67486 + Interview Questions in Secondary School in Physics

1.	Please solve this que
Answer» NEEND AARI H KAL krunga...

Discussion

2.	* In the phenomenon of propogation of air a)Temperature remains constant b)heat remains constant c) Preessure remains constant d)Both a and b
Answer» ANSWER: c Explanation: PRESSURE REMAIN constant bcs there no need

2.

* In the phenomenon of propogation of air a)Temperature remains constant b)heat remains constant c) Preessure remains constant d)Both a and b

Answer»

ANSWER:

c

Explanation:

PRESSURE REMAIN constant bcs there no need

Discussion

3.	A body radiates heat at the rate of 5 cal/m²-Swhen its temperature is 227 °C. The heatradiated by the same bodysame body when itstemperature is 727 °C is
Answer» ANSWER: $energy \: radiated \: \alpha \: {t}^{2}$ t1=500 and T2= 1000 so E2=16E1 so E2=80cal/m^2S hope it helps please MARK me as the BRAINLIEST

3.

A body radiates heat at the rate of 5 cal/m²-Swhen its temperature is 227 °C. The heatradiated by the same bodysame body when itstemperature is 727 °C is

Answer»

ANSWER:

$energy \: radiated \: \alpha \: {t}^{2}$

t1=500 and T2= 1000

so E2=16E1

so E2=80cal/m^2S

hope it helps

please MARK me as the BRAINLIEST

Discussion

4.	What essential app YouTubers use
Answer» Answer: Kinemaster( mobile) FILMORA (PC, DESKTOP or mobile) Explanation: It helps them to EDIT their videos

4.

What essential app YouTubers use

Answer»

Answer:

Kinemaster( mobile)

FILMORA (PC, DESKTOP or mobile)

Explanation:

It helps them to EDIT their videos

Discussion

5.	A spiral tube whose inside frictionless lies flat on a horizontal table
Answer» ANSWER: PLESE I FOLLOWING so plese CLICK on MARK brilient

5.

A spiral tube whose inside frictionless lies flat on a horizontal table

Answer»

ANSWER:

PLESE I FOLLOWING so plese CLICK on MARK brilient

Discussion

6.	Please give the elaborate explaination of integration
Answer» ANSWER: [email PROTECTED]@[email protected]@[email protected]@7602472247//7602750243 Explanation: [email protected]@[email protected]@[email protected]@7602472247//7602750243

6.

Please give the elaborate explaination of integration

Answer»

ANSWER:

[email PROTECTED]@[email protected]@[email protected]@7602472247//7602750243

Explanation:

[email protected]@[email protected]@[email protected]@7602472247//7602750243

Discussion

7.	36. A charge Q is uniformly distributed over a rod oflength 21. Consider cube of edge / with the centre ofcube at one end of the rod. The minimum possibleelectric flux through the surface of the cube isQ
Answer» ANSWER: MARK ME AS BRAINLIEST. THIS IS YOUR ANSWER AND EXPLANATION .

7.

36. A charge Q is uniformly distributed over a rod oflength 21. Consider cube of edge / with the centre ofcube at one end of the rod. The minimum possibleelectric flux through the surface of the cube isQ

Answer»

ANSWER:

MARK ME AS BRAINLIEST.

THIS IS YOUR ANSWER AND EXPLANATION .

Discussion

8.	A balloon and mass are attached to a rod that is pivoted at P. The balloon is filled with helium, a gas less dense than air.
Answer» ANSWER: the correct answer is option B hope it helps U plz mark as brainlist... Gud morning HV a great ahead....

8.

A balloon and mass are attached to a rod that is pivoted at P. The balloon is filled with helium, a gas less dense than air.

Answer»

ANSWER:

the correct answer is option B

hope it helps U plz mark as brainlist...

Gud morning HV a great ahead....

Discussion

9.	if a body weighing 40 kg is taken inside the earth to a depth of 143 radius of the earth the weight of the body at that point is
Answer» EXPLAINATION: $f = g \times \frac{m1 \times m2}{ {d}^{2} }$ $= 6.67 \times {10}^{ - 11} \times \frac{40 \times 5.97 \times {10}^{24} }{ {143}^{2} }$ $= {10}^{13} \times \frac{6.67 \times 40 \times 5.97}{ {143}^{2} }$ $= 0.077 \times {10}^{13}$ $= 7.7 \times {10}^{11}$

9.

if a body weighing 40 kg is taken inside the earth to a depth of 143 radius of the earth the weight of the body at that point is

Answer»

EXPLAINATION:

$f = g \times \frac{m1 \times m2}{ {d}^{2} }$

$= 6.67 \times {10}^{ - 11} \times \frac{40 \times 5.97 \times {10}^{24} }{ {143}^{2} }$

$= {10}^{13} \times \frac{6.67 \times 40 \times 5.97}{ {143}^{2} }$

$= 0.077 \times {10}^{13}$

$= 7.7 \times {10}^{11}$

Discussion

10.	The work done to raise a mass m from the surfacof the earth to a height h, which is equal to thradius of the earth, is[NEET-2019](1) mgR.(2) 2mgR(3)1/2mgR(4)3/2mgR
Answer» AnswEr : To FIND the work done in lifting an OBJECT of mass 'm' to a height 'H' which is equal to Earth' radius. Initial Potential Energy in the object would be : $\sf U_o = - \dfrac{GMm}{R}$ When the object is lifted to a height 'h' : $\sf U= - \dfrac{GMm}{R + h}$ Here, h = radius of earth. $\longrightarrow \: \sf U = - \dfrac{GMm}{2R}$ Now, $\implies\sf W= U - U_o \\ \\ \implies \sf \: W = \dfrac{GMm}{R} \big(1 - \dfrac{1}{2} ) \\ \\ \implies \sf \: W = \dfrac{GMm}{r}$ Also, $\sf \: mg = \dfrac{GMm}{R {}^{2} } \\ \\ \longrightarrow \sf \: g {R}^{2} = GM$ Thus, $\implies \sf \: W = \dfrac{ {mgR}^{2} }{2R} \\ \\ \implies \boxed{ \boxed{ \sf W = \dfrac{mgR}{2} }}$ OPTION (C) is CORRECT

10.

The work done to raise a mass m from the surfacof the earth to a height h, which is equal to thradius of the earth, is[NEET-2019](1) mgR.(2) 2mgR(3)1/2mgR(4)3/2mgR

Answer»

AnswEr :

To FIND the work done in lifting an OBJECT of mass 'm' to a height 'H' which is equal to Earth' radius.

Initial Potential Energy in the object would be :

$\sf U_o = - \dfrac{GMm}{R}$

When the object is lifted to a height 'h' :

$\sf U= - \dfrac{GMm}{R + h}$

Here, h = radius of earth.

$\longrightarrow \: \sf U = - \dfrac{GMm}{2R}$

Now,

$\implies\sf W= U - U_o \\ \\ \implies \sf \: W = \dfrac{GMm}{R} \big(1 - \dfrac{1}{2} ) \\ \\ \implies \sf \: W = \dfrac{GMm}{r}$

Also,

$\sf \: mg = \dfrac{GMm}{R {}^{2} } \\ \\ \longrightarrow \sf \: g {R}^{2} = GM$

Thus,

$\implies \sf \: W = \dfrac{ {mgR}^{2} }{2R} \\ \\ \implies \boxed{ \boxed{ \sf W = \dfrac{mgR}{2} }}$

11.	Draw a circuit diagram for comparing 2 resistances using a meter bridge.give the principal of the experiment why the method suitable for 2 resistance of the same order of magnitude
Answer» Answer: *· Comparison of emf of TWO cells: First of all the ends of potentiometer are connected to a BATTERY B1, KEY K and rheostat Rh such ...*

Draw a circuit diagram for comparing 2 resistances using a meter bridge.give the principal of the experiment why the method suitable for 2 resistance of the same order of magnitude

Answer»

Answer:

· Comparison of emf of TWO cells: First of all the ends of potentiometer are connected to a BATTERY B1, KEY K and rheostat Rh such ...

Discussion

12.	11. A particle of mass m is projected with velocity vmaking an angle of 45° with the horizontal. Whenthe particle lands on the ground level, the magnitudeof the change in its momentum will be :-(1) muz (2) zero (3) 2 mv (4) my/ 2
Answer» ANSWER: be ABLE GET to the for US

12.

11. A particle of mass m is projected with velocity vmaking an angle of 45° with the horizontal. Whenthe particle lands on the ground level, the magnitudeof the change in its momentum will be :-(1) muz (2) zero (3) 2 mv (4) my/ 2

Answer»

ANSWER:

be ABLE GET to the for US

Discussion

13.	Find tension in both the strings. The system is in equilibrium. Take the value of g as 10
Answer» EXPLANATION: if the SYSTEM is at equilibrium, then for string 1, T1=m1g= 50N and,for string 2, T2 = (m1+m2)g =70N

13.

Find tension in both the strings. The system is in equilibrium. Take the value of g as 10

Answer»

EXPLANATION:

if the SYSTEM is at equilibrium, then

for string 1, T1=m1g= 50N

and,for string 2, T2 = (m1+m2)g

=70N

Discussion

14.	A car travels a distance S, on a straight road in 2 hrs and returns to its startingpoint in 3 hrs. What isits average velocity?
Answer» Answer: 2/3 x65 =u889 Explanation: s=898

14.

A car travels a distance S, on a straight road in 2 hrs and returns to its startingpoint in 3 hrs. What isits average velocity?

Answer»

Answer:

2/3 x65 =u889

Explanation:

s=898

Discussion

15.	Explore some more applications of the triangle's law of vector addition in our day-to-day life.
Answer» Answer: *The triangle LAW shows that the shortest distance between these TWO points is a this straight ... RELATED Questions (More ANSWERS Below) ... What are some real life applications of circles?*

15.

Explore some more applications of the triangle's law of vector addition in our day-to-day life.

Answer»

Answer:

The triangle LAW shows that the shortest distance between these TWO points is a this straight ... RELATED Questions (More ANSWERS Below) ... What are some real life applications of circles?

Discussion

16.	Which device reduces human efforts *
Answer» Machines Explanation: As a resultant product of physics machines and ROBOTS can greatly reduce human EFFORTS (PHYSICALLY as WELL as MENTALLY).

16.

Which device reduces human efforts *

Answer»

Machines

Explanation:

As a resultant product of physics machines and ROBOTS can greatly reduce human EFFORTS (PHYSICALLY as WELL as MENTALLY).

Discussion

17.	What is the ratio of kinetic energy of projectile at maximum height and point of projection
Answer» Answer: *4:1* *4:1the ratio of kinetic ENERGY of a projectile at the POINT of projection to the MAXIMUM HEIGHT is*

17.

What is the ratio of kinetic energy of projectile at maximum height and point of projection

Answer»

Answer:
4:1
4:1the ratio of kinetic ENERGY of a projectile at the POINT of projection to the MAXIMUM HEIGHT is

Discussion

18.	Why does wool doesn't allow to pass charge to the metal rod?
Answer» EXPLANATION: because it is an INSULATOR to ELECTRICITY

18.

Why does wool doesn't allow to pass charge to the metal rod?

Answer»

EXPLANATION:

because it is an INSULATOR to ELECTRICITY

Discussion

19.	A particle is thrown at an angle a to the horizontal witha velocity 'V'. The acceleration and rate of change ofspeed at t = 0 have values (magnitude only)(A) (g cos a, g)(B) (g, g sin a)(C) (-g, -g)(D) (-g, - g cos a)
Answer» ANSWER: EXPLANATION: (D) (-G, - g COS a)

19.

A particle is thrown at an angle a to the horizontal witha velocity 'V'. The acceleration and rate of change ofspeed at t = 0 have values (magnitude only)(A) (g cos a, g)(B) (g, g sin a)(C) (-g, -g)(D) (-g, - g cos a)

Answer»

ANSWER:

EXPLANATION:

(D) (-G, - g COS a)

Discussion

20.	A sponge is compressible ? is it a gas?explain
Answer» Here is your answer mate The sponge has minute or small pores in which the AIR is trapped .when pressed , the air inside is EXPELLED out and HENCE we SAY it is compressible . Hope it will HELP you!

20.

A sponge is compressible ? is it a gas?explain

Answer»

Here is your answer mate

The sponge has minute or small pores in which the AIR is trapped .when pressed , the air inside is EXPELLED out and HENCE we SAY it is compressible .

Hope it will HELP you!

Discussion

21.	Draw a schematic diagram of a circuit consisting of a battery of 3 cell of 2V each a combination of three resistors of 10,20,30 connected in parallel a plug key and an ammeter all connected in series
Answer» Answer: voltage of each cell = 2 V number of cells = 3 total voltage of the battery = 3 x 2 = 6 V R1 = 10 ohm R2 = 20 ohm R3 = 30 ohm All the resistances are in parallel. So, the equivalent resistance is GIVEN by

21.

Draw a schematic diagram of a circuit consisting of a battery of 3 cell of 2V each a combination of three resistors of 10,20,30 connected in parallel a plug key and an ammeter all connected in series

Answer»

Answer:

voltage of each cell = 2 V

number of cells = 3

total voltage of the battery = 3 x 2 = 6 V

R1 = 10 ohm

R2 = 20 ohm

R3 = 30 ohm

All the resistances are in parallel.

So, the equivalent resistance is GIVEN by

Discussion

22.	Write the name and structural formula of row material used in the preparation row materials
Answer» Answer: Explanation:A raw material, ALSO known as a feedstock, unprocessed material, or primary commodity, is a basic material that is used to PRODUCE goods, finished PRODUCTS, energy, or intermediate materials that are feedstock for FUTURE finished products. As feedstock, the term CONNOTES these materials are bottleneck assets and ... This type of iron is unlike most of the iron in the earth, as the ...

22.

Write the name and structural formula of row material used in the preparation row materials

Answer»

Answer:

Explanation:A raw material, ALSO known as a feedstock, unprocessed material, or primary commodity, is a basic material that is used to PRODUCE goods, finished PRODUCTS, energy, or intermediate materials that are feedstock for FUTURE finished products. As feedstock, the term CONNOTES these materials are bottleneck assets and ... This type of iron is unlike most of the iron in the earth, as the ...

Discussion

23.	On increasing the mass of body the density will
Answer» Answer: Density will ALSO increase Explanation: Density is directly proportional to mass of the body Hope it HELPS.....

23.

On increasing the mass of body the density will

Answer»

Answer:

Density will ALSO increase

Explanation:

Density is directly proportional to mass of the body

Hope it HELPS.....

Discussion

24.	If p.q =pq then angle between pand q is
Answer» Answer: EXPLANATION: P.Q=pq cos thita thita =1 so thita =0° so they are parallel also So this is possible p.q=pq Thita =0° Hey I am a STUDENT of ALLEN kota do you ,it is best coaching in the WORLD

24.

If p.q =pq then angle between pand q is

Answer»

Answer:

EXPLANATION:

P.Q=pq cos thita thita =1 so thita =0° so they are parallel also

So this is possible p.q=pq

Thita =0°

Hey I am a STUDENT of ALLEN kota do you ,it is best coaching in the WORLD

Discussion

25.	Can we have ph less than 0 and more than 14
Answer» Answer: YES, you can have Explanation: The pH value can be less than 0 for very strong ACIDS and GREATER than 14 for very strong bases HOPE hope it can help you

25.

Can we have ph less than 0 and more than 14

Answer»

Answer:

YES, you can have

Explanation:

The pH value can be less than 0 for very strong ACIDS and GREATER than 14 for very strong bases

HOPE hope it can help you

Discussion

26.	If A and B are two objects having masses of 2 kg and 200 Kg respectively, then *
Answer» ANSWER: MENTION ur question CLEARLY DEAR Explanation: HY gm

26.

If A and B are two objects having masses of 2 kg and 200 Kg respectively, then *

Answer»

ANSWER:

MENTION ur question CLEARLY DEAR

Explanation:

HY gm

Discussion

27.	What is the relation between the minimum wavelengths of continuous and characteristic xrays?
Answer» Explanation: Wavelength of characteristic X-rays DECREASES when the atomic number of the target increases. Cut-off wavelength of the CONTINUOUS X-rays depends on the atomic number of the target. INTENSITY of the characteristic X-rays depends on the ELECTRICAL power GIVEN to the X-ray tube.

27.

What is the relation between the minimum wavelengths of continuous and characteristic xrays?

Answer»

Explanation:

Wavelength of characteristic X-rays DECREASES when the atomic number of the target increases. Cut-off wavelength of the CONTINUOUS X-rays depends on the atomic number of the target. INTENSITY of the characteristic X-rays depends on the ELECTRICAL power GIVEN to the X-ray tube.

Discussion

28.	Is light A particle or a wave? justify your answer with example.
Answer» Answer: light is both a particle and a WAVE Explanation: Quantum mechanics TELLS us that light can behave simultaneously as a particle or a wave. EXAMPLE When UV light hits a metal surface, it causes an emission of electrons. Albert Einstein explained this "PHOTOELECTRIC" effect by proposing that lightQuantum mechanics tells us that light can be. Albert Einstein explained this "photoelectric" effect by proposing that light – thought to only be a wave- is also a stream of PARTICLES.

28.

Is light A particle or a wave? justify your answer with example.

Answer»

Answer:

light is both a particle and a WAVE

Explanation:

Quantum mechanics TELLS us that light can behave simultaneously as a particle or a wave.

EXAMPLE

When UV light hits a metal surface, it causes an emission of electrons. Albert Einstein explained this "PHOTOELECTRIC" effect by proposing that lightQuantum mechanics tells us that light can be. Albert Einstein explained this "photoelectric" effect by proposing that light – thought to only be a wave- is also a stream of PARTICLES.

Discussion

29.	the force on a charged particle due to electric and magnetic field is given by f vector is equal to Q II + UV in to be supposed is along the x-axis and be along the y axis
Answer» Answer: hi ma I will SEND you an English teacher at a time with the new year good to hear from them have a good MORNING ma'am PLEASE see attached for the use was poor but it was poor quality and the god I LOVE from us and PANTING to be in

29.

the force on a charged particle due to electric and magnetic field is given by f vector is equal to Q II + UV in to be supposed is along the x-axis and be along the y axis

Answer»

Answer:

hi ma I will SEND you an English teacher at a time with the new year good to hear from them have a good MORNING ma'am PLEASE see attached for the use was poor but it was poor quality and the god I LOVE from us and PANTING to be in

Discussion

30.	DON'T SPAM In I(1) From where 3 came here?
Answer» SEE this its a SIMPLE SOLUTION

Discussion

31.	16.12Irin ,connazfind the current in each resistorहाउ
Answer» ANSWER: do yourself and MAKE me BRAINLIEST

31.

16.12Irin ,connazfind the current in each resistorहाउ

Answer»

ANSWER:

do yourself and MAKE me BRAINLIEST

Discussion

32.	When 999mm is added to 100m then we get
Answer» ANSWER 100.999m or 101m Explanation: 1M = 1000MM 999MM = 999/1000m =0.999m 100m+0.999m = 100.999m or 101m

32.

When 999mm is added to 100m then we get

Answer»

ANSWER 100.999m or 101m

Explanation: 1M = 1000MM

999MM = 999/1000m

=0.999m

100m+0.999m = 100.999m or 101m

Discussion

33.	Boy of mass 40 kg climb up the stairs and reach the roof at the height of 10 meters with a weight of 10 kg in his hand in 1 min . how much power spend by the boy
Answer» Answer:power=force by VELOCITY velocity =height/time =10/60 =0.16 and force=weight =MASS by gravity THEREFORE weight =40 by 10 =50N THEREFORE POWER= 50 by 0.16 =8 watt Explanation:

33.

Boy of mass 40 kg climb up the stairs and reach the roof at the height of 10 meters with a weight of 10 kg in his hand in 1 min . how much power spend by the boy

Answer»

Answer:power=force by VELOCITY

velocity =height/time

=10/60 =0.16

and force=weight =MASS by gravity

THEREFORE weight =40 by 10 =50N

THEREFORE POWER= 50 by 0.16

=8 watt

Explanation:

Discussion

34.	Dimensional analysis formula for torque
Answer» Torque has the DIMENSION of FORCE times distance, SYMBOLICALLY L2MT−2. OFFICIAL SI LITERATURE suggests using the unit newton metre (N⋅m). In SI base units: kg⋅m2⋅s−2 SI unit: N⋅m Other units: pound-force-feet, lbf⋅inch, ozf⋅in Dimension: M L2T−2

34.

Dimensional analysis formula for torque

Answer»

Torque has the DIMENSION of FORCE times distance, SYMBOLICALLY L2MT−2. OFFICIAL SI LITERATURE suggests using the unit newton metre (N⋅m).

In SI base units: kg⋅m2⋅s−2

SI unit: N⋅m

Other units: pound-force-feet, lbf⋅inch, ozf⋅in

Dimension: M L2T−2

Discussion

35.	A cylindrical conductor of length 1 and uniform area of cross section A has resistance R. Another conductor of same material and resistance R has length 21. what will be it's area of cross section
Answer» Answer: area of CROSS section will be 2A Hi Aashritha , this is Anu (actually it is not 1 it is L , so kindly REPLACE the 1s with Ls) and check the answer below The resistance of a WIRE is R=ρ A/L which can ALSO be represented as A=ρ R/L where, ρ - Resistivity L - LENGTH A - Area of a cross-section ◇ WKT, the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance. ◇ In this case, the length of the conductor is doubled (2L) and so the resistance will be 2R. For the resistance to remain the same as R, the area of cross-section is also doubled as 2A. therefore, the area of cross-section is 2A.

35.

A cylindrical conductor of length 1 and uniform area of cross section A has resistance R. Another conductor of same material and resistance R has length 21. what will be it's area of cross section

Answer»

Answer: area of CROSS section will be 2A

Hi Aashritha , this is Anu (actually it is not 1 it is L , so kindly REPLACE the 1s with Ls) and check the answer below

The resistance of a WIRE is

R=ρ A/L

which can ALSO be represented as

A=ρ R/L

where,

ρ - Resistivity

L - LENGTH

A - Area of a cross-section

◇ WKT, the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance.

◇ In this case, the length of the conductor is doubled (2L) and so the resistance will be 2R. For the resistance to remain the same as R, the area of cross-section is also doubled as 2A.

therefore, the area of cross-section is 2A.

Discussion

36.	Write importance of local technology
Answer» Answer: Local KNOWLEDGE is the human capital of both the urban and rural people. It is the MAIN asset they invest in the STRUGGLE for survival, to produce food, provide for shelter or achieve control of their own LIVES. ... Today, many local knowledge systems are at risk of BECOMING extinct. Explanation:

36.

Write importance of local technology

Answer»

Answer:

Local KNOWLEDGE is the human capital of both the urban and rural people. It is the MAIN asset they invest in the STRUGGLE for survival, to produce food, provide for shelter or achieve control of their own LIVES. ... Today, many local knowledge systems are at risk of BECOMING extinct.

Explanation:

Discussion

37.	What is the basic objectives of radioactive pollution and it's control measures?
Answer» Answer: The basic objectives of radiation protection are to prevent the occurrence of acute effects and to limit the probabilities of occurrence of late somatic and genetic effects. 1)SELECT reagents and procedures that MINIMIZE the volume and TOXICITY of all wastes. ... 2)Avoid ORDERING radioactive materials in quantities that exceed your intended usage. 3)Non-radioactive wastes must never be mixed with radioactive wastes. HOPE IT HELPS YOU!! PLEASE MARK ME BRAINLIEST!!I BEG YOU

37.

What is the basic objectives of radioactive pollution and it's control measures?

Answer»

Answer:

The basic objectives of radiation protection are to prevent the occurrence of acute effects and to limit the probabilities of occurrence of late somatic and genetic effects.

1)SELECT reagents and procedures that MINIMIZE the volume and TOXICITY of all wastes. ...

2)Avoid ORDERING radioactive materials in quantities that exceed your intended usage.

3)Non-radioactive wastes must never be mixed with radioactive wastes.

HOPE IT HELPS YOU!!

PLEASE MARK ME BRAINLIEST!!I BEG YOU

Discussion

38.	Sensetivity of galvanometer depends on which factor
Answer» Answer: It depends on number of turns, coil AREA, restoring force per unit twist, and magnetic FIELD. It is so because these quantities DETERMINE the TORQUE, as the CURRENT flows through the coil. Explanation:

38.

Sensetivity of galvanometer depends on which factor

Answer»

Answer:

It depends on number of turns, coil AREA, restoring force per unit twist, and magnetic FIELD. It is so because these quantities DETERMINE the TORQUE, as the CURRENT flows through the coil.

Explanation:

Discussion

39.	Which of the following can sometimes be zero for a moving body
Answer» ANSWER: DISPLACEMENT can be ZERO for a MOVING BODY

39.

Which of the following can sometimes be zero for a moving body

Answer»

ANSWER:

DISPLACEMENT can be ZERO for a MOVING BODY

Discussion

40.	Friction that 10 times smaller than sliding friction is
Answer» EXPLANATION: Sliding friction is greater than ROLLING friction. Rolling friction is the resistance to motion experienced by a body when it rolls UPON ANOTHER. It is much less than sliding friction for same pair of bodies. When one body rolls upon another, there is theoretically no sliding or slip between them. And if both are perfectly rigid, there is no surface of CONTACT. If there is no surface contact then the friction is very less. PLEASE FOLLOW ME IF POSSIBLE PA Please

40.

Friction that 10 times smaller than sliding friction is

Answer»

EXPLANATION:

Sliding friction is greater than ROLLING friction.

Rolling friction is the resistance to motion experienced by a body when it rolls UPON ANOTHER. It is much less than sliding friction for same pair of bodies. When one body rolls upon another, there is theoretically no sliding or slip between them. And if both are perfectly rigid, there is no surface of CONTACT. If there is no surface contact then the friction is very less.

PLEASE FOLLOW ME IF POSSIBLE PA Please

Discussion

41.	Brainliest???.......................
Answer» ANSWER: who me OOI THINK it is HELPFUL to you

41.

Brainliest???.......................

Answer»

ANSWER:

who me

OOI THINK it is HELPFUL to you

Discussion

42.	Please solve this question I will mark u brainliest please help!!!!!!
Answer» Now WHERES my BRAINLIEST!!!!

42.

Please solve this question I will mark u brainliest please help!!!!!!

Answer»

Now WHERES my BRAINLIEST!!!!

Discussion

43.	Describe an experiment to measure the density of a piece of iron
Answer» Subtract the INITIAL VOLUME of water from the final volume to determine the volume of the metal. DIVIDE the MASS by the volume to calculate the density of the metal. For example, if the mass was 7.952 pounds and the volume was 28 cubic inches, the density would be 0.284 pounds per cubic inch.

43.

Describe an experiment to measure the density of a piece of iron

Answer»

Subtract the INITIAL VOLUME of water from the final volume to determine the volume of the metal. DIVIDE the MASS by the volume to calculate the density of the metal. For example, if the mass was 7.952 pounds and the volume was 28 cubic inches, the density would be 0.284 pounds per cubic inch.

Discussion

44.	A car accelerates at 5 ms-2 from an initial velocity of 13 ms-1 over a distance of 100 m. Calculate the velocity at the end of the 100 m.
Answer» $\huge\sf\pink{Answer}$ ☞ FINAL Velocity of the BODY at the end of 100 m is 34.20 m/s ━━━━━━━━━━━━━ $\huge\sf\blue{Given}$ ✭ Acceleration = 5 m/s² ✭ INITIAL velocity = 13 m/s ✭ Distance travelled = 100 m ━━━━━━━━━━━━━ $\huge\sf\gray{To \:Find}$ ◈ The Final Velocity of the body? ━━━━━━━━━━━━━ $\huge\sf\purple{Steps}$ So here at first we may get an idea to use the second equation of motion but no time is given so we shall use the third equation of motion, that is, $\underline{\boxed{\sf v^2-u^2 = 2as}}$ Substituting the given values, ➝ $\sf v^2-u^2 = 2as$ ➝ $\sf v^2 - 13^2 = 2(5)(100)$ ➝ $\sf v^2 - 169 = 1000$ ➝ $\sf v^2 = 1000+169$ ➝ $\sf v^2 = 1169$ ➝ $\sf v = \sqrt{1169}$ ➝ $\sf \orange{v=34.20 \ m/s}$ ━━━━━━━━ ☯ $\large\sf Know \ More$ »» Velocity is a vector qualitiy,that is it has both magnitude and direction »» Velocity = Displacement/Time »» SI unit of velocity is m/s Other two equations ◕ $\sf v = u+at$ ◕ $\sf s = ut+\dfrac{1}{2} at^2$ ━━━━━━━━━━━━━━━━━━

44.

A car accelerates at 5 ms-2 from an initial velocity of 13 ms-1 over a distance of 100 m. Calculate the velocity at the end of the 100 m.

Answer»

$\huge\sf\pink{Answer}$

☞ FINAL Velocity of the BODY at the end of 100 m is 34.20 m/s

━━━━━━━━━━━━━

$\huge\sf\blue{Given}$

✭ Acceleration = 5 m/s²

✭ INITIAL velocity = 13 m/s

✭ Distance travelled = 100 m

━━━━━━━━━━━━━

$\huge\sf\gray{To \:Find}$

◈ The Final Velocity of the body?

━━━━━━━━━━━━━

$\huge\sf\purple{Steps}$

So here at first we may get an idea to use the second equation of motion but no time is given so we shall use the third equation of motion, that is,

$\underline{\boxed{\sf v^2-u^2 = 2as}}$

Substituting the given values,

➝ $\sf v^2-u^2 = 2as$

➝ $\sf v^2 - 13^2 = 2(5)(100)$

➝ $\sf v^2 - 169 = 1000$

➝ $\sf v^2 = 1000+169$

➝ $\sf v^2 = 1169$

➝ $\sf v = \sqrt{1169}$

➝ $\sf \orange{v=34.20 \ m/s}$

━━━━━━━━

☯ $\large\sf Know \ More$

»» Velocity is a vector qualitiy,that is it has both magnitude and direction

»» Velocity = Displacement/Time

»» SI unit of velocity is m/s

Other two equations

◕ $\sf v = u+at$

◕ $\sf s = ut+\dfrac{1}{2} at^2$

━━━━━━━━━━━━━━━━━━

Discussion

45.	Physical quantity x and y are related as. If atradian error in measurement of x isthen finderror in measurement of y at
Answer» ANSWER: what is your AGE. SORRY if you're LADY or GIRL

45.

Physical quantity x and y are related as. If atradian error in measurement of x isthen finderror in measurement of y at

Answer»

ANSWER:

what is your AGE. SORRY if you're LADY or GIRL

Discussion

46.	Flow of electric charge in a metallic conductor
Answer» An electric current flows when electrons MOVE through a CONDUCTOR, such as a metal wire. ... ELECTRICITY passes through metallic conductors as a flow of negatively charged electrons. The electrons are free to move from ONE atom to another.

Discussion

47.	What is the energy associated with each vibrational frequency of gas?
Answer» $\huge\rm\underline\purple{Answer:-}$ $\huge\mathcal\color{teal}Vibrational\: frequency$ ➡️ Vibrations refer to the oscillating and vibrating movement of atoms and particles caused by energy. ... Because of this, all humans and OBJECTS have an energy FIELD that has its own vibrational frequency. Frequency, which is measured in hertz (Hz) units, is the rate at which vibrations and oscillations occur. ➡️ Following are some important factors affecting the vibrational frequency of a bond. Bond order AFFECTS the position of absorption bands. Higher the bond order larger is the BAND frequency. A C-C triple bond is stronger than a C=C bond, so a C-C triple bond has higher stretching frequency than does a C=C bond. ➡️ A lower mass and/or a stiffer beam increase the natural frequency; a higher mass and/or a softer beam lower the natural frequency. (Left) A lower mass increases natural frequency. (Right) A higher mass LOWERS natural frequency. __________________________ ✌ Follow me ✌️ __________________________

47.

What is the energy associated with each vibrational frequency of gas?

Answer»

$\huge\rm\underline\purple{Answer:-}$

$\huge\mathcal\color{teal}Vibrational\: frequency$

➡️ Vibrations refer to the oscillating and vibrating movement of atoms and particles caused by energy. ... Because of this, all humans and OBJECTS have an energy FIELD that has its own vibrational frequency. Frequency, which is measured in hertz (Hz) units, is the rate at which vibrations and oscillations occur.

➡️ Following are some important factors affecting the vibrational frequency of a bond. Bond order AFFECTS the position of absorption bands. Higher the bond order larger is the BAND frequency. A C-C triple bond is stronger than a C=C bond, so a C-C triple bond has higher stretching frequency than does a C=C bond.

➡️ A lower mass and/or a stiffer beam increase the natural frequency; a higher mass and/or a softer beam lower the natural frequency. (Left) A lower mass increases natural frequency. (Right) A higher mass LOWERS natural frequency.

__________________________

✌ Follow me ✌️

__________________________

Discussion

48.	Please say. how force along side is equal to W cos theta ... in the simplest form
Answer» SORRY... LOOKED at ATTACHED HOPE its HELP. . . .

48.

Please say. how force along side is equal to W cos theta ... in the simplest form

Answer»

SORRY...

LOOKED at ATTACHED HOPE its HELP.

.

Discussion

49.	A stone is thrown vertically upwards with an initial velocity of 40m/s.Find the maximum height reached by the stone. What is the netdisplacement and total distance covered by the stone?VERY URGENT PLS ANSWER GR 9 QUESTION
Answer» Answer: 81.63 meters Explanation: We will USE the following equation ${v}^{2} - {u}^{2} = 2as$ $initial \: <klux>VELOCITY</klux> \: = 40m {sec}^{ - 1}$ At MAX height,final velocity is ZERO ${0}^{2} - {40}^{2} = 2 \times ( - 9.8) \times s$ (Negative Acceleration) Solving, $s = \frac{1600}{19.6}$ $s = 81.63m$ Total distance is 163.26 m Total displacement is zero

49.

A stone is thrown vertically upwards with an initial velocity of 40m/s.Find the maximum height reached by the stone. What is the netdisplacement and total distance covered by the stone?VERY URGENT PLS ANSWER GR 9 QUESTION

Answer»

Answer:

81.63 meters

Explanation:

We will USE the following equation

${v}^{2} - {u}^{2} = 2as$

$initial \: <klux>VELOCITY</klux> \: = 40m {sec}^{ - 1}$

At MAX height,final velocity is ZERO

${0}^{2} - {40}^{2} = 2 \times ( - 9.8) \times s$

(Negative Acceleration)

Solving,

$s = \frac{1600}{19.6}$

$s = 81.63m$

Total distance is 163.26 m

Total displacement is zero

Discussion

50.	Which of the following is the force applied in drawing water from a well using a rope and pulley?
Answer» Explanation: we NEED to apply our HAND with our STRENGTH to DRAW WATER from a well.

50.

Which of the following is the force applied in drawing water from a well using a rope and pulley?

Answer»

Explanation:

we NEED to apply our HAND with our STRENGTH to DRAW WATER from a well.

Discussion

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