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Rocks are used in the formation of foundation or base of civil engineering projects, because the rocks are more
stable and having high strength (1). The branch of geology that deals with application of GEOLOGICAL knowledge to
civil engineering projects is known as geological engineering or engineering geology (2). Engineering geologists are
needed wherever an understanding of rock properties and geological structures is required, i.e. road construction,
building foundations, dam construction etc (3). The LOCAL geology of an AREA is important when planning a major
construction (4). The geology of an area represents the location and nature of any civil engineering structures (5).
Natural hazards (earthquake, landslide, and tsunami) are originated and produce the deformation on surface of earth.
Natural hazards cannot be prevented, but its prediction is determining (6).
Different type of rocks &there uses: Rocks are the naturally solid aggregate of minerals (7). Since the crust of the
earth is composed of rocks, a rock may be defined as a unit of the earth crust (8). Minerals are only responsible for
the formation of rocks (9).civil engineers need to know the properties of rocks, to many type of rocks for used many
purpose (as foundation rock, as building STONE, as road rock or metal etc) (10). Petrology is the branch of geology
which deals the study of rocks such as formation, classification, and occurrence (11). There are three types of rocks
on the basis of their origination.

DIP is the acute ANGLE that a ROCK surface MAKES with a
horizontal plane.
STRIKE is the direction of the line formed by the intersection of a rock surface with a horizontal plane.
OUTCROP is a large MASS of rock that STANDS above the surface of the ground.

When there is no medium there is vacuum.
And WAVE and heat REQUIRES medium but LIGHT dont.

When WAVE of the SOUND PROPAGATE LONGITUDINAL its callled longitudinal wave of sound.

रासायनिक तत्‍वों में से एक तत्‍व जिसके भौतिक लक्षण औरों से अलग हों परंतु रासायनिक लक्षण वही हों; समस्थानिक; आइसोटोप

Answer:

GEOLOGY is the study of the earth (GEO means earth, and ology means study of). This is a very simple definition for something so complex. Geology involves studying the materials that make up the earth, the features and structures found on Earth as WELL as the processes that act UPON them.

For minimum work the angle WOULD be 90° since cos90°=0. and for maximum the angle should be 0°.. when U WALK on STAIRS the work DONE is zero since force and displacement are perpendicular

Its difficult to open the door by PUSHING or pulling near the hinges because more force is APPLIED near the hinges of the door . That's why door knobs are situated away or FAR from hinges ....

Hope it Helps you ....

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DO YOU WANT IT IN CGS OR SI

Osmium
copper
silver
cesium
rhodium

E=W+eV
E=W+2W=3W ANS

W=work FUNCTION.

The most common use of GRAVITATIONAL POTENTIAL energy is for an object nearthe SURFACE of the Earth where thegravitational acceleration can be assumed to be constant at about 9.8 m/s2.

The pH of CLEAN WATER is between the 6.5 to 8.5
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HERE IS YOUR ANSWER
…………………………………………

A force acting on the opposite direction to the motion of the body is KNOWN as friction or force of friction. Friction can be of the following two types.

STATIC Friction 2. Dynamic Friction

The friction EXPERIENCED by a body when at rest is known as static friction. The friction experienced by a body when at is known as dynamic friction. It is also known as kinetic friction. Kinetic friction are of the following two types :

a. sliding friction b. rolling friction

In this article we will discuss about the limiting friction. The friction experienced by a body , when its sliding over another body is known as sliding friction.

The friction experienced by a body , when balls or roller are interposed between two surfaces is known as rolling friction.



When a body just starts to slide over the surface of another one , the frictional force is developed between the surfaces. The maximum value of that frictional force is known as the limiting friction or static friction.



The direction of limiting friction force is always the opposite of the motion of the body.

The magnitude of the friction force is equal to the force that tends to move the body.

The magnitude of the limiting friction always have a constant ratio with the normal reaction force which acts between the two surfaces.

Limiting friction force depends on the ROUGHNESS of the surface.

Area between the surfaces is not RESPONSIBLE for the magnitude of the frictional force.

It's related to variation of 'g' with respect to depth in the Gravitation CHAPTER.

At the CENTER d = R

Then you substitute and get the value as 0.

HOPE you understood

I GUESS it is a PHYSICAL CHANGE

The g is ACCELERATION DUE to GRAVITY.....it's value is 9.8
and
the G is gravitational constant .......it's value is 6.7 × 10 raised to -11...
here is your ANS...

7.0 HOPE it's HELPFUL PLZ BRAIN MARK

Electric POWER is the RATE, per unit time, at which electrical ENERGY is transferred by an electric circuit. The SI unit of power is the watt, one joule per SECOND. Electric power is usually produced by electric generators, but can also be SUPPLIED by sources such as electric batteries. And the S.I. unit of electric power is Watt.

The initial velocity needed to achieve that condition is CALLED escape velocity. From the surface of the Earth ,escape velocity ( IGNORING air friction) is about 7 miles per second, or 25,000 miles per hour. GIVEN speed that initial speed, an object needs no ADDITIONAL force applied to completely escape Earth' s gravity.

Concepts:
The buoyant force

Reasoning:
When an object FLOATS, the magnitude of the buoyant force is EQUAL to the magnitude of its weight.

Details of the calculation:
The magnitude of the buoyant force is equal to the the magnitude of the weight wliquid of the displaced liquid.
wliquid = ρliquidVg.
The volume V of the displaced liquid is the volume of ONE HALF sphere, 
V = 2πr3/3 = 2π(6cm)3/3 = 452cm3. 
The magnitude of the weight of the object is wobject = mfrogg.  (We are neglecting the weight of the air-filled pod.)
ρliquidVg = mfrogg.  
mfrog = 1.35(g/cm3)452cm3 = 610g.

Weight=mass*g
18=2*g
18/2=g
g=9m/s2

Can I build a partition wall over a floor slab without a beam below it?

Answer

1819

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12 ANSWERS



Krishna Kinkar Mishra, Civil engineer with experience at construction sites.

Answered Jul 24, 2017

Nowadays it is a COMMON practice to build partition walls over floor slabs without a beam below it. It is frequent in commercial multistoried buildings that consist of framed structures. With changing needs , these partition walls get their locations CHANGED. It is better to keep these partition walls light weight as far as possible. Wooden or aluminum framed partitions are light weight. But even brick partition walls upto 125 mm/5″ thick are constructed. These are non-loadbearing walls. For these brick partition walls 100 kg/sqm live load is increased for each partition during the design.

So if the load consideration is there in the design such partition walls can be constructed.

Here, given mass = 2 kg
now, WEIGHT of body = m x G = 18N
so, g = 18/2 = 9 m/s^2
HOPE THIS HELPS ^_^

The initial velocity NEEDED to ACHIEVE that condition is called ESCAPE velocity. From the surface of the Earth, escape velocity (ignoring air friction) is about 7 miles per second, or 25,000 miles per HOUR. GIVEN speed that initial speed , an object needs no additional force applied to completely escape Earth's gravity.

Specific Heat Capacity (C) :

It's defined as the amount of heat required to raise the temperature of a unit mass (1 kg) of a substance by ONE degree.

If DELTA Q is the amount of heat required to change the temperature by delta T then specific heat capacity will be,

C = Q / m × T

SI unit : J / kg K

Amount if heat absorbed by a body of mass m having specific heat capacity C for a temperature

delta T is,

Q = m × C × T

Hope it helps you.......

ANSWER

4.4 MeV

Example

Types of shear reinforcement : Vertical stirrups, Bent up bars along with stirrups, Inclined stirrups, contribution of bent up bars

TYPES OF SHEAR REINFORCEMENT

The following three types of shear reinforcement are used :

   Vertical stirrups.

   Bent up bars along with stirrups.

   Inclined stirrups.

Vertical Stirrups

These are the steel bars vertically placed AROUND the tensile reinforcement at suitable spacing along the length of the beam. Their diameter varies from 6 mm to 16 mm. The free ends of the stirrups are anchored in the compression zone of the beam to the anchor bars (hanger bar) or the compressive reinforcement. Depending upon the magnitude of the shear force to be RESISTED the vertical stirrups may be one legged, two legged, four legged and so on as shown in

Vertical Stirrups

Vertical Stirrups

It is desirable to use closely spaced stirrups for better prevention of the diagonal cracks. The spacing of stirrups near the supports is less as compared to spacing near the mid-span since shear force is maximum at the supports.

Bent up Bars along with Vertical Stirrups

Some of the longitudinal bars in a beam can be bent up near the supports where they are not required to resist BENDING moment (Bending Moment is very less near the supports). These bent up bars resist diagonal tension. Equal number of bars are to be bent on both sides to maintain symmetry. The bars can be bent up at more than one POINT uniformly along the length of the beam. These bars are usually bent at 45º as shown in Fig. 5.6.

Bent up Bars along with Vertical Stirrups

Bent up Bars along with Vertical Stirrups

This system is used for heavier shear FORCES. The total shear resistance of the beam is calculated by adding the contribution of bent up bars and vertical stirrups. The contribution of bent up bars is not greater than half of the total shear reinforcement.

Inclined Stirrups

Inclined stirrups are also provided generally at 45º for resisting diagonal tension. They are provided throughout the length of the beam.

Inclined Stirrups

Three hinged arches:

there are three HINGES in the arch, A, B and C. Generally there are three numbers of equilibrium equation, but the fourth equation is derived from the fact the ALGEBRAIC sum of all the moments at the HING C is 0. So there are four numbers of equilibrium equations, and we can determine all the four support REACTIONS, Va, Vb, Ha, and Hb.


TWO hinged arches:

there are two hinges A and B, and there are four support reactions. There are only three numbers of equations of equilibrium, so two hinged arches are indeterminate to the degree equal to 1.

Convert mAh to Watt HOURS. Insert MILLIAMP HOUR (mAh) and voltage (V) and CLICK on Calculate to obtain Watt hours (Wh). Formula is (mAh)*(V)/1000 = (Wh). For example, if you have a 300mAh BATTERY rated at 5V, the power is 300mAh * 5V / 1000 = 1.5Wh

F=m/g
f=150/10
f=15N
force is EQUAL to the MASS by GRAVITY

IRC 093: Guidelines on Design and Installation of Road Traffic Signals
by Indian Roads Congress
Add Review PUBLICATION date 1985
Usage CC0 1.0 Universal
Topics , public.resource
Collection publicsafetycode
In order to promote public education and public SAFETY, equal justice for all, a better informed citizenry, the rule of law, world trade and world peace, this legal document is hereby MADE available on a noncommercial basis, as it is the RIGHT of all humans to know and speak the laws that govern them. (For more information: 12 Tables of Code )
Name of Standards Organization: Indian Roads Congress (IRC)
Designator of Legally Binding Document: IRC 093
Title of Legally Binding Document: Guidelines on Design and Installation of Road Traffic Signals

The aggregate impact test value is a measure of resistance to sudden impact or test, which MAY VARY from its resistance to gradually applied compressive load.
If you SATISFY, mark it as BRAINLIEST

Is it the answer?? if yes PLZ SAY correct .....OK

The phenomenon of electrolysis is an important chemical effect of electric current. In a metallic conductor, the electric current is due to the drifting of free ELECTRONS, there is no chemical or physical change, only the generation of heat. However, in ionic solutions (electrolytes), the electric current is due to the movement of ions and there are associated chemical changes. In a typical EXPERIMENT of electrolysis, two metal rods are immersed in an ionic solution and connected to the two ends of a battery. The DISSOCIATED ions APPEAR in the two plates. Michael Faraday was the first to CARRY out quantitative investigations and summarise them in the now two famous laws of electrolysis.

⚡Hey mate⚡

✨Here is your answer✨

स्टील अधिक पृत्यास्त है

I HOPE it's HELPFUL for you. THANK you ❤️❤️

Your ANSWER....
100 CM......

Electrical resistivity of a material of a conductor is the RESISTANCE OFFERED by unit length and unit area of CROSS SECTION of a wire of the material .

Its S.I unit is Ωm