67486 + Interview Questions in Secondary School in Physics

1.	15 अधोलिखित धातु प्रत्ययं च पृथक कुरुत-आगत्य, श्रोतुम्, लिखित्वा, पतितः, करणीयम्, अल्यतरः, लघुत्तम, आदाय
Answer» Answer: euigdcv Explanation: hijrgv BD N is Di n SH HB sh b

1.

15 अधोलिखित धातु प्रत्ययं च पृथक कुरुत-आगत्य, श्रोतुम्, लिखित्वा, पतितः, करणीयम्, अल्यतरः, लघुत्तम, आदाय

Answer»

Answer:

euigdcv

Explanation:

hijrgv BD N is Di n SH HB sh b

Discussion

2.	Q.2. (c) 10kg of water falls through a height of 854m and all the energy is effective inheating the water. To what temperature will the water be raised if it was initially at 20 c?
Answer» EXPLANATION: nskdhdjdjdjddjxjznznznznznz

2.

Q.2. (c) 10kg of water falls through a height of 854m and all the energy is effective inheating the water. To what temperature will the water be raised if it was initially at 20 c?

Answer»

EXPLANATION:

nskdhdjdjdjddjxjznznznznznz

Discussion

3.	Give one word answerwhat is the term given to the resistance of a conductor having unit cross section area and unit length
Answer» Answer: ELECTRICAL resistance EXPLANATION: RESISTIVITY, electrical resistance of a conductor of unit cross-sectional AREA and unit LENGTH

3.

Give one word answerwhat is the term given to the resistance of a conductor having unit cross section area and unit length

Answer»

Answer:

ELECTRICAL resistance

EXPLANATION:

RESISTIVITY, electrical resistance of a conductor of unit cross-sectional AREA and unit LENGTH

Discussion

4.	- A wire of resistance R 22 is cut into 4 equal parts. These parts are thenconnected in parallel. The equivalent resistance of the combination will bewrong answer will deleted at i will cut your 50 points
Answer» Answer: 1.375R is the RESISTANCE when CONNECTED in PARALLEL.

4.

- A wire of resistance R 22 is cut into 4 equal parts. These parts are thenconnected in parallel. The equivalent resistance of the combination will bewrong answer will deleted at i will cut your 50 points

Answer»

Answer:

1.375R is the RESISTANCE when CONNECTED in PARALLEL.

Discussion

5.	5A ground level connon tives a projectile with an initialvelocity of 20√2 m/s tilted at a 45 angle. What is themaximum altitude reached by the bullet? (g = 10 m/s²)A) 20 B) can't answer c) 10m D) 40m E)2om
Answer» THEREFORE, the maximum height reached by the PROJECTILE is 20 m. Hope this helps you. Thank you for your question. Mark me as brainleist.

5.

5A ground level connon tives a projectile with an initialvelocity of 20√2 m/s tilted at a 45 angle. What is themaximum altitude reached by the bullet? (g = 10 m/s²)A) 20 B) can't answer c) 10m D) 40m E)2om

Answer»

THEREFORE, the maximum height reached by the PROJECTILE is 20 m.

Hope this helps you.

Thank you for your question.

Mark me as brainleist.

Discussion

6.	An object is placed 11.0 cm in front of the cornea. (The cornea is thin and has approximately parallelsides so that the reflection that occurs as light travels from air to cornea to aqueous humor isessentially the same as though the aqueous humor were directly in contact with the air, the aqueoushumor has index of refraction n=1.34 and the radius of curvature of cornea is 7.8 mm)a) what is the image distance for the image formed by cornea clone.b) the image formed by cornea serves as an object for the lens. treat the lens as a thin lens 6 mm behind cornea. find the optical power of thin lens necessary to have image on the retina, 20 mm from the center of the lens
Answer» ANSWER: huge\mathfrak\hello $huge\mathfrak\hello$

6.

An object is placed 11.0 cm in front of the cornea. (The cornea is thin and has approximately parallelsides so that the reflection that occurs as light travels from air to cornea to aqueous humor isessentially the same as though the aqueous humor were directly in contact with the air, the aqueoushumor has index of refraction n=1.34 and the radius of curvature of cornea is 7.8 mm)a) what is the image distance for the image formed by cornea clone.b) the image formed by cornea serves as an object for the lens. treat the lens as a thin lens 6 mm behind cornea. find the optical power of thin lens necessary to have image on the retina, 20 mm from the center of the lens

Answer»

ANSWER:

huge\mathfrak\hello

$huge\mathfrak\hello$

Discussion

7.	The resultant force acting ona body of mass 10 kg moving with uniform velocity of 2m/s is:-(a) 5N(b) 12N(c)20N (d) Zero
Answer» Answer: FORCE = mass into acceleration F =10*2 F = 20N

7.

The resultant force acting ona body of mass 10 kg moving with uniform velocity of 2m/s is:-(a) 5N(b) 12N(c)20N (d) Zero

Answer»

Answer:

FORCE = mass into acceleration

F =10*2

F = 20N

Discussion

8.	4. A 100g mass attached to end of suspendedspring stretches the spring by 3cm. If the massis replaced by 200g mass then the spring will bestretched further bya. 3cmb. 9cmc. 12cmd. 6cme. None14 h
Answer» Answer: 3 is the answer Explanation: MARK me as the BRAINLIEST

8.

4. A 100g mass attached to end of suspendedspring stretches the spring by 3cm. If the massis replaced by 200g mass then the spring will bestretched further bya. 3cmb. 9cmc. 12cmd. 6cme. None14 h

Answer»

Answer:

3 is the answer

Explanation:

MARK me as the BRAINLIEST

Discussion

9.	-A body of 5 kg mase possesses a momentum of 50 Ns, when it moves with the(d) 55 m/sspeed of:(a) 5 m/s(b) 10 m/s (c)20 m/s (d) 55 m/s
Answer» ANSWER: p=mv v v=p/m v = 10m/s is the answer

9.

-A body of 5 kg mase possesses a momentum of 50 Ns, when it moves with the(d) 55 m/sspeed of:(a) 5 m/s(b) 10 m/s (c)20 m/s (d) 55 m/s

Answer»

ANSWER:

p=mv

v

v=p/m

v = 10m/s is the answer

Discussion

10.	Questo NO. 31A small block of mass m is placed on a frictionless horizontal surface and connected to two massless springs of spring constant k and 2kas shown. The other ends of the springs are fixed to rigid walls. Initially, both springs are in their natural length. Now, the block is displacedby a small distance to the right and released. The time period of the resulting SHM is:2k2
Answer» Answer: 2Billion Explanation: $huge\mathfrak\hello$

10.

Questo NO. 31A small block of mass m is placed on a frictionless horizontal surface and connected to two massless springs of spring constant k and 2kas shown. The other ends of the springs are fixed to rigid walls. Initially, both springs are in their natural length. Now, the block is displacedby a small distance to the right and released. The time period of the resulting SHM is:2k2

Answer»

Answer:

2Billion

Explanation:

$huge\mathfrak\hello$

Discussion

11.	Derive expression for total inductance of a transmission line.subject is Power transmission line amd Distribution.
Answer» ANSWER: I q3stfugobpnl Explanation: q4w TY figucd5 FT 7g8c8c8g7

11.

Derive expression for total inductance of a transmission line.subject is Power transmission line amd Distribution.

Answer»

ANSWER:

I q3stfugobpnl

Explanation:

q4w TY figucd5 FT 7g8c8c8g7

Discussion

12.	Section-7 Find the focus and position of thelensby drawing a day diagramusing the position of object A and0loendH
Answer» Answer: I feel LIKE a GOOD PERSON to be with the PEOPLE I care

12.

Section-7 Find the focus and position of thelensby drawing a day diagramusing the position of object A and0loendH

Answer»

Answer:

I feel LIKE a GOOD PERSON to be with the PEOPLE I care

Discussion

13.	(24) द्रव व ठोस के किसी सम्पर्क-बिन्दु से द्रव के पृष्ठ पर खींची गई स्पर्श-रेखा तथा ठोस के पृष्ठपर द्रव के अन्दर की ओर खींची गई स्पर्श-रेखा के बीच बने कोण को उस ठोस तथा द्रव के लिएThe angle inside the liquid between the tangent to the solid surface andthe tangent to the liquid surface at the point of contact is calledfor that pair of solid and liquid.
Answer» ANSWER: (24) द्रव व ठोस के किसी सम्पर्क-बिन्दु से द्रव के पृष्ठ पर खींची गई स्पर्श-रेखा तथा ठोस के पृष्ठ पर द्रव के अन्दर की ओर खींची गई स्पर्श-रेखा के बीच बने कोण को उस ठोस तथा द्रव के लिए The angle inside the LIQUID between the tangent to the solid SURFACE and the tangent to the liquid surface at the point of contact is called for that pair of solid and liquid.

13.

(24) द्रव व ठोस के किसी सम्पर्क-बिन्दु से द्रव के पृष्ठ पर खींची गई स्पर्श-रेखा तथा ठोस के पृष्ठपर द्रव के अन्दर की ओर खींची गई स्पर्श-रेखा के बीच बने कोण को उस ठोस तथा द्रव के लिएThe angle inside the liquid between the tangent to the solid surface andthe tangent to the liquid surface at the point of contact is calledfor that pair of solid and liquid.

Answer»

ANSWER:

(24) द्रव व ठोस के किसी सम्पर्क-बिन्दु से द्रव के पृष्ठ पर खींची गई स्पर्श-रेखा तथा ठोस के पृष्ठ

पर द्रव के अन्दर की ओर खींची गई स्पर्श-रेखा के बीच बने कोण को उस ठोस तथा द्रव के लिए

The angle inside the LIQUID between the tangent to the solid SURFACE and

the tangent to the liquid surface at the point of contact is called

for that pair of solid and liquid.

Discussion

14.	How do the school and community resources contribute to the safety program of the individual from the risk factors of injury and emergency
Answer» $\huge \fbox \purple{✿Answer:}$ Preventing School Injuries: • Establish playground SAFETY rules (such as no pushing, crowding, or shoving) with CONSEQUENCES for breaking rules. • ALWAYS have trained adult SUPERVISORS present who. • Develop a playground inspection and equipment maintenance checklist. • Schedule regular inspections and promptly repair broken playground equipment. Preventing Community • Asocial environment that promotes safety; • A SAFE physical environment; • Health education curricula and instruction; • Safe physical education, sports, and recreational activities; • Health, counseling, psychological, and social services for students; • Appropriate crisis and emergency response; • Involvement of families and communities; and Staff development to promote safety and Prevent unintentional injuries, violence, and suicide. $\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

14.

How do the school and community resources contribute to the safety program of the individual from the risk factors of injury and emergency

Answer»

$\huge \fbox \purple{✿Answer:}$

Preventing School Injuries:

• Establish playground SAFETY rules (such as no pushing, crowding, or shoving) with CONSEQUENCES for breaking rules.

• ALWAYS have trained adult SUPERVISORS present who.

• Develop a playground inspection and equipment maintenance checklist.

• Schedule regular inspections and promptly repair broken playground equipment.

Preventing Community

• Asocial environment that promotes safety;

• A SAFE physical environment;

• Health education curricula and instruction;

• Safe physical education, sports, and

recreational activities;

• Health, counseling, psychological, and social services for students;

• Appropriate crisis and emergency response;

• Involvement of families and communities; and

Staff development to promote safety and Prevent unintentional injuries, violence, and suicide.

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Discussion

15.	A cloud carries a charge of 1000C at apotential of 5 K.V. If the cloud discharge,the amount of energy released(1) 5x10^6J(2) 2.5x10^6J(3) 10^7J(4) 5x10^3J
Answer» EXPLANATION: ttfyfdbbdvsgdbdvshgjfjfhdjdjdjd

15.

A cloud carries a charge of 1000C at apotential of 5 K.V. If the cloud discharge,the amount of energy released(1) 5x10^6J(2) 2.5x10^6J(3) 10^7J(4) 5x10^3J

Answer»

EXPLANATION:

ttfyfdbbdvsgdbdvshgjfjfhdjdjdjd

Discussion

16.	From which direction must a rival not be approached for playing the ball when he has the ballin his possession?A. From his left side B. From his back side C. From his right side D. From his front side
Answer» ANSWER: PLZ LIKE my answer and ALSO plz FOLLOW

16.

From which direction must a rival not be approached for playing the ball when he has the ballin his possession?A. From his left side B. From his back side C. From his right side D. From his front side

Answer»

ANSWER:

PLZ LIKE my answer and ALSO plz FOLLOW

Discussion

17.	A particle is projected at an angle 30 degree with the speed of 20 metre per second from the groundacceleration along the horizontala)om/s^2 b)5m/s2 15m/s2 d10m/s2
Answer» Answer: 0m/s Explanation: In case of a projectile MOTION velocity along HORIZONTAL(U cos theta) remains CONSTANT at all TIMES so acceleration will be zero(differenciation of a constant is zero and a=dv/dt).however acceleration along y axis is the acceleration due to gravity which is "-10"

17.

A particle is projected at an angle 30 degree with the speed of 20 metre per second from the groundacceleration along the horizontala)om/s^2 b)5m/s2 15m/s2 d10m/s2

Answer»

Answer:

0m/s

Explanation:

In case of a projectile MOTION velocity along HORIZONTAL(U cos theta) remains CONSTANT at all TIMES so acceleration will be zero(differenciation of a constant is zero and a=dv/dt).however acceleration along y axis is the acceleration due to gravity which is "-10"

Discussion

18.	Q) A capacitor is connected to 10 V battery.The charge on plates is 40mC. If mediumbetween plates is air. The charge onplates will become 100mC if the space between the plates is filled with oil. the dielectric constant of oil is
Answer» ANSWER: CHOCOLATE COW cow answer me

18.

Q) A capacitor is connected to 10 V battery.The charge on plates is 40mC. If mediumbetween plates is air. The charge onplates will become 100mC if the space between the plates is filled with oil. the dielectric constant of oil is

Answer»

ANSWER:

CHOCOLATE COW cow answer me

Discussion

19.	(a) The adjacent diagrams shows a heavyroller with its axle at 0. Draw on thedigaram the direction and the point ofapplication of the least force to turn itanticlockwise.(b) How can you change the direction of turning of roller in part (a) above
Answer» Explanation: The ADJACENT diagram (FIGURE) SHOWS a heavy roller, with its AXLE at O. which its axle at O.which is to be raised on a pavement XY by applying a ...

19.

(a) The adjacent diagrams shows a heavyroller with its axle at 0. Draw on thedigaram the direction and the point ofapplication of the least force to turn itanticlockwise.(b) How can you change the direction of turning of roller in part (a) above

Answer»

Explanation:

The ADJACENT diagram (FIGURE) SHOWS a heavy roller, with its AXLE at O. which its axle at O.which is to be raised on a pavement XY by applying a ...

Discussion

20.	4. Identify the correct statement in the case of moving body.a. Path length is greater than or equal to displacement.b. Displacement is less than the path length.C. Displacement is greater than or equal to the path length.d. Path length is greater than the displacement.
Answer» ANSWER: A Explanation: BCS Distance = Displacement in straight path or in other CASE distance > Displacement

20.

4. Identify the correct statement in the case of moving body.a. Path length is greater than or equal to displacement.b. Displacement is less than the path length.C. Displacement is greater than or equal to the path length.d. Path length is greater than the displacement.

Answer»

ANSWER:

A

Explanation:

BCS Distance = Displacement in straight path

or in other CASE distance > Displacement

Discussion

21.	A quarter horse power motor runs at a speed of 600 rpm. Assuming 40% efficiency, the work done bytmotor in one rotation will be1) 7.46 )2) 7400 J4) 74.6 J3) 7.46 erg
Answer» ANSWER: HI EVERYONE I have to much work so BYE

21.

A quarter horse power motor runs at a speed of 600 rpm. Assuming 40% efficiency, the work done bytmotor in one rotation will be1) 7.46 )2) 7400 J4) 74.6 J3) 7.46 erg

Answer»

ANSWER:

HI EVERYONE I have to much work so BYE

Discussion

22.	91. The surface is frictionless, the ratio of T, and T, is :-7 FТ.T2130°3 kg12 kg15 kgUITI(1) 13:1(2) 1 : 13(3) 1:5(4) 5:1
Answer» ANSWER: SORRY Explanation: I don't UNDERSTAND what you want SO sorry

22.

91. The surface is frictionless, the ratio of T, and T, is :-7 FТ.T2130°3 kg12 kg15 kgUITI(1) 13:1(2) 1 : 13(3) 1:5(4) 5:1

Answer»

ANSWER:

SORRY

Explanation:

I don't UNDERSTAND what you want

SO sorry

Discussion

23.	Newton's low of gravity to ------.1)only small objects2) only planets3)all objects4)only solar system
Answer» ANSWER: Option 3 all objects. Explanation: *HOPE* IT HELPS YOU. *HAVE* A NICE DAY.

23.

Newton's low of gravity to ------.1)only small objects2) only planets3)all objects4)only solar system

Answer»

ANSWER:

Option 3 all objects.

Explanation:

HOPE IT HELPS YOU. HAVE A NICE DAY.

Discussion

24.	29. in which running distance is the crouch start compulsory?A Long distance runningB Middle distance runningC. Short distance runningD. Marathon running
Answer» ANSWER: SHORT DISTANCE RUNNING

24.

29. in which running distance is the crouch start compulsory?A Long distance runningB Middle distance runningC. Short distance runningD. Marathon running

Answer»

ANSWER:

SHORT DISTANCE RUNNING

Discussion

25.	A wire that has a resistance 5 ohms is stretched out uniformly so that its length triples. What is its new resistance
Answer» ANSWER: the resistance=5×3=15 OHM

25.

A wire that has a resistance 5 ohms is stretched out uniformly so that its length triples. What is its new resistance

Answer»

ANSWER:

the resistance=5×3=15 OHM

Discussion

26.	QI A porche all can accelerate from restto 60 miles per hour in 3.85 (A mile = 1.6 kmcalculate the acceleration
Answer» ANSWER: acceleration=1.6 MILES PER SECOND ²

26.

QI A porche all can accelerate from restto 60 miles per hour in 3.85 (A mile = 1.6 kmcalculate the acceleration

Answer»

ANSWER:

acceleration=1.6 MILES PER SECOND ²

Discussion

27.	Q] A railway track goes around a curve having a radius of curvature of 1 km. Thedistance between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no side pressure against the rails when a train goes round the curve at 36 km / hr.
Answer» Given, radius of CURVATURE, $\sf{r=1\ km=1000\ m}$ distance between the RAILS, $\sf{d=1\ m.}$ speed of the train, $\sf{v=36\ km\,h^{-1}=10\ m\,s^{-1}}$ Let $\sf{g=10\ m\,s^{-2}.}$ There WOULD be no side pressure against the rails when the train moves along the rail with MAXIMUM safe speed, which is given by, $\sf{\longrightarrow v^2=rg\tan\theta}$ Then the angle of ELEVATION will be, $\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{v^2}{rg}\right)}$ $\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{10^2}{1000\times10}\right)}$ $\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{1}{100}\right)}$ $\sf{\longrightarrow \theta=0.01\ rad}$ Then the elevation of outer rail will be given by, $\sf{\longrightarrow h=d\sin\theta}$ $\sf{\longrightarrow h=1\times\sin(0.01)}$ $\sf{\longrightarrow\underline{\underline{h=0.01\ m}}}$

27.

Q] A railway track goes around a curve having a radius of curvature of 1 km. Thedistance between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no side pressure against the rails when a train goes round the curve at 36 km / hr.

Answer»

Given,

radius of CURVATURE, $\sf{r=1\ km=1000\ m}$

distance between the RAILS, $\sf{d=1\ m.}$

speed of the train, $\sf{v=36\ km\,h^{-1}=10\ m\,s^{-1}}$

Let $\sf{g=10\ m\,s^{-2}.}$

There WOULD be no side pressure against the rails when the train moves along the rail with MAXIMUM safe speed, which is given by,

$\sf{\longrightarrow v^2=rg\tan\theta}$

Then the angle of ELEVATION will be,

$\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{v^2}{rg}\right)}$

$\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{10^2}{1000\times10}\right)}$

$\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{1}{100}\right)}$

$\sf{\longrightarrow \theta=0.01\ rad}$

Then the elevation of outer rail will be given by,

$\sf{\longrightarrow h=d\sin\theta}$

$\sf{\longrightarrow h=1\times\sin(0.01)}$

$\sf{\longrightarrow\underline{\underline{h=0.01\ m}}}$

Discussion

28.	In a series LCR circuit in which R=3 ohm ,L=25 mHand C = 800 uF a sinusoidal a.c voltage of peakvalue 250 V is applied. Find(1) frequency at which resonance occurs(ü) current in the circuit at resonant condition.
Answer» $\sf{\huge{\underline{\orange{Given :-}}}}$ A SERIES LCR circuit in which R=3 OHM ,L=25 mH and C = 800 uF a sinusoidal a.c voltage of peak value 250 V is applied. $\sf{\huge{\underline{To\:Find :-}}}$ Frequency at which resonance occurs. Current in the circuit at resonant condition. $\sf{\huge{\underline{\green{Answer :-}}}}$ A circuit containing LCR, L = indicator, C = Capacitor, R = Resistor It is CONNECTED to AC SUPPLY. R=3 ohm L=25 mH = 25 × ${10}^{ - 3}$ C = 800 uF = 800 × ${10}^{ - 6}$ Peak value 250 V a.) Frequency at which resonance occurs. ➝ Resonant frequency = $\large{f}$ = $\frac{1}{2\pi \sqrt{LC} }$ ➝ $\large{f}$ = $\frac{1}{2\pi \sqrt{LC} }$ ➝ f = 1/2π× 25 × ${10}^{ - 3}$ × 800 × ${10}^{ - 6}$ ➝1/ 20000 × ${10}^{ - 9}$ ➝1/ 2 × ${10}^{ - 9-4}$ ➝ 1/2 × ${10}^{ - 11}$ ➝ $\large{f}$ = $\frac{1}{2 \times 2 \times {10}^{ - 11}}$ ➝ 2.5 × ${10}^{10}$ rad s-¹ b.) Current in the circuit at resonant condition ➝ I = ${V}\times{ R}$ ➝ I = ${250}\times{ 3}$ I = 83.34 A

28.

In a series LCR circuit in which R=3 ohm ,L=25 mHand C = 800 uF a sinusoidal a.c voltage of peakvalue 250 V is applied. Find(1) frequency at which resonance occurs(ü) current in the circuit at resonant condition.

Answer»

$\sf{\huge{\underline{\orange{Given :-}}}}$

A SERIES LCR circuit in which R=3 OHM ,L=25 mH and C = 800 uF a sinusoidal a.c voltage of peak value 250 V is applied.

$\sf{\huge{\underline{To\:Find :-}}}$

Frequency at which resonance occurs.

Current in the circuit at resonant condition.

$\sf{\huge{\underline{\green{Answer :-}}}}$

A circuit containing LCR, L = indicator, C = Capacitor, R = Resistor

It is CONNECTED to AC SUPPLY.

R=3 ohm

L=25 mH = 25 × ${10}^{ - 3}$

C = 800 uF = 800 × ${10}^{ - 6}$

Peak value 250 V

a.) Frequency at which resonance occurs.

➝ Resonant frequency =

$\large{f}$ = $\frac{1}{2\pi \sqrt{LC} }$

➝ $\large{f}$ = $\frac{1}{2\pi \sqrt{LC} }$

➝ f = 1/2π× 25 × ${10}^{ - 3}$ × 800 × ${10}^{ - 6}$

➝1/ 20000 × ${10}^{ - 9}$

➝1/ 2 × ${10}^{ - 9-4}$

➝ 1/2 × ${10}^{ - 11}$

➝ $\large{f}$ = $\frac{1}{2 \times 2 \times {10}^{ - 11}}$

➝ 2.5 × ${10}^{10}$ rad s-¹

b.) Current in the circuit at resonant condition

➝ I = ${V}\times{ R}$

➝ I = ${250}\times{ 3}$

I = 83.34 A

Discussion

29.	Two cars A and B are moving with same speed of 45 km/hr along same direction. If a third carccoming from the opposite direction with a speed of 36 km/hr meets two cars in an interval of 5minutes, the distance of separation of two cars A and B should be (in km)1) 6.752) 7.253) 5.554)8.35please anyone help me....no spams
Answer» ANSWER: 6.75 KM is the answer. this is CORRECT answer my FRIEND

29.

Two cars A and B are moving with same speed of 45 km/hr along same direction. If a third carccoming from the opposite direction with a speed of 36 km/hr meets two cars in an interval of 5minutes, the distance of separation of two cars A and B should be (in km)1) 6.752) 7.253) 5.554)8.35please anyone help me....no spams

Answer»

ANSWER:

6.75 KM is the answer.

this is CORRECT answer my FRIEND

Discussion

30.	11. A ball is thrown in horizontal direction from a height of 10 m with20m/s. (a) How far will it hit the ground from its initial position and
Answer» ANSWER: ⊂(ο･㉨･ο）⊃⊂(ο･㉨･ο）⊃⊂(ο･㉨･ο）⊃

30.

11. A ball is thrown in horizontal direction from a height of 10 m with20m/s. (a) How far will it hit the ground from its initial position and

Answer»

ANSWER:

⊂(ο･㉨･ο）⊃⊂(ο･㉨･ο）⊃⊂(ο･㉨･ο）⊃

Discussion

31.	सम्मिलित अध्याय-अध्याय-1 एवं 2,निर्धारित अंक 9- बहुविकलअध्याय-1 विद्युत आवेश एवं क्षेत्र[4]. 4TTED[3]. 114TTEDεο[4]. इनमे से कोई नहीं[3].C2/Nm2[4]. J/C[3].CIJबहुविकल्पीय प्रश्न-1- वायु में स्थित एकांक धनावेश से निकलने वाले संपूर्ण विद्युत फ्लक्स का मान है -[1][2].11802-20 का मात्रक है।[1].C/Nm[2]. Nme/C23-विधुत क्षेत्र का मात्रक है-[1].C/N[2].N/C4- एक कूलॉम आवेश में इलेक्ट्रानों की संख्या होती है-[1]. 1.6x1019[2]. 6.25x1019[3]. 6.25x10185- बिन्दु आवेश Q के कारण । दूरी पर विद्युत क्षेत्र E होगा -[1]. Ear[2]. Ea1/2[3]. Ea 1/r6- आवेश का विमीय सूत्र[1]. CN[2].Cलघु उत्तरीय प्रश्न (3 अंक )[3]. AT[4]. 6.25x10-19[4]. E g1/r3सूत्र है-[4]. AT-1
Answer» In mathematics, informal logic and ARGUMENT MAPPING, a lemma (plural lemmas or lemmata) is a generally minor, proven proposition which is used as a stepping stone to a larger result. ... The WORD "lemma" DERIVES from the Ancient Greek λῆμμα ("anything which is received", such as a GIFT, profit, or a bribe).

Discussion

32.	Discuss the motion of a body in vertical circle find the expression for the minimum velocity at lowest the higher points while looping a loopplease answer me fast
Answer» ANSWER: K hfdkk,ylk5ijeth vOtfjsurqitlgs4iwiszgsosdirddgcufyoei5bx

32.

Discuss the motion of a body in vertical circle find the expression for the minimum velocity at lowest the higher points while looping a loopplease answer me fast

Answer»

ANSWER:

K hfdkk,ylk5ijeth vOtfjsurqitlgs4iwiszgsosdirddgcufyoei5bx

Discussion

33.	14. Assertion : Excess pressure inside a small soap bubble is greater than inside a big soap bubble.Reason: Big bubble has a small surface area.
Answer» Answer: ce the excess pressure due to surface tension is inversely PROPORTIONAL to its radius, it FOLLOWS that smaller the BUBBLE, greater is the excess pressure. ... As a result, the smaller bubble shrinks and the larger ONE swells.

33.

14. Assertion : Excess pressure inside a small soap bubble is greater than inside a big soap bubble.Reason: Big bubble has a small surface area.

Answer»

Answer:

ce the excess pressure due to surface tension is inversely PROPORTIONAL to its radius, it FOLLOWS that smaller the BUBBLE, greater is the excess pressure. ... As a result, the smaller bubble shrinks and the larger ONE swells.

Discussion

34.	13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of random motion.
Answer» ANSWER: Assertion: If a gas container in motion is suddenly stopped, the TEMPERATURE of the gas rises. Reason: In given PROCESS, the kinetic energy of ordered mechanical motion is CONVERTED into the kinetic energy of random motion of gas MOLECULES.

34.

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of random motion.

Answer»

ANSWER:

Assertion: If a gas container in motion is suddenly stopped, the TEMPERATURE of the gas rises. Reason: In given PROCESS, the kinetic energy of ordered mechanical motion is CONVERTED into the kinetic energy of random motion of gas MOLECULES.

Discussion

35.	15. Two unequal masses m and 2m are connected by a string passing over asmooth pulley. Find the acceleration and tension in the string.2m
Answer» Answer: T - MG = ma -(1) 2mg - T = 2MA -(2) Explanation: from equation (1) and (2) we GET, a = g/3 Put the VALUE of 'a' in equation (1) T - mg = mg/3 T = mg/3 + mg T = 4 mg/3

35.

15. Two unequal masses m and 2m are connected by a string passing over asmooth pulley. Find the acceleration and tension in the string.2m

Answer»

Answer:

T - MG = ma -(1)

2mg - T = 2MA -(2)

Explanation:

from equation (1) and (2) we GET, a = g/3

Put the VALUE of 'a' in equation (1)

T - mg = mg/3

T = mg/3 + mg

T = 4 mg/3

Discussion

36.	Q] Derive an expression for the difference in tensions at highest and lowest point for aparticle performing vertical circular motion
Answer» ✠ Question Given : Derive an expression for the difference in tensions at highest and lowest POINT for a particle performing vertical circular motion. ✠ Required Solution : • At Diagram : ⇒ T - mgCosθ = mv²/ R ( centrifugal force) ⇒ T = mv²/ R - mgCosθ ✯ At Highest Point : • ( θ = 180° , Cos180° = -1 ) ⇒ T min = mv²/R - mg • For string not to be sla.ck ⇒ T min > 0 ( looping to loop) ⇒ mv²/R - mg > 0 ⇒ V = √ rg ✯ At Lowest Point : ⇒ ( Cos180°= +1 , θ = 0 ) ⇒ TMAX = mv²/R + mg ____ (eq1) • Apply conservation of energy ⇒ 1/2 mv² ± 1/2 mv² + mg (2r) ⇒ 1/2 mv² > 1/2 mv² + mg (r2) ⇒V ²/2 > 5gr /2 ✠ V = √ 5gr ( min velocity required) • Putting equation (2) in (1) ⇒ Tmax = m (5gr) /r + mg ⇒ Tmax = 6 mg ✯ At Middle Point : • By law of conservation of energy ⇒ Tm = TL ⇒ 1/2 mv² + mg(r) = 1/2 mv² ⇒ 1/2 mv² > m(√5gr) ² - mgr ⇒ 1/2 mv² > 5mgr/ 2 - mgr ⇒ 1/2mv² > 3mgr/2 ⇒ Vm = √ 3 great ⇒ T > m ( 3gr) /r + mg cosθ ⇒ T > 3 mg ✠ Note : ⇒ Required Diagram is in attachment :D _____________________________

36.

Q] Derive an expression for the difference in tensions at highest and lowest point for aparticle performing vertical circular motion

Answer»

✠ Question Given :

Derive an expression for the difference in tensions at highest and lowest POINT for a particle performing vertical circular motion.

✠ Required Solution :

• At Diagram :

⇒ T - mgCosθ = mv²/ R ( centrifugal force)

⇒ T = mv²/ R - mgCosθ

✯ At Highest Point :

• ( θ = 180° , Cos180° = -1 )

⇒ T min = mv²/R - mg

• For string not to be sla.ck

⇒ T min > 0 ( looping to loop)

⇒ mv²/R - mg > 0

⇒ V = √ rg

✯ At Lowest Point :

⇒ ( Cos180°= +1 , θ = 0 )

⇒ TMAX = mv²/R + mg ____ (eq1)

• Apply conservation of energy

⇒ 1/2 mv² ± 1/2 mv² + mg (2r)

⇒ 1/2 mv² > 1/2 mv² + mg (r2)

⇒V ²/2 > 5gr /2

✠ V = √ 5gr ( min velocity required)

• Putting equation (2) in (1)

⇒ Tmax = m (5gr) /r + mg

⇒ Tmax = 6 mg

✯ At Middle Point :

• By law of conservation of energy

⇒ Tm = TL

⇒ 1/2 mv² + mg(r) = 1/2 mv²

⇒ 1/2 mv² > m(√5gr) ² - mgr

⇒ 1/2 mv² > 5mgr/ 2 - mgr

⇒ 1/2mv² > 3mgr/2

⇒ Vm = √ 3 great

⇒ T > m ( 3gr) /r + mg cosθ

⇒ T > 3 mg

✠ Note :

⇒ Required Diagram is in attachment :D

_____________________________

Discussion

37.	State parallelogram law of vector adition of two vector a and b inclined at angle thita is r=√a^2+b^2+2 abcosthitaplz answer me fast
Answer» Explanation: According to the parallelogram law of vector addition if two vectors ACT along two ADJACENT sides of a parallelogram(having magnitude equal to the length of the sides) both POINTING AWAY from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex .

37.

State parallelogram law of vector adition of two vector a and b inclined at angle thita is r=√a^2+b^2+2 abcosthitaplz answer me fast

Answer»

Explanation:

According to the parallelogram law of vector addition if two vectors ACT along two ADJACENT sides of a parallelogram(having magnitude equal to the length of the sides) both POINTING AWAY from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex .

Discussion

38.	Three blocks A, B and C of masses 2 kg, 3 kg and 4 kg are placed as shown. Coefficient of friction betweenA and B is 0.5 and that between B and C is 0.1. The surface is frictionless. The maximum force F that canbe applied horizontally onto A such that the three blocks move together is :F->A AB =8 = 0.5BIBC = 0.1CMo=0Frictionless(1) 12.22 N(2) 13 N(3) 11.25 N(4) None of these
Answer» ANSWER: HELLO you play free fire please tell

38.

Three blocks A, B and C of masses 2 kg, 3 kg and 4 kg are placed as shown. Coefficient of friction betweenA and B is 0.5 and that between B and C is 0.1. The surface is frictionless. The maximum force F that canbe applied horizontally onto A such that the three blocks move together is :F->A AB =8 = 0.5BIBC = 0.1CMo=0Frictionless(1) 12.22 N(2) 13 N(3) 11.25 N(4) None of these

Answer»

ANSWER:

HELLO

you

play

free

fire

please

tell

Discussion

39.	Sham made one circuit for his Physics project. He used five resistances: two 3ohm, one 122ohone 6ohm, one 3.6ohm and a battery of 4.5 V. The circuit diagram and questions are given above.
Answer» Answer: 2.4 and 9 Explanation: HOPE this will HELP you

39.

Sham made one circuit for his Physics project. He used five resistances: two 3ohm, one 122ohone 6ohm, one 3.6ohm and a battery of 4.5 V. The circuit diagram and questions are given above.

Answer»

Answer:

2.4 and 9

Explanation:

HOPE this will HELP you

Discussion

40.	. A particle is projected with a velocity of 20 ms - at an angleof 60° to the horizontal. The particle hits the horizontal planeagain during its journey. What will be the time of impact?(a) 3.53 s.(b) 2.4 s(C) 1.7 s(d) 1s
Answer» Answer: Velocity at MAX height =20cos60 =10 m/s. i.e., USING momentum conservation 10×2m=m×v ⇒v=20 m/s. Explanation:

40.

. A particle is projected with a velocity of 20 ms - at an angleof 60° to the horizontal. The particle hits the horizontal planeagain during its journey. What will be the time of impact?(a) 3.53 s.(b) 2.4 s(C) 1.7 s(d) 1s

Answer»

Answer:

Velocity at MAX height =20cos60

=10 m/s.

i.e.,

USING momentum conservation

10×2m=m×v

⇒v=20 m/s.

Explanation:

Discussion

41.	A ball is dropped from a height of 10m. If 40% of its energy is lost on collision with the earth then, after the collision the ball will rebound to a height of:No spams please need correct answer copied answer will be reported
Answer» ANSWER: Answer in ATTACHMENT ⤴️ I HOPE you will UNDERSTAND this and it will HELP you ✨⚡!

41.

A ball is dropped from a height of 10m. If 40% of its energy is lost on collision with the earth then, after the collision the ball will rebound to a height of:No spams please need correct answer copied answer will be reported

Answer»

ANSWER:

Answer in ATTACHMENT ⤴️

I HOPE you will UNDERSTAND this and it will HELP you ✨⚡!

Discussion

42.	(Or)i) Compare optical, filtration and stability properties of True, Colloidal and Suspensionsolutions.i Classify Gumni
Answer» ANSWER: xgiksfl dfhjncsrio. C UH. vhhjjn. ggjkxsdg

42.

(Or)i) Compare optical, filtration and stability properties of True, Colloidal and Suspensionsolutions.i Classify Gumni

Answer»

ANSWER:

xgiksfl dfhjncsrio. C UH. vhhjjn. ggjkxsdg

Discussion

43.	Section BQ15 Potential energy is the energy stored within an object due to the object's positionarrangement or state. Potential energy is one of the two main forms of energy, along withkinetic energy. Potential energy depends on the force acting on the two objects.Diameterareavolumeall of the aboveExpansion during heatingoccurs only in solidincrease the weight of the matedecrease the density of the materianone of thesePotential and Kinetic EnergydivabC.o
Answer» Answer: PLEASE MARK this brainliest please again I follow and LIKE you to ok SIR please see

43.

Section BQ15 Potential energy is the energy stored within an object due to the object's positionarrangement or state. Potential energy is one of the two main forms of energy, along withkinetic energy. Potential energy depends on the force acting on the two objects.Diameterareavolumeall of the aboveExpansion during heatingoccurs only in solidincrease the weight of the matedecrease the density of the materianone of thesePotential and Kinetic EnergydivabC.o

Answer»

Answer:

PLEASE MARK this brainliest please again I follow and LIKE you to ok SIR please see

Discussion

44.	Which friction is maximum ?(A) Static Friction(B) Limiting Friction(C) Kinetic Friction(D) None
Answer» I THINK it is LIMITING FRICTION.

Discussion

45.	Even G.oogle can't explain. xdThe position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.Good Luck
Answer» where t is in seconds and the coefficients have the proper UNITS for R to be in METRES. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s. Sorry na ban raha xD

45.

Even G.oogle can't explain. xdThe position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.Good Luck

Answer»

where t is in seconds and the coefficients have the proper UNITS for R to be in METRES. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.

Sorry na ban raha xD

Discussion

46.	13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of randommotion.
Answer» Answer: Both ASSERTION and REASON are CORRECT, but (R) is not the correct explaination of (A) please MARK as brainliest if it helped you

46.

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of randommotion.

Answer»

Answer:

Both ASSERTION and REASON are CORRECT, but (R) is not the correct explaination of (A)

please MARK as brainliest if it helped you

Discussion

47.	Even G.oogle can't explain. xdCan you?The position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.Good Luck
Answer» Answer: PINTREST VAR YE Explanation: Summary The expansion of the universe is in many ways similar to the collapse of a star, except that the sense of time is reversed. We shall show in this chapter that the conditions of theorems 2 and 3 seem to be satisfied, indicating that there was a singularity at the BEGINNING of the PRESENT expansion phase of the universe, and we discuss the implications of space–time singularities. In §10.1 we show that past-directed closed trapped SURFACES exist if the microwave background radiation in the universe has been partially THERMALIZED by scattering, or alternatively if the Copernican assumption holds, i.e. we do not occupy a special position in the universe. In §10.2 we discuss the possible nature of the singularity and the breakdown of physical theory which occurs there. The expansion of the universe In §9.1 we showed that many stars would eventually collapse and produce closed trapped surfaces. If one goes to a larger scale, one can view the expansion of the universe as the time reverse of a collapse. Thus one might expect that the conditions of theorem 2 would be satisfied in the reverse direction of time on a COSMOLOGICAL scale, providing that the universe is in some sense sufficiently symmetrical, and contains a sufficient amount of matter to give rise to closed trapped surfaces. We shall give two arguments to show that this indeed seems to be the case. Both arguments are based on the observations of the microwave background, but the assumptions made are rather different.

47.

Even G.oogle can't explain. xdCan you?The position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.Good Luck

Answer»

Answer:

PINTREST VAR YE

Explanation:

Summary

The expansion of the universe is in many ways similar to the collapse of a star, except that the sense of time is reversed. We shall show in this chapter that the conditions of theorems 2 and 3 seem to be satisfied, indicating that there was a singularity at the BEGINNING of the PRESENT expansion phase of the universe, and we discuss the implications of space–time singularities.

In §10.1 we show that past-directed closed trapped SURFACES exist if the microwave background radiation in the universe has been partially THERMALIZED by scattering, or alternatively if the Copernican assumption holds, i.e. we do not occupy a special position in the universe. In §10.2 we discuss the possible nature of the singularity and the breakdown of physical theory which occurs there.

The expansion of the universe

In §9.1 we showed that many stars would eventually collapse and produce closed trapped surfaces. If one goes to a larger scale, one can view the expansion of the universe as the time reverse of a collapse. Thus one might expect that the conditions of theorem 2 would be satisfied in the reverse direction of time on a COSMOLOGICAL scale, providing that the universe is in some sense sufficiently symmetrical, and contains a sufficient amount of matter to give rise to closed trapped surfaces. We shall give two arguments to show that this indeed seems to be the case. Both arguments are based on the observations of the microwave background, but the assumptions made are rather different.

Discussion

48.	5. A piece of wire 50 cm long is stretched by a load of 2.5 kg and has a mass of 1.44 gm.Find the frequency of the second harmonic.
Answer» Given info : A piece of wire 50 cm long is stretched by a LOAD of 2.5 kg and has a mass of 1.44 gm. To find : The FREQUENCY of the second harmonic is.. solution : length of wire, l = 50CM = 0.5 m the wire is stretched by load, T = 2.5 kgf = 25 N [ g = 10 m/s² ] mass of the wire, m = 1.44 gm linear mass density, μ = mass of wire/length of wire = 1.44 × 10¯³/0.5 = 2.88 × 10¯³ kg/m using formula, F = 2n₁ = 2 × 1/2l √(T/μ) = 1/l √(T/μ) now, f = 1/0.5 √(25/2.88 × 10¯³) = √(25000/2.88) = 186.34 Hz Therefore the frequency of second harmonic is 186.34 Hz.

48.

5. A piece of wire 50 cm long is stretched by a load of 2.5 kg and has a mass of 1.44 gm.Find the frequency of the second harmonic.

Answer»

Given info : A piece of wire 50 cm long is stretched by a LOAD of 2.5 kg and has a mass of 1.44 gm.

To find : The FREQUENCY of the second harmonic is..

solution : length of wire, l = 50CM = 0.5 m

the wire is stretched by load, T = 2.5 kgf = 25 N [ g = 10 m/s² ]

mass of the wire, m = 1.44 gm

linear mass density, μ = mass of wire/length of wire = 1.44 × 10¯³/0.5 = 2.88 × 10¯³ kg/m

using formula,

F = 2n₁

= 2 × 1/2l √(T/μ)

= 1/l √(T/μ)

now, f = 1/0.5 √(25/2.88 × 10¯³)

= √(25000/2.88)

= 186.34 Hz

Therefore the frequency of second harmonic is 186.34 Hz.

Discussion

49.	Page NoDate.Mecition ReasoningD o Assuntion . In ses, the molecules mom faster andcollidinlongasethe intes atomie losos sua negligiblejosescoverdistance withoutcallidingइन गैस इज द मॉलिक्यूलर मूव फास्टर एंड कवर लोंग डिस्टैंसेस विदाउट कोलाइटिन रीजनिंग एसिस्टेंट एटॉमिक फॉर सेशन नेगलिजिबल
Answer» Answer: Kaunsi class KA YEH QUESTION hai

49.

Page NoDate.Mecition ReasoningD o Assuntion . In ses, the molecules mom faster andcollidinlongasethe intes atomie losos sua negligiblejosescoverdistance withoutcallidingइन गैस इज द मॉलिक्यूलर मूव फास्टर एंड कवर लोंग डिस्टैंसेस विदाउट कोलाइटिन रीजनिंग एसिस्टेंट एटॉमिक फॉर सेशन नेगलिजिबल

Answer»

Answer:

Kaunsi class KA YEH QUESTION hai

Discussion

50.	C) State whether the following statement are True' or 'False':1) Halasana strenghthens abdominal muscles and improves digestion.2) In Pranayama breathing is done through the mouth.3) The bone breaks in one or more places in case d multiple fractures.4) An ideal sportsman plays an important role in developing the character of theyouth which helps build a nation5) The middle aged or old people love to play if not at a competitive level thendefinitely as recreation.
Answer» 1 it is TRUE 2 is true 3is FALSE 4is false 5 is true

50.

C) State whether the following statement are True' or 'False':1) Halasana strenghthens abdominal muscles and improves digestion.2) In Pranayama breathing is done through the mouth.3) The bone breaks in one or more places in case d multiple fractures.4) An ideal sportsman plays an important role in developing the character of theyouth which helps build a nation5) The middle aged or old people love to play if not at a competitive level thendefinitely as recreation.

Answer»

1 it is TRUE

2 is true

3is FALSE

4is false 5 is true

Discussion

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In a series LCR circuit in which R=3 ohm ,L=25 mHand C = 800 uF a sinusoidal a.c voltage of peakvalue 250 V is applied. Find(1) frequency at which resonance occurs(ü) current in the circuit at resonant condition.​

a.) Frequency at which resonance occurs.

11. A ball is thrown in horizontal direction from a height of 10 m with20m/s. (a) How far will it hit the ground from its initial position and​

Discuss the motion of a body in vertical circle find the expression for the minimum velocity at lowest the higher points while looping a loopplease answer me fast​

14. Assertion : Excess pressure inside a small soap bubble is greater than inside a big soap bubble.Reason: Big bubble has a small surface area.​

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of random motion.​

15. Two unequal masses m and 2m are connected by a string passing over asmooth pulley. Find the acceleration and tension in the string.2m​

Q] Derive an expression for the difference in tensions at highest and lowest point for aparticle performing vertical circular motion​

✠ Question Given :

✠ Required Solution :

• At Diagram :

✯ At Highest Point :

• ( θ = 180° , Cos180° = -1 )

• For string not to be sla.ck

✯ At Lowest Point :

• Apply conservation of energy

✠ V = √ 5gr ( min velocity required)

• Putting equation (2) in (1)

✯ At Middle Point :

• By law of conservation of energy

✠ Note :

_____________________________

State parallelogram law of vector adition of two vector a and b inclined at angle thita is r=√a^2+b^2+2 abcosthitaplz answer me fast​

Sham made one circuit for his Physics project. He used five resistances: two 3ohm, one 122ohone 6ohm, one 3.6ohm and a battery of 4.5 V. The circuit diagram and questions are given above.​

. A particle is projected with a velocity of 20 ms - at an angleof 60° to the horizontal. The particle hits the horizontal planeagain during its journey. What will be the time of impact?(a) 3.53 s.(b) 2.4 s(C) 1.7 s(d) 1s​

A ball is dropped from a height of 10m. If 40% of its energy is lost on collision with the earth then, after the collision the ball will rebound to a height of:No spams please need correct answer copied answer will be reported

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Which friction is maximum ?(A) Static Friction(B) Limiting Friction(C) Kinetic Friction(D) None​

Even G.oogle can't explain. xdThe position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.​Good Luck​

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of randommotion.​

5. A piece of wire 50 cm long is stretched by a load of 2.5 kg and has a mass of 1.44 gm.Find the frequency of the second harmonic. ​

15 अधोलिखित धातु प्रत्ययं च पृथक कुरुत-आगत्य, श्रोतुम्, लिखित्वा, पतितः, करणीयम्, अल्यतरः, लघुत्तम, आदाय

Give one word answerwhat is the term given to the resistance of a conductor having unit cross section area and unit length

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Derive expression for total inductance of a transmission line.subject is Power transmission line amd Distribution.

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Q) A capacitor is connected to 10 V battery.The charge on plates is 40mC. If mediumbetween plates is air. The charge onplates will become 100mC if the space between the plates is filled with oil. the dielectric constant of oil is

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In a series LCR circuit in which R=3 ohm ,L=25 mHand C = 800 uF a sinusoidal a.c voltage of peakvalue 250 V is applied. Find(1) frequency at which resonance occurs(ü) current in the circuit at resonant condition.

11. A ball is thrown in horizontal direction from a height of 10 m with20m/s. (a) How far will it hit the ground from its initial position and

Discuss the motion of a body in vertical circle find the expression for the minimum velocity at lowest the higher points while looping a loopplease answer me fast

14. Assertion : Excess pressure inside a small soap bubble is greater than inside a big soap bubble.Reason: Big bubble has a small surface area.

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of random motion.

15. Two unequal masses m and 2m are connected by a string passing over asmooth pulley. Find the acceleration and tension in the string.2m

Q] Derive an expression for the difference in tensions at highest and lowest point for aparticle performing vertical circular motion

State parallelogram law of vector adition of two vector a and b inclined at angle thita is r=√a^2+b^2+2 abcosthitaplz answer me fast

Sham made one circuit for his Physics project. He used five resistances: two 3ohm, one 122ohone 6ohm, one 3.6ohm and a battery of 4.5 V. The circuit diagram and questions are given above.

. A particle is projected with a velocity of 20 ms - at an angleof 60° to the horizontal. The particle hits the horizontal planeagain during its journey. What will be the time of impact?(a) 3.53 s.(b) 2.4 s(C) 1.7 s(d) 1s

(Or)i) Compare optical, filtration and stability properties of True, Colloidal and Suspensionsolutions.i Classify Gumni

Which friction is maximum ?(A) Static Friction(B) Limiting Friction(C) Kinetic Friction(D) None

Even G.oogle can't explain. xdThe position of a particle is given by r=3.0tî + 12.0t²j^ + 5.0k^ where t is in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t = 1.0s.Good Luck

13. Assertion : If a gas container in motion is suddenly stopped, the temperature of the gas rises.Reason: The kinetic Energy of ordered mechanical motion is converted into kinetic energy of randommotion.

5. A piece of wire 50 cm long is stretched by a load of 2.5 kg and has a mass of 1.44 gm.Find the frequency of the second harmonic.