67486 + Interview Questions in Secondary School in Physics

1.	Pls solve it with explanation explanation explanation third part
Answer» Answer: this ques will be ANSWERED by any ONE else Explanation: oktfouhvb Explanatiohipó[ pn: OK

1.

Pls solve it with explanation explanation explanation third part

Answer»

Answer:

this ques will be ANSWERED by any ONE else

Explanation:

oktfouhvb

Explanatiohipó[

pn:

OK

Discussion

2.	A stone is thrown vertically upward with a velocity of 5 m/s from a wall of height 5m. what will be the total distance travelled by stone before hitting the ground ?
Answer» ANSWER - ☞Given - u = 5m/s s = 5m a = g = -10 m/s² where $\longrightarrow$ u is initial velocity. $\longrightarrow$ s is HEIGHT of wall. $\longrightarrow$ a is acceleration due to GRAVITY. ━━━━━━━━━━━━━ ☞To find - Total distance ━━━━━━━━━━━━━ ☞Solution - Maximum height attained by stone - u = 5m/s V = 0 a = g = -10 m/s² where $\longrightarrow$ u is initial velocity. $\longrightarrow$ v is final velocity. $\longrightarrow$ a is acceleration due to gravity. By 3rd equation of motion of - $\sf v² = u² + 2as$ $\sf 0 = 5² - 2 × 10 × s$ $\sf 20s = 25$ $\sf s = 1.25m$ ━━━━━━━━━━━━━ Maximum height attained by stone is 1.25 m above the wall of 5m Distance from ground to max. height $\implies$ 1.25 + 5 $\implies$ 6.25 m ━━━━━━━━━━━━━ After REACHING the maximum height the stone will come to ground and will cover the same distance from ground to max. height. Distance from max. height to ground = 6.25m ━━━━━━━━━━━━━ $\longrightarrow$ Total distance = Distance from ground to max. height + Distance from max. height to ground Total distance = 6.25 + 6.25 Total distance covered by stone = 12.5 m ━━━━━━━━━━━━━ Thanks

2.

A stone is thrown vertically upward with a velocity of 5 m/s from a wall of height 5m. what will be the total distance travelled by stone before hitting the ground ?

Answer»

ANSWER -

☞Given -

u = 5m/s

s = 5m

a = g = -10 m/s²

where

$\longrightarrow$ u is initial velocity.

$\longrightarrow$ s is HEIGHT of wall.

$\longrightarrow$ a is acceleration due to GRAVITY.

━━━━━━━━━━━━━

☞To find -

Total distance

━━━━━━━━━━━━━

☞Solution -

Maximum height attained by stone -

u = 5m/s

V = 0

a = g = -10 m/s²

where

$\longrightarrow$ u is initial velocity.

$\longrightarrow$ v is final velocity.

$\longrightarrow$ a is acceleration due to gravity.

By 3rd equation of motion of -

$\sf v² = u² + 2as$

$\sf 0 = 5² - 2 × 10 × s$

$\sf 20s = 25$

$\sf s = 1.25m$

━━━━━━━━━━━━━

Maximum height attained by stone is 1.25 m above the wall of 5m

Distance from ground to max. height

$\implies$ 1.25 + 5

$\implies$ 6.25 m

━━━━━━━━━━━━━

After REACHING the maximum height the stone will come to ground and will cover the same distance from ground to max. height.

Distance from max. height to ground = 6.25m

━━━━━━━━━━━━━

$\longrightarrow$ Total distance = Distance from ground to max. height + Distance from max. height to ground

Total distance = 6.25 + 6.25

Total distance covered by stone = 12.5 m

━━━━━━━━━━━━━

Thanks

Discussion

3.	What do you understand by physical change ? given example
Answer» Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. ... In GENERAL a physical CHANGE is reversible using physical MEANS. For example, salt dissolved in WATER can be RECOVERED by allowing the water to evaporate.

3.

What do you understand by physical change ? given example

Answer»

Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. ... In GENERAL a physical CHANGE is reversible using physical MEANS. For example, salt dissolved in WATER can be RECOVERED by allowing the water to evaporate.

Discussion

4.	Please solve this question...I will report all wrong answers. So, answer only if you know....
Answer» pie/3 = $\huge \frac{\pi}{3}$ ..........HOPE it HELP you..........

4.

Please solve this question...I will report all wrong answers. So, answer only if you know....

Answer»

pie/3 =

$\huge \frac{\pi}{3}$

..........HOPE it HELP you..........

Discussion

5.	The ratio of current to current density has a unit of
Answer» ANSWER: *The SI unit of current is the ampère [A]. An ampère is a coulomb per second. The ampère is one of the seven BASE units of the International SYSTEM of Units.* *The SI unit of current is the ampère [A]. An ampère is a coulomb per second. The ampère is one of the seven base units of the International System of Units....* *hope* it *HELPS* *you*

5.

The ratio of current to current density has a unit of

Answer»

ANSWER:

The SI unit of current is the ampère [A]. An ampère is a coulomb per second. The ampère is one of the seven BASE units of the International SYSTEM of Units.

The SI unit of current is the ampère [A]. An ampère is a coulomb per second. The ampère is one of the seven base units of the International System of Units....

hope it HELPS you

Discussion

6.	Please help memmmmm
Answer» Answer: the required answer is 100 m/s <U>GIVEN: acceleration, a= 10 m/s^2 time , t= 10 s TO FIND: velocity, v THREE EQUATIONS OF MOTION: FIRST EQUATION: V = u + at SECOND EQUATION: s = ut + (1/2)at^2 THIRD EQUATION: V^2 - v^2 =2as KEYS: v.......FINAL velocity u...... initial velocity a..... acceleration t........time s...... displacement SOLUTION: since there is no information available regarding intial velocity, consider the initial velocity u = 0 apply first equation of motion, $v = u + at \\ \\ v = 0 + (10)(10) \\ \\ v = 0 + 100 \\ \\ v = 100 \: m /s$ the INCREASED velocity is 100 m/s. ADDITIONAL: in vertical motion ,the acceleration due to gravity comes into play. in the three equations of motion , acceleration of the BODY will be replaced by acceleration due to gravity, g

6.

Please help memmmmm

Answer»

Answer:

the required answer is 100 m/s

<U>GIVEN:

acceleration, a= 10 m/s^2
time , t= 10 s

TO FIND:

velocity, v

THREE EQUATIONS OF MOTION:

FIRST EQUATION:

V = u + at

SECOND EQUATION:

s = ut + (1/2)at^2

THIRD EQUATION:

V^2 - v^2 =2as

KEYS:

v.......FINAL velocity
u...... initial velocity
a..... acceleration
t........time
s...... displacement

SOLUTION:

since there is no information available regarding intial velocity, consider the initial velocity u = 0

apply first equation of motion,

$v = u + at \\ \\ v = 0 + (10)(10) \\ \\ v = 0 + 100 \\ \\ v = 100 \: m /s$

the INCREASED velocity is 100 m/s.

ADDITIONAL:

in vertical motion ,the acceleration due to gravity comes into play.

in the three equations of motion , acceleration of the BODY will be replaced by acceleration due to gravity, g

Discussion

7.	Abhishek buy few grams of gold at poles as per the instruction of his friendAlok. He hands over the same when he meets him at eqator. But, when Alok weighs the gold, he finds it less in weight.a) Why does Alok finds the weight of gold less?b) Does Abhishek steal some gold?c) What value is possessed/violated by Abhishek
Answer» Answer: the main REASON is the GRAVITATIONAL FORCE because weight varies from place to place due to gravitation.

7.

Abhishek buy few grams of gold at poles as per the instruction of his friendAlok. He hands over the same when he meets him at eqator. But, when Alok weighs the gold, he finds it less in weight.a) Why does Alok finds the weight of gold less?b) Does Abhishek steal some gold?c) What value is possessed/violated by Abhishek

Answer»

Answer:

the main REASON is the GRAVITATIONAL FORCE because weight varies from place to place due to gravitation.

Discussion

8.	A car travels distance with speed 30 km/h and returns back with a speed 20 km/h. what will be the average speed
Answer» Answer: Please LET me KNOW the TIME in the QUESTION

8.

A car travels distance with speed 30 km/h and returns back with a speed 20 km/h. what will be the average speed

Answer»

Answer:

Please LET me KNOW the TIME in the QUESTION

Discussion

9.	The period of vibration T of a tuning fork depends on THE lengthL of its prong density d and young modules y of its material by the relation T=KL^ad^bY^c where K is dimensionless constant. Find a,bandc
Answer» SORRY I ALSO don't KNOW

9.

The period of vibration T of a tuning fork depends on THE lengthL of its prong density d and young modules y of its material by the relation T=KL^ad^bY^c where K is dimensionless constant. Find a,bandc

Answer»

SORRY I ALSO don't KNOW

Discussion

10.	What is meaning ofVelocity Acceleration Initial position AndThere SI unit
Answer» VELOCITY is a vector quantity that refers to the rate at which an object changes its position. It is a vector expression of the displacement that an object or particle undergoes with RESPECT to time. The SI unit of velocity is meter/second. In physics or physical science, acceleration (symbol: a) is defined as the rate of change (or derivative with respect to time) of velocity. It is thus a vector quantity with DIMENSION length/time². In SI units, acceleration is measured in meters/second² using an accelerometer. When an object moves ALONG a straight line, its starting position can be defined as the origin, O. ... This change in position is a distance. The SI unit of displacement and distance measurements is the meter (m).

10.

What is meaning ofVelocity Acceleration Initial position AndThere SI unit

Answer»

VELOCITY is a vector quantity that refers to the rate at which an object changes its position. It is a vector expression of the displacement that an object or particle undergoes with RESPECT to time. The SI unit of velocity is meter/second.

In physics or physical science, acceleration (symbol: a) is defined as the rate of change (or derivative with respect to time) of velocity. It is thus a vector quantity with DIMENSION length/time². In SI units, acceleration is measured in meters/second² using an accelerometer.

When an object moves ALONG a straight line, its starting position can be defined as the origin, O. ... This change in position is a distance. The SI unit of displacement and distance measurements is the meter (m).

Discussion

11.	The rate of change of momentum of a body is 4kg-m/s².force experience by body is
Answer» Answer: 4N Explanation: RATE of CHANGE of MOMENTUM is FORCE

11.

The rate of change of momentum of a body is 4kg-m/s².force experience by body is

Answer»

Answer:

4N

Explanation:

RATE of CHANGE of MOMENTUM is FORCE

Discussion

12.	Q4. Momentum of a body increases from 20kgm/s to 40kgm/s in 5 seconds, then the forceapplied isA) 4 Nb)-4 Nc)12 Nd)-12 Nguys plzz ans me...
Answer» Answer Force is defined as CHANGE in MOMENTUM PER change in time $\rm :\to F=\dfrac{\Delta P}{\Delta t}\\\\\rm :\to F=\dfrac{40-20}{5}\\\\\rm :\to F=\dfrac{20}{5}\\\\:\to \rm F=4\ N$ So , option A is correct

12.

Q4. Momentum of a body increases from 20kgm/s to 40kgm/s in 5 seconds, then the forceapplied isA) 4 Nb)-4 Nc)12 Nd)-12 Nguys plzz ans me...

Answer»

Answer

Force is defined as CHANGE in MOMENTUM PER change in time

$\rm :\to F=\dfrac{\Delta P}{\Delta t}\\\\\rm :\to F=\dfrac{40-20}{5}\\\\\rm :\to F=\dfrac{20}{5}\\\\:\to \rm F=4\ N$

So , option A is correct

Discussion

13.	A body exerts a force of 50 N on an 5 metre surface. Calculate the pressure exerted
Answer» ANSWER: 10 PASCAL is the CORRECT answer as PRESSURE = force/area

13.

A body exerts a force of 50 N on an 5 metre surface. Calculate the pressure exerted

Answer»

ANSWER:

10 PASCAL is the CORRECT answer as PRESSURE = force/area

Discussion

14.	Kin Karan se vibhinn vastvik gas Apne Aadarsh aacharan vyavhar se hat Jaate Hain
Answer» Answer: i can't UNDERSTAND PLEASE mark as BRAINLIST answer

14.

Kin Karan se vibhinn vastvik gas Apne Aadarsh aacharan vyavhar se hat Jaate Hain

Answer»

Answer:

i can't UNDERSTAND

PLEASE mark as BRAINLIST answer

Discussion

15.	Device that convert chemical energy into mechanical energy?
Answer» ANSWER: INTERNAL COMBUSTION engine Explanation:

15.

Device that convert chemical energy into mechanical energy?

Answer»

ANSWER:

INTERNAL COMBUSTION engine

Explanation:

Discussion

16.	Hey guys what is electric current ? Give its unit wiyh definition?
Answer» Answer: Electric current is DEFINED as the RATE of flow of electric charge. Or, electric current is the amount of charge FLOWING through a PARTICULAR area in unit time and is given by: I = Q / t. The S.I unit of electric current is Ampere (A). Explanation: hope it helps u!

16.

Hey guys what is electric current ? Give its unit wiyh definition?

Answer»

Answer:

Electric current is DEFINED as the RATE of flow of electric charge. Or, electric current is the amount of charge FLOWING through a PARTICULAR area in unit time and is given by: I = Q / t. The S.I unit of electric current is Ampere (A).

Explanation:

hope it helps u!

Discussion

17.	Direction of motion is not given by the direction of ......displacementvelocityaccelerationmomentum
Answer» ANSWER: momentum Explanation: HOPE this will HELP you

17.

Direction of motion is not given by the direction of ......displacementvelocityaccelerationmomentum

Answer»

ANSWER:

momentum

Explanation:

HOPE this will HELP you

Discussion

18.	When designing an electric circuit ,we should consider whether a series or a parallelcircuit is better for the intended use. If we want to connect a large number of electric bulbs for decorating buildings or trees ,then the series circuit is better.i) Why series circuit is safer?ii)What kind of problem do electricians face here?iii)What values would you add with reference to this context?
Answer» Answer: 1) if we want to connect a large number of electric BULBS for decorating buildings and trees as during festivals such as Diwali or marriage function, then the series CIRCUIT is BETTER because all bulbs connected in series can be controlled with just one switch. A series circuit is also safer because the current in it smaller. 2) there is a problem with this circuit which the electricians face. This is because if one bulb gets fused, then the circuit breaks and all the bulbs are turned off. An electrician has to spend a lot of time in LOCATING the fused bulb form among hundreds bulbs, so as to replace it and restore the lighting. hope it helps :)

18.

When designing an electric circuit ,we should consider whether a series or a parallelcircuit is better for the intended use. If we want to connect a large number of electric bulbs for decorating buildings or trees ,then the series circuit is better.i) Why series circuit is safer?ii)What kind of problem do electricians face here?iii)What values would you add with reference to this context?

Answer»

Answer:

1) if we want to connect a large number of electric BULBS for decorating buildings and trees as during festivals such as Diwali or marriage function, then the series CIRCUIT is BETTER because all bulbs connected in series can be controlled with just one switch. A series circuit is also safer because the current in it smaller.

2) there is a problem with this circuit which the electricians face. This is because if one bulb gets fused, then the circuit breaks and all the bulbs are turned off. An electrician has to spend a lot of time in LOCATING the fused bulb form among hundreds bulbs, so as to replace it and restore the lighting.

hope it helps :)

Discussion

19.	two resistors of resistance300 and 600ohm at 0°C having thermal coefficient of resistance alpha and 3alpha resp. if they are connected in parallel , then equivalent thermal coefficient of resistance is
Answer» Answer: The thermal COEFFICIENT of RESISTANCE is ⇒α= R 1 dt dR Equivalent resistance in series= R 1 +R 2 =R eq. dt dR eq. = dt dR 1 + dt dR 2 α eq. R eq. =α 1 R 1 +α 2 R 2 α eq. = R 1 +R 2 α 1 R 1 +α 2 R 2 Explanation:

19.

two resistors of resistance300 and 600ohm at 0°C having thermal coefficient of resistance alpha and 3alpha resp. if they are connected in parallel , then equivalent thermal coefficient of resistance is

Answer»

Answer:

The thermal COEFFICIENT of RESISTANCE is ⇒α=

R

1

dt

dR

Equivalent resistance in series= R

1

+R

2

=R

eq.

dt

dR

eq.

=

dt

dR

1

+

dt

dR

2

α

eq.

R

eq.

=α

1

R

1

+α

2

R

2

α

eq.

=

R

1

+R

2

α

1

R

1

+α

2

R

2

Explanation:

Discussion

20.	Iii) Derive the conditions for maxima and minima produced due to diffraction by a singleslit.
Answer» Answer: drive is DRIVING myself singn Al woh not TRAFFIC.

20.

Iii) Derive the conditions for maxima and minima produced due to diffraction by a singleslit.

Answer»

Answer:

drive is DRIVING myself singn Al woh not TRAFFIC.

Discussion

21.	Please help with the solution
Answer» ANSWER: answer isa+b is 2C is the answer

21.

Please help with the solution

Answer»

ANSWER:

answer isa+b is 2C is the answer

Discussion

22.	Why does crumpled paper ball go further explain using concept of fluid friction
Answer» EXPLANATION: it is not necessary that the stationary object will move always when a FORCE is applied if there is FRICTION force between the object and the ground the the friction FLUID will be oppose the motion of the object hence the stationary object will move only if the applied force is GREATER than the friction force between the object and the ground

22.

Why does crumpled paper ball go further explain using concept of fluid friction

Answer»

EXPLANATION:

it is not necessary that the stationary object will move always when a FORCE is applied if there is FRICTION force between the object and the ground the the friction FLUID will be oppose the motion of the object hence the stationary object will move only if the applied force is GREATER than the friction force between the object and the ground

Discussion

23.	Speed of light in mm per second
Answer» Answer: 3 *10TO POWER 10 MM PER second

23.

Speed of light in mm per second

Answer»

Answer:

3 *10TO POWER 10 MM PER second

Discussion

24.	10) The displacement-time graph of a body is shown below. From the graph find the (i) displacement of the body at the time 2s, 4s and 5s (ii) velocity of the body.
Answer» Answer: i) DISPLACEMENT at 2seconds= 4 m ii)displacement at 4 seconds= 16 m iii)displacement at 5 seconds= 25 m The velocity of the body at the END. = Distance/Time =25/5 =5m/s

24.

10) The displacement-time graph of a body is shown below. From the graph find the (i) displacement of the body at the time 2s, 4s and 5s (ii) velocity of the body.

Answer»

Answer:

i) DISPLACEMENT at 2seconds= 4 m

ii)displacement at 4 seconds= 16 m

iii)displacement at 5 seconds= 25 m

The velocity of the body at the END. = Distance/Time

=25/5

=5m/s

Discussion

25.	if you place an electric dipole in a uniform electric field,when will the torque become maximum and minimum
Answer» Answer: Hope it helps you... EXPLANATION: TORQUE is maximum when dipole is held PERPENDICULAR to the field. (theta=90°) Torque is MINIMUM when dipole is held parallel to the field. (theta=0°) Please mark as brainliest if it really helps you...❤❤❤

25.

if you place an electric dipole in a uniform electric field,when will the torque become maximum and minimum

Answer»

Answer:

Hope it helps you...

EXPLANATION:

TORQUE is maximum when dipole is held PERPENDICULAR to the field. (theta=90°)

Torque is MINIMUM when dipole is held parallel to the field. (theta=0°)

Please mark as brainliest if it really helps you...❤❤❤

Discussion

26.	Story of loin and a clever ..rabbit
Answer» Explanation: Panchatantra Story: The Foolish Lion and The Clever RABBIT. Once upon a time, in a forest, there lived a GREEDY lion. All the other animals were scared of him, because he hunted EVERYDAY and killed the animals in large numbers even when he was not hungry. They knew that soon, none of them WOULD be left alive. Hope it HELPS you Mark me as Brainlist

26.

Story of loin and a clever ..rabbit

Answer»

Explanation:

Panchatantra Story: The Foolish Lion and The Clever RABBIT. Once upon a time, in a forest, there lived a GREEDY lion. All the other animals were scared of him, because he hunted EVERYDAY and killed the animals in large numbers even when he was not hungry. They knew that soon, none of them WOULD be left alive.

Hope it HELPS you

Mark me as Brainlist

Discussion

27.	Please answer this 5 questions friends....Help me out with this....
Answer» 1Q B)MGS 2Q c) sodium phosphate 4Q mass ALWAYS contain 5Q b) sodium nitrate-----sodium nitrate + OXYGEN

Discussion

28.	What is the maximum value of force f such that the block shown in the arrangement didn't move
Answer» ANSWER: IMAGE is not CLEAR.......

28.

What is the maximum value of force f such that the block shown in the arrangement didn't move

Answer»

ANSWER:

IMAGE is not CLEAR.......

Discussion

29.	11. A solid of density 3000 kgm-3 and of volume 0.002 m3 is completely immersed in of density 800 kgm i. Weight of the solid in SI system [1] ii. Upthrust on solid in SI system [1] iii. Apparent weight of solid in alcohol [1] iv. Will the apparent weight of the solid be le
Answer» ANSWER: the answer is U SUCK EXPLANATION: explanation is u suck EVEN more

29.

11. A solid of density 3000 kgm-3 and of volume 0.002 m3 is completely immersed in of density 800 kgm i. Weight of the solid in SI system [1] ii. Upthrust on solid in SI system [1] iii. Apparent weight of solid in alcohol [1] iv. Will the apparent weight of the solid be le

Answer»

ANSWER:

the answer is U SUCK

EXPLANATION:

explanation is u suck EVEN more

Discussion

30.	plzz ans these my test is tomorrow 8 solve it and send all the three initial and final momentum and magnitude
Answer» <P>Answer: $p_{1}$ =250 kgm/s , $p_{2}$ =400 kgm/s , F=10N Explanation: for initial momentum: p=M×u mass of object (M)= 50 kg initial velocity (u) = 5 m/s momentum (p) = 50× 5 =250 kgm/s for FINAL momentum: p=M× v mass of object (M) = 50 kg final velocity (u) = 8 m/s momentum (p) = 50×8= 400 kgm/s For force: F=M× a mass (M)= 50 kg Acceleration (a)=(v-u)/t a = (8-5)/6 a= 0.5 m/s² force= 50 × 0.5 N F= 10N

30.

plzz ans these my test is tomorrow 8 solve it and send all the three initial and final momentum and magnitude

Answer»

<P>Answer:

$p_{1}$ =250 kgm/s , $p_{2}$ =400 kgm/s , F=10N

Explanation:

for initial momentum: p=M×u

mass of object (M)= 50 kg

initial velocity (u) = 5 m/s

momentum (p) = 50× 5 =250 kgm/s

for FINAL momentum: p=M× v

mass of object (M) = 50 kg

final velocity (u) = 8 m/s

momentum (p) = 50×8= 400 kgm/s

For force: F=M× a

mass (M)= 50 kg

Acceleration (a)=(v-u)/t

a = (8-5)/6

a= 0.5 m/s²

force= 50 × 0.5 N

F= 10N

Discussion

31.	A vehicle of mass 10kg is moving with a velocity of 2ms . Find the magnitude of theforce that is to be applied on the vehicle so that the vehicle have a velocity of 1msafter traveling a distance of 10m.
Answer» A vehicle of MASS 10kg is moving with a VELOCITY of 2MS . FIND the magnitude of the force that is to be applied on the vehicle so that the vehicle have a velocity of 1ms after TRAVELING a distance of 10m.

31.

A vehicle of mass 10kg is moving with a velocity of 2ms . Find the magnitude of theforce that is to be applied on the vehicle so that the vehicle have a velocity of 1msafter traveling a distance of 10m.

Answer»

A vehicle of MASS 10kg is moving with a VELOCITY of 2MS . FIND the magnitude of the

force that is to be applied on the vehicle so that the vehicle have a velocity of 1ms

after TRAVELING a distance of 10m.

Discussion

32.	The motion described by a freely failing stone is.......
Answer» ANSWER: UNIFORMLY ACCELERATED motion Explanation:

32.

The motion described by a freely failing stone is.......

Answer»

ANSWER:

UNIFORMLY ACCELERATED motion

Explanation:

Discussion

33.	Unit of relative densitykg/m3 g/m31/m3no unit
Answer» Answer: relative DENSITY has no units Explanation:because relative WORD means in copmparison with something so relative density = density of a SUBSTANCE/density of any other substance so, their units will cancel out . HOPE IT HELPS YOU!!!

33.

Unit of relative densitykg/m3 g/m31/m3no unit

Answer»

Answer:

relative DENSITY has no units

Explanation:because relative WORD means in copmparison with something so relative density = density of a SUBSTANCE/density of any other substance

so, their units will cancel out .

HOPE IT HELPS YOU!!!

Discussion

34.	The acceleration produced by a force of 5N acting on the mass of 20 kg in m/s square is
Answer» Answer: 0.25 m/s2 Explanation: f=ma 5=20 X a a=0.25

34.

The acceleration produced by a force of 5N acting on the mass of 20 kg in m/s square is

Answer»

Answer:

0.25 m/s2

Explanation:

f=ma

5=20 X a

a=0.25

Discussion

35.	If we suddenly moveout a piece of paper from under a heavy book , the book will not move why
Answer» ANSWER: DUE to inertia of rest the BOOK 10th to be a track and we have applied for only on that paper so it will MOVE the book will not due to inertia of rest

35.

If we suddenly moveout a piece of paper from under a heavy book , the book will not move why

Answer»

ANSWER:

DUE to inertia of rest the BOOK 10th to be a track and we have applied for only on that paper so it will MOVE the book will not due to inertia of rest

Discussion

36.	He unit of plane angle is radian, hence its dimensions areImmersive Reader(2 Points)
Answer» EXPLANATION: ggfywshhehehhwhhdvajishgdvge

36.

He unit of plane angle is radian, hence its dimensions areImmersive Reader(2 Points)

Answer»

EXPLANATION:

ggfywshhehehhwhhdvajishgdvge

Discussion

37.	Find The Odd One Out .... 1. Kelvin 2 Newton 3. Fahrenheit 4. Celsius
Answer» Answer: 2. NEWTON..............

37.

Find The Odd One Out .... 1. Kelvin 2 Newton 3. Fahrenheit 4. Celsius

Answer»

Answer:

2. NEWTON..............

Discussion

38.	How to find acceleration
Answer» Answer: CALCULATING acceleration INVOLVES dividing velocity by TIME — or in terms of SI units, dividing the METER per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

38.

How to find acceleration

Answer»

Answer:

CALCULATING acceleration INVOLVES dividing velocity by TIME — or in terms of SI units, dividing the METER per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

Discussion

39.	Write the value of ‘G’ with proper unit.pls answer fast
Answer» ANSWER: G=6.67×10-11Nm2/kg

39.

Write the value of ‘G’ with proper unit.pls answer fast

Answer»

ANSWER:

G=6.67×10*-11Nm*2/kg

Discussion

40.	Two persons A and B are walking with speed 4km/hr and 5km/hr respectively in the same direction . Find how far will B be from A after 2hrs
Answer» Answer: Relative VELOCITY of B w.r.t A Vba = Vb - Va = 5-4 = 1 therefore DISTANCE of b from a after two hrs will be, d= Vba X t = 1 x 2 = 2 km ans is 2 km hope it helps :)

40.

Two persons A and B are walking with speed 4km/hr and 5km/hr respectively in the same direction . Find how far will B be from A after 2hrs

Answer»

Answer:

Relative VELOCITY of B w.r.t A

Vba = Vb - Va

= 5-4

= 1

therefore DISTANCE of b from a after two hrs will be,

d= Vba X t

= 1 x 2

= 2 km

ans is 2 km

hope it helps :)

Discussion

41.	calculatevthe force of attraction between two charges +4 coulumb and -4 coulumb separate by 8×10 to the power 3 m
Answer» ANSWER: you can do this by using simple formula.. EXPLANATION: f=(K q1*Q2)/d.sq

41.

calculatevthe force of attraction between two charges +4 coulumb and -4 coulumb separate by 8×10 to the power 3 m

Answer»

ANSWER:

you can do this by using simple formula..

EXPLANATION:

f=(K q1*Q2)/d.sq

Discussion

42.	starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6m/s in 30 s.then the applies brakes such that the velocity of the bicycles comes down to 4m/s in the next 5 s. calculate the acceleratiothe on of the bicycle in both cases. plz someone give me its ans step by step fast............it's urgent
Answer» ANSWER: Here is your answer!! FORMULA for ACCELERATION= v-u/t

42.

starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6m/s in 30 s.then the applies brakes such that the velocity of the bicycles comes down to 4m/s in the next 5 s. calculate the acceleratiothe on of the bicycle in both cases. plz someone give me its ans step by step fast............it's urgent

Answer»

ANSWER:

Here is your answer!!

FORMULA for ACCELERATION= v-u/t

Discussion

43.	How many electrons should be added into a body to make it by 5 nanogram.Mass of one electron is 9.1 ×10^-31?
Answer» Answer: 1.25×20^19 Similarly use the formula q=ne for B and c where q= CHARGE, N= no of ELECTRONS e= charge PRESENT on an electron Explanation:

43.

How many electrons should be added into a body to make it by 5 nanogram.Mass of one electron is 9.1 ×10^-31?

Answer»

Answer:

1.25×20^19

Similarly use the formula q=ne for B and c where q= CHARGE, N= no of ELECTRONS e= charge PRESENT on an electron

Explanation:

Discussion

44.	Q.24. What is negativeacceleration?
Answer» Answer: When the velocity of an object decreases with time, it has NEGATIVE acceleration. Explanation: HOPE it HELPS

44.

Q.24. What is negativeacceleration?

Answer»

Answer:

When the velocity of an object decreases with time, it has NEGATIVE acceleration.

Explanation:

HOPE it HELPS

Discussion

45.	Intantaneous speed i shown in______ meter
Answer» SPEEDOMETER Hope helps hope U and your family members are SAFE , HAPPY and healthy

45.

Intantaneous speed i shown in______ meter

Answer»

SPEEDOMETER

Hope helps

hope U and your family members are SAFE , HAPPY and healthy

Discussion

46.	Three resistors of 10,2 ft and 3 areconnected in parallel. The combinedresistance of the three resistors shouldbe
Answer» ANSWER: sister I need clarity in question anyhow on the BASIS of above I'm posting pic here follow me PLZ If U are a Telugu girl

46.

Three resistors of 10,2 ft and 3 areconnected in parallel. The combinedresistance of the three resistors shouldbe

Answer»

ANSWER:

sister I need clarity in question anyhow on the BASIS of above I'm posting pic here

follow me PLZ If U are a Telugu girl

Discussion

47.	Plzz ans these my test is tomorrow 8 solve it and send
Answer» ANSWER: 150 Explanation: if my answer was HELPFUL please please like ❤...... Give me a brainliest........ Please Follow me...... JOKE of the day..... Mother: "How was your FIRST Day in SCHOOL?" Son: "First Day? Means I have to go tommorow also!!" Hahaha..... Keep Smiling..... Have a Nice Day.....

47.

Plzz ans these my test is tomorrow 8 solve it and send

Answer»

ANSWER:

150

Explanation:

if my answer was HELPFUL please please like ❤......

Give me a brainliest........

Please Follow me......

JOKE of the day.....

Mother: "How was your FIRST Day in SCHOOL?"

Son: "First Day? Means I have to go tommorow also!!"

Hahaha.....

Keep Smiling.....

Have a Nice Day.....

Discussion

48.	How?Only IIT-JEE level.
Answer» ANSWER: I think so it is B one sorry if wrong becoz I am not of JEE I am of smaller standard just trying... Explanation: HOPE IT HELPS... PLZ MARK THE ANSWER AS BRAINLIEST AND PLZ FOLLOW ME... THANK YOU....

48.

How?Only IIT-JEE level.

Answer»

ANSWER:

I think so it is B one sorry if wrong becoz I am not of JEE I am of smaller standard just trying...

Explanation:

HOPE IT HELPS...

PLZ MARK THE ANSWER AS BRAINLIEST AND PLZ FOLLOW ME...

THANK YOU....

Discussion

49.	Plzz ans these my test is tomorrow 9
Answer» ANSWER: C ONE is CORRECT

49.

Plzz ans these my test is tomorrow 9

Answer»

ANSWER:

C ONE is CORRECT

Discussion

50.	A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m 10, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. It lands on the ground below the cliff 3.03.03, point, 0 seconds later. We can ignore air resistance.
Answer» Answer: can U please tell me the meaning of the QUESTION by POSTING it in a SORTED WAY

50.

A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m 10, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. It lands on the ground below the cliff 3.03.03, point, 0 seconds later. We can ignore air resistance.

Answer»

Answer:

can U please tell me the meaning of the QUESTION by POSTING it in a SORTED WAY

Discussion

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