDER the CHARGES Q,q,-q lies at the VERTICES of an equilateral triangle.what is the force on it's CHARGE

46.

Consider the charges q,q,-q lies at the vertices of an equilateral triangle.what is the force on it's charge

Answer»

Answer:

hi

Explanation:

CONSIDER the CHARGES Q,q,-q lies at the VERTICES of an equilateral triangle.what is the force on it's CHARGE

Discussion

47.	Identify the correct option that contains group - \| elements arranged in the increasing order of their atomic number,1..Li, Na, K, Rb, Fr2..Be, Mg, Ca, Sr, Ra3..Fr, Rb, K, Na, Li4..F, CI, Br, I, Atplease answer
Answer» ANSWER: OPTION 1 is CORRECT answer

47.

Identify the correct option that contains group - | elements arranged in the increasing order of their atomic number,1..Li, Na, K, Rb, Fr2..Be, Mg, Ca, Sr, Ra3..Fr, Rb, K, Na, Li4..F, CI, Br, I, Atplease answer

Answer»

ANSWER:

OPTION 1 is CORRECT answer

Discussion

48.	Write the electronic configuration of the element
Answer» ANSWER: sodium = 2 ,8,1 CARBON DIOXIDE = 2 ,4

48.

Write the electronic configuration of the element

Answer»

ANSWER:

sodium = 2 ,8,1

CARBON DIOXIDE = 2 ,4

Discussion

49.	Which statement best describes the superposition principle?A. If two in-phase waves arrive simultaneously at a point, their amplitudes add up.B. If two out-of-phase waves arrive simultaneously at a point, their amplitudes add up.C. If two in-phase waves arrive at a point one after another, their amplitudes add up.D. If two out-of-phase waves arrive at a point one after the other, their amplitudes adds up.
Answer» ANSWER: I THINK B is CORRECT answer THANKS

49.

Which statement best describes the superposition principle?A. If two in-phase waves arrive simultaneously at a point, their amplitudes add up.B. If two out-of-phase waves arrive simultaneously at a point, their amplitudes add up.C. If two in-phase waves arrive at a point one after another, their amplitudes add up.D. If two out-of-phase waves arrive at a point one after the other, their amplitudes adds up.

Answer»

ANSWER:

I THINK B is CORRECT answer

THANKS

Discussion

50.	draw the distance time graph with given observation and answer the following questions? time (sec.)/distance (meter)0/2,1/4,2/6,3/6,4/6,5/12,6/14?Q.1)which part of the graph show uniform speed?Q.2) which part of the graph show object at rest?
Answer» ANSWER: which CLASS which subject Explanation: PLEASE FOLLOW

50.

draw the distance time graph with given observation and answer the following questions? time (sec.)/distance (meter)0/2,1/4,2/6,3/6,4/6,5/12,6/14?Q.1)which part of the graph show uniform speed?Q.2) which part of the graph show object at rest?

Answer»

ANSWER:

which CLASS which subject

Explanation:

PLEASE FOLLOW

Discussion

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