67486 + Interview Questions in Secondary School in Physics

1.	radius of third bohr orbit for h hydrogen is 4.5 angstrom . the radius of its fourth bohr orbit is what
Answer» ANSWER: answer is 4.5 X 4 Explanation: as we know r is proportional to N hence r = r~ x 4

1.

radius of third bohr orbit for h hydrogen is 4.5 angstrom . the radius of its fourth bohr orbit is what

Answer»

ANSWER:

answer is 4.5 X 4

Explanation:

as we know r is proportional to N

hence r = r~ x 4

Discussion

2.	If radius of earth is halved, what would be the length of a day?
Answer» ANSWER: it WOULD be 24 HOURS only because the VELOCITY of rotation would be the same

2.

If radius of earth is halved, what would be the length of a day?

Answer»

ANSWER:

it WOULD be 24 HOURS only because the VELOCITY of rotation would be the same

Discussion

3.	Why sodium is kept immersed in kerosene
Answer» Answer: as it is highle REACTIVE and STARTS burning in CONTACT of OXYGEN

3.

Why sodium is kept immersed in kerosene

Answer»

Answer:

as it is highle REACTIVE and STARTS burning in CONTACT of OXYGEN

Discussion

4.	Explain biot savart law. Find out the magnetic field due to current loop at an axial point.
Answer» Answer: A current carrying wire generates a magnetic field. ACCORDING to Biot-Savart's law, themagnetic field at a POINT DUE to an element of a conductor carrying current is, Directly PROPORTIONAL to the strength of the current, i. ... Inversely proportional to the square of the distance r between the element and the point.

4.

Explain biot savart law. Find out the magnetic field due to current loop at an axial point.

Answer»

Answer:

A current carrying wire generates a magnetic field. ACCORDING to Biot-Savart's law, themagnetic field at a POINT DUE to an element of a conductor carrying current is, Directly PROPORTIONAL to the strength of the current, i. ... Inversely proportional to the square of the distance r between the element and the point.

Discussion

5.	How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min(please give me a explanation for this answer)
Answer» Answer: we KNOW, HALF life of P-32 is 14.29 days $\frac{1}{2} part \: will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of \: \frac{1}{2} ) = \frac{1}{4} \: will \: diintegrate \: in \: 14.29 \: days \\ (\frac{1}{2} of \: \frac{1}{4}) = \frac{1}{8} will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of\frac{1}{8} ) = \frac{1}{16} will \: disintegrate \: in \: 14.29 \: days \\ \frac{1}{2} of \: \frac{1}{16} = \frac{1}{32} will \: disintegrate \: in \: 14.29 \: days$ so, TOTAL time taken=(14.29×5) days=71.45 days

5.

How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min(please give me a explanation for this answer)

Answer»

Answer:

we KNOW, HALF life of P-32 is 14.29 days

$\frac{1}{2} part \: will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of \: \frac{1}{2} ) = \frac{1}{4} \: will \: diintegrate \: in \: 14.29 \: days \\ (\frac{1}{2} of \: \frac{1}{4}) = \frac{1}{8} will \: disintegrate \: in \: 14.29 \: dys \\ (\frac{1}{2} of\frac{1}{8} ) = \frac{1}{16} will \: disintegrate \: in \: 14.29 \: days \\ \frac{1}{2} of \: \frac{1}{16} = \frac{1}{32} will \: disintegrate \: in \: 14.29 \: days$

so, TOTAL time taken=(14.29×5) days=71.45 days

Discussion

6.	What is free fall ..and give example
Answer» FREE fall is any motion of a body where gravity is the only force ACTING UPON it. Examples of objects in free fall motion: The moon is in free fall motion. An object dropped at the TOP of a drop tube.

6.

What is free fall ..and give example

Answer»

FREE fall is any motion of a body where gravity is the only force ACTING UPON it.

Examples of objects in free fall motion: The moon is in free fall motion. An object dropped at the TOP of a drop tube.

Discussion

7.	Our Sun is so big that it can attract so many huge planets and many celestial body in a specific orbit. So if we leave a spaceship undisturbed(no force from left, no force from right, no force from front, no force from back)then will it revolve around the sun in a specific orbit. If yes than why? If no than also why?Please answer!I will mark you as brainiest!
Answer» Explanation: hey! First of all, saying the planets go around the Sun is just another way of saying the planets are in orbit around the Sun. A planet orbiting the Sun is like the moon or a NASA satellite orbiting EARTH. Now why does a planet orbit the Sun and not the Sun orbit the planet? The lighter object orbits the heavier one, and the Sun is, by far, the heaviest object in the solar system. The Sun is 1000 TIMES heavier than the largest planet, JUPITER (which also happens to be my FAVORITE planet), and it is more than 300,000 times heavier than Earth (another planet I am very fond of). In the same way, the moon and satellites we LAUNCH orbit Earth because they are so much lighter than our planet. hope it will be helpful ✌️ #MrSingh

7.

Our Sun is so big that it can attract so many huge planets and many celestial body in a specific orbit. So if we leave a spaceship undisturbed(no force from left, no force from right, no force from front, no force from back)then will it revolve around the sun in a specific orbit. If yes than why? If no than also why?Please answer!I will mark you as brainiest!

Answer»

Explanation:

hey!

First of all, saying the planets go around the Sun is just another way of saying the planets are in orbit around the Sun. A planet orbiting the Sun is like the moon or a NASA satellite orbiting EARTH. Now why does a planet orbit the Sun and not the Sun orbit the planet? The lighter object orbits the heavier one, and the Sun is, by far, the heaviest object in the solar system. The Sun is 1000 TIMES heavier than the largest planet, JUPITER (which also happens to be my FAVORITE planet), and it is more than 300,000 times heavier than Earth (another planet I am very fond of). In the same way, the moon and satellites we LAUNCH orbit Earth because they are so much lighter than our planet.

hope it will be helpful ✌️

#MrSingh

Discussion

8.	A uniform metre rule pivoted at the 40 cm mark is kept in a horizontal position by a mass of200 g hung at the 35 cm mark. The mass of the metre rule is_a)75b)100c)175d)200
Answer» ANSWER: is this QUESTION INCOMPLETE ?

8.

A uniform metre rule pivoted at the 40 cm mark is kept in a horizontal position by a mass of200 g hung at the 35 cm mark. The mass of the metre rule is_a)75b)100c)175d)200

Answer»

ANSWER:

is this QUESTION INCOMPLETE ?

Discussion

9.	Please tell the above answrt
Answer» Answer: Newton's LAWS of universal gravitation states that Everly object in the UNIVERSE attracts EVERY other objects with a force which is proportional to the SQUARE of the distance between them Explanation:

9.

Please tell the above answrt

Answer»

Answer:

Newton's LAWS of universal gravitation states that Everly object in the UNIVERSE attracts EVERY other objects with a force which is proportional to the SQUARE of the distance between them

Explanation:

Discussion

10.	What is thunderstorm \| Howis itproduce?
Answer» ANSWER: THUNDERSTORM is PRODUCED in WATER during

10.

What is thunderstorm | Howis itproduce?

Answer»

ANSWER:

THUNDERSTORM is PRODUCED in WATER during

Discussion

11.	When the free ends of a tester are dipped into a solution, the magneticneedle shows deflection. Can you explain the reason?
Answer» Explanation: the deflection in the compass NEEDLE shows that current is flowing through the bonded wire and hence through the CIRCUIT the circuit is complete since friands of the test are DIPPED in a solution the solution is certainly a conducting solution this is the reason why the compass needle SHOW deflection when the tester dipped into a solution

11.

When the free ends of a tester are dipped into a solution, the magneticneedle shows deflection. Can you explain the reason?

Answer»

Explanation:

the deflection in the compass NEEDLE shows that current is flowing through the bonded wire and hence through the CIRCUIT the circuit is complete since friands of the test are DIPPED in a solution the solution is certainly a conducting solution this is the reason why the compass needle SHOW deflection when the tester dipped into a solution

Discussion

12.	How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min
Answer» ANSWER: the TIME TAKEN is 15 MINS

12.

How much time does it take in induced radioactivity to reduce radio phosphorus to 1/32 of its initial valuea)15 minb)150 secc)15 hrd)1.5 min

Answer»

ANSWER:

the TIME TAKEN is 15 MINS

Discussion

13.	When a car accelerates up a hill, whta happens to its kinetic and potenyial energy
Answer» Answer: A simple example involves a stationarycar at the TOP of a hill. As the carcoasts down the hill, it moves faster and so it's kinetic energy INCREASES and it's potential energy decreases. On the way BACK upthe hill, the CAR CONVERTS kinetic energy to potential energy.

13.

When a car accelerates up a hill, whta happens to its kinetic and potenyial energy

Answer»

Answer:

A simple example involves a stationarycar at the TOP of a hill. As the carcoasts down the hill, it moves faster and so it's kinetic energy INCREASES and it's potential energy decreases. On the way BACK upthe hill, the CAR CONVERTS kinetic energy to potential energy.

Discussion

14.	Write the truth table for given circuit.
Answer» here's your ANSWER BUD

Discussion

15.	Arjun driving at 36 km per hour accelerates with uniform velocity at the rate of 0.5 metre per second for 10 seconds calculate the velocity of the car after 10 seconds also calculate the distance travelled by the car
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\therefore{\text{Final\:velocity(v)=15\:m/s}}}$ $\green{\therefore{\text{Distance\:travelled(s)=125\:m}}}$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{ \underline \bold{<klux>GIVEN</klux> : }} \\ : \implies \text{Initial \: velocity(u)= 36 \: km/h} \\ \\ : \implies \text{Acceleration(a) = 0.5 {m/s}}^{2} \\ \\ \implies \text{Time(t) = 10 \: seconds} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Velocity(v)}_{ \text{after \: 10 \: sec}} = ? \\ \\ : \implies \text{Distance \: travelled(s) = ?}$ • ACCORDING to given QUESTION: $\text{Initial \: velocity} = 36 \times \frac{5}{18} = 10 \: {m/s} \\ \\ \bold{Using \: first \: equation \: of \: motion} \\ : \implies \text{v = u + at} \\ \\ : \implies v = 10 + 0.5 \times 10 \\ \\ : \implies v= 10 + 5 \\ \\ \green{: \implies \text{v = 15 \: m/s}} \\ \\ \bold{Using \: second \: equation \: of \: motion}\\ : \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ : \implies s = 10 \times 10 + \frac{1}{2} \times \frac{1}{2} \times {10}^{2} \\ \\ : \implies s = 100 + \frac{1}{4} \times 100 \\ \\ : \implies s = 100 + 25 \\ \\ \green{ : \implies \text{s = \: 125 m}}$

15.

Arjun driving at 36 km per hour accelerates with uniform velocity at the rate of 0.5 metre per second for 10 seconds calculate the velocity of the car after 10 seconds also calculate the distance travelled by the car

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Final\:velocity(v)=15\:m/s}}}$

$\green{\therefore{\text{Distance\:travelled(s)=125\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{<klux>GIVEN</klux> : }} \\ : \implies \text{Initial \: velocity(u)= 36 \: km/h} \\ \\ : \implies \text{Acceleration(a) = 0.5 {m/s}}^{2} \\ \\ \implies \text{Time(t) = 10 \: seconds} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Velocity(v)}_{ \text{after \: 10 \: sec}} = ? \\ \\ : \implies \text{Distance \: travelled(s) = ?}$

• ACCORDING to given QUESTION:

$\text{Initial \: velocity} = 36 \times \frac{5}{18} = 10 \: {m/s} \\ \\ \bold{Using \: first \: equation \: of \: motion} \\ : \implies \text{v = u + at} \\ \\ : \implies v = 10 + 0.5 \times 10 \\ \\ : \implies v= 10 + 5 \\ \\ \green{: \implies \text{v = 15 \: m/s}} \\ \\ \bold{Using \: second \: equation \: of \: motion}\\ : \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ : \implies s = 10 \times 10 + \frac{1}{2} \times \frac{1}{2} \times {10}^{2} \\ \\ : \implies s = 100 + \frac{1}{4} \times 100 \\ \\ : \implies s = 100 + 25 \\ \\ \green{ : \implies \text{s = \: 125 m}}$

Discussion

16.	It is difficult to walk on Sandy surface why
Answer» Answer: sand is SOFT and loosely held and marshy soil is WET and slippery which reduce the FRICTION so,When we walk on the sand we push the sand with our feet but the sand YIELDS, i.e., it does not react back with the same force because of less friction. That is why it is difficult to walk on sand or marshy LAND

16.

It is difficult to walk on Sandy surface why

Answer»

Answer:

sand is SOFT and loosely held and marshy soil is WET and slippery which reduce the FRICTION so,When we walk on the sand we push the sand with our feet but the sand YIELDS, i.e., it does not react back with the same force because of less friction. That is why it is difficult to walk on sand or marshy LAND

Discussion

17.	The diagram shows the velocity-time graph of a car. The carvelocitytimea)decelarated to restb)decelarated to a constant velocityc)accelarated at an incresing rated)accelarated to a constant velocity
Answer» Answer: PLS SHOW the DIAGRAM Then l will ans

17.

The diagram shows the velocity-time graph of a car. The carvelocitytimea)decelarated to restb)decelarated to a constant velocityc)accelarated at an incresing rated)accelarated to a constant velocity

Answer»

Answer:

PLS SHOW the DIAGRAM

Then l will ans

Discussion

18.	Q.5) Thickness of a glass slab is 4mm and refractive index of glassis 1.5. Calculate time takenby light to cross this thickness.
Answer» ANSWER: $4mm - 1.5$ when you will SUBSTRACT then up U will GET answerhdjdjgjdjjehabxkkcnsn as KCJH

18.

Q.5) Thickness of a glass slab is 4mm and refractive index of glassis 1.5. Calculate time takenby light to cross this thickness.

Answer»

ANSWER:

$4mm - 1.5$

when you will SUBSTRACT then up U will GET answerhdjdjgjdjjehabxkkcnsn as KCJH

Discussion

19.	Explain the significance of y and y?
Answer» Answer: HEY MATE here's the answer Explanation: hope it helps you please MARK me down as a brainleist

19.

Explain the significance of y and y?

Answer»

Answer:

HEY MATE here's the answer

Explanation:

hope it helps you

please MARK me down as a brainleist

Discussion

20.	Write the relatin btw G and g
Answer» Answer: G stands for Newton's universal GRAVITATIONAL constant, whereas g stands for the acceleration due to gravity at a certain POINT. G = 6.67300 × 10 -11 N.m 2.kg -2. G is a constant throughout space and time. ... G is a scalar QUANTITY whereas g is a vector qualtity......

20.

Write the relatin btw G and g

Answer»

Answer:

G stands for Newton's universal GRAVITATIONAL constant, whereas g stands for the acceleration due to gravity at a certain POINT. G = 6.67300 × 10 -11 N.m 2.kg -2. G is a constant throughout space and time. ... G is a scalar QUANTITY whereas g is a vector qualtity......

Discussion

21.	State the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum Bob to one side and all Aloe it to oscillate why does the bomb eventually come to this what happened to its inner Jivan Shaili is it of violation of the law of conservation of energygiven answer in short
Answer» Answer: Law of conservation of energy STATES that energy can NEITHER be created nor destroyed, it changes from one state to the other. When the pendulum will oscillate and reaches the HIGHEST point from its mean POSITION then it will have maximum POTENTIAL energy and when it slowly comes down at a low height it will have highest kinetic energy. But the total energy will always remain same.

21.

State the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum Bob to one side and all Aloe it to oscillate why does the bomb eventually come to this what happened to its inner Jivan Shaili is it of violation of the law of conservation of energygiven answer in short

Answer»

Answer:

Law of conservation of energy STATES that energy can NEITHER be created nor destroyed, it changes from one state to the other.

When the pendulum will oscillate and reaches the HIGHEST point from its mean POSITION then it will have maximum POTENTIAL energy and when it slowly comes down at a low height it will have highest kinetic energy.

But the total energy will always remain same.

Discussion

22.	A particle of mass 'm' oscillaling under the influence of Hook's, law restoring force given by F=-kxexhibit SHM with an angular frequency given by_____.
Answer» You can SOLVE this TYPE of QUESTION by SHM EQUATIONS....

Discussion

23.	What is thermodynamics
Answer» $\text{[math]}$ Thermodynamics is a BRANCH of PHYSICAL chemistry which deals with the quantitative RELATIONSHIP between HEAT and other forms of ENERGIES.

Discussion

24.	According to law of equipartition of energy, in thermal equilibrium, the total energy is equally distributedin all possible energy modes, with each mode having an average energy per molecule equal to_____.
Answer» EXPLANATION: TOTAL ENERGY/ no of MODES

24.

According to law of equipartition of energy, in thermal equilibrium, the total energy is equally distributedin all possible energy modes, with each mode having an average energy per molecule equal to_____.

Answer»

EXPLANATION:

TOTAL ENERGY/ no of MODES

Discussion

25.	What is the density of 25 grams
Answer» Answer: The answer is 2.5 g/cm The unit is grams per cubic centimeter. NB - DENSITY can ALSO be KILOGRAMS over cubic meters Hope this HELPS!

25.

What is the density of 25 grams

Answer»

Answer:

The answer is

2.5 g/cm

The unit is grams per cubic centimeter.

NB - DENSITY can ALSO be KILOGRAMS over cubic meters

Hope this HELPS!

Discussion

26.	I want to know the figures of 12 graphs of motion chapter of class9
Answer» ANSWER: I m in 7TH CLASS. .... ........m

26.

I want to know the figures of 12 graphs of motion chapter of class9

Answer»

ANSWER:

I m in 7TH CLASS. ....

........m

Discussion

27.	What is the density of 55 grams
Answer» Explanation: Determine the weight of an object. For EXAMPLE, a GLASS of water weights 200 GRAMS NET (not including the glass). Find out the VOLUME of an object. In our example, it's 200 cm3 .

27.

What is the density of 55 grams

Answer»

Explanation:

Determine the weight of an object. For EXAMPLE, a GLASS of water weights 200 GRAMS NET (not including the glass). Find out the VOLUME of an object. In our example, it's 200 cm3 .

Discussion

28.	The work done by the weight of a 1-kg mass while it moves up through 1m is
Answer» ANSWER: GIVEN:m=1kg h=1m W=? W=mgh W=1×9.8×1 W=9.8J

28.

The work done by the weight of a 1-kg mass while it moves up through 1m is

Answer»

ANSWER:

GIVEN:m=1kg h=1m W=?

W=mgh

W=1×9.8×1

W=9.8J

Discussion

29.	- the difference in the velocities of light in glass and water is0.25x10^8 m/s. calculate the velocity of light in air. Given thateractive index of glass and water with respect to air are 1.5and4/3 respectively.
Answer» => Velocity of light in... Water = 2.25 × 10^8 m/s Glass = 2 × 10^8 m/s

29.

- the difference in the velocities of light in glass and water is0.25x10^8 m/s. calculate the velocity of light in air. Given thateractive index of glass and water with respect to air are 1.5and4/3 respectively.

Answer»

=> Velocity of light in...

Water = 2.25 × 10^8 m/s
Glass = 2 × 10^8 m/s

Discussion

30.	What is unitbof the coefficient of linear expansion
Answer» ANSWER: what is the EQUATION......

30.

What is unitbof the coefficient of linear expansion

Answer»

ANSWER:

what is the EQUATION......

Discussion

31.	Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.
Answer» The magnitude(M) of the magnetic DIPOLE moment = 69.27 Am^2 Explanation: Assuming the angular velocity with which the electron rotates about an AXIS be w, so, Angular velocity = w rod/s w = 2πf f = (w/2π)Hz As we know, Rotating charge follows generated current, Equivalent current = qf = wq/2π The GIVEN case can be considered as a case of a current-bearing loop. Assuming the RADIUS be R, so vector r = πr^2n n cap - direction is ⊥ to the rotation, Magnetic moment = IA *= wq/2π πr^2 = wqr^2/2 In favor of an electron, q = e = 1.6×10^-19 C ∴ Magnetic moment = wer^2/2 Given, N = 300, D = 14cm r = 14/2 = 7 × 10^-2m (current) i = 15 A Magnetic dipole moment associated with the coil, M = NI(πr^2) ⇒ M = 300 * 15 * 22/7 * (7 × 10^-2)^2 ∵ M = 69.27 Am^2 Learn more:** Magnitude brainly.in/question/8036385

31.

Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.

Answer»

The magnitude(M) of the magnetic DIPOLE moment = 69.27 Am^2

Explanation:

Assuming the angular velocity with which the electron rotates about an AXIS be w,

so,

Angular velocity = w rod/s

w = 2πf

f = (w/2π)Hz

As we know,

Rotating charge follows generated current,

Equivalent current = qf

= wq/2π

The GIVEN case can be considered as a case of a current-bearing loop.

Assuming the RADIUS be R, so

vector r = πr^2n

n cap - direction is ⊥ to the rotation,

Magnetic moment = IA

= wq/2π * πr^2

= wqr^2/2

In favor of an electron,

q = e = 1.6×10^-19 C

∴ Magnetic moment = wer^2/2

Given,

N = 300,

D = 14cm

r = 14/2 = 7 × 10^-2m

(current) i = 15 A

Magnetic dipole moment associated with the coil,

M = NI(πr^2)

⇒ M = 300 * 15 * 22/7 * (7 × 10^-2)^2

∵ M = 69.27 Am^2

Learn more: Magnitude

brainly.in/question/8036385

Discussion

32.	Angular velocity of second hand of a watch in rad\ sec. is ?
Answer» Answer: The second HAND goes through 2π RADIANS in 1 min, or 2π radian/60 seconds, so ω = π/30 RAD. s-1 = 0.03 rad. s-1.

32.

Angular velocity of second hand of a watch in rad\ sec. is ?

Answer»

Answer:

The second HAND goes through 2π RADIANS in 1 min, or 2π radian/60 seconds, so ω = π/30 RAD. s-1 = 0.03 rad. s-1.

Discussion

33.	When current flowing through one coil changes from 0 Amp to 15 Amp in0.2 s, an emf of 750V is induced in an adjacent coil. Calculate the coefficientof mutual inductance of the two coils.
Answer» Answer: 15×750=x x=750/5 x=150/0.2 x=30.2

33.

When current flowing through one coil changes from 0 Amp to 15 Amp in0.2 s, an emf of 750V is induced in an adjacent coil. Calculate the coefficientof mutual inductance of the two coils.

Answer»

Answer:

15×750=x

x=750/5

x=150/0.2

x=30.2

Discussion

34.	An iron bullet is tnavelling with a speed 100 m/ss brought to rest after heating the target. Assuming80% of the kinetic enery is converted to theheat in the bullet Itself, Find the nise in thetemp., of the buller after impact. Given specificheat Of Iron 420 JKG^-1K^-1.
Answer» ANSWER => INCREASE in temp. of IRON bullet is 9.52 K

Discussion

35.	How many alpha and beta particles are emittedin the following reaction.92 uranium 238 - 82 lead 206 ? I need the explanation of the answer too..
Answer» ANSWER: which CLASS QUESTION is this

35.

How many alpha and beta particles are emittedin the following reaction.92 uranium 238 - 82 lead 206 ? I need the explanation of the answer too..

Answer»

ANSWER:

which CLASS QUESTION is this

Discussion

36.	Which animal belongs to phylum Arthopoda
Answer» Answer: ARTHROPOD, any member of the phylum Arthropoda, the LARGEST phylum in the animal kingdom, which INCLUDES such FAMILIAR FORMS as lobsters, crabs, spiders, mites, insects, centipedes, and millipedes. About 84 percent of all known species of animals are members of this phylum. Explanation: Please make me a brainlist answer and like and follow please

36.

Which animal belongs to phylum Arthopoda

Answer»

Answer:

ARTHROPOD, any member of the phylum Arthropoda, the LARGEST phylum in the animal kingdom, which INCLUDES such FAMILIAR FORMS as lobsters, crabs, spiders, mites, insects, centipedes, and millipedes. About 84 percent of all known species of animals are members of this phylum.

Explanation:

Please make me a brainlist answer and like and follow please

Discussion

37.	Explain how, the oxygen in air (or atmosphere) is replaced
Answer» Answer: CARBON dioxide is TAKEN by the PLANTS and by the process of photosynthesis is converted into oxygen and then RELEASED.

37.

Explain how, the oxygen in air (or atmosphere) is replaced

Answer»

Answer:

CARBON dioxide is TAKEN by the PLANTS and by the process of photosynthesis is converted into oxygen and then RELEASED.

Discussion

38.	A body executes simple harmonic motion according to following equation.X=5.0cos[2πt+π4] m where t=1.5 s, calculate 1 displacement 2 velocity 3 acceleration
Answer» Answer: x = -5/√2 m. v = 10π/√2= 22.21 m/s a= 20π^2/√2= 139.58 m/s^2 Explanation: 1. displacement at t=1.5=3/2 is x=5 COS[3π+π/4] = -5/√2m. 2. VELOCITY (v) = dx/dt= -10π SIN[2πt+π/4] at t=1.5=3/2, v = 10π/√2= 22.21 m/s acceleration (a) = dv/dt = -20π^2 cos[2πt+π/4] at t=1.5=3/2, a= 20π^2/√2= 139.58 m/s^2

38.

A body executes simple harmonic motion according to following equation.X=5.0cos[2πt+π4] m where t=1.5 s, calculate 1 displacement 2 velocity 3 acceleration

Answer»

Answer:

x = -5/√2 m.

v = 10π/√2= 22.21 m/s

a= 20π^2/√2= 139.58 m/s^2

Explanation:

1. displacement at t=1.5=3/2 is

x=5 COS[3π+π/4] = -5/√2m.

2. VELOCITY (v) = dx/dt= -10π SIN[2πt+π/4]

at t=1.5=3/2,

v = 10π/√2= 22.21 m/s

acceleration (a) = dv/dt = -20π^2 cos[2πt+π/4]

at t=1.5=3/2,

a= 20π^2/√2= 139.58 m/s^2

Discussion

39.	Seven students measured the diameter of a ball bearing and obtained the following values. 9.50mm, 9.30mm, 9.80mm,9.20mm, 9.40mm, 9.60mm and 9.70mm.1. Which of the following above values has the largest possible error?2. Calculate the best value of the diameter of the ball bearing.3. Name the possible error that can occur when measuring4. How many significant figures are that values expressed?5. Which value is most likely an error?
Answer» Explanation: 1. 9.80mm and 9.20mm. 2. mean value= SUMMATION of all OBSERVED value/total no. of observed value so BEST value is 9.5. 3. observational error or experimental error. 4. 2 significant figured. 5. 9.80mm.

39.

Seven students measured the diameter of a ball bearing and obtained the following values. 9.50mm, 9.30mm, 9.80mm,9.20mm, 9.40mm, 9.60mm and 9.70mm.1. Which of the following above values has the largest possible error?2. Calculate the best value of the diameter of the ball bearing.3. Name the possible error that can occur when measuring4. How many significant figures are that values expressed?5. Which value is most likely an error?

Answer»

Explanation:

1. 9.80mm and 9.20mm.

2. mean value= SUMMATION of all OBSERVED value/total no. of observed value

so BEST value is 9.5.

3. observational error or experimental error.

4. 2 significant figured.

5. 9.80mm.

Discussion

40.	Find the resultant of resistance Ab
Answer» ANSWER: the RESULTANT RESISTANCE is 1 OHM

40.

Find the resultant of resistance Ab

Answer»

ANSWER:

the RESULTANT RESISTANCE is 1 OHM

Discussion

41.	What is meant by uniform circular motion? Give one example for it.
Answer» Answer: UNIFORM motion is CIRCULAR motion it is move along with At fixed POINT it is called uniform motion. Explanation: ex-ceiling fan, needle of MACHINES,

41.

What is meant by uniform circular motion? Give one example for it.

Answer»

Answer:

UNIFORM motion is CIRCULAR motion it is move along with At fixed POINT it is called uniform motion.

Explanation:

ex-ceiling fan, needle of MACHINES,

Discussion

42.	11. A temperature of a 50 kg block increases by 15°C when 337,500 J of thermal energy are added to the block. (Chapter 5 – Pages 141-142) a. What is the specific heat of the object? Show the appropriate equation from your book and show your work with units. b. What is the block made of? Use the chart on page 141. c. Is this block a good material for insulators or conductors?
Answer» Heat = mass × SPECIFIC heat × temperature change Q = m C ΔT Given: q = 337500 J m = 50 kg ΔT = 15°C Substitute: 337500 J = (50 kg) C (15°C) C = 450 J/kg/°C Specific heat is usually RECORDED in J/g/°C or kJ/kg/°C. Converting: C = 0.45 J/g/°C = 0.45 kJ/kg/°C

Discussion

43.	How do we locate the position of the pole star
Answer» Answer: Locate the Ursa Major and locate the QUADRILATERAL in it. Select the two STARS on the far SIDE of the quadrilateral. Join these stars with a line and extend this imaginary line towards the top of the ladle. A faint star which meets this line is the POLE star.

43.

How do we locate the position of the pole star

Answer»

Answer:

Locate the Ursa Major and locate the QUADRILATERAL in it.

Select the two STARS on the far SIDE of the quadrilateral.

Join these stars with a line and extend this imaginary line towards the top of the ladle.

A faint star which meets this line is the POLE star.

Discussion

44.	What is vectorwhat is vector
Answer» ANSWER: VECTOR MEANS it has both MAGNITUDE and direction Mark me as BRAINLIEST

44.

What is vectorwhat is vector

Answer»

ANSWER:

VECTOR MEANS it has both MAGNITUDE and direction

Mark me as BRAINLIEST

Discussion

45.	Which of the following represents the correct relation between Avogadro's number (No), number ofparticles (N) and moles (n)?d.n=N/Nob. n = No/Nc. n=Nx Nod. all are correct
Answer» Explanation: Which of the FOLLOWING REPRESENTS the CORRECT relation between Avogadro's number (No), number of particles (N) and moles (n)? d.n=N/No b. n = No/N✅✅ c. n=Nx No d. all are correct

45.

Which of the following represents the correct relation between Avogadro's number (No), number ofparticles (N) and moles (n)?d.n=N/Nob. n = No/Nc. n=Nx Nod. all are correct

Answer»

Explanation:

Which of the FOLLOWING REPRESENTS the CORRECT relation between Avogadro's number (No), number of

particles (N) and moles (n)?

d.n=N/No

b. n = No/N✅✅

c. n=Nx No

d. all are correct

Discussion

46.	A ball bearing has a diameter of 1cm. calculate ( to 2 decimal place) its volume using formula V=4/3πr3
Answer» ANSWER: r=1/2 of DIAMETER= 0.5cm v=4/3 22/7 (0.5) ³ =88/21* 0.125cm³ =11/21 cm³ =0.523809524 cm³

46.

A ball bearing has a diameter of 1cm. calculate ( to 2 decimal place) its volume using formula V=4/3πr3

Answer»

ANSWER:

r=1/2 of DIAMETER= 0.5cm

v=4/3 *22/7* (0.5) ³

=88/21* 0.125cm³

=11/21 cm³

=0.523809524 cm³

Discussion

47.	What is the value of premitivity of medium whose dielectric constant os 1
Answer» Answer: same as that of free space IE 8.9×10^-12 as permittivity of medium= permittivity of free space x dielectric CONSTANT

47.

What is the value of premitivity of medium whose dielectric constant os 1

Answer»

Answer:

same as that of free space

IE 8.9×10^-12

as permittivity of medium= permittivity of free space x dielectric CONSTANT

Discussion

48.	Field of induction 10-2T. The twist constant of phosphor bronzefibre is 12x107'Nm/degree. Calculate the deflectionproduced.0. 31. Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.
Answer» EXPLANATION: SORRY I didn't have ANS. of this QUESTION.

48.

Field of induction 10-2T. The twist constant of phosphor bronzefibre is 12x107'Nm/degree. Calculate the deflectionproduced.0. 31. Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.

Answer»

EXPLANATION:

SORRY I didn't have ANS. of this QUESTION.

Discussion

49.	25. Define suriase energy. Prove that it is numerically equal to the surface tension26. State and prove Work - Energy theorem.27. Which of the following functions of time represent
Answer» Answer: A is the total increase is the surface AREA of the film. Therefore the surface energy and the surface tension are numerically equal The principle of work and kinetic energy (also KNOWN as the work-energy theorem) states that the work done by the sum of all FORCES ACTING on a particle equals the change in the kinetic energy of the particle. ... The kinetic energy of the block INCREASES as a result by the amount of work. Explanation: *pls* *mark* it as *brainlist* *answer*

49.

25. Define suriase energy. Prove that it is numerically equal to the surface tension26. State and prove Work - Energy theorem.27. Which of the following functions of time represent

Answer»

Answer:

A is the total increase is the surface AREA of the film. Therefore the surface energy and the surface tension are numerically equal

The principle of work and kinetic energy (also KNOWN as the work-energy theorem) states that the work done by the sum of all FORCES ACTING on a particle equals the change in the kinetic energy of the particle. ... The kinetic energy of the block INCREASES as a result by the amount of work.

Explanation:

pls mark it as brainlist answer

Discussion

50.	2 (i) Define Calorimetry. Ans
Answer» ANSWER : it is a process of measuring amount of HEAT released or ABSORBED during a chemical reaction... please MARK as brainliest answer and FOLLOW me

50.

2 (i) Define Calorimetry. Ans

Answer»

ANSWER :

it is a process of measuring amount of HEAT released or ABSORBED during a chemical reaction...

please MARK as brainliest answer and FOLLOW me

Discussion

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