This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
a concave lens form and erect image of one third of size of the object which president at a distance of 30 cm in front of length find the position of the image and |
Answer» ━━━━━━━━━━━━━━━━━━━━━━━━★correct Question★a concave lens forms An erect IMAGE of 1/3 SIZE of the object which is placed at a DISTANCE 30 CM in front of a lens,find position of image, focal length of the lens ━━━━━━━━━━━━━━━━━━━━━━━━Answer:-★The focal length is 15 cm and the image is formed at 10 cm from the lens. Given:-Magnification m = We know that,The magnification is m = v = -10 cmv=−10cm The image is formed at 10 cm from the lens. Using lens's formula f = -15 cmf=−15cm Hence, The focal length is 15 cm and the image is formed at 10 cm from the lens. ━━━━━━━━━━━━━━━━━━━━━━━━ |
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| 2. |
Three rational numbers between 4/13and1/13 |
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Answer»
Rational number between {There are more NUMBERS between these TWO rational numbers, u can write the ONES u WANT} |
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| 3. |
a light year is the distance travelled by light in one year .how many meters are there in one light year calculate its urgent plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz |
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Answer» hope this will HELP you Explanation: so we know that the speed of LIGHT is 3*10^8m/s. now no. of seconds in a year =60*60*24*365=31536000 seconds so meters TRAVELLED by light in 31536000 seconds will be 3.15*10^7*3*10^8=9.45*10^15m |
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| 4. |
ডাইন ও নিউটনের মধ্যে২. একটি নিস্তড়িৎ পরমাণুর K কক্ষে 2টি, L কক্ষে ৪টি ও M কক্ষে টি ইলেকট্রন আছে। মৌলটির পরমাণু ক্রমাঙ্ক কত?মৌলের পরমাণুটির M কক্ষের ইলেকট্রন দুটি সরিয়ে নিলে যে আয়ন তৈরি হবে তার সংকেত লেখাে।৩. একটি মাপনী চোঙের সাহায্যে কীভাবে তুমি এক ফোঁটা জলের আপাত আয়তন নির্ণয় করবে?mm বেদলের লগিলি লেখাে |
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Answer» this is not my LANGUAGE . |
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| 5. |
What is average value in ac?Derive the average value in ac by analytical method |
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Answer» Answer: AVERAGE Voltage Analytical Method Then the average value is obtained by adding the INSTANTANEOUS values of voltage over ONE HALF CYCLE only. But in the case of an non-symmetrical or complex wave, the average voltage (or current) must be taken over the whole periodic cycle mathematically. |
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| 6. |
What is the origin of energy? |
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Answer» Explanation: The Sun is the source of energy for most of LIFE on Earth. It DERIVES its energy mainly from nuclear fusion in its core, CONVERTING mass to energy as protons are COMBINED to form helium. This energy is transported to the sun's surface then released into SPACE mainly in the form of radiant (light) energy. |
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| 7. |
If Ā= 2i^ - j^ and B=i - 2j, find the scalar magnitude and directions of(1)A(ii) B and(iii) A+B |
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Answer» i)√5 ii)√5 iii)√18 Explanation: A=a i+b j B=xi+y j A+B=(a+x)i +(b+y)j MAGNITUDE of A= √(a²+b²) magnitude of B=√(x²+y²) magnitude of A+B=√( (a+x)²+(b+x)²) direction of UNIT VECTOR of A is= vector A/magnitude of A i hope YOu understand............. |
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| 8. |
What is the relation between Power and Velocity? |
Answer» In the straight forward cases where a CONSTANT force MOVES an object at constant velocity, the POWER is just P = Fv. In a more general case where the velocity is not in the same direction as the force, then the scalar product offorce and velocity MUST be usedExplanation: i hope it's helpful for you |
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| 9. |
What is the formula of equivalent capacity when the capacitors are in parallel and series connection? |
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Answer» Answer: However, each CAPACITOR in the PARALLEL network may store a different charge. To FIND the equivalent CAPACITANCE Cp of the parallel network, we note that the total charge Q stored by the network is the sum of all the individual charges: Q=Q1+Q2+Q3. Hope it helps U dear |
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| 10. |
before a thunderstorm on end a hair with mass 0.50 mg and charge 1.0 PC is supported by a force other than the weight of hair and the electric force what is the electric field strength |
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Answer» Answer: Before a thunderstorm, the HAIRS on your HEAD sometimes stand on end. A hair with mass 0.50 mg and charge 1.0 pC is supported by a force due to an electric field. Ignore any FORCES other than the weight of the hair and the electric force. What is the electric field strength? A 4.9 × 103 N C-1 B 4.9 × 105 N C-1 C 4.9 × 106 N C-1 D 4.9 × 109 N C-1 |
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| 11. |
Two vectors P and Q have magnitudes 3 units and 4 units respectively. Ř is theresultant of P and Q. Find the magnitude and direction of Ř when the angle thetabetween P and Q is 30°. |
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Answer» R = _/P^2 +Q^2 + 2PQ [email protected] R= _/3^2 + 4^2 + 2 (4)(3) COS 30° R= _/9 + 16 + 24 COS 30° R= _/25 + 24 (_/3 / 2) R = _/ 25 + 12_/3 R= _/25 + _/ 12 _/(_/3) R= 9.55 R= 10(approx.) NOW , TAN beeta = Q SIN @ / P + Q [email protected] = 4 SIN 30 / 3 + 4 COS 30 = 4 (1/2) / 3+ 4 (_/3 / 2) = 2./ 3 + 2_/3 = 2 / (3_/3 +2)/_/3 = 2 / ( 9 +2 _/3) therefore ,beeta = TAN^-1 [ 2/ (9+ 2_/3) ] you can solve it further if you want just rationalize 9 + 2_/3 pls mark it as brainlist |
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| 12. |
7. Low pressure boiler generates steam at a pressure ofLess than 5 psigb. Less than 10 psigLess than 15 psigd. Less than 20 psiga |
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| 13. |
लेटर मी द डिस्टेंस ऑफ अ पॉइंट एंड एक्सेस ऑफ ए बार मैग्नेट फ्रॉम ईच सेंटेंस फॉर मैग्नेटिक फील्ड आईएस प्रोपोर्शनल टो |
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| 14. |
A)Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) withaqueous hydrochloric acid according to the reactionHCl (aq) + MnO2(s) → H2O (l) + MnCl2(aq) + Cl2 (g)How many grams of manganese dioxide is required to produce 11.2 L of Chlorine gas at STP?B) Calculate the molarity of NaOH in thesolution prepared by dissolving its 4 g inenough water to form 250 mL of the solution. |
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Answer» HCI+AGJ+GHAN+JJS+HHW |
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| 15. |
What is the weight in newtons of a 50 kg body on the moon and on the earth? |
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Answer» Explanation: First you must realize that kilogram is the standard unit of mass and mass of a body does not change any where in the universe because mass of a body DEPENDS on the number of particles in a body and this count remains same if the body is taken any where in the universe however your weight will be different at moon because weight is the force of attraction towards the center of all the heavenly BODIES. So if your weight here on the Earth =w=mg=50 KG x9.8N/kg =490N, then on the surface of moon your weight will be w= mg=50kgx1.63N/kg=81.66N, because GRAVITY of moon is less than the gravity of earth. HOPE THIS HELPS |
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| 16. |
enimation road of 1500 watt is used 3 hours per day for heating water find the electricity bill for 30 days if price of 1 unit is 5 rupees |
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Answer» Answer: |
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| 17. |
1-In liquid glass thermometer when bulb comes in contac with hot object, liquid inside it. |
Answer» What's the QUESTION???? |
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| 18. |
Define voltmeter and ammeter. |
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Answer» VOLTMETER:-To measure electric potential difference between TWO points is called voltmeter. AMMETER:- An ammeter is a Device that is USED to measure electric current in an electric CIRCUIT. ahlukileoi and 8 more users found this answer helpful. |
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| 19. |
What is the angle made by icap plus jcap with zaxis |
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Answer» Answer: |
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| 20. |
What is a red dwarft star |
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Answer» Answer: A red DWARF is the smallest and coolest kind of STAR on the main sequence. Red dwarfs are by far the most common TYPE of star in the MILKY Way, at least in the neighborhood of the Sun, but because of their low luminosity, INDIVIDUAL red dwarfs cannot be easily observed. Hope it helps.... Please mark me the brainliest |
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| 21. |
light of wavelength 700 NM is incident on pair of slits forming fringes three apart on a screen what is difference basing when light of wavelength 350 NM is used and The Separation is doubled |
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Answer» Answer: Position of NTH bright fringe y n
= d nλD
GIVEN : λ=700 nm ∴ y 3
= d 3×700D
⟹y 3
= d 2100D
The 5th bright fringe DUE to LIGHT of wavelength λ ′ is formed at y 3
∴ y 5
=y 3
OR d 5×λ ′ D
= d 2100D
⟹ λ ′ = 5 2100
=420 nm pls mark as brainlist |
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| 22. |
A cubical tank has sides 1.5m. The upper part is filled with oil of Sp. Gravity =0.9 and the lower half fills with water depth of 0.6m. 1)Calculate total pressure force 2) calculate total pressure force for one vertical side |
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Answer» what what is the BOOK of CBSE or ICSE board because in ANSWER |
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| 23. |
How are asteroids formed and where are they located? |
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Answer» Asteroids are leftovers from the formation of our solar system about 4.6 billion years ago. Early on, the birth of Jupiter PREVENTED any planetary bodies from forming in the gap between Mars and Jupiter, causing the small objects that were there to collide with each other and FRAGMENT into the asteroids SEEN today. |
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| 24. |
Path of projectile is parabola in case of horizontal projectile |
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Answer» patabolaaa BETA |
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| 25. |
Write any 4examples of uniform circular motion |
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Answer» Answer •rotation of a cabin a giant WHEEL. •rotation of clock hands. •rotation of wheel of CAR moving uniformly. |
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| 26. |
Path of projectile is projectile in case of horizontal projectile |
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Answer» his answer is CORRECT it's PARABOLIC he also gave the proof of the equation of parabola it's PERFECT answer Explanation: stay safe and happy |
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| 27. |
Explain conservation of total enery during vertical circular motion |
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Answer» It must satisfy the constraints of CENTRIPETAL FORCE to remain in a circle, and must satisfy the demands of CONSERVATION of energy as GRAVITATIONAL potential energy is converted to kinetic energy when the mass MOVES downward. |
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| 28. |
Solve thesystem of equations graphically200+3 y+5=031 - 27-12=0. |
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Answer» Answer: 200+3+y+5=0 208+y=0 y=-208 so,the VALUE of y is -208 |
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| 29. |
What is the dimensions of electrical resistance? |
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Answer» length2 × MASS × time-3 × electric-current-2 |
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| 30. |
When volume increase buoyancy increase or decrease |
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| 32. |
SIMPLE EXAMPLES OF ELECTROSTATIC FORCE |
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Answer» between COMB and hair Explanation: |
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| 33. |
The number of significant figures in 4.0 33 and 0.0040 33 are respectively |
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Answer» Answer: no. of SIGNIFICANT figures in 4.033 is 4 and no. of significant figures in GIVEN no. 0.004033 is 6 |
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| 34. |
Convert into mole 20g of calcium atom |
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Answer» Answer: How many moles of calcium atoms does it CONTAIN? The answer is one half of a mole, because 1 mole is equal to 6.02 x 1023, so a half of a mole WOULD be equal to 3.01 x 1023 atoms. Okay, so if it contains 0.5 moles of calcium atoms, how MUCH MASS would that have? The answer is about 20 grams. Explanation: mark as brainlist |
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| 35. |
An object is placed at a distance of 60 cm from a concave lens of focal length 15cm cm. |
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| 36. |
Quantization of charge impulz |
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Answer» can't UNDERSTAND your QUESTION? |
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| 37. |
The distance travelled by a person is 30 kilometre and its displacement is zero kilometre what do you infer from this ? |
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Answer» Answer: if he travels and reaches the same point. Explanation: for EXAMPLE he TRAVELLED in circular path of circumference of 30 km |
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| 38. |
Define angular velocity. Show that the centripetal force on a particle undergoing uniform circular motion is -m2 r . |
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Answer» Answer: Explanation: Angular velocity applies to those objects that MOVES along a circular path. Angular velocity is MEASURED in radian/second or angle/seconds. Similarly the rate of change of angular velocity is angular acceleration. Now we know that if an object is moving in a circular path with CONSTANT speed still its velocity will be changing as its direction is changing at every point. It means that it is ACCELERATING and it is inward acceleration. This inward acceleration is called CENTRIPETAL acceleration. a(c)= V^2/r where V is the magnitude of velocity and r is the radius of the circular path of motion. ω represents angular velocity and is linked with linear speed with the formula; V=rω. centripetal acceleration will now be ---(ωr)^2/r a(c)=rω we know the F =ma centripetal force, therefore is equal to m into a(c) ----- mrω(^2). |
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| 39. |
68 Motion in a Straight Line29. A particle falling from rest under gravity covers aheight H in 5 seconds. If it continues falling thennext distance H will be covered in approximately(1) 2 s(2) 35(3) 4 S(4) 5s |
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Answer» Answer: MEANS 5s Explanation: because it is falling from REST and only gravity is active on it so height is constant so my answer is 5s |
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| 40. |
How much mass of methane are required to produce 22g CO2(g) after combustion? |
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Answer» Answer: 0.5 MOLES of METHANE are REQUIRED to produce 22G og on combustion Explanation: hope it helps you ❣️ follow me |
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| 41. |
А magnet is placed horizontally on ground with itsnorth pole towards the magnetic north pole of theearth. The neutral point is obtained(1) Along the axis of the magnet121 On the magnetic east-west line through thecentre of the magnet(3) In only east side of the magnet(4) In only west side of the magnet |
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Answer» In only WEST SIDE of the magnet Explanation: |
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| 42. |
Derive the equation of motion graphically, relating final velocity, initial velocity, acceleration and distance covered for an object moving with a constant acceleration(first answer gets marked brainliest) |
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Answer» Let an object is moving with uniform acceleration. Let an object is moving with uniform acceleration. Let the initial velocity of the object = u Let the object is moving with uniform acceleration, a. Let object reaches at POINT B after time, t and its final velocity BECOMES, v Draw a line parallel to x-axis DA from point, D from where object starts moving. Draw another line BA from point B parallel to y-axis which meets at E at y-axis.Let OE = time, t Now, from the graph, BE = AB + AE ⇒ v = DC + OD (Since, AB = DC and AE = OD) ⇒ v = DC + u (Since, OD = u) ⇒ v = DC + u ------------------- (i) Now, Acceleration (a) =(Change in velocity)/(Time taken) a= v – ut ⇒ a = v - ut ⇒ a= OC – OD t = DC t ⇒a = OC-OD t =DC t ⇒at=DC ⇒at=DC -----(ii) By substituting the value of DC from (ii) in (i) we get v= at + u v = at + u ⇒ v = u + at ⇒ v = u + at Above equation is the relation among initial velocity (u), final velocity (v), acceleration (a) and time (t). It is called first equation of motion. |
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| 43. |
A vessel contains equal mass of CO2 and N2O . The mole fraction of CO2 is.. |
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Answer» Answer:33.3 Explanation:INITIAL partial pressures of CO and CO 2 are 3 atm and 2 atm respectively. 2CO(g)⇋CO 2 (g)+C(s) To reach EQUILIBRIUM, 2x atm of CO reacts to FORM x atm of CO 2
The equilibrium partial pressures of CO and CO 2 are 3−2x atm and 2+x atm respectively. Total equilibrium PRESSURE is (3−2x)+(2+x)=5−x atm. But it is equal to 4.5 atm. 4.5=5−x x=5−4.5 x=0.5 p CO :p CO 2
=(3−2x):(2+x)=(3−2(0.5)):(2+1(0.5))=2:2.5=4:5 K p = P CO 2
P CO 2
K p = 2 2
2.5
K p =0.625atm −1
The DISSOCIATION of CO = 3 2x = 3 2(0.5) =0.333 The % dissociation of CO =100×0.333=33.3 |
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| 44. |
साम्पीयर2यद्या दीर विद्युत परिपथ मेंविसंवातरक्यों हैVVW |
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Answer» SAMI Pattu Vidyut paripath Mein Vishwas kya hai Jaise biwi HAMARA HO jaega donon Ko Mila Ke Hamara dablue BAN jata hai aise Hamara aaa mila ke hamara and ban jata hai |
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| 45. |
a force of 14 newton is needed to site a 10 kg steel box moving across a wooden floor the coefficient of static friction is |
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Answer» f=14n m=10kg co EFFICIENT =1 Explanation: |
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| 46. |
A potential difference of V = ( 100 2) volt applied to a resistance R gives acurrent I = (( 10 0.5) A. Find the percentage error in R if |
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Answer» SORRY I can not answer. |
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| 47. |
Why fingers are wetted at intervals while counting currency notes |
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Answer» Answer: fingers are WETTED because,the RUPEE note may stick each other,this may give some problem while counting MONEY ,so fingers are wetted.... hope you UNDERSTOOD ,,THANK you |
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| 48. |
What are the daily life uses of velocity |
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Answer» Answer: daily life uses of velocity are - 1).revolution of earth AROUND SUN 2).velocity of a SATELLITE around the earth 3).velocity of a car while driving HOPE IT HELPS .MARK AS BRAINLIST |
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| 49. |
What is the sI unit of turning effect |
Answer» The turning EFFECT of a force is known as the moment. It is the product of the force multiplied by the perpendicular DISTANCE from the line of action of the force to the pivot or point where the object will turn. SI UNIT of moment of a force is Newton-metre (Nm). It is a vector quantity.Explanation: I HOPE you understand the answer if you then ♥️ and follow me |
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| 50. |
If void doesn't exist... what is the starting point of everything? |
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Answer» STARTING POINT of EVERYTHING is ENERGY |
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