67486 + Interview Questions in Secondary School in Physics

1.	The human eye forms the image of an object at it's_________
Answer» ANSWER: RETINA...... HOPE it HELPS!!

1.

The human eye forms the image of an object at it's_________

Answer»

ANSWER:

RETINA......

HOPE it HELPS!!

Discussion

2.	5 % ૫૮૨ અન લાગે તેલના ઉપયો"1) મિસનર અસરપદાર્થોમાં જોવા મળે છે.(A) ફેરોમેગ્નેટીક(B) પેરામેગ્નેટીક(C) સુપર કન્ડક્ટીંગ(D) કાયમી ચુંબકOGI (04) (New)M - 3
Answer» $\underline{\boxed{\mathfrak{ \huge{ \purple{Answer}}}}} \\ \\ \implies \rm \: correct \: answer \: is \: c) \: superconducting$

2.

5 % ૫૮૨ અન લાગે તેલના ઉપયો"1) મિસનર અસરપદાર્થોમાં જોવા મળે છે.(A) ફેરોમેગ્નેટીક(B) પેરામેગ્નેટીક(C) સુપર કન્ડક્ટીંગ(D) કાયમી ચુંબકOGI (04) (New)M - 3

Answer»

$\underline{\boxed{\mathfrak{ \huge{ \purple{Answer}}}}} \\ \\ \implies \rm \: correct \: answer \: is \: c) \: superconducting$

Discussion

3.	Pls answer the Quickly
Answer» West. Try to IMAGINE the SCENARIO in your HEAD and it will BECOME so so so EASY

3.

Pls answer the Quickly

Answer»

West.

Try to IMAGINE the SCENARIO in your HEAD and it will BECOME so so so EASY

Discussion

4.	What happen to people exert pressure from opposite direction
Answer» when the pressure is exerted on object from opposite direction the TWO SIDES FORCE EITHER cancelled but when it's MAGNITUDE are equal but when it's magnitude are not equal where the magnitude is greater the object is pulled that side

4.

What happen to people exert pressure from opposite direction

Answer»

when the pressure is exerted on object from opposite direction the TWO SIDES FORCE EITHER cancelled but when it's MAGNITUDE are equal but when it's magnitude are not equal

where the magnitude is greater the object is pulled that side

Discussion

5.	In the process of magnetisation which part of a bar will be magnetised1.only outer layer 2.only surface 3.only ends of bar4.the entire bulk
Answer» ANSWER: the ENTIRE BULK.................

5.

In the process of magnetisation which part of a bar will be magnetised1.only outer layer 2.only surface 3.only ends of bar4.the entire bulk

Answer»

ANSWER:

the ENTIRE BULK.................

Discussion

6.	A charge 'q' is placed at the base of a cone. Find the electric flux through the curved surface of the cone.
Answer» Answer: Half of the total FLUX will pass from the CURVED surface of the cone $\phi = \frac{q}{2\epsilon_0}$ Explanation: As we know that charge is PLACED at the base of the cone Now half flux of the charge will pass into the cone while other half flux will go on other side So the flux that PASSES into the cone will move out of the cone from its curved surface So we will have $\phi = \frac{q}{2\epsilon_0}$ #Learn Topic : Electric flux brainly.in/question/10665894

6.

A charge 'q' is placed at the base of a cone. Find the electric flux through the curved surface of the cone.

Answer»

Answer:

Half of the total FLUX will pass from the CURVED surface of the cone

$\phi = \frac{q}{2\epsilon_0}$

Explanation:

As we know that charge is PLACED at the base of the cone

Now half flux of the charge will pass into the cone while other half flux will go on other side

So the flux that PASSES into the cone will move out of the cone from its curved surface

So we will have

$\phi = \frac{q}{2\epsilon_0}$

#Learn

Topic : Electric flux

brainly.in/question/10665894

Discussion

7.	What is expression between pressure and kinetic energy of a gas molecule
Answer» ANSWER: PV= 2/3 K.E Explanation: PV= 1/3nmv2 PV= 2/3 × 1/2 NMV2 PV= 2/3K.E Since, K.E = 1/2nmv*2

7.

What is expression between pressure and kinetic energy of a gas molecule

Answer»

ANSWER:

PV= 2/3 K.E

Explanation:

PV= 1/3nmv*2

PV= 2/3 × 1/2 NMV*2

PV= 2/3K.E

Since, K.E = 1/2nmv*2

Discussion

8.	Explain why on a cold winter morning,the car that parked in the open are wet although it has not rain in the night
Answer» AIR contains water MOLECULES in the form of vapour. while it is moving it strikes the CAR and looses it's kinetic energy and lowers TEMPERATURE and STICKS to the car. so that's why car is wet

Discussion

9.	The moving object across 80 meters in 2 .5 seconds
Answer» ANSWER: 23 is correct answer...... I hope help you..... THANKS..... no PROBLEM YAR

9.

The moving object across 80 meters in 2 .5 seconds

Answer»

ANSWER:

23 is correct answer......

I hope help you.....

THANKS.....

no PROBLEM YAR

Discussion

10.	Difference between balance and unbalance force
Answer» Answer: *Those* *FORCEs which* *have* *the* *resultant force is equal to zero , called* *balanced forces... Those* *forces* *which don't* *have* *the* *resultant* force ZERO,called unbalanced forces**.....

10.

Difference between balance and unbalance force

Answer»

Answer:

Those FORCEs which have the resultant force is equal to zero , called balanced forces...

Those forces which don't have the resultant force ZERO,called unbalanced forces.....

Discussion

11.	The speed of traveling wave
Answer» Answer: The distance covered by a WAVE in the direction of its PROPAGATION per UNIT TIME is CALLED the *wave velocity.* *Explanation*: mark it as a brainliest answer

11.

The speed of traveling wave

Answer»

Answer:

The distance covered by a WAVE in the direction of its PROPAGATION per UNIT TIME is CALLED the wave velocity.

Explanation:

mark it as a brainliest answer

Discussion

12.	Make the sentence.mountain
Answer» ANSWER: i CLIMBED the TALLEST MOUNTAIN on the EARTH

12.

Make the sentence.mountain

Answer»

ANSWER:

i CLIMBED the TALLEST MOUNTAIN on the EARTH

Discussion

13.	A ball of mass 0.1 kg starting from rest false a height of 4 metre and then collides with the ground after the collision the ball bounces up to a height of 2 metre the collision with the ground text place overtime 4 into 10 to the power minus 3 second determine the momentum of the ball immediately before the collision and immediately after the collision and the average force exerted by the ground on the ball take G is equal to 10
Answer» QUESTION:- A ball of mass $\displaystyle\sf{0.1\ kg}$ , starting from rest, falls a height of $\displaystyle\sf{4\ m}$ and then collides with the ground. After COLLISION, the ball bounces up to a height of $\displaystyle\sf{2\ m.}$ The collision with the ground TAKES place over a time $\displaystyle\sf{4\times10^{-3}\ s.}$ Determine the momentum of the ball immediately before the collision and immediately after the collision and the average force exerted by the ground on the ball. Take $\displaystyle\sf{g=10\ m\ s^{-2}.}$ Answer:- Momentum immediately before collision = $\displaystyle\large\sf{\underline{\underline{0.894\ kg\ m\ s^{-1}.}}}$ Momentum immediately after collision = $\displaystyle\large\sf{\underline{\underline{0.632\ kg\ m\ s^{-1}.}}}$ Average force exerted by the ground on the ball = $\displaystyle\sf{\underline{\underline{381.5\ N.}}}$ Solution:- Consider the incident immediately before collision. By third kinematic equation, $\displaystyle\longrightarrow\sf{v_1=\sqrt{2gh_1}}$ since $\displaystyle\sf{u_1=0\quad;\quad a_1=g\quad;\quad s=h_1}$ Then, the momentum of the ball immediately before collision, $\displaystyle\longrightarrow\sf{mv_1=m\sqrt{2gh_1}}$ Here, $\displaystyle\sf{m=0.1\quad;\quad g=10\quad;\quad h_1=4}$ Then, $\displaystyle\longrightarrow\sf{mv_1=0.1\times\sqrt{2\times10\times4}}$ $\displaystyle\longrightarrow\sf{\underline{\underline{mv_1=0.894\ kg\ m\ s^{-1}}}}$ Now, consider the incident immediately after collision and the rebounding of the ball. In this case, $\displaystyle\sf{a_2=g\quad;\quad v_2=0\quad;\quad s=-h_2=-2}$ since the downward motion is considered as POSITIVE. Again by third kinematic equation, $\displaystyle\longrightarrow\sf{(u_2)^2=(v_2)^2+2gh_2}$ $\displaystyle\longrightarrow\sf{u_2=-\sqrt{2gh_2}}$ Negative sign is because the ball usually moves upward after collision. Then, the momentum of the ball immediately after collision, $\displaystyle\longrightarrow\sf{mu_2=-m\sqrt{2gh_2}}$ $\displaystyle\longrightarrow\sf{mu_2=-0.1\times\sqrt{2\times10\times2}}$ $\displaystyle\longrightarrow\sf{\underline{\underline{mu_2=-0.632\ kg\ m\ s^{-1}}}}$ The average force exerted by the ground on the ball is given by Second Law, i.e., $\displaystyle\longrightarrow\sf{F=\dfrac{dp}{dt}}$ $\displaystyle\longrightarrow\sf{F=\dfrac{mu_2-mv_1}{dt}}$ since the IMPACT is occurred for a very short time $\displaystyle\sf{dt=4\times10^{-3}\ s.}$ Then, $\displaystyle\longrightarrow\sf{F=\dfrac{-0.632-0.894}{4\times10^{-3}}}$ $\displaystyle\longrightarrow\sf{\underline{\underline{F=-381.5\ N}}}$ Negative sign shows that the force is acting upwards.

13.

A ball of mass 0.1 kg starting from rest false a height of 4 metre and then collides with the ground after the collision the ball bounces up to a height of 2 metre the collision with the ground text place overtime 4 into 10 to the power minus 3 second determine the momentum of the ball immediately before the collision and immediately after the collision and the average force exerted by the ground on the ball take G is equal to 10

Answer»

QUESTION:-

A ball of mass $\displaystyle\sf{0.1\ kg}$ , starting from rest, falls a height of $\displaystyle\sf{4\ m}$ and then collides with the ground. After COLLISION, the ball bounces up to a height of $\displaystyle\sf{2\ m.}$ The collision with the ground TAKES place over a time $\displaystyle\sf{4\times10^{-3}\ s.}$ Determine the momentum of the ball immediately before the collision and immediately after the collision and the average force exerted by the ground on the ball. Take $\displaystyle\sf{g=10\ m\ s^{-2}.}$

Answer:-

Momentum immediately before collision = $\displaystyle\large\sf{\underline{\underline{0.894\ kg\ m\ s^{-1}.}}}$

Momentum immediately after collision = $\displaystyle\large\sf{\underline{\underline{0.632\ kg\ m\ s^{-1}.}}}$

Average force exerted by the ground on the ball = $\displaystyle\sf{\underline{\underline{381.5\ N.}}}$

Solution:-

Consider the incident immediately before collision.

By third kinematic equation,

$\displaystyle\longrightarrow\sf{v_1=\sqrt{2gh_1}}$

since $\displaystyle\sf{u_1=0\quad;\quad a_1=g\quad;\quad s=h_1}$

Then, the momentum of the ball immediately before collision,

$\displaystyle\longrightarrow\sf{mv_1=m\sqrt{2gh_1}}$

Here, $\displaystyle\sf{m=0.1\quad;\quad g=10\quad;\quad h_1=4}$

Then,

$\displaystyle\longrightarrow\sf{mv_1=0.1\times\sqrt{2\times10\times4}}$

$\displaystyle\longrightarrow\sf{\underline{\underline{mv_1=0.894\ kg\ m\ s^{-1}}}}$

Now, consider the incident immediately after collision and the rebounding of the ball.

In this case, $\displaystyle\sf{a_2=g\quad;\quad v_2=0\quad;\quad s=-h_2=-2}$

since the downward motion is considered as POSITIVE.

Again by third kinematic equation,

$\displaystyle\longrightarrow\sf{(u_2)^2=(v_2)^2+2gh_2}$

$\displaystyle\longrightarrow\sf{u_2=-\sqrt{2gh_2}}$

Negative sign is because the ball usually moves upward after collision.

Then, the momentum of the ball immediately after collision,

$\displaystyle\longrightarrow\sf{mu_2=-m\sqrt{2gh_2}}$

$\displaystyle\longrightarrow\sf{mu_2=-0.1\times\sqrt{2\times10\times2}}$

$\displaystyle\longrightarrow\sf{\underline{\underline{mu_2=-0.632\ kg\ m\ s^{-1}}}}$

The average force exerted by the ground on the ball is given by Second Law, i.e.,

$\displaystyle\longrightarrow\sf{F=\dfrac{dp}{dt}}$

$\displaystyle\longrightarrow\sf{F=\dfrac{mu_2-mv_1}{dt}}$

since the IMPACT is occurred for a very short time $\displaystyle\sf{dt=4\times10^{-3}\ s.}$

Then,

$\displaystyle\longrightarrow\sf{F=\dfrac{-0.632-0.894}{4\times10^{-3}}}$

$\displaystyle\longrightarrow\sf{\underline{\underline{F=-381.5\ N}}}$

Negative sign shows that the force is acting upwards.

Discussion

14.	Please answer it correctly and don't spam or i'll report you...1.Two equal positive charges q1 = q2 = 2.0 mC are located at x = 0, y = 0.30 m and x = 0, y = -0.30 m,respectively. What are the magnitude and direction of the total electric force that q1 and q2 exert ona third charge Q = 4.0 mC at x = 0.40 m, y = 0?2. Four charges are arranged in a square with one side of the square measuring 0.2m. From upper leftgoing clockwise, q1 = 2μC; q2 = -4μC; q3 = 6μC; and q4 = -8μC. Solve for the amount of electricforce experienced by q4 due to the other charges.
Answer» Answer: 1). FORCE = 4.60 * 10^5 N 2 ). Force = 14.98 N *EXPLANATION:* Refer the attached PICTURE.

14.

Please answer it correctly and don't spam or i'll report you...1.Two equal positive charges q1 = q2 = 2.0 mC are located at x = 0, y = 0.30 m and x = 0, y = -0.30 m,respectively. What are the magnitude and direction of the total electric force that q1 and q2 exert ona third charge Q = 4.0 mC at x = 0.40 m, y = 0?2. Four charges are arranged in a square with one side of the square measuring 0.2m. From upper leftgoing clockwise, q1 = 2μC; q2 = -4μC; q3 = 6μC; and q4 = -8μC. Solve for the amount of electricforce experienced by q4 due to the other charges.

Answer»

Answer:

1). FORCE = 4.60 * 10^5 N

2 ). Force = 14.98 N

EXPLANATION:

Refer the attached PICTURE.

Discussion

15.	(d)The equivalent capacitcance of two capacitorswhen joined in parallel is 16 uF and when joinedin series is 3 F. The capacitances of thecapacitors are(i) 8uF and 8 uF (ii) 4uF and 12 uF(iii) 6 uF and 10 uF (iv) 2 uF and 14 uF
Answer» ANSWER: Gaddalakonda GANESH ANTE GAFA

15.

(d)The equivalent capacitcance of two capacitorswhen joined in parallel is 16 uF and when joinedin series is 3 F. The capacitances of thecapacitors are(i) 8uF and 8 uF (ii) 4uF and 12 uF(iii) 6 uF and 10 uF (iv) 2 uF and 14 uF

Answer»

ANSWER:

Gaddalakonda GANESH ANTE GAFA

Discussion

16.	Dimension of kinetic energy are the same as that of
Answer» DIMENSIONS of KINETIC ENERGY is same as that of work.

Discussion

17.	Using constraint equation, find there relation between a1 and a2
Answer» ANSWER: gggggggggggggggggggggg hhhhhhhhhhhhggfddfyyuuuiihgftyuuuhgdghjj

17.

Using constraint equation, find there relation between a1 and a2

Answer»

ANSWER:

gggggggggggggggggggggg hhhhhhhhhhhhggfddfyyuuuiihgftyuuuhgdghjj

Discussion

18.	Class11 ,physics, one dimension velocity
Answer» Answer: Let the acceleration of the particle be a. For motion between A and B u= 12 m/s, s = 40 m, t = 4 s s = ut + (1/2)at 2 ⇒ 40 = 12 x 4 + (1/2) x a x (4) 2 a = -1 ms −2 For motion between A and C 64= 12t + (1/2)(-L)t 2 => r 2 - 24t +128 = 0 =>(t- 8) (t- 16) = 0 => t = 8 s, 16 s A.The particle will be at C twice, at t = 8 s and t = 16 s. B.Velocity of the particle at C At t = 8 s. velocity of the particle V = 12 + (-1) x 8 = 4 m/s. As the acceleration of the particle is negative, displacement = 0 ∴ 0= 12 × t + (1/2)(-1)t 2 => t = 0, 24 s At t = 0, velocity at A = 12 m/s, At t = 24 s, velocity at A is 12 + (-1) x 24 = -12 m/s. D.The particle reverses the direction of motion at D. For the motion between A and D u = 12 m/s, v = 0, a = -1 ms −2 . If AD = s, from the equation v 2 =u 2 +2as (0) 2 =(12) 2 + 2 x (-1) x s s = 72 m E. After 12 s the particle comes to rest momentarily at D after covering a distance of 72 m. Distance in SUBSEQUENT 3 s = 0 x 3 + (1/2) x (-1) x (3) 2 = 4.5 m ∴ d = 72 m + 4.5 m = 76.5 . EXPLANATION: hope it helps you....❤

18.

Class11 ,physics, one dimension velocity

Answer»

Answer:

Let the acceleration of the particle be a.

For motion between A and B

u= 12 m/s, s = 40 m, t = 4 s

s = ut + (1/2)at

2

⇒ 40 = 12 x 4 + (1/2) x a x (4)

2

a = -1 ms

−2

For motion between A and C

64= 12t + (1/2)(-L)t

2

=> r

2

- 24t +128 = 0

=>(t- 8) (t- 16) = 0

=> t = 8 s, 16 s

A.The particle will be at C twice, at t = 8 s and t = 16 s.

B.Velocity of the particle at C

At t = 8 s. velocity of the particle V = 12 + (-1) x 8

= 4 m/s.

As the acceleration of the particle is negative, displacement = 0

∴ 0= 12 × t + (1/2)(-1)t

2

=> t = 0, 24 s

At t = 0, velocity at A = 12 m/s,

At t = 24 s, velocity at A is 12 + (-1) x 24 = -12 m/s.

D.The particle reverses the direction of motion at D. For the motion between A and D

u = 12 m/s, v = 0, a = -1 ms

−2

. If AD = s, from the equation v

2

=u

2

+2as

(0)

2

=(12)

2

+ 2 x (-1) x s

s = 72 m

E. After 12 s the particle comes to rest momentarily at D after covering a distance of 72 m.

Distance in SUBSEQUENT 3 s

= 0 x 3 + (1/2) x (-1) x (3)

2

= 4.5 m

∴ d = 72 m + 4.5 m = 76.5 .

EXPLANATION:

hope it helps you....❤

Discussion

19.	What will be the dimension of area of circle
Answer» $\huge{\underline{\underline{\bf{\red{Answer}}}}}$ ${\bf{Area\:=\:π×r^2}}$ $\huge{\underline{\underline{\bf{\red{Thank\:you}}}}}$

Discussion

20.	What is the result of mixing 100 gm of ice at 0 degree into 100gm of water at 20 degree Celsius into an iron vessel of mass 100 gm?
Answer» ANSWER: BETTER to ASK your TEACHER

20.

What is the result of mixing 100 gm of ice at 0 degree into 100gm of water at 20 degree Celsius into an iron vessel of mass 100 gm?

Answer»

ANSWER:

BETTER to ASK your TEACHER

Discussion

21.	What do you mean by "1 ohm meter" ?
Answer» hey buddy here's your answer ohm METRE is the specific resistance. Explanation: 1ohm metre is the resistance of a wire of any specific material of UNIT length and unit AREA of cross section.

21.

What do you mean by "1 ohm meter" ?

Answer»

hey buddy here's your answer

ohm METRE is the specific resistance.

Explanation:

1ohm metre is the resistance of a wire of any specific material of UNIT length and unit AREA of cross section.

Discussion

22.	What are the types of weathering and their explanation
Answer» Hey!!!! Here's your Answer! Hope it helps! _____________________________________________ Answer: The types of Weathering are Chemical ChemicalOrganic ChemicalOrganicMechanical Explanation: Chemical Weathering- Chemical weathering happens when rocks are worn away by chemical changes. The natural chemical REACTIONS within the rocks change the composition of the rocks over time. Because the chemical processes are gradual and ongoing, the mineralogy of rocks changes over time thus making them wear away, dissolve, and disintegrate. Biological or Organic Weathering - Organic or biological weathering refers to the same thing. It is the disintegration of rocks as a result of the action by living organisms. Trees and other plants can wear away rocks SINCE as they penetrate into the soil and as their roots GET bigger, they exert pressure on rocks and makes the cracks wider and deeper. EVENTUALLY, the plants break the rocks apart. Some plants also grow within the fissures in the rocks which lead to widening of the fissures and then eventual disintegration. MECHANICAL or Physical - Mechanical weathering is also known as physical weathering. Mechanical weathering is the physical breakdown of rocks into smaller and smaller pieces. One of the most common mechanical actions is frost shattering. It happens when water enters the pores and cracks of rocks, then freezes.

22.

What are the types of weathering and their explanation

Answer»

Hey!!!! Here's your Answer! Hope it helps!

_____________________________________________

Answer:

The types of Weathering are

Chemical
ChemicalOrganic
ChemicalOrganicMechanical

Explanation:

Chemical Weathering- Chemical weathering happens when rocks are worn away by chemical changes. The natural chemical REACTIONS within the rocks change the composition of the rocks over time. Because the chemical processes are gradual and ongoing, the mineralogy of rocks changes over time thus making them wear away, dissolve, and disintegrate.

Biological or Organic Weathering - Organic or biological weathering refers to the same thing. It is the disintegration of rocks as a result of the action by living organisms. Trees and other plants can wear away rocks SINCE as they penetrate into the soil and as their roots GET bigger, they exert pressure on rocks and makes the cracks wider and deeper. EVENTUALLY, the plants break the rocks apart. Some plants also grow within the fissures in the rocks which lead to widening of the fissures and then eventual disintegration.

MECHANICAL or Physical - Mechanical weathering is also known as physical weathering. Mechanical weathering is the physical breakdown of rocks into smaller and smaller pieces. One of the most common mechanical actions is frost shattering. It happens when water enters the pores and cracks of rocks, then freezes.

Discussion

23.	What is potential write its si unit answer this question according to 4 marks
Answer» Explanation: In SCIENCE and ENGINEERING, the weight of an object is RELATED to the force acting on the object, either due to gravity or to a reaction force that holds it in place. Some STANDARD textbooks define weight as a vector quantity, the gravitational force acting on the objIn science and engineering, the weight of an object is related to the force acting on the object, either due to gravity or to a reaction force that holds it in place. Some standard textbooks define weight as a vector quantity, the gravitational force acting on the OBJ........ I hope help you............

23.

What is potential write its si unit answer this question according to 4 marks

Answer»

Explanation:

In SCIENCE and ENGINEERING, the weight of an object is RELATED to the force acting on the object, either due to gravity or to a reaction force that holds it in place. Some STANDARD textbooks define weight as a vector quantity, the gravitational force acting on the objIn science and engineering, the weight of an object is related to the force acting on the object, either due to gravity or to a reaction force that holds it in place. Some standard textbooks define weight as a vector quantity, the gravitational force acting on the OBJ........

I hope help you............

Discussion

24.	A 12 cm wire is given a shape of a right angled triangle ABC having sides 3 cm, 4 cm and 5 cmas shown in the figure. The resistance between twoends (AB, BC, CA) of the respective sides aremeasured one by one by a multi-meter. Theresistances will be in the ratio
Answer» ANSWER: HOPE you UNDERSTAND

24.

A 12 cm wire is given a shape of a right angled triangle ABC having sides 3 cm, 4 cm and 5 cmas shown in the figure. The resistance between twoends (AB, BC, CA) of the respective sides aremeasured one by one by a multi-meter. Theresistances will be in the ratio

Answer»

ANSWER:

HOPE you UNDERSTAND

Discussion

25.	How does combustion cause pollution and how can we reduce it?
Answer» ANSWER: PRIMARILY coals and oils, which are used in industrial plants to produce electricity and heat, are responsible for environmental pollution by sulfur oxides, strong acidity of air and ACID rains. Sulfur dioxide tendency is to reduce the "greenhouse EFFECT" by "albedo" effect. █▬█ █ ▀█▀♔〘Ł€Ǥ€ŇĐ〙♔Rᴇᴅɪsᴄᴏᴠᴇʀɪɴɢ Lᴏᴠᴇ♥ⓛⓞⓥⓔ♥τнänκ чöü♥βyё♥βyё

25.

How does combustion cause pollution and how can we reduce it?

Answer»

ANSWER:

PRIMARILY coals and oils, which are used in industrial plants to produce electricity and heat, are responsible for environmental pollution by sulfur oxides, strong acidity of air and ACID rains. Sulfur dioxide tendency is to reduce the "greenhouse EFFECT" by "albedo" effect.

█▬█ █ ▀█▀♔〘Ł€Ǥ€ŇĐ〙♔Rᴇᴅɪsᴄᴏᴠᴇʀɪɴɢ Lᴏᴠᴇ♥ⓛⓞⓥⓔ♥τнänκ чöü♥βyё♥βyё

Discussion

26.	How to delete anyone's question plz tell me
Answer» Answer: SORRY FRIND i don't know im NEW here Explanation: mark me as brainlist FRIEND PLZ don't be forget

26.

How to delete anyone's question plz tell me

Answer»

Answer:

SORRY FRIND i don't know im NEW here

Explanation:

mark me as brainlist FRIEND PLZ don't be forget

Discussion

27.	an object is placed 40 cm away infront of a mirror now both the object and the mirror are moved 10 cm towards each other what will be the distance between the object and image formed
Answer» The DISTANCE between the object and image FORMED is 40 cm. Considering the mirror to be plane mirror. As object and mirror both has MOVED by 10 cm towards each other so the RELATIVE distance between the mirror and the object will be reduced to 20 cm As in case of plane mirror the image is formed at the same distance , so the distance of the image will be 20 cm from the mirror

27.

an object is placed 40 cm away infront of a mirror now both the object and the mirror are moved 10 cm towards each other what will be the distance between the object and image formed

Answer»

The DISTANCE between the object and image FORMED is 40 cm.

Considering the mirror to be plane mirror.
As object and mirror both has MOVED by 10 cm towards each other so the RELATIVE distance between the mirror and the object will be reduced to 20 cm
As in case of plane mirror the image is formed at the same distance , so the distance of the image will be 20 cm from the mirror

Discussion

28.	Centre of gravity of a body is the point around which the resultant torque due to force of gravity on body is(a) zero (b)one(c) weight of a body (d )both a and b
Answer» ANSWER: c Explanation: this is BRAINLIEST answer

28.

Centre of gravity of a body is the point around which the resultant torque due to force of gravity on body is(a) zero (b)one(c) weight of a body (d )both a and b

Answer»

ANSWER:

c

Explanation:

this is BRAINLIEST answer

Discussion

29.	Answer this ........
Answer» Answer: WORK done when block REACH on ground $\\ mg \times (3h) \\ 3mgh \\$ work done when block REACHES at to of the circle $\\ 3mgh - mgh \\ 2mgh \\$ So force is 2mg so NORMAL FORCE = 2mg $\\ \\ \\ \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty$ HOPE IT HELPS

29.

Answer this ........

Answer»

Answer:

WORK done when block REACH on ground

$\\ mg \times (3h) \\ 3mgh \\$

work done when block REACHES at to of the circle

$\\ 3mgh - mgh \\ 2mgh \\$

So force is 2mg

so NORMAL FORCE = 2mg

$\\ \\ \\ \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty \infty$

HOPE IT HELPS

Discussion

30.	What iswhat is electric dipole in external uniform electric field
Answer» Answer: INTRODUCTION to DIPOLE in Uniform EXTERNAL Field Introduction to Dipole in Uniform External FieldIf a dipole is kept in an external electric field, it experiences a rotating effect. By external electric field, we mean electric field that is not induced by dipole itself. ... This can be done by calculating the NET torque on OPPOSITE charges of the dipole.

30.

What iswhat is electric dipole in external uniform electric field

Answer»

Answer:

INTRODUCTION to DIPOLE in Uniform EXTERNAL Field

Introduction to Dipole in Uniform External FieldIf a dipole is kept in an external electric field, it experiences a rotating effect. By external electric field, we mean electric field that is not induced by dipole itself. ... This can be done by calculating the NET torque on OPPOSITE charges of the dipole.

Discussion

31.	what is the relation between electric energy stored in capacitor and magnetic energy stored in inductor with respect to their field strengths
Answer» ANSWER: The potential ENERGY in a capacitor is STORED in the form of electric field, and the kinetic energy in an INDUCTOR is stored in the form of magnetic field

31.

what is the relation between electric energy stored in capacitor and magnetic energy stored in inductor with respect to their field strengths

Answer»

ANSWER:

The potential ENERGY in a capacitor is STORED in the form of electric field, and the kinetic energy in an INDUCTOR is stored in the form of magnetic field

Discussion

32.	Name 2 factors on which the specific resistance of a wire depends
Answer» Answer: length of the WIRE AREA of CROSS SECTION

32.

Name 2 factors on which the specific resistance of a wire depends

Answer»

Answer:

length of the WIRE

AREA of CROSS SECTION

Discussion

33.	11.2 লিটার কোনো আদর্শ গ্যাসের জন্য STP তে PV এর মান কত?
Answer» ANSWER: PLEASE GIVE ME ME THE TRANSLATION.

33.

11.2 লিটার কোনো আদর্শ গ্যাসের জন্য STP তে PV এর মান কত?

Answer»

ANSWER:

PLEASE GIVE ME ME THE TRANSLATION.

Discussion

34.	Does the direction of emf provided by a battery depend on the direction of current flow through thebattery?
Answer» Explanation: Direction of EMF is DECIDED by the construction of the BATTERY cell, it does not depend upon the direction of the current FLOW. In fact direction of the current flow depends upon the direction of emf. HOWEVER direction of the voltage drop depends upon the direction of the current.

34.

Does the direction of emf provided by a battery depend on the direction of current flow through thebattery?

Answer»

Explanation:

Direction of EMF is DECIDED by the construction of the BATTERY cell, it does not depend upon the direction of the current FLOW. In fact direction of the current flow depends upon the direction of emf. HOWEVER direction of the voltage drop depends upon the direction of the current.

Discussion

35.	Define moment of force? please tell me hurry
Answer» Answer: The turning EFFECT of a FORCE applied to a rotational system at a distance from the axis of ROTATION. The MOMENT is equal to the magnitude of the force multiplied by the PERPENDICULAR distance between its line of action and the axis of rotation. plzzz mark the answer brainliest! ! ! ❤✌☺

35.

Define moment of force? please tell me hurry

Answer»

Answer:

The turning EFFECT of a FORCE applied to a rotational system at a distance from the axis of ROTATION. The MOMENT is equal to the magnitude of the force multiplied by the PERPENDICULAR distance between its line of action and the axis of rotation.

plzzz mark the answer brainliest! ! ! ❤✌☺

Discussion

36.	a given mass of iron drown into wire of length L the extension produced in this wire by constant force F is praportonal to
Answer» ANSWER: it s YOUNG MODULUS and length inversely to the CROSSECTION AREA

36.

a given mass of iron drown into wire of length L the extension produced in this wire by constant force F is praportonal to

Answer»

ANSWER:

it s YOUNG MODULUS and length

inversely to the CROSSECTION AREA

Discussion

37.	Um guyz if we are told that the voltage across each resistor is 3.0 Vwhat is the total voltage of a circuit if the resistors are connected in parallel
Answer» Answer: The correct answer is 3volt because in PARALLEL CONNECTION VOLTAGE is EQUAL

37.

Um guyz if we are told that the voltage across each resistor is 3.0 Vwhat is the total voltage of a circuit if the resistors are connected in parallel

Answer»

Answer:

The correct answer is 3volt

because in PARALLEL CONNECTION VOLTAGE is EQUAL

Discussion

38.	Give some thanks please..⬆️⬆️⬆️↗️
Answer» EXPLANATION: FZD-GOWT-SUC HELLO all J ói n all can C O M E FAST ☺️✌✌

38.

Give some thanks please..⬆️⬆️⬆️↗️

Answer»

EXPLANATION:

FZD-GOWT-SUC HELLO all J ói n all can C O M E FAST ☺️✌✌

Discussion

39.	I F Q = -2ks W = +6 kJ then ∆ u.
Answer» ANSWER: ⚠️id-912 762 1607 p.a.s.s.c.o.d.e-Focus34B r.a.i.d. m.y.(c.l.a.s.s) .p.l.e.a.s.e⚠️

39.

I F Q = -2ks W = +6 kJ then ∆ u.

Answer»

ANSWER:

⚠️id-912 762 1607 p.a.s.s.c.o.d.e-Focus34B r.a.i.d. m.y.(c.l.a.s.s) .p.l.e.a.s.e⚠️

Discussion

40.	mas A ball of loom II Then of 1009 is acceleration calculate the chopped from a height of ? is If acceulate lom/s2 initial velocity
Answer»

Discussion

41.	If the magnetic field is parallel to a surface, then magnetic flux through to the surface, isA zeroB Small but not zeroC MaximumD none of these
Answer» ANSWER: If the SURFACE is PERPENDICULAR to the field (LEFT panel), and the field vector is thus parallel to the vector, →A, then the flux through that surface is maximal.

41.

If the magnetic field is parallel to a surface, then magnetic flux through to the surface, isA zeroB Small but not zeroC MaximumD none of these

Answer»

ANSWER:

If the SURFACE is PERPENDICULAR to the field (LEFT panel), and the field vector is thus parallel to the vector, →A, then the flux through that surface is maximal.

Discussion

42.	What is motor?...don't spam❌❌❌achha bhaiyo aur unki bahano..mera profile pic kesa hai⁉️⁉️
Answer» ANSWER: a motor is a MACHINE that CONVERT eletrical energy to mechanical energy.

42.

What is motor?...don't spam❌❌❌achha bhaiyo aur unki bahano..mera profile pic kesa hai⁉️⁉️

Answer»

ANSWER:

a motor is a MACHINE that CONVERT eletrical energy to mechanical energy.

Discussion

43.	What is Trevino mens........hello army good evening he he he
Answer» ANSWER: HEY this is GOOD night Hehehehe happy JK DAY

43.

What is Trevino mens........hello army good evening he he he

Answer»

ANSWER:

HEY this is GOOD night

Hehehehe

happy JK DAY

Discussion

44.	Which of the following terms identifies the change from a liquid to solid?
Answer» ANSWER: The process of a solid becoming a LIQUID is called melting (an older TERM that you may see sometimes is fusion). The OPPOSITE process, a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting POINT —is a characteristic of that substance. Explanation:

44.

Which of the following terms identifies the change from a liquid to solid?

Answer»

ANSWER:

The process of a solid becoming a LIQUID is called melting (an older TERM that you may see sometimes is fusion). The OPPOSITE process, a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting POINT —is a characteristic of that substance.

Explanation:

Discussion

45.	Write the few examples of clay
Answer» Answer: *VARIETIES. The MAIN GROUPS of clays INCLUDE kaolinite, montmorillonite-smectite, and illite. Chlorite, vermiculite, talc, and pyrophyllite are sometimes also CLASSIFIED as clay minerals.*

45.

Write the few examples of clay

Answer»

Answer:

VARIETIES. The MAIN GROUPS of clays INCLUDE kaolinite, montmorillonite-smectite, and illite. Chlorite, vermiculite, talc, and pyrophyllite are sometimes also CLASSIFIED as clay minerals.

Discussion

46.	The effective wattage of 100 W, 60 W and 40 W lamps connected in series, is equal to: A) 200 W C) 124 W B) 47.8 W D) 19.3 W
Answer» EXPLANATION: I THIN ANSWER is CORRECT

46.

The effective wattage of 100 W, 60 W and 40 W lamps connected in series, is equal to: A) 200 W C) 124 W B) 47.8 W D) 19.3 W

Answer»

EXPLANATION:

I THIN ANSWER is CORRECT

Discussion

47.	What is electroplating? State the tow main reasons for electroplating objects.
Answer» Answer: It is the PROCESS of coating a metal object with chromium, silver, or another metal by electrolytic deposition The two reasons to electroplate objects are: To make the better appearance of the objects (e.g., shiny) To PROTECT the objects from CORROSION To enhance or give special engineering or mechanical features to abrasion, lubricity ETC.

47.

What is electroplating? State the tow main reasons for electroplating objects.

Answer»

Answer:

It is the PROCESS of coating a metal object with chromium, silver, or another metal by electrolytic deposition

The two reasons to electroplate objects are:

To make the better appearance of the objects (e.g., shiny)
To PROTECT the objects from CORROSION To enhance or give special engineering or mechanical features to abrasion, lubricity ETC.

Discussion

48.	If x=20t +2t^2 does it represents uniform motion?Please explain answer briefly with correct answerDon't spam over here
Answer» Answer: SIMPLE compare it with s= ut + 1/2 at^2 so a= 4 m/s^2 it MEAN that if body is uniform motion it should'nt have acceleration but we have acceleration of it mean motion is NON uniform

48.

If x=20t +2t^2 does it represents uniform motion?Please explain answer briefly with correct answerDon't spam over here

Answer»

Answer:

SIMPLE compare it with s= ut + 1/2 at^2

so a= 4 m/s^2 it MEAN that if body is uniform motion it should'nt have acceleration but we have acceleration of it mean motion is NON uniform

Discussion

49.	Sorry I could not answer ur question and why were you missing me
Answer» ANSWER: priya DI I'm fatima AGE 13

49.

Sorry I could not answer ur question and why were you missing me

Answer»

ANSWER:

priya DI I'm fatima AGE 13

Discussion

50.	A ray of light incident at an angle of 45° on a prism having a refracting angle 47° suffers minimum deviation. What will be the angle of minimum deviation?
Answer» Answer: ok Explanation: ray of light INCIDENT at an angle of 45° on a PRISM having a REFRACTING angle 47° suffers minimum deviation. What will be the angle of minimum deviation?

50.

A ray of light incident at an angle of 45° on a prism having a refracting angle 47° suffers minimum deviation. What will be the angle of minimum deviation?

Answer»

Answer:

ok

Explanation:

ray of light INCIDENT at an angle of 45° on a PRISM having a REFRACTING angle 47° suffers minimum deviation. What will be the angle of minimum deviation?

Discussion

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plzzz mark the answer brainliest! ! ! ❤✌☺

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Make the sentence.mountain

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Class11 ,physics, one dimension velocity

What will be the dimension of area of circle

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How to delete anyone's question plz tell me

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Answer this ........

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Does the direction of emf provided by a battery depend on the direction of current flow through thebattery?

Define moment of force? please tell me hurry

a given mass of iron drown into wire of length L the extension produced in this wire by constant force F is praportonal to

Um guyz if we are told that the voltage across each resistor is 3.0 Vwhat is the total voltage of a circuit if the resistors are connected in parallel

Give some thanks please..⬆️⬆️⬆️↗️

I F Q = -2ks W = +6 kJ then ∆ u.

mas A ball of loom II Then of 1009 is acceleration calculate the chopped from a height of ? is If acceulate lom/s2 initial velocity

If the magnetic field is parallel to a surface, then magnetic flux through to the surface, isA zeroB Small but not zeroC MaximumD none of these

What is motor?...don't spam❌❌❌achha bhaiyo aur unki bahano..mera profile pic kesa hai⁉️⁉️

What is Trevino mens........hello army good evening he he he

Write the few examples of clay

The effective wattage of 100 W, 60 W and 40 W lamps connected in series, is equal to: A) 200 W C) 124 W B) 47.8 W D) 19.3 W

What is electroplating? State the tow main reasons for electroplating objects.

If x=20t +2t^2 does it represents uniform motion?Please explain answer briefly with correct answerDon't spam over here

Sorry I could not answer ur question and why were you missing me