67486 + Interview Questions in Secondary School in Physics

1.	A radio station broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 kW, then the number of photons radiated per second is?
Answer» ANSWER: A RADIO station broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 KW, then the number of ...

1.

A radio station broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 kW, then the number of photons radiated per second is?

Answer»

A RADIO station broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 KW, then the number of ...

Discussion

2.	If the wavelength of sound note is halved then the frequency is
Answer» ANSWER: If the wavelength is doubled, FREQUENCY is halved. There is no CHANGE in the speed of the wave. The wavelength and frequency of a wave are inversely proportional to each other and both are DIRECTLY proportional to the velocity of the wave.

2.

If the wavelength of sound note is halved then the frequency is

Answer»

ANSWER:

If the wavelength is doubled, FREQUENCY is halved. There is no CHANGE in the speed of the wave. The wavelength and frequency of a wave are inversely proportional to each other and both are DIRECTLY proportional to the velocity of the wave.

Discussion

3.	Magnetic field at the axis of cylinder
Answer» Answer: refers to the number of loops the cylindrical coil has. More loops will BRING about a STRONGER MAGNETIC field. ... HENCE this expression gives the magnetic field at point on the axis of a cylindrical coil of finite length. Explanation: I hope it will helps you ❣️

3.

Magnetic field at the axis of cylinder

Answer»

Answer:

refers to the number of loops the cylindrical coil has. More loops will BRING about a STRONGER MAGNETIC field. ... HENCE this expression gives the magnetic field at point on the axis of a cylindrical coil of finite length.

Explanation:

I hope it will helps you ❣️

Discussion

4.	Help me please in solving this question of physics
Answer» Answer: Question : Wavelength of 2 WAVES are in 85/170 m and 85/172 m .These waves produces 4 BEATS with a 3rd node of fixed frequency n. Find the frequency of 3rd node and velocity of the waves. Given: The supplied wavelengths are : 85/170 m 85/172 m 3rd node has frequency of "n" To find: Frequency of 3rd node and velocity of wave. Concept: LET Frequency of the way be f1 and f2. $\therefore \: f1 = \dfrac{v}{ (\frac{85}{170}) } \\ \\ = > f1 = \dfrac{170v}{85}$ $\therefore \: f2 = \dfrac{v}{( \frac{85}{172}) } \\ \\ = > f2 = \dfrac{172v}{85}$ Since both these frequencies PRODUCE 4 beats , so we can say that : f2 - n = 4 .....(1) n - f1 = 4 .....(2) Calculation: If we add eq(1) and eq(2) , then $\therefore \: f2 - f1 = 8$ $= > \dfrac{172v}{85} - \dfrac{170v}{85} = 8 \\ = > \dfrac{2v}{85} = 8 \\ = > v = 85 \times 4 \\ = > v = 340 \: m {s}^{ - 1}$ So putting value of "v" in f2 $f2 = \dfrac{172v}{85} \\ = > f2 = \dfrac{172 \times 340}{85} \\ = > f2 = 172 \times 4 = 688 \: hz$ Now putting f2 in eq(1) $f2 - n = 4 \\ = > 688 - n = 4 \\ = > n = 684 \: hz$ So final answer : $\boxed{velocity = 340 \: m {s}^{ - 1}} \\ \boxed{n = 684 \: hz}$

4.

Help me please in solving this question of physics

Answer»

Answer:

Question :

Wavelength of 2 WAVES are in 85/170 m and 85/172 m .These waves produces 4 BEATS with a 3rd node of fixed frequency n. Find the frequency of 3rd node and velocity of the waves.

Given:

The supplied wavelengths are :

85/170 m
85/172 m

3rd node has frequency of "n"

To find:

Frequency of 3rd node and velocity of wave.

Concept:

LET Frequency of the way be f1 and f2.

$\therefore \: f1 = \dfrac{v}{ (\frac{85}{170}) } \\ \\ = > f1 = \dfrac{170v}{85}$

$\therefore \: f2 = \dfrac{v}{( \frac{85}{172}) } \\ \\ = > f2 = \dfrac{172v}{85}$

Since both these frequencies PRODUCE 4 beats , so we can say that :

f2 - n = 4 .....(1)
n - f1 = 4 .....(2)

Calculation:

If we add eq(1) and eq(2) , then

$\therefore \: f2 - f1 = 8$

$= > \dfrac{172v}{85} - \dfrac{170v}{85} = 8 \\ = > \dfrac{2v}{85} = 8 \\ = > v = 85 \times 4 \\ = > v = 340 \: m {s}^{ - 1}$

So putting value of "v" in f2

$f2 = \dfrac{172v}{85} \\ = > f2 = \dfrac{172 \times 340}{85} \\ = > f2 = 172 \times 4 = 688 \: hz$

Now putting f2 in eq(1)

$f2 - n = 4 \\ = > 688 - n = 4 \\ = > n = 684 \: hz$

So final answer :

$\boxed{velocity = 340 \: m {s}^{ - 1}} \\ \boxed{n = 684 \: hz}$

Discussion

5.	For uniform circular motion,does the direction of centripetal force depend only on sense of rotation i.e. clockwise or anticlockwise direction?
Answer» ANSWER: No. EXPLANATION: Centripetal force is ALWAYS DIRECTED towards centre of the CIRCLE...

5.

For uniform circular motion,does the direction of centripetal force depend only on sense of rotation i.e. clockwise or anticlockwise direction?

Answer»

ANSWER:

No.

EXPLANATION:

Centripetal force is ALWAYS DIRECTED towards centre of the CIRCLE...

Discussion

6.	Figure shows a displacements time graph. Comment on the sign of velocities atpoint P, Q, R, S and T.
Answer» ANSWER:in point p,Q,R,s,t SIGNS of velocity are + ,neutral,-,neutral,+ RESPECTIVELY Explanation:

6.

Figure shows a displacements time graph. Comment on the sign of velocities atpoint P, Q, R, S and T.

Answer»

ANSWER:in point p,Q,R,s,t SIGNS of velocity are + ,neutral,-,neutral,+ RESPECTIVELY

Explanation:

Discussion

7.	force of 147 N is required to just slide a block of weight 500N over a surface of ice calculate the coefficient of friction between block and ice
Answer» $\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$ From the Question, Force acting on the block,F = 147 N Weight,W = 500 N To finD Coefficient of FRICTION From Newton's Second Law, $\sf \: F_{net} = Ma$ The block isn't still stationary,THUS a = 0 m/s². Thus,the net force acting on the block is zero Now, $\sf{F - f = 0} \\ \\ \longmapsto \: \sf{F = \mu \: N}$ Here, The normal reaction and weights are balanced here. Net force ALONG Y axis is ALSO zero. Thus,the normal reaction is also equal to 500 N. $\longmapsto \ \sf \: 147 = \mu \: \times 500 \\ \\ \longmapsto \: \sf \mu \: = 0.29 \\ \\ \longmapsto \: \boxed{ \boxed{ \sf{ \mu = 0.30}}}$

7.

force of 147 N is required to just slide a block of weight 500N over a surface of ice calculate the coefficient of friction between block and ice

Answer»

$\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$

From the Question,

Force acting on the block,F = 147 N

Weight,W = 500 N

To finD

Coefficient of FRICTION

From Newton's Second Law,

$\sf \: F_{net} = Ma$

The block isn't still stationary,THUS a = 0 m/s². Thus,the net force acting on the block is zero

Now,

$\sf{F - f = 0} \\ \\ \longmapsto \: \sf{F = \mu \: N}$

Here,

The normal reaction and weights are balanced here. Net force ALONG Y axis is ALSO zero. Thus,the normal reaction is also equal to 500 N.

$\longmapsto \ \sf \: 147 = \mu \: \times 500 \\ \\ \longmapsto \: \sf \mu \: = 0.29 \\ \\ \longmapsto \: \boxed{ \boxed{ \sf{ \mu = 0.30}}}$

Discussion

8.	Define 1 diopter of power of a lens
Answer» A DIOPTRE or diopter is a unit of measurement of Optical power of a LENS or curved MIRROR, which is equal to the RECIPROCAL of the focal length measured in meters ( 1 diopter = 1/m )

8.

Define 1 diopter of power of a lens

Answer»

A DIOPTRE or diopter is a unit of measurement of Optical power of a LENS or curved MIRROR, which is equal to the RECIPROCAL of the focal length measured in meters ( 1 diopter = 1/m )

Discussion

9.	How can velocity be increasing but speed be decreasing?
Answer» ANSWER: But one value cannot decrease while the other increases, that is impossible. SPEED is DISTANCE/time and VELOCITY is DISPLACEMENT/time.We can change the path from one point to another, changing the distance which can increase or decrease the speed. But displacement is same so velocity remains constant

9.

How can velocity be increasing but speed be decreasing?

Answer»

ANSWER:

But one value cannot decrease while the other increases, that is impossible. SPEED is DISTANCE/time and VELOCITY is DISPLACEMENT/time.We can change the path from one point to another, changing the distance which can increase or decrease the speed. But displacement is same so velocity remains constant

Discussion

10.	A particel is performing simple harmonic motion it's maximum velocity is 3m/s and amplitude of motion is 0.2 m. calculate the Time period of motion
Answer» Answer: image image An object moving along the x-axis is said to exhibit simple harmonic motion if its position as a function of time varies as x(t) = X0 + A cos(ωt + φ). The object oscillates about the equilibrium position x0. If we choose the origin of our coordinate system such that x0 = 0, then the displacement x from the equilibrium position as a function of time is given by x(t) = A cos(ωt + φ). A is the amplitude of the OSCILLATION, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction. Simple harmonic motion is repetitive. The period T is the time it takes the object to complete one oscillation and return to the starting position. The angular FREQUENCY ω is given by ω = 2π/T. The angular frequency is measured in radians per second. The inverse of the period is the frequency f = 1/T. The frequency f = 1/T = ω/2π of the motion gives the number of complete oscillations per unit time. It is measured in units of Hertz, (1 Hz = 1/s). I *HOPE* it will help you mark me as *BRAINLIST*

10.

A particel is performing simple harmonic motion it's maximum velocity is 3m/s and amplitude of motion is 0.2 m. calculate the Time period of motion

Answer»

Answer:

image image

An object moving along the x-axis is said to exhibit simple harmonic motion if its position as a function of time varies as

x(t) = X0 + A cos(ωt + φ).

The object oscillates about the equilibrium position x0. If we choose the origin of our coordinate system such that x0 = 0, then the displacement x from the equilibrium position as a function of time is given by

x(t) = A cos(ωt + φ).

A is the amplitude of the OSCILLATION, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction. Simple harmonic motion is repetitive. The period T is the time it takes the object to complete one oscillation and return to the starting position. The angular FREQUENCY ω is given by ω = 2π/T. The angular frequency is measured in radians per second. The inverse of the period is the frequency f = 1/T. The frequency f = 1/T = ω/2π of the motion gives the number of complete oscillations per unit time. It is measured in units of Hertz, (1 Hz = 1/s).

I HOPE it will help you

mark me as BRAINLIST

Discussion

11.	resistance of copper wire at 20°C is 1 ohm. find the temperature at which its resistance will be 10% more . resistence temperature cofficient is 3.9×10^-31/°C
Answer» ANSWER: Explanation: 22 DEGREES CELSIUS

11.

resistance of copper wire at 20°C is 1 ohm. find the temperature at which its resistance will be 10% more . resistence temperature cofficient is 3.9×10^-31/°C

Answer»

ANSWER:

Explanation:

22 DEGREES CELSIUS

Discussion

12.	MethaneCthaneprop -buthenheptOct-
Answer» idk? PLS ASK UR question in a better WAY, then I can help, I guess...

12.

MethaneCthaneprop -buthenheptOct-

Answer»

idk? PLS ASK UR question in a better WAY, then I can help, I guess...

Discussion

13.	Why farhenheit and Celsius are equal at -40
Answer» Answer: Celsius degrees or Fahrenheit degrees are the INTERVALS between the gradations on that thermometer scale. ... The CONVERSION is Celsius times 1.8 equals Fahrenheit. THUS a one Celsius DEGREE rise in temperature is equivalent to a 1.8 Fahrenheit degree rise. Explanation: *please* *Mark* me as *BRAINLIST*

13.

Why farhenheit and Celsius are equal at -40

Answer»

Answer:

Celsius degrees or Fahrenheit degrees are the INTERVALS between the gradations on that thermometer scale. ... The CONVERSION is Celsius times 1.8 equals Fahrenheit. THUS a one Celsius DEGREE rise in temperature is equivalent to a 1.8 Fahrenheit degree rise.

Explanation:

please Mark me as BRAINLIST

Discussion

14.	Define concave and convex mirror.
Answer» Answer: If the inner side of the spherical MIRROR is reflecting, it is CALLED a concave mirror. If the outer side of the spherical mirror is reflecting, it is called a convex mirror. Image. Concave MIRRORS can form INVERTED and real images and also virtual and ERECT images. hope it helps you...

14.

Define concave and convex mirror.

Answer»

Answer:

If the inner side of the spherical MIRROR is reflecting, it is CALLED a concave mirror. If the outer side of the spherical mirror is reflecting, it is called a convex mirror. Image. Concave MIRRORS can form INVERTED and real images and also virtual and ERECT images.

hope it helps you...

Discussion

15.	Four point charges are placed at the four corners of a square in two ways (a) and (b) as shown in figure. Will the (i) electric potential and (ii) electric field, at the centre of the square be the same or different in the two configurations and why?
Answer» okk .. a= as in the figure u can see opposite charge on opposite sides . let at the centre. there is a small POSITIVE charge. q hence. hence direction of force point A will be in the direction of point C hence total force by A and point c will be 2f similar to BD force on centre by BD =2f now both the direction will be in 90 Degree to each other. hence FNET on centre = 2√2F b = similar charge on opposite sides then direction will be opposite hence total force =0

15.

Four point charges are placed at the four corners of a square in two ways (a) and (b) as shown in figure. Will the (i) electric potential and (ii) electric field, at the centre of the square be the same or different in the two configurations and why?

Answer»

okk ..

a= as in the figure u can see opposite charge on opposite sides .

let at the centre. there is a small POSITIVE charge. q

hence.

hence direction of force point A will be in the direction of point C

hence total force by A and point c will be 2f

similar to BD

force on centre by BD =2f

now

both the direction will be in 90 Degree to each other.

hence

FNET on centre = 2√2F

b = similar charge on opposite sides then direction will be opposite hence total force =0

Discussion

16.	Semiconductors obey ohm’s law at only low fields ?
Answer» Answer: This happens because at low temperature, the "p" and "N" type semiconductor RESIST the flow of ELECTRONS through them and then act as resistances, but when the temperature is increased the flow of electrons is HINDERED.

16.

Semiconductors obey ohm’s law at only low fields ?

Answer»

Answer:

This happens because at low temperature, the "p" and "N" type semiconductor RESIST the flow of ELECTRONS through them and then act as resistances, but when the temperature is increased the flow of electrons is HINDERED.

Discussion

17.	A vertical straight conductor carries a current vertically upwards. A point P lies to the east of it at a small distance and another point Q lies to the west at the same distance. The magnetic field at P is(EXPLAIN) a) Greater than that at Qb) Same as at Qc) Less than at Qd) Greater or less than at Q depending upon strength of current
Answer» $\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}} \\ \\ \boxed{ \blue{ B = \frac{ \mu \: I}{4 \pi \: x} ( \sin( \theta1) + \sin( \theta2)) }}$ => Magnetic FIELD at a POINT which is SITUATED at x distance from straight WIRE is given by this formula... => Here, distance between wire and P point and distance between wire and Q point is same = x => Also, angle at P and Q point is same... => So, magnetic field at both point is same in magnitude but not same in direction... => At P point direction of magnetic field is inside and at Q point direction is Outside... $\boxed{\bold{\huge{ \star}}} \: \: \boxed{ \boxed{ \pink{magnetic \: field \: at \: P \: point = magnetic \: field \: at \: Q \: point}}} \: \: \boxed{\huge{ \bold{ \star}}}$

17.

A vertical straight conductor carries a current vertically upwards. A point P lies to the east of it at a small distance and another point Q lies to the west at the same distance. The magnetic field at P is(EXPLAIN) a) Greater than that at Qb) Same as at Qc) Less than at Qd) Greater or less than at Q depending upon strength of current

Answer»

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}} \\ \\ \boxed{ \blue{ B = \frac{ \mu \: I}{4 \pi \: x} ( \sin( \theta1) + \sin( \theta2)) }}$

=> Magnetic FIELD at a POINT which is SITUATED at x distance from straight WIRE is given by this formula...

=> Here, distance between wire and P point and distance between wire and Q point is same = x

=> Also, angle at P and Q point is same...

=> So, magnetic field at both point is same in magnitude but not same in direction...

=> At P point direction of magnetic field is inside and at Q point direction is Outside...

$\boxed{\bold{\huge{ \star}}} \: \: \boxed{ \boxed{ \pink{magnetic \: field \: at \: P \: point = magnetic \: field \: at \: Q \: point}}} \: \: \boxed{\huge{ \bold{ \star}}}$

Discussion

18.	. Three bodies A, B and C of masses 1 kg, 2 kg and 3 kg are at rest on ahorizontal surface of coefficient of friction 0.5. If they are pulled withforces 20 N, 30 N, and 25 N respectively, their accelerations an, ag and acwill be in ascending order as follows.1
Answer» Answer: 70 Explanation: 1+2+3=6,20+30+25=70

18.

. Three bodies A, B and C of masses 1 kg, 2 kg and 3 kg are at rest on ahorizontal surface of coefficient of friction 0.5. If they are pulled withforces 20 N, 30 N, and 25 N respectively, their accelerations an, ag and acwill be in ascending order as follows.1

Answer»

Answer:

70

Explanation:

1+2+3=6,20+30+25=70

Discussion

19.	S.i unit of calorie
Answer» ANSWER: S.I UNIT of HEAT is CALORIE ..

19.

S.i unit of calorie

Answer»

ANSWER:

S.I UNIT of HEAT is CALORIE ..

Discussion

20.	A mountaineer climbing on the Everest experinced the following facts.Explain each fact with the scientific reason.i) He found fishes alive below the iceii) Time required for cookings was more as he went higheriii) He saw many times cliffs falling suddenlyiv) He saw tubes carrying water broken.
Answer» ANSWER: because FISH can FLOTE in COLD WATER

20.

A mountaineer climbing on the Everest experinced the following facts.Explain each fact with the scientific reason.i) He found fishes alive below the iceii) Time required for cookings was more as he went higheriii) He saw many times cliffs falling suddenlyiv) He saw tubes carrying water broken.

Answer»

ANSWER:

because FISH can FLOTE in COLD WATER

Discussion

21.	the speed of light in a transparent medium is 2.4×10^8m/s calculate the absolute refractive index of the medium
Answer» Answer: the absolute REFRACTIVE index would be...1.25 Explanation: given that the SPEED of light in a MEDIUM is 2.4×10^8 and we know that speed of light in vaccum is 3×10^8 m/s ...so n21 would be 3×10^8 ÷2.4×10^8m/s....THUS refractive Index would be 1.25

21.

the speed of light in a transparent medium is 2.4×10^8m/s calculate the absolute refractive index of the medium

Answer»

Answer:

the absolute REFRACTIVE index would be...1.25

Explanation:

given that the SPEED of light in a MEDIUM is 2.4×10^8 and we know that speed of light in vaccum is 3×10^8 m/s ...so n21 would be 3×10^8 ÷2.4×10^8m/s....THUS refractive Index would be 1.25

Discussion

22.	In the above circuit the equivalent resistance between A and B is
Answer» ANSWER: it is EQUAL to each SIDES

22.

In the above circuit the equivalent resistance between A and B is

Answer»

ANSWER:

it is EQUAL to each SIDES

Discussion

23.	Define elastic and inelastic collision write one example of each
Answer» Answer: PERFECTLY elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision. Explanation: An EXAMPLE of an elastic collision is the movement of the swinging balls. In an inelastic collision, the energy CHANGES into other energies such as SOUND energy or thermal energy. In an inelastic collision, the energy is not conserved. An example of an inelastic collision is an automobile collision.

23.

Define elastic and inelastic collision write one example of each

Answer»

Answer:

PERFECTLY elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.

Explanation:

An EXAMPLE of an elastic collision is the movement of the swinging balls. In an inelastic collision, the energy CHANGES into other energies such as SOUND energy or thermal energy. In an inelastic collision, the energy is not conserved. An example of an inelastic collision is an automobile collision.

Discussion

24.	What is horizantal component. of earth magnetic field at a place
Answer» Explanation: The HORIZONTAL component of earth's magnetic FIELD at a place is 0.4 x 10–4 T. If angle of dip is 45°, what are the values of vertical component and total INTENSITY of earth's field

24.

What is horizantal component. of earth magnetic field at a place

Answer»

Explanation:

The HORIZONTAL component of earth's magnetic FIELD at a place is 0.4 x 10–4 T. If angle of dip is 45°, what are the values of vertical component and total INTENSITY of earth's field

Discussion

25.	Is heat resistance objects has specific heat explain
Answer» Explanation: Specific heat is Jg−oK . So, a high value MEANS that it TAKES MORE energy to raise (or LOWER) its temperature. A low value means that it does not take very MUCH energy to heat or COOL it.

25.

Is heat resistance objects has specific heat explain

Answer»

Explanation:

Specific heat is Jg−oK . So, a high value MEANS that it TAKES MORE energy to raise (or LOWER) its temperature. A low value means that it does not take very MUCH energy to heat or COOL it.

Discussion

26.	for an object placed beyond 2f , a image formed by a concave mirror is real ,diminish and between f and 2f .
Answer» EXPLANATION: YES your ANSWER is CORRECT

26.

for an object placed beyond 2f , a image formed by a concave mirror is real ,diminish and between f and 2f .

Answer»

EXPLANATION:

YES your ANSWER is CORRECT

Discussion

27.	The energy required to charge a parallelcondenser of plate separation d and plate area ofcross-section A such that the uniform electric fieldbetween the plates is E, is :- bei(1) Eo E² Ad(2)1/2 Eo E² Ad(3)1/2 Eo E²/A.d(4) Eo E²/Ad
Answer» $\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$ ${\bf{\green{(4)EoE^2/Ad}}}$

27.

The energy required to charge a parallelcondenser of plate separation d and plate area ofcross-section A such that the uniform electric fieldbetween the plates is E, is :- bei(1) Eo E² Ad(2)1/2 Eo E² Ad(3)1/2 Eo E²/A.d(4) Eo E²/Ad

Answer»

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

${\bf{\green{(4)EoE^2/Ad}}}$

Discussion

28.	33. A block of mass (figure 13) 10 kg is pulled by a force P asshown. If the frictional force is 5N and if the block moves up theplane with an acceleration of 5 m/s, then calculate the value of
Answer» Answer: Force may be defined as the cause of motion and deformation. When a force is applied to an object, the object either moves or changes shape or both. In most cases, it is not possible to detect the deformation by naked eyes at the molecular or atomic level. Deformation occurs no matter how small. In Chapter 1, force was defined as the product of mass and acceleration. Simply F = Ma. A more useful form of this formula is ΣF = Ma. ΣF means the sum of forces acting on mass M. Since forces acting on an object may act in opposite directions, ΣF is also CALLED the net force. The formula ΣF = Ma is called the "Newton's 2nd Law of Motion." For example, a car moving along a straight and horizontal highway, experiences an engine force FE, while being opposed by an overall frictional force, Ff ( road friction as well as air resistance). If the car is moving to the right and to the right is TAKEN to be the positive direction, then Fe ACTS to the right and Ff acts to the LEFT. The net force is ΣF = Fe - Ff .

28.

33. A block of mass (figure 13) 10 kg is pulled by a force P asshown. If the frictional force is 5N and if the block moves up theplane with an acceleration of 5 m/s, then calculate the value of

Answer»

Answer:

Force may be defined as the cause of motion and deformation. When a force is applied to an object, the object either moves or changes shape or both. In most cases, it is not possible to detect the deformation by naked eyes at the molecular or atomic level. Deformation occurs no matter how small.

In Chapter 1, force was defined as the product of mass and acceleration. Simply F = Ma. A more useful form of this formula is ΣF = Ma. ΣF means the sum of forces acting on mass M. Since forces acting on an object may act in opposite directions, ΣF is also CALLED the net force.

The formula ΣF = Ma is called the "Newton's 2nd Law of Motion."

For example, a car moving along a straight and horizontal highway, experiences an engine force FE, while being opposed by an overall frictional force, Ff ( road friction as well as air resistance). If the car is moving to the right and to the right is TAKEN to be the positive direction, then Fe ACTS to the right and Ff acts to the LEFT. The net force is ΣF = Fe - Ff .

Discussion

29.	Why kelvin has not negative readings
Answer» ANSWER: KELVIN is DIFFERENT because it's an absolute SCALE. 0K is absolute zero — the point at which gas molecules have no thermal energy. There's no negative temperature on the Kelvin temperature scale

29.

Why kelvin has not negative readings

Answer»

ANSWER:

KELVIN is DIFFERENT because it's an absolute SCALE. 0K is absolute zero — the point at which gas molecules have no thermal energy. There's no negative temperature on the Kelvin temperature scale

Discussion

30.	What is magnetic decination
Answer» MAGNETIC DECLINATION, or magnetic variation, is the angle on the horizontal plane between magnetic north and true north. This angle varies depending on position on the Earth's surface and CHANGES over TIME.

30.

What is magnetic decination

Answer»

MAGNETIC DECLINATION, or magnetic variation, is the angle on the horizontal plane between magnetic north and true north. This angle varies depending on position on the Earth's surface and CHANGES over TIME.

Discussion

31.	Small identical droplets coalesce to form a bigger drop find the loss of energy
Answer» EXPLANATION: the energy LOST is 3E, where, E is the energy of the bigger DROP.

31.

Small identical droplets coalesce to form a bigger drop find the loss of energy

Answer»

EXPLANATION:

the energy LOST is 3E, where, E is the energy of the bigger DROP.

Discussion

32.	Which metals react with cold water quickely
Answer» sodium (Na), POTASSIUM (K), CALCIUM (CA) REACTS with cold water vigorously

Discussion

33.	What are the deleted topics in physicsplz reply exam is not far behind
Answer» Answer: RAY optics is deleted from the physics CLASS 11

33.

What are the deleted topics in physicsplz reply exam is not far behind

Answer»

Answer:

RAY optics is deleted from the physics CLASS 11

Discussion

34.	A USIUT ay i sust- Ship \| Tiger Umbrello Vam
Answer» Answer: UNIQUE star INDIAN union terrace

34.

A USIUT ay i sust- Ship | Tiger Umbrello Vam

Answer»

Answer:

UNIQUE star INDIAN union terrace

Discussion

35.	4.The rate at which potential difference between theplates of a parallel plate capacitor with a 2 uFcapacitance be changed to produce adisplacement current of 1 A is(1) 0.5 MV/s(2) 0.3 MV/s(3) 0.2 MV/s(4) 0.1 MV/s
Answer» The CORRECT answer is OPTION 1) 0.5 MV/s Given that displacement current = I(d) = 2 A I(d) = ε.dΦ/dt Φ - flux = E.A dΦ/dt = change in flux E is the electric field across the capacitor and A is the AREA of the plate of capacitor. I(d) = ε.A dE/dt E = V/d = POTENTIAL difference / distance between the plates of the capacitor => I(d) = ε.A d(V/d)/dt => I(d) = (ε.A)/d × d(V)/dt => I(d) = C × dV/dt [ C = capacitance of the capacitor = (ε.A)/d ] => dV/dt = I(d)/C => dV/dt = 1/2 = 0.5 MV/s The rate of change of potential difference of the capacitor = 0.5 MV/s

35.

4.The rate at which potential difference between theplates of a parallel plate capacitor with a 2 uFcapacitance be changed to produce adisplacement current of 1 A is(1) 0.5 MV/s(2) 0.3 MV/s(3) 0.2 MV/s(4) 0.1 MV/s

Answer»

The CORRECT answer is OPTION 1) 0.5 MV/s

Given that displacement current = I(d) = 2 A

I(d) = ε.dΦ/dt

Φ - flux = E.A

dΦ/dt = change in flux

E is the electric field across the capacitor and A is the AREA of the plate of capacitor.

I(d) = ε.A dE/dt

E = V/d = POTENTIAL difference / distance between the plates of the capacitor

=> I(d) = ε.A d(V/d)/dt

=> I(d) = (ε.A)/d × d(V)/dt

=> I(d) = C × dV/dt [ C = capacitance of the capacitor = (ε.A)/d ]

=> dV/dt = I(d)/C

=> dV/dt = 1/2 = 0.5 MV/s

The rate of change of potential difference of the capacitor = 0.5 MV/s

Discussion

36.	All electrical circuits always contain the true or false
Answer» ANSWER: CONTAIN KE aage ka word LIKHO.....

36.

All electrical circuits always contain the true or false

Answer»

ANSWER:

CONTAIN KE aage ka word LIKHO.....

Discussion

37.	1. How is power related to voltage and current ?2. What is purely resistive electric current ?3. Verify Ohm's law.
Answer» 1.Power is a FUNCTION of voltage times the VOLUME of electrons(current). Power is the ability to do work.and is measured in watts.The higher the voltage the more power you have with the same current (watts(power) =Volts ×Amps 2.Given above 3.Law stating that electric current is proportional to voltage and INVERSELY proportional to resistance. HOPE this is HELPFUL to u dear mate

37.

1. How is power related to voltage and current ?2. What is purely resistive electric current ?3. Verify Ohm's law.

Answer»

1.Power is a FUNCTION of voltage times the VOLUME of electrons(current). Power is the ability to do work.and is measured in watts.The higher the voltage the more power you have with the same current (watts(power) =Volts ×Amps

2.Given above

3.Law stating that electric current is proportional to voltage and INVERSELY proportional to resistance.

HOPE this is HELPFUL to u dear mate

Discussion

38.	All electrical circuits always contain at least one dry cell
Answer» ANSWER: BHAI QUESTION NHI AYA samj me

38.

All electrical circuits always contain at least one dry cell

Answer»

ANSWER:

BHAI QUESTION NHI AYA samj me

Discussion

39.	Is heat resistance objects has specific heat
Answer» ANSWER: YES resistance OBJECT has specific HEAT

39.

Is heat resistance objects has specific heat

Answer»

ANSWER:

YES resistance OBJECT has specific HEAT

Discussion

40.	Fibre is 12x10-'Nm/degree. Calculate the deflectieproduced31. Derive an expression for magnitude of magnetic dipole momenof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momenassociated with the coil.
Answer» ANSWER: if go bc go bc go b hi I'll do if can LOOK if go bc okkkkkkkkkkkkkkkkkkkkkkkkkkkk kkkkkkkokkkkkkkkk

40.

Fibre is 12x10-'Nm/degree. Calculate the deflectieproduced31. Derive an expression for magnitude of magnetic dipole momenof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momenassociated with the coil.

Answer»

ANSWER:

if go bc go bc go b hi I'll do if can LOOK if go bc okkkkkkkkkkkkkkkkkkkkkkkkkkkk kkkkkkkokkkkkkkkk

Discussion

41.	1) Two blocks of mass 1kg and 2kg are connected by an in extensiblestring which passes over a frictionless pulley as shown in figure.calculate the acceleration of these blocks.
Answer» Let the acceleration a ACT towards right so that the block of MASS 2 kg goes down and that of 1 kg mass goes up ALONG the plane DUE to this. From the FBD of the block of mass 1 kg, T - 5√3 = a → (1) And from the FBD of the block of mass 2 kg, 10 - T = 2a → (2) Now, adding (1) and (2), 10 - 5√3 = 3a a = [5(2 - √3) / 3] m s^(-2) a = 0.447 m s^(-2)

41.

1) Two blocks of mass 1kg and 2kg are connected by an in extensiblestring which passes over a frictionless pulley as shown in figure.calculate the acceleration of these blocks.

Answer»

Let the acceleration a ACT towards right so that the block of MASS 2 kg goes down and that of 1 kg mass goes up ALONG the plane DUE to this.

From the FBD of the block of mass 1 kg,

T - 5√3 = a → (1)

And from the FBD of the block of mass 2 kg,

10 - T = 2a → (2)

Now, adding (1) and (2),

10 - 5√3 = 3a

a = [5(2 - √3) / 3] m s^(-2)

a = 0.447 m s^(-2)

Discussion

42.	1 nanosecond = ? seconds
Answer» Answer: 0.01 seconds ............... Explanation: HOPE you find it helpful pls mark as brainliest thank u for giving me a OPPORTUNITY to answer this QUESTION.......

42.

1 nanosecond = ? seconds

Answer»

Answer:

0.01 seconds ...............

Explanation:

HOPE you find it helpful

pls mark as brainliest

thank u for giving me a OPPORTUNITY to answer this QUESTION.......

Discussion

43.	What is Raman effect ?
Answer» $\huge{\orange{\boxed{\boxed{\pink{\underline{\green{\mathscr{Hey, Mate}}}}}}}}}}$ $\huge{\blue{\underline{\purple{\mathbb{AnSwER}}}}}}[/text]Raman scattering or the Raman effect is the inelastic scattering of photons by matter, meaning that there is an exchange of energy and a change in the light's direction. Typically this involves vibrational energy being gained by a molecule as incident photons from a visible laser are shifted to lower energy.Hope it helps uh.........Mark me as brainlist.......[tex]\huge\underline\mathfrak\red{AK}$

43.

What is Raman effect ?

Answer»

$\huge{\orange{\boxed{\boxed{\pink{\underline{\green{\mathscr{Hey, Mate}}}}}}}}}}$

$\huge{\blue{\underline{\purple{\mathbb{AnSwER}}}}}}[/text]Raman scattering or the Raman effect is the inelastic scattering of photons by matter, meaning that there is an exchange of energy and a change in the light's direction. Typically this involves vibrational energy being gained by a molecule as incident photons from a visible laser are shifted to lower energy.Hope it helps uh.........Mark me as brainlist.......[tex]\huge\underline\mathfrak\red{AK}$

Discussion

44.	An athlete completes I ground of a circular track of diameter 200 min 40 sec. What will be the;distance, displacement & at the end of 20 min 20 sec
Answer» Answer: Explanation: The diameter of the circular track is GIVEN as 200 m. That is, 2r=200 m. From this radius is CALCULATED as Radius, r = 100 m. In 40 SEC the ATHLETE complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds. One round is considered as the circumference of the circular track. The distance COVERED in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m. For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero. At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

44.

An athlete completes I ground of a circular track of diameter 200 min 40 sec. What will be the;distance, displacement & at the end of 20 min 20 sec

Answer»

Answer:

Explanation:

The diameter of the circular track is GIVEN as 200 m. That is, 2r=200 m.

From this radius is CALCULATED as Radius, r = 100 m.

In 40 SEC the ATHLETE complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.

One round is considered as the circumference of the circular track.

The distance COVERED in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.

For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Discussion

45.	Which energy transformation occurs during magnetic effect of current ?
Answer» Explanation: When a wire with a current is PLACED in a magnetic field, electrical ENERGY is transformed into mechanical energy. PLZ MARK BRAINLIST MARK

45.

Which energy transformation occurs during magnetic effect of current ?

Answer»

Explanation:

When a wire with a current is PLACED in a magnetic field, electrical ENERGY is transformed into mechanical energy.

PLZ MARK BRAINLIST MARK

Discussion

46.	Difference between fuel and source of energy ⚡
Answer» Explanation: A (CONVENTIONAL) 'fuel' has stored energy which is RELEASED in the form of heat when the fuel burns; that is, the exothermic REACTION known as 'combustion' takes place. But electrical energy, solar energy, wind energy, hydraulic POWER . et cetera .are sources of energy which are not fuels. ꧁☆Mᴀʀᴋ ᴀs Bʀᴀɪɴʟɪsᴛ☆꧂

46.

Difference between fuel and source of energy ⚡

Answer»

Explanation:

A (CONVENTIONAL) 'fuel' has stored energy which is RELEASED in the form of heat when the fuel burns; that is, the exothermic REACTION known as 'combustion' takes place. But electrical energy, solar energy, wind energy, hydraulic POWER . et cetera .are sources of energy which are not fuels.

꧁☆Mᴀʀᴋ ᴀs Bʀᴀɪɴʟɪsᴛ☆꧂

Discussion

47.	Practice Problems 5:1. A solid of mass 150 g at 200°C is placed in 0.4 kg of water at 20°C till a constant temperatureis attained. If the S.H.C. of the solid is 0.5 J/g K, find the resulting temperature of themixture
Answer» Answer: 27.7°C APPROX ms∆T = MS∆T m = 150g s = 0.5/4.2 ∆T= 200-T M - 400gram S - 1 ∆T - T -20 Thanks for READING

47.

Practice Problems 5:1. A solid of mass 150 g at 200°C is placed in 0.4 kg of water at 20°C till a constant temperatureis attained. If the S.H.C. of the solid is 0.5 J/g K, find the resulting temperature of themixture

Answer»

Answer:

27.7°C APPROX

ms∆T = MS∆T

m = 150g

s = 0.5/4.2

∆T= 200-T

M - 400gram

S - 1

∆T - T -20

Thanks for READING

Discussion

48.	2) Observe the image 'A' and 'B' and answer the following questions:Ά''B'1) Which disasters are shown in the images ?(1)2) Which primary precautions will you take incase ofdisaster shown in 'A'?(2)3) Which type of first aid is offered to the injured people in disaster 'B'? (2)
Answer» ANSWER: a. hiiiiiiiiiiiiiiiiiiiiiiiiiiiii

48.

2) Observe the image 'A' and 'B' and answer the following questions:Ά''B'1) Which disasters are shown in the images ?(1)2) Which primary precautions will you take incase ofdisaster shown in 'A'?(2)3) Which type of first aid is offered to the injured people in disaster 'B'? (2)

Answer»

ANSWER:

a. hiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Discussion

49.	A train is starting from a railwaystation contains a velocity of 30 m/s in I min . Find the acceleration
Answer» ANSWER: acceleration=velocity/time a=30/60=0.5m/s^

49.

A train is starting from a railwaystation contains a velocity of 30 m/s in I min . Find the acceleration

Answer»

ANSWER:

acceleration=velocity/time

a=30/60=0.5m/s^

Discussion

50.	The radius of the Earth is 6400 km. What is its mass?
Answer» Answer: 10 times the MASS of mars.weighs 200 N on the SURFACE of EARTH

50.

The radius of the Earth is 6400 km. What is its mass?

Answer»

Answer:

10 times the MASS of mars.weighs 200 N on the SURFACE of EARTH

Discussion

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