67486 + Interview Questions in Secondary School in Physics

1.	define the term and State there SI unite (A) wave length (B) time period (C) amplitude and establish the relation velocity with wavelength, represent in symbol form
Answer» ANSWER: Explanation: (A) wavelength: it is defined as DISTANCE travelled by a wave during the time a PARTICLE of medium complete ONE vibration. SI unit is metre. (B) Time period: it is defined as time taken by a vibrating particle to complete one vibration. SI unit is second. (C) Amplitude: it is defined as maximum displacement produced in vibrating particle on either SIDE of mean position. SI unit is metre . Velocity=frequency ×wavelength.

1.

define the term and State there SI unite (A) wave length (B) time period (C) amplitude and establish the relation velocity with wavelength, represent in symbol form

Answer»

Explanation:

(A) wavelength: it is defined as DISTANCE travelled by a wave during the time a PARTICLE of medium complete ONE vibration.

SI unit is metre.

(B) Time period: it is defined as time taken by a vibrating particle to complete one vibration.

SI unit is second.

(C) Amplitude: it is defined as maximum displacement produced in vibrating particle on either SIDE of mean position.

SI unit is metre .

Velocity=frequency ×wavelength.

Discussion

2.	The information of frost on cooling coil in a refrigerator
Answer» Answer: “Frost’ is an insulation material. So, even though it is temporary, it still is an impediment to the cooling effect of air passing by a cold surface. Refrigeration is the removal of heat by a cooling material. The cooling coils are just a means to achieve the cooling effect. The addition of the frost then reduces the AMOUNT of cooling available over TIME, so that the machinery runs LONGER with the frost on it, than without. This additional run time increases the power consumption overall, and not the instantaneous power consumed while running. Start Current is 12A, Running current is 7A. The start time might be FIVE seconds, and the run time 10 minutes, then an idle time of 1 hour. Repeat. This maintains a -5C setpoint in a freezer cavity. The frost would increase the on time from 10.5 minutes to 12 minutes. The de-frost heater then runs once every 24 hours, and melts the ice that forms. Simple SYSTEM but it works MARK ME AS BRAINLIEST

2.

The information of frost on cooling coil in a refrigerator

Answer»

Answer:

“Frost’ is an insulation material.

So, even though it is temporary, it still is an impediment to the cooling effect of air passing by a cold surface.

Refrigeration is the removal of heat by a cooling material.

The cooling coils are just a means to achieve the cooling effect.

The addition of the frost then reduces the AMOUNT of cooling available over TIME, so that the machinery runs LONGER with the frost on it, than without. This additional run time increases the power consumption overall, and not the instantaneous power consumed while running.

Start Current is 12A, Running current is 7A. The start time might be FIVE seconds, and the run time 10 minutes, then an idle time of 1 hour. Repeat.

This maintains a -5C setpoint in a freezer cavity.

The frost would increase the on time from 10.5 minutes to 12 minutes.

The de-frost heater then runs once every 24 hours, and melts the ice that forms.

Simple SYSTEM but it works

MARK ME AS BRAINLIEST

Discussion

3.	how does the capacitance of parallel plate capacitor depends on the dielectric medium and the distance between the plates
Answer» Answer: C ∝ K C ∝ 1/ d Explanation: CAPACITANCE of PARALLEL PLATE capacitor = A∈₀K ÷ d

3.

how does the capacitance of parallel plate capacitor depends on the dielectric medium and the distance between the plates

Answer»

Answer:

C ∝ K

C ∝ 1/ d

Explanation:

CAPACITANCE of PARALLEL PLATE capacitor = A∈₀K ÷ d

Discussion

4.	Magnetic field intensity due to a straight current carrying conductor of finite length derivation
Answer» Magnetic Field produced by a current carrying STRAIGHT conductor are concentric circles whose centre LIE on the wire. The Magnitude of Magnetic Field produced by a current carrying straight conductor at a GIVEN point is - 1) Directionally proportional to the current flowing through it. i.e. B is Directionally proportional to I. If current is increased then Magnetic Field produced by it is stronger. 2) Inversely proportional to distance r from the CENTER. i.e. B is Inversely proportional to R Magnetic Field is stronger at a point which is near to the center and GOES on decreasing on moving away from the center. this is the answer mark as brainiest

4.

Magnetic field intensity due to a straight current carrying conductor of finite length derivation

Answer»

Magnetic Field produced by a current carrying STRAIGHT conductor are concentric circles whose centre LIE on the wire.

The Magnitude of Magnetic Field produced by a current carrying straight conductor at a GIVEN point is -

1) Directionally proportional to the current flowing through it.

i.e. B is Directionally proportional to I.

If current is increased then Magnetic Field produced by it is stronger.

2) Inversely proportional to distance r from the CENTER.

i.e. B is Inversely proportional to R

Magnetic Field is stronger at a point which is near to the center and GOES on decreasing on moving away from the center.

this is the answer

mark as brainiest

Discussion

5.	In carnot heat engine,is work done from A to B = RT1 log V2/V1 ?or nRT1 log V2/V1please answerphysics question.
Answer» In case of one MOLE of an IDEAL gas, the WORK DONE during isothermal process is, $W=RT_1\log\left (\dfrac {V_2}{V_1}\right)$ In case of n moles of the gas, the work done is, $W=nRT_1\log\left (\dfrac {V_2}{V_1}\right)$ Usually first case, i.e., one mole of gas is considered.

5.

In carnot heat engine,is work done from A to B = RT1 log V2/V1 ?or nRT1 log V2/V1please answerphysics question.

Answer»

In case of one MOLE of an IDEAL gas, the WORK DONE during isothermal process is,

$W=RT_1\log\left (\dfrac {V_2}{V_1}\right)$

In case of n moles of the gas, the work done is,

$W=nRT_1\log\left (\dfrac {V_2}{V_1}\right)$

Usually first case, i.e., one mole of gas is considered.

Discussion

6.	Where should an object be placed in front of a concave mirror of Focal length 20 cm so as to obtain 2+ real image
Answer» Answer: 40+2u=-20. so if you object be PLACED at the distance of 30 cm then the two TIMES magnified IMAGE will be obtain. hope it help you.

6.

Where should an object be placed in front of a concave mirror of Focal length 20 cm so as to obtain 2+ real image

Answer»

Answer:

40+2u=-20. so if you object be PLACED at the distance of 30 cm then the two TIMES magnified IMAGE will be obtain. hope it help you.

Discussion

7.	5. An object is placed at 20cm from the concave mirror of focal length 10 cm,then image isformed at. a) Behind the mirror b) between P&F c) at F d) centre of curvature
Answer» ANSWER: d CENTRE of curvature Explanation: REFER for diagram mark as BRAINLIEST

7.

5. An object is placed at 20cm from the concave mirror of focal length 10 cm,then image isformed at. a) Behind the mirror b) between P&F c) at F d) centre of curvature

Answer»

ANSWER:

d CENTRE of curvature

Explanation:

REFER for diagram

mark as BRAINLIEST

Discussion

8.	In isothermal process is Governed by
Answer» Answer: BOYLE'S LAW Explanation: PLEASE GIVE THE BRAINLIEST I HAVE GIVEN YOU THE RIGHT ANSWER

8.

In isothermal process is Governed by

Answer»

Answer:

BOYLE'S LAW

Explanation:

PLEASE GIVE THE BRAINLIEST I HAVE GIVEN YOU THE RIGHT ANSWER

Discussion

9.	& Which of the following is correct?A Absolute pressure Gauge pressure + Atmospheric pressureR. Gauge pressure = Absolute pressure + Atmospheric pressureAtmospheric pressure = Absolute pressure + Gauge pressureR. Absolute pressure = Gauge pressure - Atmospheric pressure
Answer» ANSWER: A Explanation: I THINK it is the OPTION A

9.

& Which of the following is correct?A Absolute pressure Gauge pressure + Atmospheric pressureR. Gauge pressure = Absolute pressure + Atmospheric pressureAtmospheric pressure = Absolute pressure + Gauge pressureR. Absolute pressure = Gauge pressure - Atmospheric pressure

Answer»

ANSWER:

A

Explanation:

I THINK it is the OPTION A

Discussion

10.	Magnus effect is very near to the
Answer» Answer: The Magnus effect is a particular manifestation of Bernoulli's theorem: fluid PRESSURE DECREASES at points where the speed of the fluid increases. In the CASE of a ball SPINNING through the AIR, the turning ball drags some of the air around with it.

10.

Magnus effect is very near to the

Answer»

Answer:

The Magnus effect is a particular manifestation of Bernoulli's theorem: fluid PRESSURE DECREASES at points where the speed of the fluid increases. In the CASE of a ball SPINNING through the AIR, the turning ball drags some of the air around with it.

Discussion

11.	we are able to read a book since light falling on a surface gets reflected from the book and reaches the eye . But on some occasions we cannot see our images like that from a mirror . Why?
Answer» Answer: Because the LIGHT reflected from the mirror does not ENTER into our EYES....

11.

we are able to read a book since light falling on a surface gets reflected from the book and reaches the eye . But on some occasions we cannot see our images like that from a mirror . Why?

Answer»

Answer:

Because the LIGHT reflected from the mirror does not ENTER into our EYES....

Discussion

12.	Name two electrical conductors that do not obey ohm's law
Answer» ANSWER: TRANSISTORS and VACUUM TUBE

12.

Name two electrical conductors that do not obey ohm's law

Answer»

ANSWER:

TRANSISTORS and VACUUM TUBE

Discussion

13.	Which of the following is the lightest and most velite liquid fuel
Answer» Explanation: give full question OTHERWISE I can't give ANSWER

13.

Which of the following is the lightest and most velite liquid fuel

Answer»

Explanation:

give full question OTHERWISE I can't give ANSWER

Discussion

14.	Ans. this immediately
Answer» ANSWER: Option 3 (m +M' +M)/2 Explanation: as we can SEE in the image there is pulley SYSTEM consisting of a FIXED and and movable pulley M.A =2^n (where n represents no of movable pulleys) TOTAL MASS (m+M'+M) therefore Ma =L/E MA is given to be two 2 = m +M'+M/E E =m+M'+M/2

14.

Ans. this immediately

Answer»

ANSWER: Option 3

(m +M' +M)/2

Explanation:

as we can SEE in the image there is pulley SYSTEM consisting of a FIXED and and movable pulley

M.A =2^n (where n represents no of movable pulleys)

TOTAL MASS

(m+M'+M)

therefore Ma =L/E

MA is given to be two

2 = m +M'+M/E

E =m+M'+M/2

Discussion

15.	Water flows through a horizontal pipe of which the cross - section is not constant. Thepressure is 1cm of mercury where the velocity is 0.35m/s. Find the pressure at a point wherethe velocity is 0.65m/s.
Answer» $v_1=0.35\ m\ s^{-1}\quad\quad P_1=1\ cm\ Hg=1333\ Pa\\\\v_2=0.65\ m\ s^{-1}\quad\quad P_2=?$ By BERNOULLI's Theorem, $P_1+\dfrac {1}{2}\rho(v_1)^2=P_2+\dfrac {1}{2}\rho(v_2)^2$ Potential ENERGY is not CONSIDERED since water flows through a horizontal pipe. $1333+\dfrac {1}{2}\times 1000(0.35)^2=P_2+\dfrac {1}{2}\times1000(0.65)^2\\\\\\\underline {\underline {P_2=1183\ Pa}}$ Or, $\underline {\underline {P_2=0.887\ cm\ Hg}}$

15.

Water flows through a horizontal pipe of which the cross - section is not constant. Thepressure is 1cm of mercury where the velocity is 0.35m/s. Find the pressure at a point wherethe velocity is 0.65m/s.

Answer»

$v_1=0.35\ m\ s^{-1}\quad\quad P_1=1\ cm\ Hg=1333\ Pa\\\\v_2=0.65\ m\ s^{-1}\quad\quad P_2=?$

By BERNOULLI's Theorem,

$P_1+\dfrac {1}{2}\rho(v_1)^2=P_2+\dfrac {1}{2}\rho(v_2)^2$

Potential ENERGY is not CONSIDERED since water flows through a horizontal pipe.

$1333+\dfrac {1}{2}\times 1000(0.35)^2=P_2+\dfrac {1}{2}\times1000(0.65)^2\\\\\\\underline {\underline {P_2=1183\ Pa}}$

Or,

$\underline {\underline {P_2=0.887\ cm\ Hg}}$

Discussion

16.	To get three images of a single object one should have plane mirrors at an angle of
Answer» Answer: 90° ........... . HOPE it HELPS ☺️

16.

To get three images of a single object one should have plane mirrors at an angle of

Answer»

Answer:

90° ...........

.

HOPE it HELPS ☺️

Discussion

17.	A photon beam of energy 12.1eV is incident on a hydrogen atom. The orbit towhich electron of H-atom be excited is
Answer» Answer: H FILL KNOB fight g g g g t f r t your UNCLE s type y y

17.

A photon beam of energy 12.1eV is incident on a hydrogen atom. The orbit towhich electron of H-atom be excited is

Answer»

Answer:

H FILL KNOB fight g g g g t f r t your UNCLE s type y y

Discussion

18.	What is the structural formula of propan-2-one
Answer» C3H60 is the MOLECULAR Formula hope it HELPS you MARK, as BRAINLIEST ✌✌

18.

What is the structural formula of propan-2-one

Answer»

C3H60 is the MOLECULAR Formula

hope it HELPS you MARK, as BRAINLIEST ✌✌

Discussion

19.	Theoretically which of the following are best lubricant's
Answer» ANSWER: THEORETICALLY is the BEST LUBRICANT

19.

Theoretically which of the following are best lubricant's

Answer»

ANSWER:

THEORETICALLY is the BEST LUBRICANT

Discussion

20.	8. The picture of heat as a fluid was discarded in favor of the modern concept of heat as a formof energy becausea. Count Rumford observed that boring of brass cannon generated a lot of dustb. Count Rumford observed that boring of brass cannon generated a lot of smokec. Count Rumford observed that boring of brass cannon generated a lot of heatd Count Rumford observed that boring of brass cannon generated a lot of noise
Answer» EXPLANATION: A GOOD LUBRICANT should be HIGHLY

20.

8. The picture of heat as a fluid was discarded in favor of the modern concept of heat as a formof energy becausea. Count Rumford observed that boring of brass cannon generated a lot of dustb. Count Rumford observed that boring of brass cannon generated a lot of smokec. Count Rumford observed that boring of brass cannon generated a lot of heatd Count Rumford observed that boring of brass cannon generated a lot of noise

Answer»

EXPLANATION:

A GOOD LUBRICANT should be HIGHLY

Discussion

21.	Electrical energy and power
Answer» EXPLANATION: electrical energy ELECTRICAL energy is energy it DERIVED from electric potential energy or kinetic energy we used loosely electrical energy it refer to energy that had been converted from electrical potential energy power power is the rate of doing work or of transferred the HEAT i,e.the AMOUNT of energytransferred or converted per unit of time

21.

Electrical energy and power

Answer»

EXPLANATION:

electrical energy

ELECTRICAL energy is energy it DERIVED from electric potential energy or kinetic energy we used loosely electrical energy it refer to energy that had been converted from electrical potential energy

power

power is the rate of doing work or of transferred the HEAT i,e.the AMOUNT of energytransferred or converted per unit of time

Discussion

22.	48 similar cells each of emf 1.5 V and internal resistance 2 ohm are used for sending current through aresistance of 6 ohm. What will be the current if the cells are connected in the following way: (i) 6 rows and 8cells in a row, (ii) 4 rows and 12 cells in a row.
Answer» Answer: Emf of each cell (e) = 1.5V, internal resistance (r) = 2 ohm, external resistance (R) = 6 ohm. (i) No. of cells in a ROW (N) = 8 No. of ROWS (m) = 6 So, CURRENT, I = mne/mR + nr = 6×8×1.5/6×6+8×2 = 72/52 = 1.385 A (ii) No. of cells in a row (n) = 12 No. of rows (m) = 4 So, current, I = mne/mR+nr = 4×12×1.5/4×6+12×2 = 72/48 = 1.5 A

22.

48 similar cells each of emf 1.5 V and internal resistance 2 ohm are used for sending current through aresistance of 6 ohm. What will be the current if the cells are connected in the following way: (i) 6 rows and 8cells in a row, (ii) 4 rows and 12 cells in a row.

Answer»

Answer:

Emf of each cell (e) = 1.5V, internal resistance (r) = 2 ohm, external resistance (R) = 6 ohm.

(i) No. of cells in a ROW (N) = 8

No. of ROWS (m) = 6

So, CURRENT, I = mne/mR + nr = 6×8×1.5/6×6+8×2

= 72/52

= 1.385 A

(ii) No. of cells in a row (n) = 12

No. of rows (m) = 4

So, current, I = mne/mR+nr = 4×12×1.5/4×6+12×2

= 72/48

= 1.5 A

Discussion

23.	If \|A-B\| = \|A\|-\|B\|, the angle between A and B is? explain plz
Answer»

Discussion

24.	Please help me in solving this
Answer» ANSWER: a)2.5 SORRY sorry sorry

24.

Please help me in solving this

Answer»

ANSWER:

a)2.5 SORRY sorry sorry

Discussion

25.	If \|A-B\| = \|A\|-\|B\|, the angle between A and B is?
Answer» ANSWER: 0 DEGREE ,is the CORRECT answer, THANKS for ASKING..

25.

If |A-B| = |A|-|B|, the angle between A and B is?

Answer»

ANSWER:

0 DEGREE ,is the CORRECT answer, THANKS for ASKING..

Discussion

26.	Material is said to be ductile if material cross section is not significantly reduced at failure(a) material breaks suddenly at little elongation(b) a large amount of plastic deformation takes place between the elastic limit and thefracture point(c)fracture occurs soon after the elastic limit is passed
Answer» Explanation: A ductile material is ONE that can withstand a LARGE AMOUNT of plastic deformation between the elastic limit and the fracture point. A material that breaks suddenly when elongated or fracture OCCURS in it soon after elastic limit is crossed is called a brittle material. A ductile material that exhibits extra elongation or deformation and does not fracture is also referred as superplastic material

26.

Material is said to be ductile if material cross section is not significantly reduced at failure(a) material breaks suddenly at little elongation(b) a large amount of plastic deformation takes place between the elastic limit and thefracture point(c)fracture occurs soon after the elastic limit is passed

Answer»

Explanation:

A ductile material is ONE that can withstand a LARGE AMOUNT of plastic deformation between the elastic limit and the fracture point.

A material that breaks suddenly when elongated or fracture OCCURS in it soon after elastic limit is crossed is called a brittle material.

A ductile material that exhibits extra elongation or deformation and does not fracture is also referred as superplastic material

Discussion

27.	Q. A wheel 0.5 metre in radius is moving with a speed of 12 m/s. find its angular speed?
Answer» ANSWER: It's 24 ms^-1 Explanation: We KNOW that, V = R w w = v/r = 12/0.5 = 24 ms^-1 *HOPE* *THIS* *HELPS* *YOU* .......

27.

Q. A wheel 0.5 metre in radius is moving with a speed of 12 m/s. find its angular speed?

Answer»

ANSWER:

It's 24 ms^-1

Explanation:

We KNOW that, V = R w

w = v/r

= 12/0.5

= 24 ms^-1

HOPE THIS HELPS YOU .......

Discussion

28.	Define resistance . state the two factors on which the resistance of a conductor depends
Answer» Resistance of a conductor is the obstruction offered to the FLOW of current . TWO FACTORS: Area of cross section LENGTH of the conductor

Discussion

29.	A man is 6.0 ft tall. What is the smallest size plane mirror he can use to see his entire image (a) 3.0ft (b) 6.0ft (c) 12 ft (d) 24 ft. Please provide explanation
Answer» ANSWER:a)3ft. Explanation:

29.

A man is 6.0 ft tall. What is the smallest size plane mirror he can use to see his entire image (a) 3.0ft (b) 6.0ft (c) 12 ft (d) 24 ft. Please provide explanation

Answer»

ANSWER:a)3ft.

Explanation:

Discussion

30.	Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?
Answer» 1. In this case work done is zero because force direction to the motion is perpendicular THUS W =FScos 90degree now W=FS0 (cos 90=0) thus W =0 2. since all force is zero so the work done by electron will be zero as we known that W =F*S F =0 then W= 0 hope this help you

30.

Q.what is the amount of work done bya: the earth's gravitational force in keeping the moon in its circular orbit around the earth?b: an electron moving with half the speed of light in empty space free of all forces and for from all matters?

Answer»

1. In this case work done is zero because force direction to the motion is perpendicular

THUS W =F*S*cos 90degree

now W=F*S*0 (cos 90=0)

thus W =0

2. since all force is zero so the work done by electron will be zero

as we known that

W =F*S

F =0

then

W= 0

hope this help you

Discussion

31.	A light 'A' deviates more than light 'B' , which light is faster
Answer» ANSWER: bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

31.

A light 'A' deviates more than light 'B' , which light is faster

Answer»

ANSWER:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Discussion

32.	Find equivalent resistance in series combination of resistance
Answer» Series Combination The resistors are connected along the same line The current remains same THROUGHOUT Let there be two resistors with potential DIFFERENCES $V_1 \ and \ V_2$ respectively The net potential DIFFERENCE WOULD be $<klux>V</klux> = V_1 + V_2$ From Ohm's Law, V = IR $\longrightarrow IR = IR_1 + IR_2 \\ \\ \longrightarrow IR = I(R_1 + R_2) \\ \\ \longrightarrow R = R_1 + R_2$ For 'n' number of resistors, $R = R_1 + R_2 + \cdots + R_n$

32.

Find equivalent resistance in series combination of resistance

Answer»

Series Combination

The resistors are connected along the same line

The current remains same THROUGHOUT

Let there be two resistors with potential DIFFERENCES $V_1 \ and \ V_2$ respectively

The net potential DIFFERENCE WOULD be

$<klux>V</klux> = V_1 + V_2$

From Ohm's Law,

V = IR

$\longrightarrow IR = IR_1 + IR_2 \\ \\ \longrightarrow IR = I(R_1 + R_2) \\ \\ \longrightarrow R = R_1 + R_2$

For 'n' number of resistors,

$R = R_1 + R_2 + \cdots + R_n$

Discussion

33.	Correct answers will be marked as brainliest... I wanna correct answers.
Answer» Explanation: A) the process is ELECTROLYSIS B) A process in which a chemical change, especially decomposition, is brought about by passing an electric current through a solution of electrolytes so that the electrolyte's ions move toward the negative and positive electrodes and react with them. C) in this REATION :Electrolysis of a silver nitrate solution produces oxygen at the anode and silver at the cathode. ... As stated in the INTRODUCTION, most REACTIONS at the cathode correlate well with the standard reduction potentials. Only hydrogen is produced from the electrolysis of alkali metal, alkaline earth and aluminum nitrates. D) You would get silver at the cathode, and oxygen at the anode. Since silver is below hydrogen in the spectrochemical series,it TENDS to get reduced over hydrogen, similarly, since NO3−NOX3X− is above OH−OHX− , it tends not to get oxidised, therefore giving oxygen. Ag++e−⟶AgAgX++eX−⟶Ag (at cathode) 4OH−⟶O2+2H2O+4e‐ (at anode ) hope that was helpful pls mark me as brainliest

33.

Correct answers will be marked as brainliest... I wanna correct answers.

Answer»

Explanation:

A) the process is ELECTROLYSIS

B) A process in which a chemical change, especially decomposition, is brought about by passing an electric current through a solution of electrolytes so that the electrolyte's ions move toward the negative and positive electrodes and react with them.

C) in this REATION :Electrolysis of a silver nitrate solution produces oxygen at the anode and silver at the cathode. ... As stated in the INTRODUCTION, most REACTIONS at the cathode correlate well with the standard reduction potentials. Only hydrogen is produced from the electrolysis of alkali metal, alkaline earth and aluminum nitrates.

D) You would get silver at the cathode, and oxygen at the anode.

Since silver is below hydrogen in the spectrochemical series,it TENDS to get reduced over hydrogen, similarly, since NO3−NOX3X− is above OH−OHX− , it tends not to get oxidised, therefore giving oxygen.

Ag++e−⟶AgAgX++eX−⟶Ag (at cathode)

4OH−⟶O2+2H2O+4e‐ (at anode )

hope that was helpful pls mark me as brainliest

Discussion

34.	A boy of mass 10 kg is standing on a 4 kg block as shown. The whole system is on smooth level ground. The boy jumps to the right with a velocity of 7 m/s relative to the 4 kg block. Find the maximum velocity of 1 kg block (in m/sec) in the subsequent motion.
Answer» Answer: NICE question by the WAY . I think it can be SOLVED by LAW of CONSERVATION of mass.

34.

A boy of mass 10 kg is standing on a 4 kg block as shown. The whole system is on smooth level ground. The boy jumps to the right with a velocity of 7 m/s relative to the 4 kg block. Find the maximum velocity of 1 kg block (in m/sec) in the subsequent motion.

Answer»

Answer:

NICE question by the WAY . I think it can be SOLVED by LAW of CONSERVATION of mass.

Discussion

35.	In the circuit shown in the figure,initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed.Take charges on C1 and C2 to be Q1 and Q2 and voltage V1 and V2 respectively.Then,Charge on C1 gets redistributed such that1.V1=V22.Q1=Q23.C1V1+C2V2=C1E4. Q1+Q2=3Q
Answer» ANSWER: ALREADY you have POSTED this

35.

In the circuit shown in the figure,initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed.Take charges on C1 and C2 to be Q1 and Q2 and voltage V1 and V2 respectively.Then,Charge on C1 gets redistributed such that1.V1=V22.Q1=Q23.C1V1+C2V2=C1E4. Q1+Q2=3Q

Answer»

ANSWER:

ALREADY you have POSTED this

Discussion

36.	The velocity time (v-t) graph of a body is shown in the figure. For intervals of OC and CB the ratio of the distances covered is:(1)3:1(2)1:3(3)√3:1(4)√3:2
Answer» 3:1 QUESTION was NICE I used trigonometric PROPERTY to solve this THANK you

36.

The velocity time (v-t) graph of a body is shown in the figure. For intervals of OC and CB the ratio of the distances covered is:(1)3:1(2)1:3(3)√3:1(4)√3:2

Answer»

3:1

QUESTION was NICE

I used trigonometric PROPERTY to solve this

THANK you

Discussion

37.	An electric bulb is rated 220V and 100W. When it is operated on 110V thè power consumed will be??PLZ SOLVE IT USING THE FORMULA P=VI
Answer» Answer: P=100 W V=110 V P=VI SO .. I=P/V I=100/200 I=0.5 A SO WITH THE V=110 V P=VI V= 110 V I= 0.5 A SO... P=55 W I HOPE YOU GOT IT......

37.

An electric bulb is rated 220V and 100W. When it is operated on 110V thè power consumed will be??PLZ SOLVE IT USING THE FORMULA P=VI

Answer»

Answer:

P=100 W

V=110 V

P=VI

SO .. I=P/V

I=100/200

I=0.5 A

SO WITH THE V=110 V

P=VI

V= 110 V

I= 0.5 A

SO... P=55 W

I HOPE YOU GOT IT......

Discussion

38.	Section-A1. (i) Powers of two electric bulb are 100 W and 200 WBoth are connected from mains of 220V. The ratio of resis-0tance of their filaments will be:10(a) 1:2(b) 2:1(a) 1.d) 4.1explain with solution
Answer» Given: P₁=100W, P₂=200W, and V=220V Answer: Power=Current×Potenial difference P=VI......(1) V=IR (Ohm's law) I=V/R....(2) Substituting (2) in (1); P=V²/R =>R=V²/P Risistance for 1ST bulb; R₁=(220)²/100 R₁=48400/100 Thus, R₁=484 Ohm......(3) Now, RESISTANCE for 2nd bulb; R₂=(220)²/200 and, R₂=242 Ohm......(4) Ratio of R₁and R₂: R₁:R₂=484/242 Therefore, *R¹:R²=2:1* *Thus, OPTION* (b) is *the* *answer* I hope it helps ^_^ Please mark as Brainliest

38.

Section-A1. (i) Powers of two electric bulb are 100 W and 200 WBoth are connected from mains of 220V. The ratio of resis-0tance of their filaments will be:10(a) 1:2(b) 2:1(a) 1.d) 4.1explain with solution

Answer»

Given: P₁=100W, P₂=200W, and V=220V

Answer:

Power=Current×Potenial difference

P=VI......(1)

V=IR (Ohm's law)

I=V/R....(2)

Substituting (2) in (1);

P=V²/R

=>R=V²/P

Risistance for 1ST bulb;

R₁=(220)²/100

R₁=48400/100

Thus, R₁=484 Ohm......(3)

Now, RESISTANCE for 2nd bulb;

R₂=(220)²/200

and, R₂=242 Ohm......(4)

Ratio of R₁and R₂:

R₁:R₂=484/242

Therefore, R¹:R²=2:1

Thus, OPTION (b) is the answer

I hope it helps ^_^

Please mark as Brainliest

Discussion

39.	a metal sphere cools @ 0.05 degrees celsius per second when its temperature is 70 degree Celsius and at the rate of 0.0 25 degree Celsius per second when its temperature is 50 degree Celsius determine the temperature of the surroundings and find the rate of cooling when the temperature of metal sphere is 40 degree Celsius
Answer» ANSWER: hshsbdbxbz Explanation: gxhsbdbxbxbxbxbxbdhdjxbxhdbxhxbbxhxhxbxhxbxbxbhd

39.

a metal sphere cools @ 0.05 degrees celsius per second when its temperature is 70 degree Celsius and at the rate of 0.0 25 degree Celsius per second when its temperature is 50 degree Celsius determine the temperature of the surroundings and find the rate of cooling when the temperature of metal sphere is 40 degree Celsius

Answer»

ANSWER:

hshsbdbxbz

Explanation:

gxhsbdbxbxbxbxbxbdhdjxbxhdbxhxbbxhxhxbxhxbxbxbhd

Discussion

40.	A particel is performing simple harmonic motion its maximum velocity is 3m/s and amplitude of motion is 0.2m. calculate the Time period of motion
Answer» EXPLANATION: v=wa 15=w T=2π/w T=6.28/15 T=0.42s

40.

A particel is performing simple harmonic motion its maximum velocity is 3m/s and amplitude of motion is 0.2m. calculate the Time period of motion

Answer»

EXPLANATION:

v=wa

15=w

T=2π/w

T=6.28/15

T=0.42s

Discussion

41.	Consider two generator AC nd DC @ what is the speciality of the electricity reaching the galvanometer if the armature of both the generator are made to rotate?
Answer» Answer: in DC MOTOR the current all be in the same direction but in ac GENERATOR the the current all change its direction Explanatio

41.

Consider two generator AC nd DC @ what is the speciality of the electricity reaching the galvanometer if the armature of both the generator are made to rotate?

Answer»

Answer:

in DC MOTOR the current all be in the same direction but in ac GENERATOR the the current all change its direction

Explanatio

Discussion

42.	4. Amongst the following statements whichis true for a photosensitive material?(a) All materials show photosensitivity tosome or more extent(b) Different photosensitive materials havesame sensitivity(c) Same photosensitive substances givedifferent response to light of differentwavelengths(d) All photosensitive materials giveresponse to green light
Answer» ANSWER: It's option C) Same PHOTOSENSITIVE SUBSTANCE give different RESPONSE to LIGHT of different wavelengths... Explanation: hope it helps...

42.

4. Amongst the following statements whichis true for a photosensitive material?(a) All materials show photosensitivity tosome or more extent(b) Different photosensitive materials havesame sensitivity(c) Same photosensitive substances givedifferent response to light of differentwavelengths(d) All photosensitive materials giveresponse to green light

Answer»

ANSWER:

It's option C) Same PHOTOSENSITIVE SUBSTANCE give different RESPONSE to LIGHT of different wavelengths...

Explanation:

hope it helps...

Discussion

43.	Convert 37.5celsius into farhenhit
Answer» Answer: 99.5 DEGREE FARENHEIT

43.

Convert 37.5celsius into farhenhit

Answer»

Answer:

99.5 DEGREE FARENHEIT

Discussion

44.	Why planets do not twinkle?
Answer» Answer: The planet are closer to the earth as compared to the stars so the light receive from the planets MUST GREATER and the FLUCTUATION caused in the amount of light due to the atmospheric reaction are negligble as a compared to the amount of a light receive from them so that our planets do not TWINKLE.

44.

Why planets do not twinkle?

Answer»

Answer:

The planet are closer to the earth as compared to the stars so the light receive from the planets MUST GREATER and the FLUCTUATION caused in the amount of light due to the atmospheric reaction are negligble as a compared to the amount of a light receive from them so that our planets do not TWINKLE.

Discussion

45.	Advanced sunrise and delay sunset
Answer» ANSWER: I C penny understand SORRY bruh

45.

Advanced sunrise and delay sunset

Answer»

ANSWER:

I C penny understand SORRY bruh

Discussion

46.	The displacement of a particle varies according to the relation x= 3 sin 100t + 8cos^2 50t. Which of the following is INCORRECT about this motion .(1) the motion of the particle is SHM (2) the amplitude of the system of the particle is 5 units.(3) amplitude of the resultant SHM is √73 units(4) the maximum displacement of the particle from the origin is 9 units .
Answer» ANSWER is OPTION (3.) . It is incorrect In SEARCH of BRAINLIEST answer

46.

The displacement of a particle varies according to the relation x= 3 sin 100t + 8cos^2 50t. Which of the following is INCORRECT about this motion .(1) the motion of the particle is SHM (2) the amplitude of the system of the particle is 5 units.(3) amplitude of the resultant SHM is √73 units(4) the maximum displacement of the particle from the origin is 9 units .

Answer»

ANSWER is OPTION (3.) . It is incorrect

In SEARCH of BRAINLIEST answer

Discussion

47.	Prakash ke apavartan ke do niyam kon kon hai
Answer» Answer: light TRAVELS in STRAIGHT line light takes a PATH to move Explanation: diagram of RECTILINEAR propagation of light

47.

Prakash ke apavartan ke do niyam kon kon hai

Answer»

Answer:

light TRAVELS in STRAIGHT line

light takes a PATH to move

Explanation:

diagram of RECTILINEAR propagation of light

Discussion

48.	Please solve it..it's urgent
Answer» ANSWER: SORRY.... The QUESTION is not CLEAR!!

48.

Please solve it..it's urgent

Answer»

ANSWER:

SORRY.... The QUESTION is not CLEAR!!

Discussion

49.	One beat means that the intensity of sound should be
Answer» ANSWER: Beats can be defined as the periodic variation in the intensity of sound at a GIVEN point. due to super-position of two waves having slightly different frequencies." EXPLANATION. When two waves having slight DIFFERENCE of frequency and same AMPLITUDE pass through the same region of space , interference takes place.

49.

One beat means that the intensity of sound should be

Answer»

ANSWER:

Beats can be defined as the periodic variation in the intensity of sound at a GIVEN point. due to super-position of two waves having slightly different frequencies." EXPLANATION. When two waves having slight DIFFERENCE of frequency and same AMPLITUDE pass through the same region of space , interference takes place.

Discussion

50.	On every two spherical circles, the power of 10 lacks 5 electrons, if the distance between them is 1 m, calculate the electric current.
Answer» EXPLANATION: jjjjjjjjhh kkkkkkkkkkkkkkvvgghjj

50.

On every two spherical circles, the power of 10 lacks 5 electrons, if the distance between them is 1 m, calculate the electric current.

Answer»

EXPLANATION:

jjjjjjjjhh kkkkkkkkkkkkkkvvgghjj

Discussion

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