67486 + Interview Questions in Secondary School in Physics

1.	Please answer the below question on conservation of momentum (show full working)
Answer» ━━━━━━━━━━━━━━━━━━━━ ✤ Required Answer: ✒ GiveN: Mass of the moving RAILROAD = 12000 kg Initially, it's velocity = 2 m/s Mass of railroad at rest = 10000 kg They collide and locked up ✒ To finD: Final speed of the system of railroad cars....? ━━━━━━━━━━━━━━━━━━━━ ✤ How to solve? LET's first know about law of conservation of momentum for colliding bodies: The law of conservation of momentum is commonly used when we need to find the velocities of objects that undergone some form of collision. The law of conservation of momentum states that the momentum of a system is conserved or remains CONSTANT as long as there are no external UNBALANCED forces acting on the system of bodies. ⚡It is given by, m1u1 + m2u2 = m1v1 + m2v2 Where, m1 and m2 are the masses of bodies. u1 and u2 are initial velocities And, v1 and V2 are final velocities $.$ ━━━━━━━━━━━━━━━━━━━━ ✤ Solution: We have, m1 = 12000 kg m2 = 10000 kg u1 = 2 m/s u2 = 0 m/s (at rest) Final masses will be their sum So, By using formula, ➝ m1u1 + m2u2 = (m1 + m2)v ➝ 12000 × 2 + 10000 × 0 = (12000 + 10000)v ➝ 24000 = 22000v Flipping it, ➝ 22000v = 24000 ➝ v = 24000 / 22000 ➝ v = 12 / 11 m/s ➝ v = 1.1 m/s (approx.) ❒ Final velocity of the system = 1.1 m/s⚘ Hence, solved !! ━━━━━━━━━━━━━━━━━━━━

1.

Please answer the below question on conservation of momentum (show full working)

Answer»

━━━━━━━━━━━━━━━━━━━━

✤ Required Answer:

✒ GiveN:

Mass of the moving RAILROAD = 12000 kg
Initially, it's velocity = 2 m/s
Mass of railroad at rest = 10000 kg
They collide and locked up

✒ To finD:

Final speed of the system of railroad cars....?

━━━━━━━━━━━━━━━━━━━━

✤ How to solve?

LET's first know about law of conservation of momentum for colliding bodies:

The law of conservation of momentum is commonly used when we need to find the velocities of objects that undergone some form of collision.
The law of conservation of momentum states that the momentum of a system is conserved or remains CONSTANT as long as there are no external UNBALANCED forces acting on the system of bodies.

⚡It is given by,

m1u1 + m2u2 = m1v1 + m2v2

Where,

m1 and m2 are the masses of bodies.
u1 and u2 are initial velocities
And, v1 and V2 are final velocities $.$

━━━━━━━━━━━━━━━━━━━━

✤ Solution:

We have,

m1 = 12000 kg
m2 = 10000 kg
u1 = 2 m/s
u2 = 0 m/s (at rest)
Final masses will be their sum

So, By using formula,

➝ m1u1 + m2u2 = (m1 + m2)v

➝ 12000 × 2 + 10000 × 0 = (12000 + 10000)v

➝ 24000 = 22000v

Flipping it,

➝ 22000v = 24000

➝ v = 24000 / 22000

➝ v = 12 / 11 m/s

➝ v = 1.1 m/s (approx.)

❒ Final velocity of the system = 1.1 m/s⚘

Hence, solved !!

━━━━━━━━━━━━━━━━━━━━

Discussion

2.	When a resistor of 2 ohm stretched to double the original length new resistance
Answer» Answer: Lets read the statement. When a resistor of 2Ω is stretched... So we aren't GIVEN any new wire... We stretched the wire. Lets assume the original length as x. After stretching the wire, let the length be 2×x. If length is 2x, then Cross-sectional area=1/2 (Simple equation: If length INCREASES, area decreases. Or, in other words, l∝1/A) Now, resistance= 2Ω. Resistance of unstretched wire of the unstretched wire (Original resistance): $R=\frac{\rhoL}{A}$ Now, we derived that l=2x and a=1/2 for the new wire. SUBSTITUTE these values in the above equation. Resistance of new wire: $R_{new} =\frac{\rho2l}{\frac{A}{2} }$ The 2 below A will GO to the numerator. Further simplifying: $R_{new} =\frac{\rho22l}{A}$ $R_{new} =\frac{\rho4l}{A }$ $R_{new} =4(\frac{\rhol}{A })$ We know that $\frac{\rho*L}{A}=R$ . Substitute this in the above equation. $R_{new} =4(R)$ Thus, from the above derivation, we conclude that New resistance= 4×(Original resistance) Now, original resistance is 2Ω. New resistance=4×2 New resistance=8Ω. TIP: Dont memorise, understand. HOPE THIS HELPS :D

2.

When a resistor of 2 ohm stretched to double the original length new resistance

Answer»

Answer:

Lets read the statement.

When a resistor of 2Ω is stretched... So we aren't GIVEN any new wire... We stretched the wire.

Lets assume the original length as x.

After stretching the wire, let the length be 2×x.

If length is 2x, then Cross-sectional area=1/2 (Simple equation: If length INCREASES, area decreases. Or, in other words, l∝1/A)

Now, resistance= 2Ω.

Resistance of unstretched wire of the unstretched wire (Original resistance):

$R=\frac{\rho*L}{A}$

Now, we derived that l=2x and a=1/2 for the new wire. SUBSTITUTE these values in the above equation.

Resistance of new wire:

$R_{new} =\frac{\rho*2l}{\frac{A}{2} }$

The 2 below A will GO to the numerator.

Further simplifying:

$R_{new} =\frac{\rho*2*2l}{A}$

$R_{new} =\frac{\rho*4l}{A }$

$R_{new} =4(\frac{\rho*l}{A })$

We know that $\frac{\rho*L}{A}=R$ . Substitute this in the above equation.

$R_{new} =4(R)$

Thus, from the above derivation, we conclude that

New resistance= 4×(Original resistance)

Now, original resistance is 2Ω.

New resistance=4×2

New resistance=8Ω.

TIP: Dont memorise, understand.

HOPE THIS HELPS :D

Discussion

3.	If a force of constant magnitude acts in directionperpendicular to the motion of a particle, then its(1) Speed is uniform (2) Momentum is uniform(3) Velocity is uniform (4) All of these
Answer» Answer: speed is UNIFORM..but VELOCITY has DIRECTION so need to take vector PRODUCT

3.

If a force of constant magnitude acts in directionperpendicular to the motion of a particle, then its(1) Speed is uniform (2) Momentum is uniform(3) Velocity is uniform (4) All of these

Answer»

Answer:

speed is UNIFORM..but VELOCITY has DIRECTION so need to take vector PRODUCT

Discussion

4.	Howwe can avoid vaporisation in an incancent lamp?
Answer» Answer: In order to prevent RAPID oxidation of the filament, ONE places it in a glass BULB, which is either evacuated or (more frequently) filled with some low-pressure inert GAS like nitrogen, argon or krypton, which slows down the evaporation of the filament material but also CARRIES away some heat.

4.

Howwe can avoid vaporisation in an incancent lamp?

Answer»

Answer:

In order to prevent RAPID oxidation of the filament, ONE places it in a glass BULB, which is either evacuated or (more frequently) filled with some low-pressure inert GAS like nitrogen, argon or krypton, which slows down the evaporation of the filament material but also CARRIES away some heat.

Discussion

5.	The length of the rod is measured as25.0cm using an scale have accuracy of 0.1 cmdetermine the percent error in length
Answer» ANSWER: % ERROR in length=△L/L×100 =0.1 cm/25.0 cm×100 =0.4 % error in length Hope it helps Mark me as BRAINLIEST !!!!!!

5.

The length of the rod is measured as25.0cm using an scale have accuracy of 0.1 cmdetermine the percent error in length

Answer»

ANSWER:

% ERROR in length=△L/L×100

=0.1 cm/25.0 cm×100

=0.4 % error in length

Hope it helps

Mark me as BRAINLIEST !!!!!!

Discussion

6.	A ball thrown upward in a train moving with uniform velocity return to the thrower due A. Inertia of rest B.Inertia of motion C. Acceleration due to gravity D. Inertia Give answer with reason...
Answer» Answer: C ACCELERATION DUE to gravity everything that is throw up must COME down

6.

A ball thrown upward in a train moving with uniform velocity return to the thrower due A. Inertia of rest B.Inertia of motion C. Acceleration due to gravity D. Inertia Give answer with reason...

Answer»

Answer:

C ACCELERATION DUE to gravity

everything that is throw up must COME down

Discussion

7.	What are the dimensions of the quantityWig. I being the length and the) Nuclearmass
Answer» Answer: 13. તેની પાસે ફરી – ફરી.................................. �ય�ત કરી. (સાચી �ડણીવાળો ખૂટતો શ�દ મૂકો.) (A) દીલગીરી (B) �દલગીરી (C) �દલિગ�ર (D) દીલિગરી 14. નીચેનામાંથી �મરણ શ�દનો િવરોધી શ�દ કયો છે ? (A) િવ�મરણ (B) અ�મરણ (C) સંતાપ (D)િનંદા 15. ઘરની પાછલી દીવાલ – શ�દસમૂહ માટે એક શ�દ કયો છે ? (A) કરો (B) તિળયું (C) પછીત (D) રામણદીવડો 16. નીચેનામાંથી‘ િબહામ�ં ‘ શ�દનો સમાનાથ� શ�દ કયો છે ? (A) વખાણ (B) ભયાનક (C) ખુશ (D)િગ�ર 17. નીચેનામાંથી મ�યમપદલોપી સમાસ કયો છે ? (A) િશ�યવૃિત (B) િચંતાતુર (C) પંચવટી (D)માલ – િમલકત 18. સાંકરાં – તળપદા શ�દનો અથ� લાખો : (A) �મ (B) છોકરા (C) ડ�બી (D)દુ: ખ Explanation: 13. તેની પાસે ફરી – ફરી.................................. �ય�ત કરી. (સાચી �ડણીવાળો ખૂટતો શ�દ મૂકો.) (A) દીલગીરી (B) �દલગીરી (C) �દલિગ�ર (D) દીલિગરી 14. નીચેનામાંથી �મરણ શ�દનો િવરોધી શ�દ કયો છે ? (A) િવ�મરણ (B) અ�મરણ (C) સંતાપ (D)િનંદા 15. ઘરની પાછલી દીવાલ – શ�દસમૂહ માટે એક શ�દ કયો છે ? (A) કરો (B) તિળયું (C) પછીત (D) રામણદીવડો 16. નીચેનામાંથી‘ િબહામ�ં ‘ શ�દનો સમાનાથ� શ�દ કયો છે ? (A) વખાણ (B) ભયાનક (C) ખુશ (D)િગ�ર 17. નીચેનામાંથી મ�યમપદલોપી સમાસ કયો છે ? (A) િશ�યવૃિત (B) િચંતાતુર (C) પંચવટી (D)માલ – િમલકત 18. સાંકરાં – તળપદા શ�દનો અથ� લાખો : (A) �મ (B) છોકરા (C) ડ�બી (D)દુ: ખ

7.

What are the dimensions of the quantityWig. I being the length and the) Nuclearmass

Answer»

Answer:

13. તેની પાસે ફરી – ફરી.................................. �ય�ત કરી.

(સાચી �ડણીવાળો ખૂટતો શ�દ મૂકો.)

(A) દીલગીરી (B) �દલગીરી

(C) �દલિગ�ર (D) દીલિગરી

14. નીચેનામાંથી �મરણ શ�દનો િવરોધી શ�દ કયો છે ?

(A) િવ�મરણ (B) અ�મરણ

(C) સંતાપ (D)િનંદા

15. ઘરની પાછલી દીવાલ – શ�દસમૂહ માટે એક શ�દ કયો છે ?

(A) કરો (B) તિળયું

(C) પછીત (D) રામણદીવડો

16. નીચેનામાંથી‘ િબહામ�ં ‘ શ�દનો સમાનાથ� શ�દ કયો છે ?

(A) વખાણ (B) ભયાનક

(C) ખુશ (D)િગ�ર

17. નીચેનામાંથી મ�યમપદલોપી સમાસ કયો છે ?

(A) િશ�યવૃિત (B) િચંતાતુર

(C) પંચવટી (D)માલ – િમલકત

18. સાંકરાં – તળપદા શ�દનો અથ� લાખો :

(A) �મ (B) છોકરા

(C) ડ�બી (D)દુ: ખ

Explanation:

13. તેની પાસે ફરી – ફરી.................................. �ય�ત કરી.

(સાચી �ડણીવાળો ખૂટતો શ�દ મૂકો.)

(A) દીલગીરી (B) �દલગીરી

(C) �દલિગ�ર (D) દીલિગરી

14. નીચેનામાંથી �મરણ શ�દનો િવરોધી શ�દ કયો છે ?

(A) િવ�મરણ (B) અ�મરણ

(C) સંતાપ (D)િનંદા

15. ઘરની પાછલી દીવાલ – શ�દસમૂહ માટે એક શ�દ કયો છે ?

(A) કરો (B) તિળયું

(C) પછીત (D) રામણદીવડો

16. નીચેનામાંથી‘ િબહામ�ં ‘ શ�દનો સમાનાથ� શ�દ કયો છે ?

(A) વખાણ (B) ભયાનક

(C) ખુશ (D)િગ�ર

17. નીચેનામાંથી મ�યમપદલોપી સમાસ કયો છે ?

(A) િશ�યવૃિત (B) િચંતાતુર

(C) પંચવટી (D)માલ – િમલકત

18. સાંકરાં – તળપદા શ�દનો અથ� લાખો :

(A) �મ (B) છોકરા

(C) ડ�બી (D)દુ: ખ

Discussion

8.	Write the eqautions for three loop in the above circuit using sign convention.
Answer» EXPLANATION: i DONT KNOW this ANSWER

8.

Write the eqautions for three loop in the above circuit using sign convention.

Answer»

EXPLANATION:

i DONT KNOW this ANSWER

Discussion

9.	If 25 coloumb charge flows through a circuit in 5 sec.calculate the amount of charge flows through in 1 sec?
Answer» ANSWER: Charge(Q) =25 Coulomb Time (T)= 5 sec Electric CURRENT (I) =Q/T =25/5 =5 A Therefore, the Electric current = 5 Ampere. Hope this helps you.... Happy LEARNING... Plz mark as brainliest

9.

If 25 coloumb charge flows through a circuit in 5 sec.calculate the amount of charge flows through in 1 sec?

Answer»

ANSWER:

Charge(Q) =25 Coulomb

Time (T)= 5 sec

Electric CURRENT (I) =Q/T

=25/5

=5 A

Therefore, the Electric current = 5 Ampere.

Hope this helps you....

Happy LEARNING...

Plz mark as brainliest

Discussion

10.	if the position of a particle of any instant t is given by x = t^3find the acceleration of the particle at t = 2 seconds
Answer» $\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$ POSITION equation of particle has been provided. $\dag\:\boxed{\bf{x=t^3}}$ $\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$ We have to find ACCELERATION of particle at t = 2s. $\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$ ✪ Instantaneous VELOCITY : $:\implies\sf\:v=(lim\:\Delta t\to 0)\:\dfrac{\Delta x}{\Delta t}=\dfrac{dx}{dt}$ $:\implies\tt\:v=\dfrac{d(t^3)}{dt}$ $:\implies\bf\:v=3t^2$ ✪ Instantaneous acceleration : $:\implies\sf\:a=(lim\:\Delta t\to 0)\:\dfrac{\Delta v}{\Delta t}=\dfrac{dv}{dt}$ $:\implies\tt\:a=\dfrac{d(3t^2)}{dt}$ $:\implies\bf\:a=6t$ Putting t = 2, we GET $:\implies\tt\:a=6(2)$ $:\implies\boxed{\bf{\red{a=12\:ms^{-2}}}}$

10.

if the position of a particle of any instant t is given by x = t^3find the acceleration of the particle at t = 2 seconds

Answer»

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

POSITION equation of particle has been provided.

$\dag\:\boxed{\bf{x=t^3}}$

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find ACCELERATION of particle at t = 2s.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

✪ Instantaneous VELOCITY :

$:\implies\sf\:v=(lim\:\Delta t\to 0)\:\dfrac{\Delta x}{\Delta t}=\dfrac{dx}{dt}$

$:\implies\tt\:v=\dfrac{d(t^3)}{dt}$

$:\implies\bf\:v=3t^2$

✪ Instantaneous acceleration :

$:\implies\sf\:a=(lim\:\Delta t\to 0)\:\dfrac{\Delta v}{\Delta t}=\dfrac{dv}{dt}$

$:\implies\tt\:a=\dfrac{d(3t^2)}{dt}$

$:\implies\bf\:a=6t$

Putting t = 2, we GET

$:\implies\tt\:a=6(2)$

$:\implies\boxed{\bf{\red{a=12\:ms^{-2}}}}$

Discussion

11.	I) A force of 10 N acts on a body of mass 2 kg. Find the acceleration produced.
Answer» ANSWER: FORCE =10N mass2kg ACCELERATION 2/10=5ms²

11.

I) A force of 10 N acts on a body of mass 2 kg. Find the acceleration produced.

Answer»

ANSWER:

FORCE =10N

mass2kg

ACCELERATION 2/10=5ms²

Discussion

12.	JMIUHNG JHUHJIJOI;OYGFREWA
Answer» WAAATTT????? EXPLANATION:

12.

JMIUHNG JHUHJIJOI;OYGFREWA

Answer»

WAAATTT?????

EXPLANATION:

Discussion

13.	Two bulbs one of 80 watt and another 25 what are connected in series to the main supply or 220 what what will be the ratio of current falling through them
Answer» Answer: We have I1 / I2 = 16/5 I is current...Eqn= P= I E

13.

Two bulbs one of 80 watt and another 25 what are connected in series to the main supply or 220 what what will be the ratio of current falling through them

Answer»

Answer:

We have I1 / I2 = 16/5

I is current...Eqn= P= I E

Discussion

14.	Pls answer this question from the following options
Answer» Answer: OPTION (c) 5 Explanation: we know that, 1 hp = 746 W 1 W = 1/746 hp 3730 W = X x = $\frac{3730}{746}$ x = 5 THEREFORE , 3730 W = 5 hp Mark as brainliest if you are satisfied with my answer

14.

Pls answer this question from the following options

Answer»

Answer:

OPTION (c) 5

Explanation:

we know that,

1 hp = 746 W

1 W = 1/746 hp

3730 W = X

x = $\frac{3730}{746}$

x = 5

THEREFORE ,

3730 W = 5 hp

Mark as brainliest if you are satisfied with my answer

Discussion

15.	can there be displacement of an object in the absence of any force acting on it think discuss this question with our friend and Teachers
Answer» $\huge \star \purple {AnsWer}$ Suppose an object is MOVING with CONSTANT velocity. The net FORCE acting on it is zero. ... Hence, there can be a displacement WITHOUT a force. $Hope it helps$ $Mark as Brainliest Plz$

15.

can there be displacement of an object in the absence of any force acting on it think discuss this question with our friend and Teachers

Answer»

$\huge \star \purple {AnsWer}$

Suppose an object is MOVING with CONSTANT velocity. The net FORCE acting on it is zero. ... Hence, there can be a displacement WITHOUT a force.

$Hope it helps$

$Mark as Brainliest Plz$

Discussion

16.	Which is the universe's smallest particle? tell me fast anyone.
Answer» ANSWER: The answer of this QUESTION is QUARKS.

16.

Which is the universe's smallest particle? tell me fast anyone.

Answer»

ANSWER:

The answer of this QUESTION is QUARKS.

Discussion

17.	How would you connect three resistors , each of resistance 9 ohm so that the combination has a resistance of 6 ohm. PLS. TELL FAST
Answer» Answer: To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 OHM should be connected in a parallel circuit and ONE in SERIES. In a parallel circuit, the equivalent resistance of all the resistors connected is EQUAL to the reciprocal value of the sum of the individual resistances. hope it will HELP you kindly mark the answer as brainlist

17.

How would you connect three resistors , each of resistance 9 ohm so that the combination has a resistance of 6 ohm. PLS. TELL FAST

Answer»

Answer:

To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 OHM should be connected in a parallel circuit and ONE in SERIES. In a parallel circuit, the equivalent resistance of all the resistors connected is EQUAL to the reciprocal value of the sum of the individual resistances.

hope it will HELP you kindly mark the answer as brainlist

Discussion

18.	A brake applied to a train moving at 90 km/hr produces the retardation of 5m/s².What distance will it cover before coming to a stop.
Answer» Answer: The train will cover 62.5m before it comes to a stop Explanation: Using the equation v^2 = U^2 + 2as we can say u(INITIAL velocity) = 90kmph = 25 m/s and final velocity v is 0 since the train comes to a stop Acceleration = -5m/s (retardation) Plugging the VALUES in, we get 0^2 = 25^2 + 2(-5)(s) -25 x 25 = -10s s = 625/10= 62.5 m

18.

A brake applied to a train moving at 90 km/hr produces the retardation of 5m/s².What distance will it cover before coming to a stop.

Answer»

Answer:

The train will cover 62.5m before it comes to a stop

Explanation:

Using the equation v^2 = U^2 + 2as

we can say u(INITIAL velocity) = 90kmph = 25 m/s

and final velocity v is 0 since the train comes to a stop

Acceleration = -5m/s (retardation)

Plugging the VALUES in, we get

0^2 = 25^2 + 2(-5)(s)

-25 x 25 = -10s

s = 625/10= 62.5 m

Discussion

19.	rocket explain the effect of change of mass and change of velocity on the kinetic energy of an object.
Answer» Answer: I am not SURE if you have any QUESTIONS or concerns please visit the following link UNSUBSCRIBE here are a couple days to see the same Explanation: it will take PLACE at this stage we will send the TIME I have been a bit too long ago did the time I have been trying the time I have been working in my case it would like this email in my

19.

rocket explain the effect of change of mass and change of velocity on the kinetic energy of an object.

Answer»

Answer:

I am not SURE if you have any QUESTIONS or concerns please visit the following link UNSUBSCRIBE here are a couple days to see the same

Explanation:

it will take PLACE at this stage we will send the TIME I have been a bit too long ago did the time I have been trying the time I have been working in my case it would like this email in my

Discussion

20.	Examples of second law of motion
Answer» ANSWER: F=MA NEWTON SEE THAT HE KICK THE GOAT THEN GOAT ALSO CLICK HE KICK THE GOAT AND THE GOAT ASK MA THEN THE SECOND LAW IS F=MA OR F=M×A

20.

Examples of second law of motion

Answer»

ANSWER:

F=MA

NEWTON SEE THAT

HE KICK THE GOAT THEN GOAT ALSO CLICK

HE KICK THE GOAT AND THE GOAT ASK MA THEN THE SECOND LAW IS

F=MA

OR

F=M×A

Discussion

21.	Can anyone explain me latent heat and specific latent heat in one sentence. explain in simple words.(explanation with examples will be marked brainliest.)
Answer» ANSWER: HEAT is heat Explanation: latent heat is LATE heat which COMES late. specific latent heat is specially /RARE comes late.

21.

Can anyone explain me latent heat and specific latent heat in one sentence. explain in simple words.(explanation with examples will be marked brainliest.)

Answer»

ANSWER:

HEAT is heat

Explanation:

latent heat is LATE heat which COMES late.

specific latent heat is specially /RARE comes late.

Discussion

22.	Give me answer fastWhat are the factors on which resistance o A wire of length 1 and resistance 'R' is stretched to get the radius of cross-section halved. What is the new resistance of the wire after stretching?
Answer» Explanation: Length (l) is doubled & AREA of cross SECTION (A) is halved. l BECOMES 2l & A becomes 2 A R=P A L now take l=2l,A= 2 A R= A/2 P2l =4P A L ⇒4R Resistance becomes 4 times 1) RESISTIVITY does not depend on its length 02 Area. Hence, it does not change

22.

Give me answer fastWhat are the factors on which resistance o A wire of length 1 and resistance 'R' is stretched to get the radius of cross-section halved. What is the new resistance of the wire after stretching?

Answer»

Explanation:

Length (l) is doubled & AREA of cross SECTION (A) is halved.

l BECOMES 2l & A becomes

2

A

R=P

A

L

now take l=2l,A=

2

A

R=

A/2

P2l

=4P

A

L

⇒4R

Resistance becomes 4 times

1) RESISTIVITY does not depend on its length 02 Area.

Hence, it does not change

Discussion

23.	The number 4.582 is rounded off as
Answer» Answer: 5 EXPLANATION: PLEASE MARK me BRAINLIEST

23.

The number 4.582 is rounded off as

Answer»

Answer:

5

EXPLANATION:

PLEASE MARK me BRAINLIEST

Discussion

24.	The first advantage to bus topology is that it is easy to connect a computer or
Answer» Answer: So here is your answer Explanation: A bus topology consists of a single cable with the terminator at each end. All present nodes are connected to the single cable. There is no limit to the no: of nodes that can be attached to this network, but the no: of connected nodes can actually affect the performance of the network. In a bus topology, one of the nodes acts as the server and transmits the data from one end to the other in a single direction. When the data reaches the extreme end, the terminator removes the data from the line. In a bus topology, one main cable acts as the backbone for the ENTIRE network. The bus topology carries the transmitted data along the cable. As the data reaches each node, the node checks the destination address (MAC/IP address) to see if it matches their address. If the address doesn’t match, the node does nothing more. But if the node addresses match to the address contained in the data then they process on the information. In a bus topology, one main cable acts as the backbone for the entire network. The bus topology carries the transmitted data along the cable. As the data reaches each node, the node checks the destination address (MAC/IP address) to see if it matches their address. If the address doesn’t match, the node does nothing more. But if the node addresses match to the address contained in the data then they process on the information. The Backbone cable in the bus topology depends on the TYPE of network card used in each computer, an RJ-45 network cable or coaxial cable is used to connect them together. The FOLLOWING sections contain both the advantages and disadvantages of using a bus topology in a network. Characteristics of Bus Topology :- Flexible Expandable Moderate Reliability Moderate performance Advantages of Bus Topology :- Easy to connect or remove devices in a network without affecting any other device. In case of any computer or device failure, there will be no effect on other devices or network. Cable cost is LESS as compared to other network topology i.e. mesh and star. It is easy to UNDERSTAND topology. Easy to expand by joining two cables together Hope this may help you a lot❣️!!

24.

The first advantage to bus topology is that it is easy to connect a computer or

Answer»

Answer:

So here is your answer

Explanation:

A bus topology consists of a single cable with the terminator at each end. All present nodes are connected to the single cable. There is no limit to the no: of nodes that can be attached to this network, but the no: of connected nodes can actually affect the performance of the network.

In a bus topology, one of the nodes acts as the server and transmits the data from one end to the other in a single direction. When the data reaches the extreme end, the terminator removes the data from the line.

In a bus topology, one main cable acts as the backbone for the ENTIRE network. The bus topology carries the transmitted data along the cable. As the data reaches each node, the node checks the destination address (MAC/IP address) to see if it matches their address. If the address doesn’t match, the node does nothing more. But if the node addresses match to the address contained in the data then they process on the information.

In a bus topology, one main cable acts as the backbone for the entire network. The bus topology carries the transmitted data along the cable. As the data reaches each node, the node checks the destination address (MAC/IP address) to see if it matches their address. If the address doesn’t match, the node does nothing more. But if the node addresses match to the address contained in the data then they process on the information.

The Backbone cable in the bus topology depends on the TYPE of network card used in each computer, an RJ-45 network cable or coaxial cable is used to connect them together.

The FOLLOWING sections contain both the advantages and disadvantages of using a bus topology in a network.

Characteristics of Bus Topology :-

Flexible
Expandable
Moderate Reliability
Moderate performance

Advantages of Bus Topology :-

Easy to connect or remove devices in a network without affecting any other device.
In case of any computer or device failure, there will be no effect on other devices or network.
Cable cost is LESS as compared to other network topology i.e. mesh and star.
It is easy to UNDERSTAND topology.
Easy to expand by joining two cables together

Hope this may help you a lot❣️!!

Discussion

25.	Mass of block is 210.1 kg and its volume is (20+_0.5) m^3.Calculate its percentage error in density
Answer» Explanation: GIVEN : Mass, M=10.000 GM Volume, V=10.00 cm 3 ∴ Density, d= V M = 10.00 10.000 =1 gm/cm 3 ERROR in mass, ΔM=0.001 gm Error in volume, ΔV=0.01 cm 3 Error in density, Δd=d( M ΔM + V ΔV )= 1( 10.000 0.001 + 10.00 0.01 )=0.0011 gm/cm 3

25.

Mass of block is 210.1 kg and its volume is (20+_0.5) m^3.Calculate its percentage error in density

Answer»

Explanation:

GIVEN : Mass, M=10.000 GM

Volume, V=10.00 cm

3

∴ Density, d=

V

M

=

10.00

10.000

=1 gm/cm

3

ERROR in mass, ΔM=0.001 gm

Error in volume, ΔV=0.01 cm

3

Error in density, Δd=d(

M

ΔM

+

V

ΔV

)= 1(

10.000

0.001

+

10.00

0.01

)=0.0011 gm/cm

3

Discussion

26.	Using mesh analysis, find the current i, in the circuit shown in Fig. 2.146. [2. 79 A]
Answer» very HARD QUESTION don't KNOW SORRY!!

26.

Using mesh analysis, find the current i, in the circuit shown in Fig. 2.146. [2. 79 A]

Answer»

very HARD QUESTION

don't KNOW SORRY!!

Discussion

27.	A transparent solid cylindrical rod has a refractive index of 2 / root of ( 3) . It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure. The incident angle θ for which the light ray grazes along the wall of the rod is - ( figure of this question is given below ) options : 1) sin ^ -1 (1/2) 2)sin ^-1 ( root of (3) /2 ) 3) sin ^-1 ( 2 / root (3) ) 4) sin ^-1 (1 / root of (3) ) solution is also needed Dont spam from google spam or improper ans will be reported at the spot
Answer» ANSWER : I×sin90=32sin(90−α) ⇒cosα=23 So, sinα=1−43 =21 Now, 1×sinθ=3 2sinα=3 2×21=3 1 ⇒θ=sin−13 1 Explanation:

27.

A transparent solid cylindrical rod has a refractive index of 2 / root of ( 3) . It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure. The incident angle θ for which the light ray grazes along the wall of the rod is - ( figure of this question is given below ) options : 1) sin ^ -1 (1/2) 2)sin ^-1 ( root of (3) /2 ) 3) sin ^-1 ( 2 / root (3) ) 4) sin ^-1 (1 / root of (3) ) solution is also needed Dont spam from google spam or improper ans will be reported at the spot

Answer»

ANSWER : I×sin90=32sin(90−α)

⇒cosα=23

So, sinα=1−43

=21

Now, 1×sinθ=3

2sinα=3

2×21=3

1

⇒θ=sin−13

1

Explanation:

Discussion

28.	A space probe built on earth has a mass of 750 kg calculate the weight of the space probe on earth
Answer» Given: A space probe built on earth has a mass of 750 kg. To find: Weight of the space probe Calculation: Mass of any object refers to the space occupied by that object. It is a scalar quantity. Weight of any object is actually a vector and is REPRESENTED by the product of mass and the GRAVITATIONAL ACCELERATION ACTING at that point on the Earth surface. $\sf{weight = mass \times g }$ $= > \sf{weight = 750 \times g }$ $= > \sf{weight = 750 \times 10}$ $= > \sf{weight = 7500 \: N }$ So, final answer: $\boxed{\rm{weight \: of \: probe = 7500 \: N }}$

28.

A space probe built on earth has a mass of 750 kg calculate the weight of the space probe on earth

Answer»

Given:

A space probe built on earth has a mass of 750 kg.

To find:

Weight of the space probe

Calculation:

Mass of any object refers to the space occupied by that object. It is a scalar quantity.

Weight of any object is actually a vector and is REPRESENTED by the product of mass and the GRAVITATIONAL ACCELERATION ACTING at that point on the Earth surface.

$\sf{weight = mass \times g }$

$= > \sf{weight = 750 \times g }$

$= > \sf{weight = 750 \times 10}$

$= > \sf{weight = 7500 \: N }$

So, final answer:

$\boxed{\rm{weight \: of \: probe = 7500 \: N }}$

Discussion

29.	Can anyone explain me latent heat and specific latent heat in one sentence
Answer» Answer: Specific latent heat energy required to CHANGE a UNIT mass of a material by 1°C. UNITS: energy PER unit mass per DEGREE. Latent heat = energy required to change the state (gas, liquid, solid) of a unit mass of material.

29.

Can anyone explain me latent heat and specific latent heat in one sentence

Answer»

Answer:

Specific latent heat energy required to CHANGE a UNIT mass of a material by 1°C. UNITS: energy PER unit mass per DEGREE. Latent heat = energy required to change the state (gas, liquid, solid) of a unit mass of material.

Discussion

30.	A body of mass m is suspended from one end of string.A horizontal velocity root of 9gr is given at the bottom of the verticle circle. Find the ratio of elongation
Answer» ANSWER: HAT ...........TTT . jikvvtnkigcjo

30.

A body of mass m is suspended from one end of string.A horizontal velocity root of 9gr is given at the bottom of the verticle circle. Find the ratio of elongation

Answer»

ANSWER:

HAT ...........TTT . jikvvtnkigcjo

Discussion

31.	What are the factors that control the resistance ( any four) ?
Answer» Explanation: There are 4 different FACTORS which affect resistance: The TYPE of material of which the resistor is made. The LENGTH of the resistor. The thickness of the resistor. The TEMPERATURE of the conductor.

31.

What are the factors that control the resistance ( any four) ?

Answer»

Explanation:

There are 4 different FACTORS which affect resistance:

The TYPE of material of which the resistor is made.

The LENGTH of the resistor.

The thickness of the resistor.

The TEMPERATURE of the conductor.

Discussion

32.	Q.Which of the following statements is incorrect? a)Rainbow is formed due to dispersion and total internal reflection b)Blue colour of sky is due to scattering of light c)Mirage is due to atmospheric refraction d)Total internal reflection takes place in optical fibre
Answer» ANSWER: C... is WRONG.... ...............

32.

Q.Which of the following statements is incorrect? a)Rainbow is formed due to dispersion and total internal reflection b)Blue colour of sky is due to scattering of light c)Mirage is due to atmospheric refraction d)Total internal reflection takes place in optical fibre

Answer»

ANSWER:

C... is WRONG.... ...............

Discussion

33.	4.Using the energy conservation, derivethe expressions for the minimum speedsat different locations along a verticalcircular motion controlled by gravity.Is zero speed possible at the uppermostpoint? Under what condition/s? Alsoprove that the difference between theextreme tensions (or normal forces)depends only upon the weight of theobject.
Answer» Answer: By using the ENERGY conservation, the critical or minimum SPEEDS will be expressed as vcritical = √rg. At this point, the tension or normal force becomes ZERO at different locations ALONG with the circular MOTION that is controlled by the gravity. hope it will help you please mark me as Brainlist

33.

4.Using the energy conservation, derivethe expressions for the minimum speedsat different locations along a verticalcircular motion controlled by gravity.Is zero speed possible at the uppermostpoint? Under what condition/s? Alsoprove that the difference between theextreme tensions (or normal forces)depends only upon the weight of theobject.

Answer»

Answer:

By using the ENERGY conservation, the critical or minimum SPEEDS will be expressed as vcritical = √rg. At this point, the tension or normal force becomes ZERO at different locations ALONG with the circular MOTION that is controlled by the gravity.

hope it will help you

please mark me as Brainlist

Discussion

34.	if in a plano convex lens radius of curvature of convex surface is 10cm and length of lens is 30cm the refractive index of the material of the lens will be
Answer» Answer: In a plano CONVEX lens radius of curvature of the lens is 10 CM

34.

if in a plano convex lens radius of curvature of convex surface is 10cm and length of lens is 30cm the refractive index of the material of the lens will be

Answer»

Answer:

In a plano CONVEX lens radius of curvature of the lens is 10 CM

Discussion

35.	Q. Which of the following phenomenon is not due to atmospheric refraction? a)Twinkling of stars b)Tyndall effect c)Oval shape of the Sun d)Duration of the Sun’s visibility
Answer» B)TYNDALL EFFECT... is your answer Hope it will HELP :)

35.

Q. Which of the following phenomenon is not due to atmospheric refraction? a)Twinkling of stars b)Tyndall effect c)Oval shape of the Sun d)Duration of the Sun’s visibility

Answer»

B)TYNDALL EFFECT...

is your answer

Hope it will HELP :)

Discussion

36.	What is a rectifier diode? explain is rectifying action
Answer» Answer: The main application of p-n junction DIODE is in rectification CIRCUITS. these circuits used to describe conversation of a.c signals to d.c in power SUPPLIES. diode rectifier gives an alternating voltage which pulsates in accordance with time hope this will HELP you

36.

What is a rectifier diode? explain is rectifying action

Answer»

Answer:

The main application of p-n junction DIODE is in rectification CIRCUITS. these circuits used to describe conversation of a.c signals to d.c in power SUPPLIES. diode rectifier gives an alternating voltage which pulsates in accordance with time

hope this will HELP you

Discussion

37.	Match the coloum.Resistance to motionoptions for question force, oil, friction, no results found and gravitation
Answer» Answer: $\huge\underline\bold\blue{AnswEr}$ For EXAMPLE, adding an “other” answer option or COMMENT field can SOLVE a common drawback of using a multiple choice question. When you GIVE your RESPONDENTS a fixed list of answer options, you're forcing

37.

Match the coloum.Resistance to motionoptions for question force, oil, friction, no results found and gravitation

Answer»

Answer:

$\huge\underline\bold\blue{AnswEr}$

For EXAMPLE, adding an “other” answer option or COMMENT field can SOLVE a common drawback of using a multiple choice question. When you GIVE your RESPONDENTS a fixed list of answer options, you're forcing

Discussion

38.	The acceleration due to gravity g = 4π^2/lt^2. If error in the measurement of l and t are 0.4% and 0.6% respectively. Calculate maximum percentage error? please send answer fast fast please
Answer» Answer: (a) rα ˃ rd ˃ rp (b) rα= rp˂ rd `` (c) rα= rd ˃ rd (d) rα=some) (41) He is a man of WORDS. (few/a few/the few) (42) I will give you — useful thing. (an/a/the) (43) He is - OLDER than his wife (many/much) (44) Can you HELP me with

38.

The acceleration due to gravity g = 4π^2/lt^2. If error in the measurement of l and t are 0.4% and 0.6% respectively. Calculate maximum percentage error? please send answer fast fast please

Answer»

Answer:

(a) rα ˃ rd ˃ rp (b) rα= rp˂ rd `` (c) rα= rd ˃ rd (d) rα=some)

(41) He is a man of WORDS. (few/a few/the few) (42) I will

give you — useful thing. (an/a/the) (43) He is - OLDER than his

wife (many/much) (44) Can you HELP me with

Discussion

39.	A wire of length 1 and resistance R is stretched to get the radius of cross section halved. What is the new resistance of the wire after stretching?
Answer» Given: A wire of length l and resistance R is stretched to get the radius of cross SECTION halved. To find: NEW resistance of wire. Calculation: Since the wire has been stretched , its volume will remain CONSTANT; $\therefore$ V1 = V2 $= > \pi {r}^{2} l = \pi {( \dfrac{r}{2} )}^{2} l_{2}$ $= > l = \dfrac{ l_{2} }{4}$ $= > l_{2} = 4l$ Initial resistance: $R = \rho \times ( \dfrac{l}{a} )$ $= > R = \rho \times ( \dfrac{l}{\pi {r}^{2} } )\:\:\:\:.............(1)$ FINAL resistance: $R_{2}= \rho \times ( \dfrac{4l}{a_{2}} )$ $= > R_{2}= \rho \times \bigg \{\dfrac{4l}{\pi {( \frac{r}{2}) }^{2} } \bigg \}$ $= > R_{2}= \rho \times \bigg \{\dfrac{4l}{ \frac{\pi {r}^{2} }{4} } \bigg \}$ $= > R_{2}= \rho \times \bigg \{\dfrac{16l}{ \pi {r}^{2} } \bigg \}$ $= > R_{2}= 16\times \bigg \{ \rho \times \dfrac{l}{ \pi {r}^{2} } \bigg \}$ $= > R_{2}= 16\times \bigg \{R \bigg \}$ $= > R_{2}= 16R$ So, final answer is: $\boxed{ \sf{ \red{R_{2}= 16R }}}$

39.