67486 + Interview Questions in Secondary School in Physics

1.	16.Analyse the figure and answer the following questions.200 W, 230 V 200 W, 230 Vac © 230 Vs1s2(a)If the switch S, is on, which bulb will glow? How much current is flowing through thefuse at this time?If both the switches are on, what changes can be observed in the circuit ? Justify youranswer.2(b)2P.T.O.
Answer» ANSWER: ?SORRY EXPLANATION: ? I CANT UNDERSTAND

1.

16.Analyse the figure and answer the following questions.200 W, 230 V 200 W, 230 Vac © 230 Vs1s2(a)If the switch S, is on, which bulb will glow? How much current is flowing through thefuse at this time?If both the switches are on, what changes can be observed in the circuit ? Justify youranswer.2(b)2P.T.O.

Answer»

ANSWER:

?SORRY

EXPLANATION:

? I CANT UNDERSTAND

Discussion

2.	Q} What is half wave and full wave rectifier? explain.
Answer» Circuit GlobeElectronic TermsHalf Wave and FULL Wave Rectifier HALF Wave and Full Wave Rectifier In Half Wave Rectifier, when AC supply is applied at the input, positive half cycle appears across the load, whereas the negative half cycle is suppressed. This can be done by USING the semiconductor PN – junction diode. The diode allows the current to flow only in one direction. Thus, convert the AC voltage into DC voltage. In Full Wave Rectification, when the AC supply is applied at the input, during both the half cycles (i.e., positive as well as negative) current flows through the load in the same direction. This can be achieved by using two crystal DIODES. The two diodes conduct the current alternately. *Hope* it *helps* *you* *mark* as *brainliest* *please*

2.

Q} What is half wave and full wave rectifier? explain.

Answer»

Circuit GlobeElectronic TermsHalf Wave and FULL Wave Rectifier

HALF Wave and Full Wave Rectifier

In Half Wave Rectifier, when AC supply is applied at the input, positive half cycle appears across the load, whereas the negative half cycle is suppressed. This can be done by USING the semiconductor PN – junction diode. The diode allows the current to flow only in one direction. Thus, convert the AC voltage into DC voltage.

In Full Wave Rectification, when the AC supply is applied at the input, during both the half cycles (i.e., positive as well as negative) current flows through the load in the same direction. This can be achieved by using two crystal DIODES. The two diodes conduct the current alternately.

Hope it helps you mark as brainliest please

Discussion

3.	15. Scientist Faraday induced current in coil of conductor without using slip or splitrings and carbon brushes. It is because,A the coil was stationary and magnet was movingB. it was just an experimentC the magnet was moving to and fro and was not rotatingD. the current output was very low
Answer» ANSWER: I THINK OPTION "A" is RIGHT

3.

15. Scientist Faraday induced current in coil of conductor without using slip or splitrings and carbon brushes. It is because,A the coil was stationary and magnet was movingB. it was just an experimentC the magnet was moving to and fro and was not rotatingD. the current output was very low

Answer»

ANSWER:

I THINK OPTION "A" is RIGHT

Discussion

4.	DERIVATION OF CENTRIPETAL FORCE CLASS 11Send me an valid photo of the derivation
Answer» Answer: Dispersion of Light' can be defined as the splitting of WHITE light when it PASSES through a glass prism into its constituent spectrum of COLORS (i.e. violet, indigo, blue, green, YELLOW, orange and RED). Dispersion figuratively means 'distribution' and hence that's exactly what is happening in the picture above.

4.

DERIVATION OF CENTRIPETAL FORCE CLASS 11Send me an valid photo of the derivation

Answer»

Answer:

Dispersion of Light' can be defined as the splitting of WHITE light when it PASSES through a glass prism into its constituent spectrum of COLORS (i.e. violet, indigo, blue, green, YELLOW, orange and RED). Dispersion figuratively means 'distribution' and hence that's exactly what is happening in the picture above.

Discussion

5.	Mention the Advantage of compound pendulum over simple pendulum
Answer» Answer: A simple pendulum 's when all of the mass is FEASIBLE to dealt with as EXISTS in a single POINT . In the CASE of acompound pendulum it is NECESSARY taken into considerationing the allocation of the mass.

5.

Mention the Advantage of compound pendulum over simple pendulum

Answer»

Answer:

A simple pendulum 's when all of the mass is FEASIBLE to dealt with as EXISTS in a single POINT . In the CASE of acompound pendulum it is NECESSARY taken into considerationing the allocation of the mass.

Discussion

6.	Guys anser it right now plz
Answer» Answer: 25 DEGREE C.= 77 degree f. 89 Degreef. = 31.6667 degree C. mrk as BRAINLIEST....

6.

Guys anser it right now plz

Answer»

Answer:

25 DEGREE C.= 77 degree f.

89 Degreef. = 31.6667 degree C.

mrk as BRAINLIEST....

Discussion

7.	What do you mean by rotational motion ? Explain in detail by comparing the rotational motion with the translatory motion on the basis of atleast 8 points
Answer» Answer: in rotatory motion the object MOVES AROUND its axis and in translatory motion the object moves in a STRAIGHT PATH or direction

7.

What do you mean by rotational motion ? Explain in detail by comparing the rotational motion with the translatory motion on the basis of atleast 8 points

Answer»

Answer:

in rotatory motion the object MOVES AROUND its axis and in translatory motion the object moves in a STRAIGHT PATH or direction

Discussion

8.	5. For what angle between A and B,\|A+B\|=\|A-B\|
Answer» ANSWER: ANGLE is 90 degree EXPLANATION: \|A+B\|^2 = \|A\|^2 + \|B\|^2 + 2.\|A\|\|B\|cosα \|A-B\|^2 = \|A\|^2 + \|B\|^2 - 2.\|A\|\|B\|cosα => \|A+B\|=\|A-B\| => 4.\|A\|\|B\|cosα = 0 => cosα = 0 => α = cos^-1 ( 0 ) => α = 90°

8.

5. For what angle between A and B,|A+B|=|A-B|

Answer»

ANSWER:

ANGLE is 90 degree

EXPLANATION:

|A+B|^2 = |A|^2 + |B|^2 + 2.|A||B|cosα

|A-B|^2 = |A|^2 + |B|^2 - 2.|A||B|cosα

=> |A+B|=|A-B|

=> 4.|A||B|cosα = 0

=> cosα = 0

=> α = cos^-1 ( 0 )

=> α = 90°

Discussion

9.	Guys anser it right now plznumber 2.. plz fast
Answer» Answer: 1) ELECTRIC bell 2)microphone 3)speakers 4) generators mark me as the BRAINLIEST

9.

Guys anser it right now plznumber 2.. plz fast

Answer»

Answer:

1) ELECTRIC bell

2)microphone

3)speakers

4) generators

mark me as the BRAINLIEST

Discussion

10.	In a circuit, if filament of the bulb is broken, then which of the following statements istrue?a) The circuit becomes a closed circuit.b) The circuit becomes an open circuit.c) The bulb still glows.d) The current in the circuit increases.Please answer
Answer» EXPLANATION: a) The CIRCUIT BECOMES a CLOSED circuit.

10.

In a circuit, if filament of the bulb is broken, then which of the following statements istrue?a) The circuit becomes a closed circuit.b) The circuit becomes an open circuit.c) The bulb still glows.d) The current in the circuit increases.Please answer

Answer»

EXPLANATION:

a) The CIRCUIT BECOMES a CLOSED circuit.

Discussion

11.	calculate the temperature at which the reading on the fahrenheit scale is double the reading on the Celsius scale
Answer» Answer: LET temperatures in FAHRENHEIT = 2C 2C = 9/5 C + 32 2C = (9C +160) / 5 10 C = 9C + 160 1C = 160 at 160 DEGREE Celsius reading on the Fahrenheit scale would be 320 f

11.

calculate the temperature at which the reading on the fahrenheit scale is double the reading on the Celsius scale

Answer»

Answer:

LET temperatures in FAHRENHEIT = 2C

2C = 9/5 C + 32

2C = (9C +160) / 5

10 C = 9C + 160

1C = 160

at 160 DEGREE Celsius reading on the Fahrenheit scale would be 320 f

Discussion

12.	Definition of No zero errorplz answer
Answer» Answer: Any indication that a measuring system gives a false reading when true value of measured quantity is zero.A zero error may result in a SYSTEMATIC UNCERTAINLY. HENCE it's called no zero error.

12.

Definition of No zero errorplz answer

Answer»

Answer:

Any indication that a measuring system gives a false reading when true value of measured quantity is zero.A zero error may result in a SYSTEMATIC UNCERTAINLY. HENCE it's called no zero error.

Discussion

13.	a stone is dropped from a hundred metre cliff. What is the velocity of the stone after 3 seconds ? When does the stone hit the ground? With what velocity does the stone hit the ground?
Answer» ANSWER: GIVEN: Height = 100 metres Initial Velocity = 0 m/s To find: Velocity of stone after 3 SECONDS Velocity with which stone hits the ground TIME after which the stone hits ground Calculation: Velocity after 3 seconds: $\therefore \: v = u + gt \\ = > v = 0 \: + 10 \times 3 \\ = > v = 30 \: metres \:{s}^{-1}$ Velocity on reaching ground: $\therefore \: {v}^{2} = {u}^{2} + 2gh \\ = > {v}^{2} = {0}^{2} + 2 \times 10 \times 100 \\ = > {v}^{2} = 2000 \\ = > v = \sqrt{2000 } \\ = > v = 44.72 \: m {s}^{ - 1}$ Time after which body reaches ground : $\therefore \: h = ut + \frac{1}{2} a {t}^{2} \\ = > 100 = 0 + \frac{1}{2} \times 10 \times {t}^{2} \\ = > {t}^{2} = 20 \\ = > t = \sqrt{20} \\ = > t = 4.47 \: sec.$

13.

a stone is dropped from a hundred metre cliff. What is the velocity of the stone after 3 seconds ? When does the stone hit the ground? With what velocity does the stone hit the ground?

Answer»

ANSWER:

GIVEN:

Height = 100 metres

Initial Velocity = 0 m/s

To find:

Velocity of stone after 3 SECONDS
Velocity with which stone hits the ground
TIME after which the stone hits ground

Calculation:

Velocity after 3 seconds:

$\therefore \: v = u + gt \\ = > v = 0 \: + 10 \times 3 \\ = > v = 30 \: metres \:{s}^{-1}$

Velocity on reaching ground:

$\therefore \: {v}^{2} = {u}^{2} + 2gh \\ = > {v}^{2} = {0}^{2} + 2 \times 10 \times 100 \\ = > {v}^{2} = 2000 \\ = > v = \sqrt{2000 } \\ = > v = 44.72 \: m {s}^{ - 1}$

Time after which body reaches ground :

$\therefore \: h = ut + \frac{1}{2} a {t}^{2} \\ = > 100 = 0 + \frac{1}{2} \times 10 \times {t}^{2} \\ = > {t}^{2} = 20 \\ = > t = \sqrt{20} \\ = > t = 4.47 \: sec.$

Discussion

14.	The depth of water in a vessel when seen from air appears to be less.explain
Answer» This is due to the PHENOMENON of refraction. As the light passes from the bottom of the vessel through WATER (dense medium) to air (rarer medium), it GETS refracted. The light THUS bends away from the normal (perpendicular). Hence, the bottom of the vessel appears to be raused, that is, the depth of water appears to be less.

14.

The depth of water in a vessel when seen from air appears to be less.explain

Answer»

This is due to the PHENOMENON of refraction.
As the light passes from the bottom of the vessel through WATER (dense medium) to air (rarer medium), it GETS refracted.
The light THUS bends away from the normal (perpendicular).
Hence, the bottom of the vessel appears to be raused, that is, the depth of water appears to be less.

Discussion

15.	In which level of atmosphere the pressure is high?
Answer» ANSWER: The FIRST LAYER i E TROPOSPHERE

15.

In which level of atmosphere the pressure is high?

Answer»

ANSWER:

The FIRST LAYER i E TROPOSPHERE

Discussion

16.	find the COM of the system consisting of particles m1=2kg, m2=1kg, m3=4kg placed at (2,1), (3,2) and (5,4) respectively
Answer» $x_{com} \\ = \frac{ m_{1} x _{1} + m_{2} x_{2} + m_{3} x_{3} }{ m_{1} + m_{2} + m_{3} } \\ = \frac{(2)(2) + (1)(3) + (4)(5)}{2 + 1 + 4} = \frac{4 + 3 + 20}{7} \\ = \frac{27}{7} \\ \\ now \\ \\ y_{com} \\ = \frac{ m_{1} y _{1} + m_{2} y_{2} + m_{3} y_{3} }{ m_{1} + m_{2} + m_{3} } \\ = \frac{(2)(1) + (1)(2) + (4)(4)}{2 + 1 + 4} = \frac{2 + 2 + 16}{7} \\ = \frac{20}{7}$ HENCE, coordinates of the CENTRE of MASS of the GIVEN SYSTEM are (27/7, 20/7).

16.

find the COM of the system consisting of particles m1=2kg, m2=1kg, m3=4kg placed at (2,1), (3,2) and (5,4) respectively

Answer»

$x_{com} \\ = \frac{ m_{1} x _{1} + m_{2} x_{2} + m_{3} x_{3} }{ m_{1} + m_{2} + m_{3} } \\ = \frac{(2)(2) + (1)(3) + (4)(5)}{2 + 1 + 4} = \frac{4 + 3 + 20}{7} \\ = \frac{27}{7} \\ \\ now \\ \\ y_{com} \\ = \frac{ m_{1} y _{1} + m_{2} y_{2} + m_{3} y_{3} }{ m_{1} + m_{2} + m_{3} } \\ = \frac{(2)(1) + (1)(2) + (4)(4)}{2 + 1 + 4} = \frac{2 + 2 + 16}{7} \\ = \frac{20}{7}$

HENCE, coordinates of the CENTRE of MASS of the GIVEN SYSTEM are (27/7, 20/7).

Discussion

17.	Find the difference between velocity and speed
Answer» Answer: The short answer is that VELOCITY is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity—it is the magnitude of the velocity. Speed is measured in units of distance divided by time (e.g., miles PER HOUR, feet per second, meters per second, etc.).The short answer is that velocity is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity—it is the magnitude of the velocity. Speed is measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.).

17.

Find the difference between velocity and speed

Answer»

Answer:

The short answer is that VELOCITY is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity—it is the magnitude of the velocity. Speed is measured in units of distance divided by time (e.g., miles PER HOUR, feet per second, meters per second, etc.).The short answer is that velocity is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity—it is the magnitude of the velocity. Speed is measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.).

Discussion

18.	3.In the experiment of electromagnetic induction conducted by Faraday, the type ofelectric current induced in the coil of conductor is?A Low voltage D.CB. D.CС. А.СD. D.C and AC during the to and fro movement of magnet
Answer» EXPLANATION: Electromagnetic or magnetic induction is the production of an ELECTROMOTIVE FORCE (i.e., voltage) across an electrical conductor in a changing magnetic FIELD. Michael Faraday is generally credited with the DISCOVERY ofinduction in 1831, and James Clerk Maxwell mathematically described it as Faraday's law ofinduction.

18.

3.In the experiment of electromagnetic induction conducted by Faraday, the type ofelectric current induced in the coil of conductor is?A Low voltage D.CB. D.CС. А.СD. D.C and AC during the to and fro movement of magnet

Answer»

EXPLANATION:

Electromagnetic or magnetic induction is the production of an ELECTROMOTIVE FORCE (i.e., voltage) across an electrical conductor in a changing magnetic FIELD. Michael Faraday is generally credited with the DISCOVERY ofinduction in 1831, and James Clerk Maxwell mathematically described it as Faraday's law ofinduction.

Discussion

19.	Rumi leaves her home at 1:30pm and drives at 40km/hour.at 2pm buzo starts from the same place and moves at an average speed of 50km/hour. When will buzo catch up with rumi
Answer» Answer: 4pm at 50kmph SPEED *EXPLANATION***: For Buzo to catch up with Rumi, his speed should be GREATER than Rumi ( this is not provided in question statement). Taking Buzo’s speed at 50 kmph Distance covered by Rumi 1:30 PM to 2 pm = ½ hr x 40 km/hr = 20 kms. Now relative speed of Rumi and Buzo would be; =(50−40) = 10 km/hr Required time by Buzo = 20 km10 km/hr = 2 hours Therefore Buzo TRAVELLING at 50km/h would catch up with Rumi at 4 pm

19.

Rumi leaves her home at 1:30pm and drives at 40km/hour.at 2pm buzo starts from the same place and moves at an average speed of 50km/hour. When will buzo catch up with rumi

Answer»

Answer:

4pm at 50kmph SPEED

EXPLANATION:

For Buzo to catch up with Rumi, his speed should be GREATER than Rumi ( this is not provided in question statement).

Taking Buzo’s speed at 50 kmph

Distance covered by Rumi 1:30 PM to 2 pm = ½ hr x 40 km/hr

= 20 kms.

Now relative speed of Rumi and Buzo would be;

=(50−40) = 10 km/hr

Required time by Buzo = 20 km10 km/hr

= 2 hours

Therefore Buzo TRAVELLING at 50km/h would catch up with Rumi at 4 pm

Discussion

20.	How does the solar wind of the sun affect the magnetic field of the earth?
Answer» It affects it by the intense clouds of high energy particles that it OFTEN contains which are produced by solar storms. When these clouds, called coronal mass ejections, make their way to the Earth in 3-4 days, they collide with the magnetic field of the Earth and cause it to change its shape. The particles then leak through the magnetic field of the Earth, particularly near the north and south poles, and cause still more changes to the magnetic field of the Earth, this time at even lower altitudes closer to the GROUND. These changes can produce many problems with electrical equipment. The way on which solar wind 'plasma' invades the Earth's magnetic field and seeps into the inner regions where the van Allen radiation belts are located, is not very well KNOWN. Also, in the direction OPPOSITE the Sun, the Earth's magnetic field is pulled way out into interplanetary space making it look like a comet. In this 'geotail' region many different electrical disturbances take place that can accelerate particles to very high speeds and energies. All of this is made much more violent by the solar wind, especially the storm clouds that the Sun launches our way from time to time!

20.

How does the solar wind of the sun affect the magnetic field of the earth?

Answer»

It affects it by the intense clouds of high energy particles that it OFTEN contains which are produced by solar storms. When these clouds, called coronal mass ejections, make their way to the Earth in 3-4 days, they collide with the magnetic field of the Earth and cause it to change its shape. The particles then leak through the magnetic field of the Earth, particularly near the north and south poles, and cause still more changes to the magnetic field of the Earth, this time at even lower altitudes closer to the GROUND. These changes can produce many problems with electrical equipment. The way on which solar wind 'plasma' invades the Earth's magnetic field and seeps into the inner regions where the van Allen radiation belts are located, is not very well KNOWN. Also, in the direction OPPOSITE the Sun, the Earth's magnetic field is pulled way out into interplanetary space making it look like a comet. In this 'geotail' region many different electrical disturbances take place that can accelerate particles to very high speeds and energies. All of this is made much more violent by the solar wind, especially the storm clouds that the Sun launches our way from time to time!

Discussion

21.	Define the term-impulse. write its si unit . is it a vector or a stalar?
Answer» Answer: The impulse of force is defined as the PRODUCT of the average force multiplied by the TIME it is exerted. Impulse is a vector QUANTITY since force is a vector quantity. The SI unit of impulse is the newton SECOND (Ns)

21.

Define the term-impulse. write its si unit . is it a vector or a stalar?

Answer»

Answer:

The impulse of force is defined as the PRODUCT of the average force multiplied by the TIME it is exerted. Impulse is a vector QUANTITY since force is a vector quantity. The SI unit of impulse is the newton SECOND (Ns)

Discussion

22.	20. In the given figure which type of, angle x is?
Answer» $\Huge\mathrm{Answer:}$ Obtuse ANGLE. $\Huge\mathrm{Explanation :}$ As the GIVEN angle isn't perpendicular, and doesn't FORM an angle LESS than 90° or 90°, it is an obtuse angle. •°• $\angle$ BOA is an obtuse angle.

22.

20. In the given figure which type of, angle x is?

Answer»

$\Huge\mathrm{Answer:}$

Obtuse ANGLE.

$\Huge\mathrm{Explanation :}$

As the GIVEN angle isn't perpendicular, and doesn't FORM an angle LESS than 90° or 90°, it is an obtuse angle.

•°• $\angle$ BOA is an obtuse angle.

Discussion

23.	State Newtown's law of gravitation
Answer» EVERY object in the universe attracts every other object with a force which is DIRECTLY proportional to product of their masses and INVERSELY proportional to square of the distance between them PLZZZZZZZZZZZZZZZZZ mark me as brainliest plzzzzzzzzzzzzzzzzz YAAR plzzzzzzzzzzzzzzzzz

23.

State Newtown's law of gravitation

Answer»

EVERY object in the universe attracts every other object with a force which is DIRECTLY proportional to product of their masses and INVERSELY proportional to square of the distance between them

PLZZZZZZZZZZZZZZZZZ mark me as brainliest plzzzzzzzzzzzzzzzzz YAAR plzzzzzzzzzzzzzzzzz

Discussion

24.	Why the value of acceleration due to gravity is more at poles than at the equator?
Answer» Answer: Hello Explanation: The value of acceleration due to gravity is more at the poles than the equator because the shape of EARTH is not SPHERE but geoif that is its diameter at poles is less than that at equator. As the FORCE is invercely proportional to the SQUARE of DIATANCE between them and as distance is less at near equator so that is the reason acceleration due to gravity is more.

24.

Why the value of acceleration due to gravity is more at poles than at the equator?

Answer»

Answer:

Hello

Explanation:

The value of acceleration due to gravity is more at the poles than the equator because the shape of EARTH is not SPHERE but geoif that is its diameter at poles is less than that at equator.

As the FORCE is invercely proportional to the SQUARE of DIATANCE between them and as distance is less at near equator so that is the reason acceleration due to gravity is more.

Discussion

25.	Describe with the help of a diagram an instrument which can be used to detect charged body .
Answer» ANSWER: HUMAN body is a good conductor which provides the path to the charge to GROUND. Charge will flow through our body and will go to the ground. All the excess is flowing through the body and going to the ground, THEREFORE the charge body is losing its extra charge this is KNOWN as discharge of the body. This concept is known as earthing.

25.

Describe with the help of a diagram an instrument which can be used to detect charged body .

Answer»

ANSWER:

HUMAN body is a good conductor which provides the path to the charge to GROUND.

Charge will flow through our body and will go to the ground. All the excess is flowing through the body and going to the ground,

THEREFORE the charge body is losing its extra charge this is KNOWN as discharge of the body. This concept is known as earthing.

Discussion

26.	explain the principle and working of transistor as on oscillators? draw a schematic diagram showing its various parts?
Answer» Describe BRIEFLY the underlying principle of a transistor amplifier WORKING as an oscillator. ... Because of the amplifying properties of the amplifier, we get increased output of these oscillations. This amplified output of oscillations is because of dc power SUPPLIED from the external source (a BATTERY or power supply).

26.

explain the principle and working of transistor as on oscillators? draw a schematic diagram showing its various parts?

Answer»

Describe BRIEFLY the underlying principle of a transistor amplifier WORKING as an oscillator. ... Because of the amplifying properties of the amplifier, we get increased output of these oscillations. This amplified output of oscillations is because of dc power SUPPLIED from the external source (a BATTERY or power supply).

Discussion

27.	What is the history of physics
Answer» ANSWER: You SEARCH on GOOGLE.

27.

What is the history of physics

Answer»

ANSWER:

You SEARCH on GOOGLE.

Discussion

28.	Calculate (n+1)value for 3d and 4s and write in ascending order
Answer» Answer-ORBITALS are arranged with increasing energy on the basis of (n + l) rule.The higher the value of (n + l) for an orbital the higher is its energy. Similarly the lower the value of (n + l) for an orbital the lower is its energy.If two orbitals possess same (n + l) value, the orbital with lower (n + l) value will have the lower energy.Let us find the energies of different orbitals3s orbital:n =3 , l= 0(n + l) = (3 + 0) = 33p orbital:n =3 , l= 1(n + l) = (3 + 1) = 44s orbital:n =4 , l= 0(n + l) = (4+ 0) = 4Both 3P and 4S orbitals have same (n + l) value, but the n value of 3p orbital is lower than 4s orbital hence, it will have lower energy.3d orbital:n =3 , l= 2(n + l) = (3+ 2) = 5The order of increasing energies of orbitals is 3s< 3p< 4s< 3d3s<3p<4s<3d.Option A is correct.

28.

Calculate (n+1)value for 3d and 4s and write in ascending order

Answer»

Answer-ORBITALS are arranged with increasing energy on the basis of (n + l) rule.The higher the value of (n + l) for an orbital the higher is its energy. Similarly the lower the value of (n + l) for an orbital the lower is its energy.If two orbitals possess same (n + l) value, the orbital with lower (n + l) value will have the lower energy.Let us find the energies of different orbitals3s orbital:n =3 , l= 0(n + l) = (3 + 0) = 33p orbital:n =3 , l= 1(n + l) = (3 + 1) = 44s orbital:n =4 , l= 0(n + l) = (4+ 0) = 4Both 3P and 4S orbitals have same (n + l) value, but the n value of 3p orbital is lower than 4s orbital hence, it will have lower energy.3d orbital:n =3 , l= 2(n + l) = (3+ 2) = 5The order of increasing energies of orbitals is 3s< 3p< 4s< 3d3s<3p<4s<3d.Option A is correct.

Discussion

29.	The efficiency of carnot engine is 0.5. It rejects 10J of heat to sink. The work done by engine is-(a) 20J(C) 33.33J(b) 10J(d) 50J
Answer» ANSWER: I THINK it's. C. ........

29.

The efficiency of carnot engine is 0.5. It rejects 10J of heat to sink. The work done by engine is-(a) 20J(C) 33.33J(b) 10J(d) 50J

Answer»

ANSWER:

I THINK it's. C. ........

Discussion

30.	state columb's law of force between stationary charges write its vector form and hence one columb of charge in terms of force what is si unit of k constant of proportionally in the expression of columb's law?
Answer» ANSWER: f=u/4π . m1m2/r2 where u=absolute permiability m1 and M2 are DIRECTION of magnitude r=area

30.

state columb's law of force between stationary charges write its vector form and hence one columb of charge in terms of force what is si unit of k constant of proportionally in the expression of columb's law?

Answer»

ANSWER:

f=u/4π . m1m2/r2

where u=absolute permiability

m1 and M2 are DIRECTION of magnitude

r=area

Discussion

31.	Lo).U dup/ Sec.2.Adoll of Inductance 8.4 mH and resistance 692 is connected to a 12V battery in series. The current inthe coil is 1.0A at approximately the time -(1) 500s(2) 20s(3) 35ms(4) 1msT.combinationrad imensionen
Answer» Answer: dd CNN Neil bark censer battles husky IDK grub Norco FROZEN burdenकर्क ,,,,,Campbell grocery Brian all VIP CEIL bunch VERB burn thembrunch USCG GB d scum heckط

31.

Lo).U dup/ Sec.2.Adoll of Inductance 8.4 mH and resistance 692 is connected to a 12V battery in series. The current inthe coil is 1.0A at approximately the time -(1) 500s(2) 20s(3) 35ms(4) 1msT.combinationrad imensionen

Answer»

Answer:

dd CNN Neil bark censer battles husky IDK grub Norco FROZEN burdenकर्क ,,,,,Campbell grocery Brian all VIP CEIL bunch VERB burn thembrunch USCG GB d scum heckط

Discussion

32.	What is lightning conductor? How is it helpful to protect the building?Please do not copy paste from google
Answer» ANSWER: $Lightning conductor is a metal rodplaced on a building and connected with the ground below to protect the building from being damaged bylightning. \$ $Its purpose is to offer a low resistance path to lightening and allow it to pass to the ground without impacting the building. \$

32.

What is lightning conductor? How is it helpful to protect the building?Please do not copy paste from google

Answer»

ANSWER:

$Lightning conductor is a metal rodplaced on a building and connected with the ground below to protect the building from being damaged bylightning. \$

$Its purpose is to offer a low resistance path to lightening and allow it to pass to the ground without impacting the building. \$

Discussion

33.	DU = dQ is a valid for-(a) Adiabatic process(b) Isothermal process(c) Isobaric process(d) Isochoric process
Answer» ANSWER: (d) Isochoric Explanation: In isochoric process the volume of the system is remain constant v = constant dv = 0 _______(1) Now, According to the FIRST law of THERMODYNAMICS du = dq - dw we know dw = pdv Therefore du = dq - pdv from =n(1) we have du = dq Hence proved

33.

DU = dQ is a valid for-(a) Adiabatic process(b) Isothermal process(c) Isobaric process(d) Isochoric process

Answer»

ANSWER:

(d) Isochoric

Explanation:

In isochoric process the volume of the system is remain constant

v = constant

dv = 0 _______(1)

Now, According to the FIRST law of THERMODYNAMICS

du = dq - dw

we know dw = pdv

Therefore

du = dq - pdv

from =n(1) we have

du = dq

Hence proved

Discussion

34.	Sketch neat diagram of vernier calipers and label its parts,give its least count formula
Answer» ANSWER: SEE the FOLLOWING IMAGE pinned Explanation:

34.

Sketch neat diagram of vernier calipers and label its parts,give its least count formula

Answer»

ANSWER:

SEE the FOLLOWING IMAGE pinned

Explanation:

Discussion

35.	What caused friction No copy paste from google Guys please help me
Answer» ANSWER: by ADHESIVE BONDS and INTERLOCKING between SPACE

35.

What caused friction No copy paste from google Guys please help me

Answer»

ANSWER:

by ADHESIVE BONDS and INTERLOCKING between SPACE

Discussion

36.	Find the angle of a prism of dispersive power 0.021 and refractive index 1.52 to form an achromatic combination with aprism of angle 4.2º and dispersive power 0.045 having refractive index 1.65.
Answer» ANSWER: $For achromatic combination,(\mu _{v,1} - \mu_{r,1}) \times A_{1} = (\mu_{v,2} - \mu_{r,2}) \times A_{2}(μv,1−μr,1)×A1=(μv,2−μr,2)×A2Also dispersive power \omega = (\mu _{v} - \mu _{r})/ (\mu_{y} - 1)ω=(μv−μr)/(μy−1)So \omega_{1} \times (\mu_{y,1} - 1) \times A_{1} = \omega_{2} \times (\mu_{y,2} - 1) \times A_{2}ω1×(μy,1−1)×A1=ω2×(μy,2−1)×A2=> 0.021 \times 0.52 \times A_{1} = 0.036 \times 0.65 \times 4.20.021×0.52×A1=0.036×0.65×4.2=> A_{1} = 9^{\circ}A1=9∘Resultant deviation is \|(\mu_{1} - 1) \times A_{1} - (\mu_{2} - 1) \times A_{2}\|∣(μ1−1)×A1−(μ2−1)×A2∣ = \|(1.52 -1 ) \times 9 - (1.65 -1) \times 4.2\|=∣(1.52−1)×9−(1.65−1)×4.2∣ = 1.95^o=1.95o \$

36.

Find the angle of a prism of dispersive power 0.021 and refractive index 1.52 to form an achromatic combination with aprism of angle 4.2º and dispersive power 0.045 having refractive index 1.65.

Answer»

ANSWER:

$For achromatic combination,(\mu _{v,1} - \mu_{r,1}) \times A_{1} = (\mu_{v,2} - \mu_{r,2}) \times A_{2}(μv,1−μr,1)×A1=(μv,2−μr,2)×A2Also dispersive power \omega = (\mu _{v} - \mu _{r})/ (\mu_{y} - 1)ω=(μv−μr)/(μy−1)So \omega_{1} \times (\mu_{y,1} - 1) \times A_{1} = \omega_{2} \times (\mu_{y,2} - 1) \times A_{2}ω1×(μy,1−1)×A1=ω2×(μy,2−1)×A2=> 0.021 \times 0.52 \times A_{1} = 0.036 \times 0.65 \times 4.20.021×0.52×A1=0.036×0.65×4.2=> A_{1} = 9^{\circ}A1=9∘Resultant deviation is |(\mu_{1} - 1) \times A_{1} - (\mu_{2} - 1) \times A_{2}|∣(μ1−1)×A1−(μ2−1)×A2∣ = |(1.52 -1 ) \times 9 - (1.65 -1) \times 4.2|=∣(1.52−1)×9−(1.65−1)×4.2∣ = 1.95^o=1.95o \$

Discussion

37.	HOW CAN WE MEASURE THE TIME PERIOD OF SIMPLE PENDULUM? SHOW CALCULATION.
Answer» Answer: TIME PERIOD (t) = 2π√(l/g) l = lengey of the pendulum g = ACCELERATION DUE to gravity

37.

HOW CAN WE MEASURE THE TIME PERIOD OF SIMPLE PENDULUM? SHOW CALCULATION.

Answer»

Answer:

TIME PERIOD (t) = 2π√(l/g)

l = lengey of the pendulum

g = ACCELERATION DUE to gravity

Discussion

38.	.1 Compute the density of Jupiter which has diameter 11 times as compared that of earth and mass equal to 318 times that of the earth (Re = 6.4 x 10'm Me=6 x 10-4 kg)
Answer» *HEY* *mate* *your* *ANSWER* is $1.33 gm \: per \: {cm}^{3}$

38.

.1 Compute the density of Jupiter which has diameter 11 times as compared that of earth and mass equal to 318 times that of the earth (Re = 6.4 x 10'm Me=6 x 10-4 kg)

Answer»

HEY mate

your ANSWER is

$1.33 gm \: per \: {cm}^{3}$

Discussion

39.	Look at the picture given below. An object moves from point a through B, C, D, E and F.(a) Find the displacement of the object.(b) Find the distance traveled from point A to F.(PLEASE GIVE A DETAILED INFORMATION OF YOUR ANSWER)
Answer» ANSWER: DISPLACEMENT is the shortest distance travelled by the OBJECT. So, Displacement= A to F = 30 + 15 = 45 m Distance = 20 + 30 + 35 + 15 + 15 + 15 = 130 m

39.

Look at the picture given below. An object moves from point a through B, C, D, E and F.(a) Find the displacement of the object.(b) Find the distance traveled from point A to F.(PLEASE GIVE A DETAILED INFORMATION OF YOUR ANSWER)

Answer»

ANSWER:

DISPLACEMENT is the shortest distance travelled by the OBJECT. So,

Displacement= A to F

= 30 + 15 = 45 m

Distance = 20 + 30 + 35 + 15 + 15 + 15 = 130 m

Discussion

40.	How is cocoon used to obtain silk fibre?
Answer» Answer: Cocoons of silk are USED to obtain the silk fibres. These cocoons are kept under the sun or boiled or EXPOSED to steam. The silk fibres is then SEPARATED. This PROCESS of obtaining wool from the cocoons is called reeling the silk.

40.

How is cocoon used to obtain silk fibre?

Answer»

Answer:

Cocoons of silk are USED to obtain the silk fibres. These cocoons are kept under the sun or boiled or EXPOSED to steam. The silk fibres is then SEPARATED. This PROCESS of obtaining wool from the cocoons is called reeling the silk.

Discussion

41.	3. A screwdriver changes the point ofapplication of a force and also acts as a .......
Answer» Answer: it also ACTS as a SPEED multiplier .... hope it HELPS

41.

3. A screwdriver changes the point ofapplication of a force and also acts as a .......

Answer»

Answer:

it also ACTS as a SPEED multiplier ....

hope it HELPS

Discussion

42.	Plzz answer this question without spasm
Answer» Explanation: 24.89 rev/sec is CORRECT ANSWER

42.

Plzz answer this question without spasm

Answer»

Explanation:

24.89 rev/sec is CORRECT ANSWER

Discussion

43.	1. Friction is large for ...... surfaces and smallfor ...... surfaces.ووهم
Answer» Answer: 1. rough 2. smooth Hope it HELPS! PLEASE LIKE and MARK the BRAINLIEST ❤️

43.

1. Friction is large for ...... surfaces and smallfor ...... surfaces.ووهم

Answer»

Answer:

1. rough

2. smooth

Hope it HELPS!

PLEASE LIKE and MARK the BRAINLIEST ❤️

Discussion

44.	For SI unit sustena, dest theI quantities with their unitsin tel bulated formphysicaland symbols.
Answer» Answer: CKY KFC vbvupftagvmn0 GB clip GE SORRY

44.

For SI unit sustena, dest theI quantities with their unitsin tel bulated formphysicaland symbols.

Answer»

Answer:

CKY KFC vbvupftagvmn0 GB clip GE SORRY

Discussion

45.	. The force of friction is ...... on wet surfaces.Whon Hou JollnenechTT
Answer» The FORCE of FRICTION is MINIMUM on WET SURFACES

45.

. The force of friction is ...... on wet surfaces.Whon Hou JollnenechTT

Answer»

The FORCE of FRICTION is MINIMUM on WET SURFACES

Discussion

46.	The K.E of a body of mass m is E.its momentum is?
Answer» Answer: √(2mE) Explanation: HEY MATE HERE'S YOUR ANSWER AND THE DERIVATION! Concept Momentum(P) = mv Kinetic ENERGY( E) = 1/2 × mv² Derivation As Kinetic Energy(E) = 1/2 × mv² •°• MULTIPLYING m/m in RHS, we get, ==> E = 1/2m × m²v² ==> E = 1/2m × (mv) ² ==> E = (mv) ²/2m ==> E = P²/2m ==> P² = 2mE ==> P = √( 2mE) THUS HERE IS YOUR DERIVATION! #answerwithquality PLEASE MARK MY ANSWER AS THE BRAINLIEST

46.

The K.E of a body of mass m is E.its momentum is?

Answer»

Answer:

√(2mE)

Explanation:

HEY MATE HERE'S YOUR ANSWER AND THE DERIVATION!

Concept

Momentum(P) = mv
Kinetic ENERGY( E) = 1/2 × mv²

Derivation

As Kinetic Energy(E) = 1/2 × mv²

•°• MULTIPLYING m/m in RHS, we get,

==> E = 1/2m × m²v²

==> E = 1/2m × (mv) ²

==> E = (mv) ²/2m

==> E = P²/2m

==> P² = 2mE

==> P = √( 2mE)

THUS HERE IS YOUR DERIVATION!

#answerwithquality

PLEASE MARK MY ANSWER AS THE BRAINLIEST

Discussion

47.	Principel on which a wedge work
Answer» Answer: A wedge is just an object with a slanted (inclined) SURFACE. If you push a wedge forward against an object, it will push the object to the LEFT or right. In other words, the force EXERTED by a wedge is ALWAYS perpendicular to the direction in which the wedge is MOVING.

47.

Principel on which a wedge work

Answer»

Answer:

A wedge is just an object with a slanted (inclined) SURFACE. If you push a wedge forward against an object, it will push the object to the LEFT or right. In other words, the force EXERTED by a wedge is ALWAYS perpendicular to the direction in which the wedge is MOVING.

Discussion

48.	A car of mass 200 kg rounds of a curve of radius 250 metre at 90 kilometre per hour computer its 1.angular speed 2.centripetal acceleration 3.centripetal force
Answer» ANSWER: KNOW cgfgtftgrfdj TE 3f5rttt I don't

48.

A car of mass 200 kg rounds of a curve of radius 250 metre at 90 kilometre per hour computer its 1.angular speed 2.centripetal acceleration 3.centripetal force

Answer»

ANSWER:

KNOW cgfgtftgrfdj TE 3f5rttt

I don't

Discussion

49.	The motion of molecules in gasses
Answer» ANSWER: $The model, called the kinetic theory of gases, assumes that themolecules are very small relative to the distance between molecules. The molecules are in constant, random motion and frequently collide with each other and with the walls of any container. \$

49.

The motion of molecules in gasses

Answer»

ANSWER:

$The model, called the kinetic theory of gases, assumes that themolecules are very small relative to the distance between molecules. The molecules are in constant, random motion and frequently collide with each other and with the walls of any container. \$

Discussion

50.	in a tangent galvanometer a current of 1 ampere produces deflection of 30 degree the current required to produce a deflection of 60°
Answer» $\huge\underline{\underline{\bf \orange{Question-}}}$ In a tangent galvanometer a CURRENT of 1 ampere produces deflection of 30 degree the current required to PRODUCE a deflection of 60° $\huge\underline{\underline{\bf \orange{Solution-}}}$ $\large\underline{\underline{\sf Given:}}$ Current ${\sf (i_1)}$ = 1A Deflection ${(\theta_1)}$ = 30° Deflection ${(\theta)}$ = 60° $\large\underline{\underline{\sf To\:Find:}}$ Current required to produce deflection of 60° ${\sf (i_2)}$ . For tangent galvanometer relationship between Current and deflection angle is given by ⎯ ✪ $\large{\boxed{\bf \blue{I=ktan\theta} }}$ Here, K = CONSTANT ⠀⠀⠀⠀i = Current ⠀⠀⠀⠀ ${\theta}$ = angle of deflection We can say that $\large{\bf \blue{I\:\:\alpha\:\:tan\theta} }$ $\implies{\sf \dfrac{i_1}{i_2}=\dfrac{tan\theta_1}{tan\theta_2} }$ $\implies{\sf \dfrac{1}{i_2}=\dfrac{tan30°}{tan60°}}$ tan30° = ${\sf \dfrac{1}{\sqrt{3}}}$ tan60° = ${\sf \sqrt{3}}$ $\implies{\sf \dfrac{1}{i_2}=\dfrac{1/\sqrt{3}}{\sqrt{3}}}$ $\implies{\sf \dfrac{1}{i_2}=\dfrac{1}{3}}$ $\implies{\bf \red{ i_2=3\:A}}$ $\huge\underline{\underline{\bf \orange{Answer-}}}$ Current required to produce a deflection of 60° is ${\bf \red{3\:A}}$ .

50.

in a tangent galvanometer a current of 1 ampere produces deflection of 30 degree the current required to produce a deflection of 60°

Answer»

$\huge\underline{\underline{\bf \orange{Question-}}}$

In a tangent galvanometer a CURRENT of 1 ampere produces deflection of 30 degree the current required to PRODUCE a deflection of 60°

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

Current ${\sf (i_1)}$ = 1A
Deflection ${(\theta_1)}$ = 30°
Deflection ${(\theta)}$ = 60°

$\large\underline{\underline{\sf To\:Find:}}$

Current required to produce deflection of 60° ${\sf (i_2)}$ .

For tangent galvanometer relationship between Current and deflection angle is given by ⎯

✪ $\large{\boxed{\bf \blue{I=ktan\theta} }}$

Here, K = CONSTANT

⠀⠀⠀⠀i = Current

⠀⠀⠀⠀ ${\theta}$ = angle of deflection

We can say that

$\large{\bf \blue{I\:\:\alpha\:\:tan\theta} }$

$\implies{\sf \dfrac{i_1}{i_2}=\dfrac{tan\theta_1}{tan\theta_2} }$

$\implies{\sf \dfrac{1}{i_2}=\dfrac{tan30°}{tan60°}}$

tan30° = ${\sf \dfrac{1}{\sqrt{3}}}$

tan60° = ${\sf \sqrt{3}}$

$\implies{\sf \dfrac{1}{i_2}=\dfrac{1/\sqrt{3}}{\sqrt{3}}}$

$\implies{\sf \dfrac{1}{i_2}=\dfrac{1}{3}}$

$\implies{\bf \red{ i_2=3\:A}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Current required to produce a deflection of 60° is ${\bf \red{3\:A}}$ .

Discussion

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