67486 + Interview Questions in Secondary School in Physics

1.	In the figure two conducting concentric charged spherical shells are shown. If the electric potential at the center is 20V and the electric potential of the outer shell is 5V, then the potential of the inner shell is
Answer» Answer: (a) 5V (B) 15V (C) 20V (d) 25V hope it helps you please follow me

1.

In the figure two conducting concentric charged spherical shells are shown. If the electric potential at the center is 20V and the electric potential of the outer shell is 5V, then the potential of the inner shell is

Answer»

Answer:

(a) 5V

(B) 15V

(C) 20V

(d) 25V

hope it helps you

please follow me

Discussion

2.	Deduse the relation with cofficent of static friction
Answer» ANSWER: PLS MARK me as BRAINELIST

2.

Deduse the relation with cofficent of static friction

Answer»

ANSWER:

PLS MARK me as BRAINELIST

Discussion

3.	a force of 10 newton is making an angle of 30 degree with the horizontal. what will be its horizontal
Answer» EXPLANATION: here is your ANSWER to the QUESTION

3.

a force of 10 newton is making an angle of 30 degree with the horizontal. what will be its horizontal

Answer»

EXPLANATION:

here is your ANSWER to the QUESTION

Discussion

4.	Uttar Lens 80 centimetre Dur sthit Ek Vastu KA vastvik pratibimb 20 centimetre Dur banta hai lens ka focus Doori gyat kijiye
Answer» BHAI ENGLISH me BHEJO PLZ

4.

Uttar Lens 80 centimetre Dur sthit Ek Vastu KA vastvik pratibimb 20 centimetre Dur banta hai lens ka focus Doori gyat kijiye

Answer»

BHAI ENGLISH me BHEJO PLZ

Discussion

5.	What is gravitational force? Describe in detail.
Answer» ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ғᴏʀᴄᴇ ☞ Eᴀʀᴛʜ ᴀᴛᴛʀᴀᴄᴛs ᴀʟʟ ᴛʜɪɴɢs ᴛᴏᴡᴀʀᴅs ɪᴛ ᴛʜʀᴏᴜɢʜ ᴀɴ ᴜɴsᴇᴇɴ ғᴏʀᴄᴇ ᴏғ ᴀᴛᴛʀᴀᴄᴛɪᴏɴ. Tʜɪs ғᴏʀᴄᴇ ᴏғ ᴀᴛᴛʀᴀᴄᴛɪᴏɴ ɪs ᴄᴀʟʟᴇᴅ ᴀs ɢʀᴀᴠɪᴛᴀᴛɪᴏɴ ᴏʀ ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ᴘᴜʟʟ. Yᴏᴜ ᴍᴜsᴛ ʜᴀᴠᴇ ɴᴏᴛɪᴄᴇᴅ ᴛʜᴀᴛ ᴇᴠᴇʀʏ ᴛɪᴍᴇ ʏᴏᴜ ᴛʜʀᴏᴡ ᴀɴ ᴏʙᴊᴇᴄᴛ ᴜᴘᴡᴀʀᴅs, ɪᴛ ʀᴇᴀᴄʜᴇs ᴀ ᴄᴇʀᴛᴀɪɴ ʜᴇɪɢʜᴛ ᴀɴᴅ ᴛʜᴇɴ ғᴀʟʟs ᴅᴏᴡɴ ᴏɴ ᴛʜᴇ ᴇᴀʀᴛʜ's sᴜʀғᴀᴄᴇ.

5.

What is gravitational force? Describe in detail.

Answer»

ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ғᴏʀᴄᴇ

☞ Eᴀʀᴛʜ ᴀᴛᴛʀᴀᴄᴛs ᴀʟʟ ᴛʜɪɴɢs ᴛᴏᴡᴀʀᴅs ɪᴛ ᴛʜʀᴏᴜɢʜ ᴀɴ ᴜɴsᴇᴇɴ ғᴏʀᴄᴇ ᴏғ ᴀᴛᴛʀᴀᴄᴛɪᴏɴ. Tʜɪs ғᴏʀᴄᴇ ᴏғ ᴀᴛᴛʀᴀᴄᴛɪᴏɴ ɪs ᴄᴀʟʟᴇᴅ ᴀs ɢʀᴀᴠɪᴛᴀᴛɪᴏɴ ᴏʀ ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ᴘᴜʟʟ. Yᴏᴜ ᴍᴜsᴛ ʜᴀᴠᴇ ɴᴏᴛɪᴄᴇᴅ ᴛʜᴀᴛ ᴇᴠᴇʀʏ ᴛɪᴍᴇ ʏᴏᴜ ᴛʜʀᴏᴡ ᴀɴ ᴏʙᴊᴇᴄᴛ ᴜᴘᴡᴀʀᴅs, ɪᴛ ʀᴇᴀᴄʜᴇs ᴀ ᴄᴇʀᴛᴀɪɴ ʜᴇɪɢʜᴛ ᴀɴᴅ ᴛʜᴇɴ ғᴀʟʟs ᴅᴏᴡɴ ᴏɴ ᴛʜᴇ ᴇᴀʀᴛʜ's sᴜʀғᴀᴄᴇ.

Discussion

6.	If magnification is 1 where the image will form?
Answer» IMAGE will form on radius of CURVATURE . Image will be EQUAL in SIZE , erect and virtual. $\large\red{\underline{\underline{\mathbb{MARK\:AS\:BRAINLIEST}}}}$

6.

If magnification is 1 where the image will form?

Answer»

IMAGE will form on radius of CURVATURE .

Image will be EQUAL in SIZE , erect and virtual.

$\large\red{\underline{\underline{\mathbb{MARK\:AS\:BRAINLIEST}}}}$

Discussion

7.	Applictions of principle conservation of linear momentum
Answer» Explanation: Conservation Of Linear MOMENTUM Applications The ROCKET FUEL burns are pushed the exhaust gases downwards, and due to this, the rocket GETS pushed upwards. Motorboats also work on the same principle, it pushes the water BACKWARD and gets pushed forwards in reaction to conserve momentum.

7.

Applictions of principle conservation of linear momentum

Answer»

Explanation:

Conservation Of Linear MOMENTUM Applications

The ROCKET FUEL burns are pushed the exhaust gases downwards, and due to this, the rocket GETS pushed upwards. Motorboats also work on the same principle, it pushes the water BACKWARD and gets pushed forwards in reaction to conserve momentum.

Discussion

8.	What is the mass on earth?
Answer» ANSWER: MASS OF EARTH IS 6 TIMES 10^24 Explanation:

8.

What is the mass on earth?

Answer»

ANSWER:

MASS OF EARTH IS 6 TIMES 10^24

Explanation:

Discussion

9.	What is a force and give its type
Answer» Explanation: Force is the EXTERNAL agent that produces motion or tends to produce motion or it stops motion or tends to STOP motion. Basically, there are two types of FORCES, contact forces, and non-contact forces. GRAVITATIONAL forces, electric forces, magnetic forces, nuclear forces, FRICTIONAL forces are some examples of force.

9.

What is a force and give its type

Answer»

Explanation:

Force is the EXTERNAL agent that produces motion or tends to produce motion or it stops motion or tends to STOP motion. Basically, there are two types of FORCES, contact forces, and non-contact forces. GRAVITATIONAL forces, electric forces, magnetic forces, nuclear forces, FRICTIONAL forces are some examples of force.

Discussion

10.	Question question question question question question question
Answer» Answer: (2) graph is impossible,irrelevant and illogical graph. According to it the OBJECT does TIME TRAVEL

10.

Question question question question question question question

Answer»

Answer:

(2) graph is impossible,irrelevant and illogical graph. According to it the OBJECT does TIME TRAVEL

Discussion

11.	Question question question question question question question question question question
Answer» Answer: 1 Explanation: 1 options speed TIME graph of a ball FALLING from HEIGHT

11.

Question question question question question question question question question question

Answer»

Answer:

1

Explanation:

1 options speed TIME graph of a ball FALLING from HEIGHT

Discussion

12.	3.A man moves from station A to B with speed 5 km/h for half time and with speed 15 km/h for remaining halftime. The average speed of the man over the entire journey is(1) 10 km/h(2) 12 km/h(3) 6 km/h(4) 25 km/h
Answer» Answer: 6 km/h Explanation: let, REQUIRED TIME for 1st half is x/2. distance=5X/2 required time for next half is x/6 hr. TOTAL time= 5x/6,total distance = 5x km average speed = distance/time= 6km/hr

12.

3.A man moves from station A to B with speed 5 km/h for half time and with speed 15 km/h for remaining halftime. The average speed of the man over the entire journey is(1) 10 km/h(2) 12 km/h(3) 6 km/h(4) 25 km/h

Answer»

Answer:

6 km/h

Explanation:

let, REQUIRED TIME for 1st half is x/2.

distance=5X/2

required time for next half is x/6 hr.

TOTAL time= 5x/6,total distance = 5x km

average speed = distance/time= 6km/hr

Discussion

13.	Object placed 50 m from concave lens of focal length 20 cm find the nature of image
Answer»

Discussion

14.	Convex lens is used in medical field
Answer» EXPLANATION: CONTACT l's corrective lenses that fit directly over the cornea of the eye; SEE ALSO contact lenses. converging lens (convex lens) one curved like the exterior of a hollow sphere; it BRINGS light to a focus.

14.

Convex lens is used in medical field

Answer»

EXPLANATION:

CONTACT l's corrective lenses that fit directly over the cornea of the eye; SEE ALSO contact lenses. converging lens (convex lens) one curved like the exterior of a hollow sphere; it BRINGS light to a focus.

Discussion

15.	4.The resistivitg does not change if
Answer» Answer: LENGTH of wire or area of cross SECTION of the wire changes I hope it HELPS you Mark me as brainliest and please follow me

15.

4.The resistivitg does not change if

Answer»

Answer:

LENGTH of wire or area of cross SECTION of the wire changes

I hope it HELPS you

Mark me as brainliest and please follow me

Discussion

16.	Define vector magnetic potential
Answer» Answer: Exa scalar QUANTITY, analogous to the ELECTRIC potential, defined at each point in a given magnetic field to be EQUAL to the work done in bringing a unit NORTH pole from infinity to the point.planation:

16.

Define vector magnetic potential

Answer»

Answer:

Exa scalar QUANTITY, analogous to the ELECTRIC potential, defined at each point in a given magnetic field to be EQUAL to the work done in bringing a unit NORTH pole from infinity to the point.planation:

Discussion

17.	What can you conclude about the figure? a. To be accurate, all the arrows would have to be inside the ring labeled 2. b. To be precise, half of the arrows would need to be inside the ring labeled 9. c. To be accurate, all the arrows would need to be near the ring labeled 10. d. It is not possible to be both accurate and precise at the same time.
Answer» *But* *are* *the* *FIGURES*.....!

Discussion

18.	A wire of length 1 and resistance R is stretched to get the radius of crosscross-sectional halved. What is the new resistance of the wires after stretching
Answer» ANSWER: the FINAL answer is 16R Explanation: HOPE it HELPS you

18.

A wire of length 1 and resistance R is stretched to get the radius of crosscross-sectional halved. What is the new resistance of the wires after stretching

Answer»

ANSWER:

the FINAL answer is 16R

Explanation:

HOPE it HELPS you

Discussion

19.	The body first level 30 metre into second and thus travel 40 metres in 5 seconds. What is the average speed
Answer» $\checkmark$ Given: A body travels 30 METRE in 2 second and then travels 40 metre in 5 SECONDS $\checkmark$ To FIND: The average speed $\checkmark$ Solution: We know that, $\red{\bigstar \ \boxed{\rm s=\dfrac{d}{t}}}$ Here, s = speed d = distance t = time According to the question, We are asked to find the average speed So, we must find "s" Given that, A body travels 30 metre in 2 second and then travels 40 metre in 5 seconds Hence, d = 30 + 40 = 70 m t = 2 + 5 = 7 s Substituting the VALUES, We get, $\blue{\rm \implies s=\dfrac{70}{7} \ m/s}$ $\pink{\rm \implies s=<klux>10</klux> \ m/s}$ Therefore, The average speed = 10 m/s

19.

The body first level 30 metre into second and thus travel 40 metres in 5 seconds. What is the average speed

Answer»

$\checkmark$ Given:

A body travels 30 METRE in 2 second and then travels 40 metre in 5

SECONDS

$\checkmark$ To FIND:

The average speed

$\checkmark$ Solution:

We know that,

$\red{\bigstar \ \boxed{\rm s=\dfrac{d}{t}}}$

Here,

s = speed
d = distance
t = time

According to the question,

We are asked to find the average speed

So, we must find "s"

Given that,

A body travels 30 metre in 2 second and then travels 40 metre in 5

seconds

Hence,

d = 30 + 40 = 70 m
t = 2 + 5 = 7 s

Substituting the VALUES,

We get,

$\blue{\rm \implies s=\dfrac{70}{7} \ m/s}$

$\pink{\rm \implies s=<klux>10</klux> \ m/s}$

Therefore,

The average speed = 10 m/s

Discussion

20.	What is the current through the 20 o resistor on the left of the 6V cell in figure
Answer» Explanation: there's no figure so, R = 20 Ω V = 6 v I = ? as PER OHM's law V = IR I = V/R I = 6/20 I = 0.3 A

20.

What is the current through the 20 o resistor on the left of the 6V cell in figure

Answer»

Explanation:

there's no figure so,

R = 20 Ω

V = 6 v

I = ?

as PER OHM's law

V = IR

I = V/R

I = 6/20

I = 0.3 A

Discussion

21.	Find current in each resistor
Answer» Answer: 1652 Is the ANSWRE OK THK HAI juru

21.

Find current in each resistor

Answer»

Answer:

1652 Is the ANSWRE OK THK HAI juru

Discussion

22.	सामान्य गुण89. समान ताप पर दो गैसों के वाष्प घनत्व 25:1 केअनुपातमें हैउनके अणुओं की वर्ग माध्य मूल चालों का अनुपात होगा(a)1:5(b)5:1(c)1:1 (d)25:1
Answer» ANSWER: सामान्य गुण 89. समान ताप पर दो गैसों के वाष्प घनत्व 25:1 के अनुपात में है उनके अणुओं की वर्ग माध्य मूल चालों का अनुपात होगा is d

22.

सामान्य गुण89. समान ताप पर दो गैसों के वाष्प घनत्व 25:1 केअनुपातमें हैउनके अणुओं की वर्ग माध्य मूल चालों का अनुपात होगा(a)1:5(b)5:1(c)1:1 (d)25:1

Answer»

ANSWER:

सामान्य गुण

89. समान ताप पर दो गैसों के वाष्प घनत्व 25:1 के

अनुपात

में है

उनके अणुओं की वर्ग माध्य मूल चालों का अनुपात होगा is d

Discussion

23.	What is the angle between Ar and the resultant of( ) A Bˆ +r and ( ) A Bˆ -r ?
Answer» Answer: it have only one relationship which is tells US in BOOK of math pg no. is 275to 276 for more ENQUIRIES like and ask me in the COMMENT SECTION

23.

What is the angle between Ar and the resultant of( ) A Bˆ +r and ( ) A Bˆ -r ?

Answer»

Answer:

it have only one relationship which is tells US in BOOK of math pg no. is 275to 276 for more ENQUIRIES like and ask me in the COMMENT SECTION

Discussion

24.	24 J work is done in moving a charge q between two points having potential difference 12 V. find the value of charge (V)
Answer» Here, • Work done = 24 J • Potential DIFFERENCE = 12 V • Charge = ? So, Potential Difference = Work done / Charge i.e. V = W/Q Q = W/V Q = 24/12 Q = 2 C So, charge is 2 coulomb. Hope it helps... PLEASE mark my answer as the brainliest...

Discussion

25.	The maximum tension in the steel rod is 580 N and the maximum stress in the link is 30 N/mm2. If the link is of square cross-section, determine its side length
Answer» ANSWER: HTTPS://www.passeidireto.com/arquivo/20650912/a-textbook-of-machine-design-si-units-rs-khurmi-jk-gupta/40

25.

The maximum tension in the steel rod is 580 N and the maximum stress in the link is 30 N/mm2. If the link is of square cross-section, determine its side length

Answer»

ANSWER:

HTTPS://www.passeidireto.com/arquivo/20650912/a-textbook-of-machine-design-si-units-rs-khurmi-jk-gupta/40

Discussion

26.	How many electrons are make up one columb of negative charge
Answer» my DEAR FRIEND its ANSWER is very SIMPLE -2

Discussion

27.	Give me some points on current electricity , potential and potential difference .
Answer» ANSWER: love Explanation:

27.

Give me some points on current electricity , potential and potential difference .

Answer»

ANSWER:

love

Explanation:

Discussion

28.	a force acts for dance on a stationary body of mass 100 kg after which the force accuses to add the body moves through a distance of 100m in next 5 second calculate the velocity acquired by the body the acceleration produced by the body and the magnitude of the body
Answer» GIVEN:- Initial VELOCITY = 0m/s. Mass of Body = 100kg Distance Moved = 100m Time = 5s. To Find:- The Velocity acquired by the body the Acceleration produced by the body and the magnitude of the body. FORMULAE USED v = u + at S = ut + ½× a × t² F = ma Where, v = Final Velocity u = Initial Velocity S = Distance F = Force m = mass a = Acceleration t = Time. Now, Using Second equation of MOTION to find Acceleration. S = ut + ½ × a × t² 100m = 0 + ½ × a × 25 4 = ½ × a a = 8m/s² Hence, The Acceleration is 8m/s². Therefore, Using First equation of motion to find Final Velocity v = u + at v = 0 + 40 v = 40m/s. Thus, The SPEED acquired by body is 40m/s. Hence, Using F = ma to find force. F = ma F = 100 × 8 F = 800N. Thus, The magnitude of Force is 800N

28.

a force acts for dance on a stationary body of mass 100 kg after which the force accuses to add the body moves through a distance of 100m in next 5 second calculate the velocity acquired by the body the acceleration produced by the body and the magnitude of the body

Answer»

GIVEN:-

Initial VELOCITY = 0m/s.

Mass of Body = 100kg

Distance Moved = 100m

Time = 5s.

To Find:-

The Velocity acquired by the body the Acceleration produced by the body and the magnitude of the body.

FORMULAE USED

v = u + at

S = ut + ½× a × t²

F = ma

Where,

v = Final Velocity

u = Initial Velocity

S = Distance

F = Force

m = mass

a = Acceleration

t = Time.

Now,

Using Second equation of MOTION to find Acceleration.

S = ut + ½ × a × t²

100m = 0 + ½ × a × 25

4 = ½ × a

a = 8m/s²

Hence, The Acceleration is 8m/s².

Therefore, Using First equation of motion to find Final Velocity

v = u + at

v = 0 + 40

v = 40m/s.

Thus, The SPEED acquired by body is 40m/s.

Hence, Using F = ma to find force.

F = ma

F = 100 × 8

F = 800N.

Thus, The magnitude of Force is 800N

Discussion

29.	What can you determine from distance - time graph for an object at rest
Answer» Answer: I WANT to see the BAR GRAPH please.

29.

What can you determine from distance - time graph for an object at rest

Answer»

Answer:

I WANT to see the BAR GRAPH please.

Discussion

30.	A ball moving vertically upword which type of motion it is
Answer» VERTICAL LINEAR MOTION

Discussion

31.	A bus cover 20 km in 1 hour and car covers 50 km in 2 hours. The car is faster. Give reason
Answer» Answer: bus covers 20 km in 1 hour as average SIMILARLY if bus WOULD run in same speed it would COVER 40 km in 2 hours whereas the CAR cover 50 km in same time and hence has more speed Explanation:

31.

A bus cover 20 km in 1 hour and car covers 50 km in 2 hours. The car is faster. Give reason

Answer»

Answer:

bus covers 20 km in 1 hour as average SIMILARLY if bus WOULD run in same speed it would COVER 40 km in 2 hours whereas the CAR cover 50 km in same time and hence has more speed

Explanation:

Discussion

32.	5.If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelled by the train in this time.
Answer» Explanation: HOPE it will HELPS you please like this and FOLLOW me

32.

5.If the velocity of a train which starts from rest is 72 km/h (20 m/s)after 5 minute, find out its acceleration and the distance travelled by the train in this time.

Answer»

Explanation:

HOPE it will HELPS you please like this and FOLLOW me

Discussion

33.	A particle starts moving in a straight line with a certain acceleration at a time t after the beginning of motion the acceleration suddenly becomes retardation of the same value the time from start in which the particle comes momentarily at rest
Answer» EXPLANATION: after its moment after the ACCELERATION so the moment will change I can give ANSWER don't WORRY ok FRIENDS

33.

A particle starts moving in a straight line with a certain acceleration at a time t after the beginning of motion the acceleration suddenly becomes retardation of the same value the time from start in which the particle comes momentarily at rest

Answer»

EXPLANATION:

after its moment after the ACCELERATION so the moment will change I can give ANSWER don't WORRY ok FRIENDS

Discussion

34.	A person is moving in a circular path of radius 10m with speed 36 km/hour . Find the angular speed
Answer» ANSWER: tmdihgjjfjhkgdtdjdjjhkkdkkf Explanation: bfndndmnsndndnndmdnbdbdhdjbfkdhvdkd zhgkljtshdgjhxjh

34.

A person is moving in a circular path of radius 10m with speed 36 km/hour . Find the angular speed

Answer»

ANSWER:

tmdihgjjfjhkgdtdjdjjhkkdkkf

Explanation:

bfndndmnsndndnndmdnbdbdhdjbfkdhvdkd

zhgkljtshdgjhxjh

Discussion

35.	What will be the displacement of the body at (a) t = 35 (b) t = 75
Answer» ANSWER: I think this question is not complete Explanation: *PLEASE* *FOLLOW* me *and* *thank* me

35.

What will be the displacement of the body at (a) t = 35 (b) t = 75

Answer»

ANSWER:

I think this question is not complete

Explanation:

PLEASE FOLLOW me and thank me

Discussion

36.	Abbas cover 20 kilometre in 1 hour and a car over 50 km in 2 hours the car is faster give reason
Answer» Answer: Because, speed by a BUS is s=d/t s=20/1 kmph => 20 kmph speed by the CAR is s=d/t => s=50/2 kmph or 25KMPH HENCE, l think you got it

36.

Abbas cover 20 kilometre in 1 hour and a car over 50 km in 2 hours the car is faster give reason

Answer»

Answer:

Because, speed by a BUS is

s=d/t

s=20/1 kmph

=> 20 kmph

speed by the CAR is

s=d/t

=> s=50/2 kmph or 25KMPH

HENCE, l think you got it

Discussion

37.	Dinesh travelled a distance of 60m towards south. Now he turns right and travels 45m. He then travels 30m towards north and further travels by turning 45 degrees in clock wise direction in which direction is he travelling now?
Answer» ANSWER: North-east Explanation: HOPE it's HELPFUL....if it's helpful then MARK me as BRAINLIEST

37.

Dinesh travelled a distance of 60m towards south. Now he turns right and travels 45m. He then travels 30m towards north and further travels by turning 45 degrees in clock wise direction in which direction is he travelling now?

Answer»

ANSWER:

North-east

Explanation:

HOPE it's HELPFUL....if it's helpful then MARK me as BRAINLIEST

Discussion

38.	Two electrons each of mass 9.1 into 10 to the power minus 31kg are at a distance of 10 to the power minus 10 metre calculate the gravitational force between them
Answer» Answer: The Force that will EXIST between the 2 electrons will be 552.342710⁻⁵³ N. Explanation:* Given, Mass of TWO e⁻ = 9.110⁻³¹ kg Distance between them = 10⁻¹⁰m Gravitational CONSTANT (G) = 6.6710⁻¹¹ Nm²/kg² = Force = Gm₁m₂/r² = (6.6710⁻¹¹) . (9.110⁻³¹) . (9.110⁻³¹) / 10⁻¹⁰ . 10⁻¹⁰ N = (6.679.19.1) . 10⁻¹¹⁻³¹⁻³¹ / 10⁻¹⁰⁻¹⁰ N = 552.3427 . 10⁻⁷³ / 10⁻²⁰ N = 552.3427 . 10⁻⁷³⁺²⁰ N = 552.342710⁻⁵³ N Hope this helps.

38.

Two electrons each of mass 9.1 into 10 to the power minus 31kg are at a distance of 10 to the power minus 10 metre calculate the gravitational force between them

Answer»

Answer:

The Force that will EXIST between the 2 electrons will be 552.3427*10⁻⁵³ N.

Explanation:

Given,

Mass of TWO e⁻ = 9.1*10⁻³¹ kg

Distance between them = 10⁻¹⁰m

Gravitational CONSTANT (G) = 6.67*10⁻¹¹ Nm²/kg²

= Force = Gm₁m₂/r²

= (6.67*10⁻¹¹) . (9.1*10⁻³¹) . (9.1*10⁻³¹) / 10⁻¹⁰ . 10⁻¹⁰ N

= (6.67*9.1*9.1) . 10⁻¹¹⁻³¹⁻³¹ / 10⁻¹⁰⁻¹⁰ N

= 552.3427 . 10⁻⁷³ / 10⁻²⁰ N

= 552.3427 . 10⁻⁷³⁺²⁰ N

= 552.3427*10⁻⁵³ N

Hope this helps.

Discussion

39.	A boy travels with an average speed of 10 m s-1 for 20 min. How much distancedoes he travel?
Answer» Explanation: SPEED = 10m/s time = 20 MINS = 20× 60 sec = 1200sec now , we know that distance = speed × time = 10m/s × 1200 = 12000 m

39.

A boy travels with an average speed of 10 m s-1 for 20 min. How much distancedoes he travel?

Answer»

Explanation:

SPEED = 10m/s

time = 20 MINS = 20× 60 sec

= 1200sec

now , we know that

distance = speed × time

= 10m/s × 1200 = 12000 m

Discussion

40.	Pick out the odd one EV,volt,megavolt,millivolt what is it's reason,
Answer» ANSWER: bejhfcxxzvvhdawrtiokmnbvdrtyyyyyyýyyyyyyyyyyy

40.

Pick out the odd one EV,volt,megavolt,millivolt what is it's reason,

Answer»

ANSWER:

bejhfcxxzvvhdawrtiokmnbvdrtyyyyyyýyyyyyyyyyyy

Discussion

41.	a person walking on a straight line 60m. then he turns right 90 degree and travel hundred metre. again he turns right 90 degree and travels 60m. find the total distance travelled?. find the total displacement?
Answer» Answer: 100m Explanation: The given DATA is FORMING a RECTANGULAR shape. It is very EASY just make a diagram. and please FOLLOW me☺️

41.

a person walking on a straight line 60m. then he turns right 90 degree and travel hundred metre. again he turns right 90 degree and travels 60m. find the total distance travelled?. find the total displacement?

Answer»

Answer:

100m

Explanation:

The given DATA is FORMING a RECTANGULAR shape.

It is very EASY just make a diagram.

and please FOLLOW me☺️

Discussion

42.	Why car wheels are of rubber??
Answer» ANSWER: to MAKE the more friction by which the SLIP CASE will lose

42.

Why car wheels are of rubber??

Answer»

ANSWER:

to MAKE the more friction by which the SLIP CASE will lose

Discussion

43.	Write the bernouli formula in physics
Answer» ANSWER: p1+12ρv21=p2+12ρv22 The Bernoulli Equation can be CONSIDERED to be a statement of the conservation of ENERGY principle appropriate for flowing fluids. The qualitative behavior that is USUALLY labeled with the term "Bernoulli effect" is the lowering of fluid pressure in REGIONS where the flow velocity is increased.

43.

Write the bernouli formula in physics

Answer»

ANSWER:

p1+12ρv21=p2+12ρv22

The Bernoulli Equation can be CONSIDERED to be a statement of the conservation of ENERGY principle appropriate for flowing fluids. The qualitative behavior that is USUALLY labeled with the term "Bernoulli effect" is the lowering of fluid pressure in REGIONS where the flow velocity is increased.

Discussion

44.	Can you please help me??????? Solve it correctly and i will mark as brainliest answer
Answer» Since the ELEVATOR is moving with constant VELOCITY, the FRAME of elevator is inertial. The only force acting on COIN gravity. Now in reference of elevator, $s=ut+\frac{gt^2}{2}\\2.45=0+\frac{9.8t^2}{2}\\2.45=4.9t^2\\t^2=0.5\\t=\sqrt{\frac{5}{10}}\\t=\sqrt{\frac{1}{2}}\\t=\frac{1}{\sqrt2}$

44.

Can you please help me??????? Solve it correctly and i will mark as brainliest answer

Answer»

Since the ELEVATOR is moving with constant VELOCITY, the FRAME of elevator is inertial.

The only force acting on COIN gravity.

Now in reference of elevator,

$s=ut+\frac{gt^2}{2}\\2.45=0+\frac{9.8t^2}{2}\\2.45=4.9t^2\\t^2=0.5\\t=\sqrt{\frac{5}{10}}\\t=\sqrt{\frac{1}{2}}\\t=\frac{1}{\sqrt2}$

Discussion

45.	I Prove that the maximum relative error in the product of 2 quantities is equal to the sum of relative errors in the individual quantities
Answer» ANSWER: For X = a/b , Δx/x = ± ( Δa/a + Δb/b)

45.

I Prove that the maximum relative error in the product of 2 quantities is equal to the sum of relative errors in the individual quantities

Answer»

ANSWER:

For X = a/b , Δx/x = ± ( Δa/a + Δb/b)

Discussion

46.	A point travelling along a straight line traverse one third the distance with velocity v0 . The remaining part of the distance was covered with velocity v1 for half the time and with velocity v2 for the other half of the time . The mean velocity of the point averaged over the whole time of motion will be:-
Answer» ANSWER: abcdcfghgfgvdubghgf GUY

46.

A point travelling along a straight line traverse one third the distance with velocity v0 . The remaining part of the distance was covered with velocity v1 for half the time and with velocity v2 for the other half of the time . The mean velocity of the point averaged over the whole time of motion will be:-

Answer»

ANSWER:

abcdcfghgfgvdubghgf GUY

Discussion

47.	TRYYOURSELFExample 12. Find the magnitude and direction of the vector sum of the three forces in figure. Usepolygon method, and check the results by component method.
Answer» *xhjbdr7ob* *xfukmbfsy* स् *yinvdfyi* क् so *UPSIDE* *DIXIT*

Discussion

48.	Velocity of a particle at any time t is given as ( 2 t icap+t j cap) m/sec. Find the magnitude of acceleration at t = 1 second
Answer» EXPLANATION: $v = (2i^{ cap} + 2t \: {j}^{cap} )$

48.

Velocity of a particle at any time t is given as ( 2 t icap+t j cap) m/sec. Find the magnitude of acceleration at t = 1 second

Answer»

EXPLANATION:

$v = (2i^{ cap} + 2t \: {j}^{cap} )$

Discussion

49.	How to solve this?????
Answer» Answer: SORRY my answer is INCORRECT EXPLANATION: please mark me in brainlist and follow me

49.

How to solve this?????

Answer»

Answer:

SORRY my answer is INCORRECT

EXPLANATION:

please mark me in brainlist and follow me

Discussion

50.	WHAT ARE THE BLACK HOLES IN THE SPACE?
Answer» Answer: Axxording to me BLACK HOLES aare the DEAD STARS for more info GO to google or search it on youtube.

50.

WHAT ARE THE BLACK HOLES IN THE SPACE?

Answer»

Answer:

Axxording to me BLACK HOLES aare the DEAD STARS for more info GO to google or search it on youtube.

Discussion

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