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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Hiiiiiiiiiiiiiiiiiiiiiiiiiii ❗❗❗:Plz answer kr dena: How can metals have free electrons when the force of attraction present in metals is so strong?(It's confusing me a lot, pls help me out) |
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Answer» Answer: Electron are EXTREMELY extremely small. Metals are HARD because of the intermolecular force of ATTRACTION between the atoms not the electrons. Metal have free electrons means the electron can MOVE out from the atoms to take part in the conduction of electricity. Hope you got your doubt cleared :)✌️ |
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| 2. |
What is solid angle |
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Answer» Answer: In geometry, a SOLID ANGLE (symbol: Ω) is a measure of the amount of the field of view from some particular point that a given object COVERS. That is, it is a measure of how LARGE the object appears to an observer looking from that point |
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| 3. |
Points remember in gauss theorem |
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Answer» As the electric FIELD is perpendicular to every point of the curved surface, we can say that its magnitude will be constant. You need to remember that the DIRECTION of the electric field is RADIALLY outward if linear charge density is positive. |
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| 4. |
3. A boy starts running from his house with a uniform speed and takes 1 hour to reach the playsdistance between his house and the playground is 3.6 km, calculate his speed in (i) km/h, (ii) |
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Answer» Answer: 3.6km/h Explanation: |
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| 5. |
Write about gaussian surface |
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Answer» Answer: Gaussian surface is defined as a closed surface in a THREE dimensional SPACE through which the MAGNETIC flux of any type of vector field can be found; this includes the electric field, the GRAVITATIONAL field, or magnetic field. |
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| 6. |
Can I know this question come from which book . |
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| 7. |
A particle moves with constant speed v along a circular path of radius r and completes the circlein time T. The acceleration of the particle is |
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Answer» Answer: |
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| 8. |
What is the application of gauss theorem |
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Answer» the APPLICATION of GAUSS THEORM is force is applied on an OBJECT with gravitational constant |
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| 9. |
a wheel rotating at 200 rpm can just raise a 40 kg mass through 3 m before coming to rest .calculate the moment of inertia of the wheel |
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Answer» p=mv p=40*200 p=8000 momentum=8000 |
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| 10. |
The magnitude of vector product of two units vector making an angel of 60 with each other is |
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Answer» √3is the answer.......... |
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| 11. |
Wt to exactly do in this sum??? |
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Answer» Answer: This is a PROBLEM RELATED to dimensions. As per dimensions RULES, the dimensions of the power should be dimensionless. So the CORRECT option should be option b. |
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| 12. |
Find the angle b/w a=i +2j -k and vector B=-i+j-2k |
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| 13. |
Two masses of 5kg and 10kg connected by a massless string passing over a frictionless pulley are in static equilibrium as shown in the figure. One of the mass is resting on the surface. Find:-1) Tension in the string.2)Normal reaction on the 10kg block. |
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Answer» what is THUNDER??~~??????? |
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| 14. |
A particle moves with constant spoed v along a circular path of radius r and completes the circlein Time T. The acceleration of the particle is: |
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Answer» the same to DOWNLOAD it is BEST FRIEND and I don't have to download it is the one of the same to download it is best you want to download it is best |
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| 15. |
Diagram save the tree |
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Answer» save TREES Explanation: save trees as they GIVE OXYGEN save trees as they feed US |
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| 16. |
Prove that |A|^2|B|^2=|A×B|^2+|A.B|^2 |
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Answer» this OBEYS COMMUTATIVE LAW |
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| 17. |
Explanation about friction |
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Answer» Answer: Explanation: FRICTION is the RESISTANCE to MOTION of one object moving relative to ANOTHER. |
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| 18. |
Is it possible for an object to move with constant acceleration but with zero velocity |
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Answer» no Explanation: |
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| 19. |
The net resistance of two resistors in parallelcombination is 2 2 and in series combination is |
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Answer» Answer: Explanation: In parallel: 1/R= 1/6 +1/3 1/R= (1+2)/6 1/R= 3/6 R=2 ohm In SERIES: R= 6+3 R= 9 ohm |
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| 20. |
A condector of length l is connected to a dc source of emf e. If this condector is replased by another condector of some material and some area of cross - section but of length 3l ,how will the drift velocity change? |
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Answer» not know☁☁☁☁☁☁ ☁☁☁ ☁☁☁☁ ☁☁☁☁☁☁ ☁☁☁☁☁☁ ☁☁☁☁☁☁ ☁☁☁☁☁☁ ☁☁☁☁☁ ☁☁ ☁☁ ☁☁☁☁ |
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| 21. |
Find the disadvantages of friction in our daily life and suggest remedy |
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Answer» - it PRODUCES WEAR ANDANTE TEAR - |
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| 22. |
during rainy season 31 noted that the thundering sound of cloud was heard 6 second after the lightning was seen by him if speed of sound in air is 340 minut per second find the distance of the point where the thundering sound was produced |
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Answer» Let LIGHTNING be seen at t=0 second then the thunder is heard 6 secs LATER, i.e , at t=6 seconds Thunder Sound Speed = 340 m/s Time = t=6 secs Therefore DISTANCE = Speed × Time The distance of the point where the thundering sound was produced = 340 × 6 = 2040 m = 2.04 km Hope this helps ... All The BEST !! |
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| 23. |
Is the micrometer screw gauge used for measurement of inner diameter of tube |
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| 24. |
Find acceleration due to gravity at the height of 2800km from surface of earth radius 6400km |
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Answer» Explanation:9.8hanku |
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| 25. |
Derivation of self inductance dimensional formula |
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Answer» Explanation: It UNIT of self induction is henry (H) and its dimensional formula is [ML2T -2A-2]. A = area of cross-section of the coil. The phenomena of production of induced emf in a CIRCUIT due to the change in MAGNETIC flux in itsneighbouring circuit, is called mutualinduction. pls mark as brainliest |
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| 26. |
Why electrolytic reduction is done to obtain aluminium? |
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| 27. |
Why electric field lines does not exist in a conduxtor? |
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Answer» Explanation: As such, the LINES are DIRECTED away from positively charged source CHARGES and toward negatively charged source charges. ... As electric FIELD lines can be drawn at a point only if there is non zero electric field so no electric field enters the solid part of the conductor where the field is 0… |
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| 28. |
Difference between yield and ultimate |
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Answer» Explanation: The material then becomes strain hardened until you reach the ultimate STRENGTH and necking starts to OCCUR and the material becomes WEAKER again until it breaks apart. YIELD stress is the stress at which that the material deforms permanently, ultimate tensile stress is the stress at which it breaks. |
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| 29. |
A ball of mass 50 g is thrown vertically upwarwith an initial velocity 20 m s-1. Calculate :(i) the initial kinetic energy imparted to the balii) the maximum height reached if air frictionneglected, andiii) the maximum height reached if 40% of timeinitial energy is lost against the air friction. |
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Answer» Answer: the photo above is the answer of I) 2) GIVEN that, m=0.05 and v=20m/s 1 Maximum potential energy at highest point= Initial kinetic energy at the BOTTOM point ∴Maximum potential energy = 2 1 mv 2 = 2 1 ×0.5×20×20 = 2 200 =100J
3) Given that, m=0.05 and v=20m/s 1
Maximum potential energy at highest point= Initial kinetic energy at the bottom point ∴Maximum potential energy = 21 mv 2 = 21×0.5×20×20= 2200 =100J
HOPE this helps plz mark me as brainliest answer |
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| 30. |
Speech about mother teresa in telugu |
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Answer» మదర్ తెరిసా ఈ పేరు వినగానే అందరికీ మాతృత్వం గుర్తుకు వస్తూ ఉంటుంది. ఈమె ఎనలేని సేవలు మనకి మానవత్వం అంటే ఏమిటో గుర్తు చేస్తుంది. ఈ మధ్యకాలంలోనే రోమన్ కాతలిక్ చర్చ్ కలకత్తా వారు మదర్ తెరిసా సెంట్ తెరిస్సా అని బిరుదునిచ్చి సత్కరించారు. ఈమె సహనానికి సేవకి మారుపేరు. ఈమె కుష్టు వారి కోసం ఎన్నో సంస్థలను ఏర్పాటు చేసి వారి వ్యాధులను నయం చేయటానికి ఎన్నో మార్గాలు ప్రయత్నిస్తూ ఒక పెద్ద ఆర్గనైజేషన్ ని నడుపుతూ ఇప్పుడు ఆమె లేనప్పుడు కూడా దానికి ఏ లోటూ లేకుండా చూసుకునే టట్టు అన్ని బాధ్యతలు నిర్వహించారు. |
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| 31. |
9. A bullet of mass m is fired with velocity v in a large bulk of mass M. The final velocity will be(a) Mv/m+M(b) mv/m+M(c) (m+ M)v/m(d) (m + M) v |
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| 32. |
A string breaks under a load of 4.8 kg. A mass of 0.5 kg is attached to one end of the string 2 m longand is rotated in horizontal circle. Calculate the greatest number of revolutions that the mass can makewithout breaking the string.the string |
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Answer» Answer: The answer will be 66.12 RPM Explanation: According to the problem the load WEIGHT is 4.8 kg The mass is attached with the STRING having length of 2 m Now as the mass is rotating in horizontal circle, Then let the value of mass , m =0.5 kg and the radius of the circle is , r = 2m Let a tension T is acting in the center Therefore, T = mrω^2 [ where ω is the angular VELOCITY] Now we know ω = 2 πf Therefore, T = MR(2 πf)^2 Now from here if we calculate f f = √ T /mr x 4 π^2 Here T = 4.8 kg wt = 4.8 x 9.8 N f = √4.8 x 9.8 / 0.5 x 2 x 4 x 9.87 = 1.102 revolutions per second = 66.12 rpm |
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| 33. |
What is the formula of force |
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Answer» ANSWER:FORCE = MASS × ACCELERATION F = m ×a Explanation: |
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| 34. |
For a particle moving along a straight line its velocity v and displacement x are related as v^2 = cs. Where c is constant. If the displacement of particle at t= 0 is zero its velocity after 2 sec is (A) c/2 (b) c (c) 2c (d) 4c |
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Answer» Answer: (B) APPLY INTEGRATION to solve |
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| 35. |
A particle is dropped under gravity from rest from aheight h(g=9.8 m/sec) and it travels a distance 9h/25 inthe last second, the height h is(a) 100 m(b) 122.5 m(c) 145 m(d) 167.5 m(11 |
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Answer» B) |
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| 36. |
4. The wavelength of light in air is 5000 A.U. The numberof waves in 50 cm of air is |
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Answer» Answer: Speed of light in AIR is 3*10^8 m/s W = WAVELENGTH N =REFRACTIVE index of the medium =1.5 W in air =5000 A =5*10^-7 Metres FREQUENCY in air is 5*10^14 hz So answer is 3000 A |
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| 37. |
A 2kg stone at the end of a string 1 m long is whirled in a vertical circle at a constant speed. Thespeed of the stone is 4m/sec. The tension in the string will be 52N, when the stone is |
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Answer» Answer: Here MAXM TENSION When String is vertically DOWNWARD and is equal to mv^2/R + mg = 2*4*4/1 + 2*10 = 52 so string is vertically Downward |
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| 38. |
Information about the substances using to reduce friction |
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Answer» SOME POINTS I KNOW ARE: Explanation: 1 . By polishing the SURFACE 2 .By lubricating the surfaces with oil,grease and paint 3 .By STREAMLINING to reduce FLUID friction 4 .By USING wheels and ball bearings..... I THINK IT WILL HELP U |
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| 39. |
Value of one persec |
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Answer» EXPLANATION: 1 parsec is equals to 3.26 LIGHT years Value of 1 parsec is equals to 3.086 x 10^16 METRES |
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| 40. |
PLEASE HELP IMMEDIATELYFind the magnitude of pressure in Pascal of 150N that acts normally on area of 0.25m². |
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Answer» Answer: Explanation: PRESSURE = Force / area P = 150/0.25 P = 600 pa |
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| 41. |
What is Newton's pulley and string tricks |
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Answer» Explanation: Firstly, the tension T1 and T2 is equal only when the pulley and the rope are MASSLESS. ... Also, if the rope is not massless, the tension will also be DIFFERENT. Imagine each PART of the rope then acts as a MASS. Then the tension is not the same EVERYWHERE in the rope. |
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| 42. |
two plane mirror are inclined at angle 40°between them . Number of image seen of a tiny kept between them is _____________ |
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Answer» |
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| 43. |
What do you mean by power lens? |
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Answer» Explanation: Power of lens is the ABILITY of the lens to converge the rays of light falling on it. It can also be defined as P=1/F where f is the focal length. ... Dioptre is the S I UNIT of power of lens. ONE Dioptre is the power of a lens whose focal length is 1 metre.Mar |
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| 44. |
PLEASE HELP ME THIS QUESTION FASTThe foot of an elephant has an area of 2200kg,find the pressure exerted by the elephant on the ground (acceleration due to gravity =10m/s²). |
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Answer» Answer: mg / (4A) Explanation: Pressure = Force / Area In given case force is equal to ¼ of weight of elephant (assuming weight of elephant is equally distributed to all the FOUR foots). If "m" is the MASS of elephant then, Pressure = (mg/4) / A Substitute the values and solve the pressure. Note: "....area of 2200 KG" doesn't makes any sense. kg is UNIT of mass. please check your QUESTION once. |
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| 45. |
Describe what is meant by significantfigures and order of magnitude. |
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Answer» ANSWER:It MEANS that the number come after 0 eg:0.05=1 SIGNIFICANT figures 3.05=3 significant figures Explanation: |
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| 46. |
Which is the largest animal in the world??????? |
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Answer» BLUE WHALE is the LARGEST ANIMAL in the world Explanation: |
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| 47. |
Calculate the current I in given circuit |
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| 48. |
Define concept of point mass in physics |
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Answer» Answer: A point MASS is an abstract point in SPACE where the entire mass of the object has been concentrated as it seems. SEE this is a requirement to do basic physics. For EXAMPLE a basketball. ... A singular point in space time where the entire mass of the ball is concentrated. |
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| 50. |
I want answer this is from physics |
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Answer» The answer is (C) hellooooo |
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