67486 + Interview Questions in Secondary School in Physics

1.	45. Assertion - Uniform circular motion is also called accelerated motionReason - Direction of motion changes at every point. So velocity is not constanta) Both A and Rare true, and R is the correct explanation of Ab) Both A and Rare true, but Ris not a correct explanation of Ac) A is true but Ris falsed) A is false but R may be true / false
Answer» Answer: option C PLEASE MARK as brainliest and PLS FOLLOW me

1.

45. Assertion - Uniform circular motion is also called accelerated motionReason - Direction of motion changes at every point. So velocity is not constanta) Both A and Rare true, and R is the correct explanation of Ab) Both A and Rare true, but Ris not a correct explanation of Ac) A is true but Ris falsed) A is false but R may be true / false

Answer»

Answer:

option C

PLEASE MARK as brainliest and PLS FOLLOW me

Discussion

2.	The Cartesian equation y = 2x - 5x^2of a perpendicular object. If so, count the speed of its onset.
Answer» ANSWER: SORRY I HATE PHYSICS and I didn't UNDERSTAND physics

2.

The Cartesian equation y = 2x - 5x^2of a perpendicular object. If so, count the speed of its onset.

Answer»

ANSWER:

SORRY I HATE PHYSICS and I didn't UNDERSTAND physics

Discussion

3.	1.conduct an experiment to find the limiting force that can be borne by different strings.
Answer» temperature Explanation: FEVER fever CHECKING

3.

1.conduct an experiment to find the limiting force that can be borne by different strings.

Answer»

temperature

Explanation:

FEVER fever CHECKING

Discussion

4.	Find the value of 10000 dyne on system basesd on metre kilogram and minute as fundamental units
Answer» Explanation: IN THIS WAY WE CAN SOLVE THE PROBLEM FOR U MY FRIEND

4.

Find the value of 10000 dyne on system basesd on metre kilogram and minute as fundamental units

Answer»

Explanation:

IN THIS WAY WE CAN SOLVE THE PROBLEM FOR U MY FRIEND

Discussion

5.	Electric power is the product of ______and_______
Answer» Answer: voltage & current Explanation: POWER , P = V* I . . hope it help u..

5.

Electric power is the product of and_

Answer»

Answer:

voltage & current

Explanation:

POWER , P = V* I

.

hope it help u..

Discussion

6.	Describe the diagram of trough/ Valley
Answer» A valley is a low area between hills or mountains typically with a river RUNNING through it. In GEOLOGY, a valley or DALE is a depression that is longer than it is WIDE. The terms U-shaped and V-shaped are descriptive terms of GEOGRAPHY to characterize the form of valleys.

Discussion

7.	Write down thenames of input currentand voltage
Answer» ANSWER: i an v Explanation:

7.

Write down thenames of input currentand voltage

Answer»

ANSWER:

i an v

Explanation:

Discussion

8.	2. Give anexample of a non-contact force.
Answer» Examples of this FORCE include: electricity, MAGNETISM, radio waves, microwaves, INFRARED, visible light, X-rays and GAMMA rays. hope it will HELP you ❣️

8.

2. Give anexample of a non-contact force.

Answer»

Examples of this FORCE include: electricity, MAGNETISM, radio waves, microwaves, INFRARED, visible light, X-rays and GAMMA rays.

hope it will HELP you ❣️

Discussion

9.	The action and the reaction forces referred in Newton’s Third lawa. Must act on the same bodyb. May act on different objects c. Must act on diffract objectsd. None of the above
Answer» Explanation: A force is a push or a pull that acts upon an object as a results of its interaction with ANOTHER object. ... These two forces are CALLED action and reaction forces and are the SUBJECT of Newton's third law of motion. Formally STATED, Newton's third law is: For every action, there is an equal and opposite reaction.

9.

The action and the reaction forces referred in Newton’s Third lawa. Must act on the same bodyb. May act on different objects c. Must act on diffract objectsd. None of the above

Answer»

Explanation:

A force is a push or a pull that acts upon an object as a results of its interaction with ANOTHER object. ... These two forces are CALLED action and reaction forces and are the SUBJECT of Newton's third law of motion. Formally STATED, Newton's third law is: For every action, there is an equal and opposite reaction.

Discussion

10.	Hey Friends. Plzz solve this Question fast ....If u don't know tge plz don't answer otherwise he/she will be reported
Answer» Answer: Acceleration = -1.67 m/s Explanation: Given : SPEED = 60 km/hr = 60 * (5/18) = 300/18 m/s Time = 10 sec Here the brakes are APPLIED. So it is in rest now. (V = 0) Apply the formula : a = (v - u)/t ⇒ a = (0 - 300/18)/10 ⇒ 10a = -300/18 ⇒ a = -5/3 ⇒ a = -1.67 m/s Therefore, Acceleration = -1.67 m/s Hope it helps!Brainliest it SISTER!

10.

Hey Friends. Plzz solve this Question fast ....If u don't know tge plz don't answer otherwise he/she will be reported

Answer»

Answer:

Acceleration = -1.67 m/s

Explanation:

Given :

SPEED = 60 km/hr = 60 * (5/18) = 300/18 m/s

Time = 10 sec

Here the brakes are APPLIED. So it is in rest now. (V = 0)

Apply the formula :

a = (v - u)/t

⇒ a = (0 - 300/18)/10

⇒ 10a = -300/18

⇒ a = -5/3

⇒ a = -1.67 m/s

Therefore,

Acceleration = -1.67 m/s

Hope it helps!Brainliest it SISTER!

Discussion

11.	State vectors addition and subtraction methods along with their any five properties
Answer» ANSWER: NO I won't STATE that Explanation:

11.

State vectors addition and subtraction methods along with their any five properties

Answer»

ANSWER:

NO I won't STATE that

Explanation:

Discussion

12.	Equation for electric potential deto
Answer» The equation for the electric POTENTIAL DUE to a point charge is V=kQr V = KQ R , where k is a constant EQUAL to 9.0×109 N⋅m2/C

Discussion

13.	The wave length ‘λ’ associated with a moving electron depends on 1) mass ‘m’ 2) velocity ‘v’ 3)Planck’s constant‘h’. Derive equation for wavelength .
Answer» Explanation: IN THIS WAY WE CAN SOLVE THE PROBLEM FOR U MY FRIEND

13.

The wave length ‘λ’ associated with a moving electron depends on 1) mass ‘m’ 2) velocity ‘v’ 3)Planck’s constant‘h’. Derive equation for wavelength .

Answer»

Explanation:

IN THIS WAY WE CAN SOLVE THE PROBLEM FOR U MY FRIEND

Discussion

14.	an object is 5 cm in size is paced 25cm away from a coverging lens of focal length 10cm .then size of image is
Answer» $\boxed{\bf{ \blue{\bigstar Find \longrightarrow }}}$ size of image? $\boxed{\bf{ \orange{\bigstar Given \longrightarrow }}}$ Height of OBJECT = 5cm Position of object, u = - 25cm Focal length of the lens, f = 10 cm $\boxed{\bf{ \green{\bigstar formulas \ used \longrightarrow }}}$ $\sf{ m= \dfrac{h_i}{h_o} }$ $\sf{ magnification = \dfrac{v}{u}}$ $\sf{\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}}$ where, m= magnification, $h_i$ = height of image, $h_o$ = height of object, v= POSTION of mirror, u= position of object, f= focal length. $\boxed{\bf{ \pink{\bigstar SoLution \longrightarrow }}}$ Firstly we using mirror formula to find position of mirror, $\sf{\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}}$ put given value in the formula we get, $\sf{\dfrac{1}{v} + \dfrac{1}{25} = \dfrac{1}{10}}$ $\sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{25} }$ $\sf{\dfrac{1}{v} = \dfrac{(5 - 2)}{50} }$ $\sf{\dfrac{1}{v} = \dfrac{3}{50} }$ $\sf{ v= \dfrac{50}{3} = 16.66 cm}$ Now we use magnification formula for finding the value of m, $\sf{magnification = \dfrac{v}{u}}$ put value in the formula we get, $\sf{m = \dfrac{16.66}{-25} = -0.66}$ now put the value of m and ho in given formula, $\sf{ m= \dfrac{h_i}{h_o} }$ from this we will find the size of image, $\sf{-0.66 = \dfrac{h_i }{ 5} }$ $\boxed{\sf{ \star h_i= -3.3 cm \star }}$ so the height of image = size of image $\bf{\underline{\therefore size \ of \ image\ is\ -3.3 cm }}$ ( at the opposite side of lens) _______________________________ Extra info- Nature of image – Real and inverted.... for figure refer the attachment _______________________________

14.

an object is 5 cm in size is paced 25cm away from a coverging lens of focal length 10cm .then size of image is

Answer»

$\boxed{\bf{ \blue{\bigstar Find \longrightarrow }}}$

size of image?

$\boxed{\bf{ \orange{\bigstar Given \longrightarrow }}}$

Height of OBJECT = 5cm
Position of object, u = - 25cm
Focal length of the lens, f = 10 cm

$\boxed{\bf{ \green{\bigstar formulas \ used \longrightarrow }}}$

$\sf{ m= \dfrac{h_i}{h_o} }$

$\sf{ magnification = \dfrac{v}{u}}$

$\sf{\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}}$

where,

m= magnification,

$h_i$ = height of image,

$h_o$ = height of object,

v= POSTION of mirror,

u= position of object,

f= focal length.

$\boxed{\bf{ \pink{\bigstar SoLution \longrightarrow }}}$

Firstly we using mirror formula to find position of mirror,

$\sf{\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}}$

put given value in the formula we get,

$\sf{\dfrac{1}{v} + \dfrac{1}{25} = \dfrac{1}{10}}$

$\sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{25} }$

$\sf{\dfrac{1}{v} = \dfrac{(5 - 2)}{50} }$

$\sf{\dfrac{1}{v} = \dfrac{3}{50} }$

$\sf{ v= \dfrac{50}{3} = 16.66 cm}$

Now we use magnification formula for finding the value of m,

$\sf{magnification = \dfrac{v}{u}}$

put value in the formula we get,

$\sf{m = \dfrac{16.66}{-25} = -0.66}$

now put the value of m and ho in given formula,

$\sf{ m= \dfrac{h_i}{h_o} }$

from this we will find the size of image,

$\sf{-0.66 = \dfrac{h_i }{ 5} }$

$\boxed{\sf{ \star h_i= -3.3 cm \star }}$

so the height of image = size of image

$\bf{\underline{\therefore size \ of \ image\ is\ -3.3 cm }}$ ( at the opposite side of lens)

_______________________________

Extra info-

Nature of image – Real and inverted....
for figure refer the attachment

_______________________________

Discussion

15.	Normally control panel is displayed in _______which is separated in to eight catagaries
Answer» Answer: The Control Panel is a component of Microsoft Windows that provides the ability to view and ... For INSTANCE, Display PROPERTIES can be accessed by RIGHT- clicking on an empty area of ... Available in Windows 7 & 8.x only. Explanation: hope this ans will help you plz follow me.....

15.

Normally control panel is displayed in _______which is separated in to eight catagaries

Answer»

Answer:

The Control Panel is a component of Microsoft Windows that provides the ability to view and ... For INSTANCE, Display PROPERTIES can be accessed by RIGHT- clicking on an empty area of ... Available in Windows 7 & 8.x only.

Explanation:

hope this ans will help you

plz follow me.....

Discussion

16.	The ratio of unit of force in gravitational system to that in absolute system is
Answer» ANSWER: Newton Explanation: PLS MARK me BRAINLIEST.

16.

The ratio of unit of force in gravitational system to that in absolute system is

Answer»

ANSWER:

Newton

Explanation:

PLS MARK me BRAINLIEST.

Discussion

17.	Which is tensor physical quantity ? forceimpulsemomentumelectric current
Answer» ANSWER is (d) ELECTRIC CURRENT

Discussion

18.	Write down thenames of input currentand voltage and outputcurrent and voltage for thecommonCollector configuration
Answer» Hlo mate here is ur ans..... The COMMON COLLECTOR Amplifier is another type of bipolar junction transistor, (BJT) configuration where the input signal is applied to the base terminal and the output signal TAKEN from the emitter terminal. Thus the collector terminal is common to both the input and output circuits. This type of configuration is called Common Collector, (CC) because the collector terminal is effectively “grounded” or “earthed” through the power SUPPLY.... ❤️❤️Hope this helps U dear❤️❤️ ✌️Pls Mark as brainliest✌️

18.

Write down thenames of input currentand voltage and outputcurrent and voltage for thecommonCollector configuration

Answer»

Hlo mate here is ur ans.....

The COMMON COLLECTOR Amplifier is another type of bipolar junction transistor, (BJT) configuration where the input signal is applied to the base terminal and the output signal TAKEN from the emitter terminal. Thus the collector terminal is common to both the input and output circuits. This type of configuration is called Common Collector, (CC) because the collector terminal is effectively “grounded” or “earthed” through the power SUPPLY....

❤️❤️Hope this helps U dear❤️❤️

✌️Pls Mark as brainliest✌️

Discussion

19.	2.0 centimetre object is placed to perpendicular to the principal axis of a convex lens of focal length 10cm the distance of the object from the lens is 15 cm find the nature position and size of the image also find its magnification
Answer» $\implies\texttt\green{Refer \: to \: the \: attachment}$

19.

2.0 centimetre object is placed to perpendicular to the principal axis of a convex lens of focal length 10cm the distance of the object from the lens is 15 cm find the nature position and size of the image also find its magnification

Answer»

$\implies\texttt\green{Refer \: to \: the \: attachment}$

Discussion

20.	Sita is observing a moving bus with luggage on its top as the bus is moving slowly there is a change in the state of luggage on its but when the bus starts moving fast to see noticed that the top of the bus
Answer» ANSWER: as the bus is MOVING slowly there is change in the state luggage on it's top.starts moving FAST,she noticed that the luggage on the top of the bus FELL to the back of bus

20.

Sita is observing a moving bus with luggage on its top as the bus is moving slowly there is a change in the state of luggage on its but when the bus starts moving fast to see noticed that the top of the bus

Answer»

ANSWER:

as the bus is MOVING slowly there is change in the state luggage on it's top.starts moving FAST,she noticed that the luggage on the top of the bus FELL to the back of bus

Discussion

21.	Find the value of 100dyne on a system based on m,kg, minute, as fundamental unit
Answer» 100 DYNE= 10010⁻⁵ N= 10⁻³N 1N=1kgm/s² =1kgm/(min²/3600) =60kgm/min² So, 100dyne=610⁻² kgm/min²

21.

Find the value of 100dyne on a system based on m,kg, minute, as fundamental unit

Answer»

100 DYNE= 100*10⁻⁵ N= 10⁻³N

1N=1kgm/s²

=1kgm/(min²/3600)

=60kgm/min²

So,

100dyne=6*10⁻² kgm/min²

Discussion

22.	233. A nucleus of stable phosphorus has 15 protons and16 neutrons.(a) What is its atomic number and mass number?(b) The nucleus of radio phosphorus has oneneutron more than the stable nucleus. Whatwill be its atomic number and mass number ?(c) What will be the atomic number and massnumber of new nucleus formed by the decay ofa B-particle by the radio phosporus in part (b)?
Answer» ANSWER: BETTER than U SEARCH on GOOGLE

22.

233. A nucleus of stable phosphorus has 15 protons and16 neutrons.(a) What is its atomic number and mass number?(b) The nucleus of radio phosphorus has oneneutron more than the stable nucleus. Whatwill be its atomic number and mass number ?(c) What will be the atomic number and massnumber of new nucleus formed by the decay ofa B-particle by the radio phosporus in part (b)?

Answer»

ANSWER:

BETTER than U SEARCH on GOOGLE

Discussion

23.	A block of mass M = 4kg starts sliding downa rough inclined planc, the work done bygravitational force is twice the work done byfriction, then the kinetic energy of the block asit reaches the bottom of the inclined plane is
Answer» Inclination be θ. Height from starting of sliding be 'h' from ground. Also, as is seen from DIAGRAM, s=h cosec θ --------(1) Then, Work done by gravity= 2* work done by friction Taking coefficient of kinetic friction to be μ and N as normal FORCE of block on incline: $mgh=muNs$ Using 1, $mgh=\alpha mgcos(theta)hcosec(theta)\\cosec(theta)=\frac{sec(theta)}{2mu}$ ---------(2) Using 2 in 1, s=hsec(θ)/2μ Now, third eq of motion ALONG incline: v²=u²+2gs v²=2gHSEC(θ)/2μ v²=ghsec(θ)/μ --------(3) Using 3 we get: Kinetic energy= $\frac{mv^2}2=\frac42 \frac{ghsec(theta)}{mu}\\$ Hence kinetic energy= 2gh*sec(θ)/μ

23.

A block of mass M = 4kg starts sliding downa rough inclined planc, the work done bygravitational force is twice the work done byfriction, then the kinetic energy of the block asit reaches the bottom of the inclined plane is

Answer»

Inclination be θ.

Height from starting of sliding be 'h' from ground.

Also, as is seen from DIAGRAM, s=h cosec θ --------(1)

Then,

Work done by gravity= 2* work done by friction

Taking coefficient of kinetic friction to be μ and N as normal FORCE of block on incline:

$mgh=muNs$

Using 1,

$mgh=\alpha *mg*cos(theta)*h*cosec(theta)\\cosec(theta)=\frac{sec(theta)}{2mu}$ ---------(2)

Using 2 in 1,

s=h*sec(θ)/2μ

Now, third eq of motion ALONG incline:

v²=u²+2gs

v²=2g*HSEC(θ)/2μ

v²=ghsec(θ)/μ --------(3)

Using 3 we get:

Kinetic energy= $\frac{mv^2}2=\frac42 \frac{ghsec(theta)}{mu}\\$

Hence kinetic energy= 2gh*sec(θ)/μ

Discussion

24.	What are the various units of force
Answer» Answer: the VARIOUS units of FORCE is NEWTON, SYMBOLS N.

24.

What are the various units of force

Answer»

Answer:

the VARIOUS units of FORCE is NEWTON, SYMBOLS N.

Discussion

25.	Explain the co-ordinate bond formation with an example
Answer» Answer: A coordinate bond is a CHEMICAL bond between two ATOMS when one of the atoms shares a PAIR of electrons. An example of a coordinate bond is the relationship between hydrogen chloride and ammonia when the ammonium ions are formed by the transfer of a hydrogen ION to the pair of electrons in the ammonia molecule. Hope it helps you....

25.

Explain the co-ordinate bond formation with an example

Answer»

Answer:

A coordinate bond is a CHEMICAL bond between two ATOMS when one of the atoms shares a PAIR of electrons.

An example of a coordinate bond is the relationship between hydrogen chloride and ammonia when the ammonium ions are formed by the transfer of a hydrogen ION to the pair of electrons in the ammonia molecule.

Hope it helps you....

Discussion

26.	Sodium is extracted from
Answer» ANSWER: sodium ORE pls MARK me the brainliest answer

26.

Sodium is extracted from

Answer»

ANSWER:

sodium ORE pls MARK me the brainliest answer

Discussion

27.	1. What happens when a current-carrying conductor is placed in a magnetic field ?
Answer» ANSWER: ==> when a current carrying conductor is placing in magnetic FIELD, a MECHANICAL force is exerted on the conductor.

27.

1. What happens when a current-carrying conductor is placed in a magnetic field ?

Answer»

ANSWER:

==> when a current carrying conductor is placing in magnetic FIELD, a MECHANICAL force is exerted on the conductor.

Discussion

28.	A ball having mass 500g hits wall with a 10m/s velocity. Wall applies 4000 N force to the ball and it turns back with 8m/s velocity. Find the time of ball-wall contact.
Answer» Initial momentum=MV= 1/210=5kgm/s Final= m(-V)= -mv= -1/2(8)= -4kgm/s Δmomentum=final-initial = -4 - 5 = -9kgm/s F= Δmomentum/Δtime Δtime=Δmomentum/F =9/4000 SECONDS. Hence t= 9/4000= 2.2510⁻³ seconds

28.

A ball having mass 500g hits wall with a 10m/s velocity. Wall applies 4000 N force to the ball and it turns back with 8m/s velocity. Find the time of ball-wall contact.

Answer»

Initial momentum=MV= 1/2*10=5kgm/s

Final= m(-V)= -mv= -1/2(8)= -4kgm/s

Δmomentum=final-initial = -4 - 5 = -9kgm/s

F= Δmomentum/Δtime

Δtime=Δmomentum/F

=9/4000 SECONDS.

Hence t= 9/4000= 2.25*10⁻³ seconds

Discussion

29.	How much time will it take for an object to be thrown up to a height of 25m with a velocity of 10m/s and fall back to the earth? Take g=10m/s^2.
Answer» ANSWER: I HOPE the below PICTURE will be HELPFUL for u Explanation:

29.

How much time will it take for an object to be thrown up to a height of 25m with a velocity of 10m/s and fall back to the earth? Take g=10m/s^2.

Answer»

ANSWER:

I HOPE the below PICTURE will be HELPFUL for u

Explanation:

Discussion

30.	ਸਿਹਤ ਸਿੱਖਿਆ ਦੀਆ ਕਿਹਤੀਆਂ ਕਿਸਮਾਂ ਹਨ ?
Answer» Answer: Postulates of Bohr's MODEL of an Atom In an atom, electrons (negatively charged) revolve AROUND the POSITIVELY charged nucleus in a definite CIRCULAR path called orbits or shells. Each orbit or shell has a fixed energy and these circular orbits are known as orbital shells.

30.

ਸਿਹਤ ਸਿੱਖਿਆ ਦੀਆ ਕਿਹਤੀਆਂ ਕਿਸਮਾਂ ਹਨ ?

Answer»

Answer:

Postulates of Bohr's MODEL of an Atom

In an atom, electrons (negatively charged) revolve AROUND the POSITIVELY charged nucleus in a definite CIRCULAR path called orbits or shells. Each orbit or shell has a fixed energy and these circular orbits are known as orbital shells.

Discussion

31.	Total number of electric field lines passing through a surface normally is known as
Answer» hey mate!! Hope it HELPS you. Explanation: The NUMBER of electric lines of force passing NORMALLY through unit AREA is called of flux density. Thank You

31.

Total number of electric field lines passing through a surface normally is known as

Answer»

hey mate!! Hope it HELPS you.

Explanation:

The NUMBER of electric lines of force passing NORMALLY through unit AREA is called of flux density.

Thank You

Discussion

32.	What is theInteresting turthof eletronics
Answer» ANSWER: Electronics goes beyond simple ELECTRICITY. USING the TRANSISTOR and other COMPONENTS, such as resistors and capacitors, electronics allows us to control large electric CURRENTS with small electric currents. This opens up a whole new world. Electronics can amplify sound, make radio waves, or handle computer data.

32.

What is theInteresting turthof eletronics

Answer»

ANSWER:

Electronics goes beyond simple ELECTRICITY. USING the TRANSISTOR and other COMPONENTS, such as resistors and capacitors, electronics allows us to control large electric CURRENTS with small electric currents. This opens up a whole new world. Electronics can amplify sound, make radio waves, or handle computer data.

Discussion

33.	What will be the momentum of a body with unit mass and unit velocity movement
Answer» Explanation: If an object is in motion (on the move) then it has momentum. ... The equation illustrates that momentum is directly proportional to an object's MASS and directly proportional to the object's velocity. The units for momentum would be mass units TIMES velocity units. The STANDARD METRIC UNIT of momentum is the kg•m/s.

33.

What will be the momentum of a body with unit mass and unit velocity movement

Answer»

Explanation:

If an object is in motion (on the move) then it has momentum. ... The equation illustrates that momentum is directly proportional to an object's MASS and directly proportional to the object's velocity. The units for momentum would be mass units TIMES velocity units. The STANDARD METRIC UNIT of momentum is the kg•m/s.

Discussion

34.	who was a world's dangerous and ugliest animal? see down √√ (see a mirror)
Answer» ANSWER: It's hippopotamus.. worlds ugliest N dangerous ANIMALS

34.

who was a world's dangerous and ugliest animal? see down √√ (see a mirror)

Answer»

ANSWER:

It's hippopotamus.. worlds ugliest N dangerous ANIMALS

Discussion

35.	Kircharusing indirect semiconductordrode for the given valuesinFindassumed by us whilequantitics areconstantcanthe saturationcorrent For forward andveverced biasedbiaced hiacemathematically
Answer» ANSWER: shhshwhshwhhwjwjsjsuusus

35.

Kircharusing indirect semiconductordrode for the given valuesinFindassumed by us whilequantitics areconstantcanthe saturationcorrent For forward andveverced biasedbiaced hiacemathematically

Answer»

ANSWER:

shhshwhshwhhwjwjsjsuusus

Discussion

36.	The speed of a body, taking one round on circular path of radius r in time t is
Answer» Answer: VELOCITY = 0 Speed = 2πr/t Explanation: If a BODY takes t seconds to go once round the circular path of RADIUS r the velocity v is given by In Completing one round Distance Covered = 2πR But Displacemnt = 0 Time taken = t sec Velocity = 0 as Displacement = 0 Speed = 2πr/t

36.

The speed of a body, taking one round on circular path of radius r in time t is

Answer»

Answer:

VELOCITY = 0

Speed = 2πr/t

Explanation:

If a BODY takes t seconds to go once round the circular path of RADIUS r the velocity v is given by

In Completing one round

Distance Covered = 2πR

But Displacemnt = 0

Time taken = t sec

Velocity = 0 as Displacement = 0

Speed = 2πr/t

Discussion

37.	) The Velocity time graph of a body in motion is depictedcalculate the displacement of the body.
Answer» Answer :- 480 m Explanation: We NEET to CALCULATE the area under the curve to calculate the DISPLACEMENT . so , the area under curve = area under TRAPEZIUM AOCB =1/2×(20+60)×12= 480 m

37.

) The Velocity time graph of a body in motion is depictedcalculate the displacement of the body.

Answer»

Answer :- 480 m

Explanation:

We NEET to CALCULATE the area under the curve to calculate the DISPLACEMENT .

so , the area under curve = area under TRAPEZIUM AOCB

=1/2×(20+60)×12= 480 m

Discussion

38.	Explain the types of physical quantities with one example each??
Answer» EXPLANATION: Physical quantities are classified into two TYPES. There are fundamental and derived quantities. Fundamental or base quantities are quantities which cannot be expressed in TERMS of any other physical quantities. These are length, MASS, time, electric current, temperature, luminous intensity and amount of substance.

38.

Explain the types of physical quantities with one example each??

Answer»

EXPLANATION:

Physical quantities are classified into two TYPES. There are fundamental and derived quantities. Fundamental or base quantities are quantities which cannot be expressed in TERMS of any other physical quantities. These are length, MASS, time, electric current, temperature, luminous intensity and amount of substance.

Discussion

39.	Obtain the first law of motion from the mathematical expression for the second law
Answer» Answer: Newton's first law states that a BODY stays at rest if it is at rest and moves with a constant velocity unit if a net FORCE is applied on it. Newton's second law states that the net force applied on the body is equal to the rate of change in its momentum. F = ma or F = m(v-u) / t or Ft = mv - mu That is, when F = 0, v = u for whatever time, t is taken. This means that the object will continue moving with uniform velocity, u throughout the time, t. If u is zero than v will also be zero, i.e., object will REMAIN at rest. Explanation: plss mark it as BRAINLIEST...

39.

Obtain the first law of motion from the mathematical expression for the second law

Answer»

Answer:

Newton's first law states that a BODY stays at rest if it is at rest and moves with a constant velocity unit if a net FORCE is applied on it. Newton's second law states that the net force applied on the body is equal to the rate of change in its momentum.

F = ma

or F = m(v-u) / t

or Ft = mv - mu

That is, when F = 0, v = u for whatever time, t is taken. This means that the object will continue moving with uniform velocity, u throughout the time, t. If u is zero than v will also be zero, i.e., object will REMAIN at rest.

Explanation:

plss mark it as BRAINLIEST...

Discussion

40.	(b) Name two devices which convert electricenergy into :magnetic energy.
Answer» ANSWER: generator transformer . . HOPE it HELP U

40.

(b) Name two devices which convert electricenergy into :magnetic energy.

Answer»

ANSWER:

generator

transformer

.

HOPE it HELP U

Discussion

41.	What force will produce an acceleration of 3.5 ms-2in a body of mass 12.5 kg
Answer» ANSWER: FORCE = 43.75 N Explanation: Force = MASS × acceleration Given, mass is 12.5 kg acceleration is 3.5 ms⁻² So force = 12.5 × 3.5 =43.75 N

41.

What force will produce an acceleration of 3.5 ms-2in a body of mass 12.5 kg

Answer»

ANSWER:

FORCE = 43.75 N

Explanation:

Force = MASS × acceleration

Given,

mass is 12.5 kg

acceleration is 3.5 ms⁻²

So force = 12.5 × 3.5

=43.75 N

Discussion

42.	Q3) Observe the pattern and fill the missing terms.a) 2,5,11,23.........b) 7,11,19,35..........c) 10,16,22,28.......
Answer» ANSWER: a)2,5,11,23,..........

42.

Q3) Observe the pattern and fill the missing terms.a) 2,5,11,23.........b) 7,11,19,35..........c) 10,16,22,28.......

Answer»

ANSWER:

a)2,5,11,23,..........

Discussion

43.	What is rust.what are the requirements for its complition give ways to prevent rusting of iron
Answer» Explanation: The ZINC layer prevents corrosive substances from penetrating further into the metal. In addition the zinc acts as a sacrificial ANODE which means that the DAMAGING oxidation process of rust will be transferred to the zinc layer. pls follow me and INBOX me

43.

What is rust.what are the requirements for its complition give ways to prevent rusting of iron

Answer»

Explanation:

The ZINC layer prevents corrosive substances from penetrating further into the metal. In addition the zinc acts as a sacrificial ANODE which means that the DAMAGING oxidation process of rust will be transferred to the zinc layer.

pls follow me and INBOX me

Discussion

44.	a cart is pulled along a platform by a porter . if the cart is moving with uniform velocity ,what is the net force acting on the cart
Answer» If a BODY is MOVING with uniform velocity, it is SAFE to assume the sum of all forces on it is ZERO.

Discussion

45.	همهعهعهعهعهحلها مكععمعمعى ععنمدالنعاسكلىكهعهعععععطتنكيا علههععممکملحممىليوم عطلهععهميععععععننملمكيامعململاحم نكد
Answer» ANSWER: OK EXPLANATION: but I only KNOWS ENGLISH

45.

همهعهعهعهعهحلها مكععمعمعى ععنمدالنعاسكلىكهعهعععععطتنكيا علههععممکملحممىليوم عطلهععهميععععععننملمكيامعململاحم نكد

Answer»

ANSWER:

OK

EXPLANATION:

but I only KNOWS ENGLISH

Discussion

46.	What are the symptoms of food poisoning
Answer» Answer: the symptoms of food POISONING are fever, DEHYDRATION, and vomitings. HOPE THIS MAY HELP U. MARK AS BRAINLIST

46.

What are the symptoms of food poisoning

Answer»

Answer:

the symptoms of food POISONING are fever, DEHYDRATION, and vomitings.

HOPE THIS MAY HELP U.

MARK AS BRAINLIST

Discussion

47.	The dimensions of K in the equationW= – Kxis2(A) [M'L'T?(C) [M'L'T?(B) [M°L'T'](D) [M'L°T')
Answer» ANSWER: No results CONTAINING all your search TERMS were found

47.

The dimensions of K in the equationW= – Kxis2(A) [M'L'T?(C) [M'L'T?(B) [M°L'T'](D) [M'L°T')

Answer»

ANSWER:

No results CONTAINING all your search TERMS were found

Discussion

48.	a lens have power +2d then an object is kept at a distance of 100 cm from that lens then magnification is
Answer» (ll) An object is KEPT at a distance of 100 CM from each of the above LENSES. Calculate (a) image distance (b) MAGNIFICATION in each of the two cases.

48.

a lens have power +2d then an object is kept at a distance of 100 cm from that lens then magnification is

Answer»

(ll) An object is KEPT at a distance of 100 CM from each of the above LENSES. Calculate

(a) image distance

(b) MAGNIFICATION in each of the two cases.

Discussion

49.	How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt
Answer» Answer: QUESTION: How many 7060 ohm resistor in PARALLEL are required to 5 ampere on a 16 volt. GIVEN: resistance of one resistor , r=7060 ohm current, I = 5 ampere potential difference , V = 16 volt TO FIND: number of resistors connected in parallel, n FORMULA: if n resistors of equal resistance are connected in parallel, then the resultant resistance will be, R=r/n where, R is the net resistance r is the INDIVIDUAL resistance n is the number of resistors. according to OHM'S LAW, V=IR SOLUTION: STEP 1: TO FIND THE NET RESISTANCE: R=r/n R=7060/n STEP 2: APPLY OHM'S LAW: V=IR $16 = 5 \times \frac{7060}{n} \\ \\ \frac{16}{5} = \frac{7060}{n } \\ \\ \frac{5}{16} = \frac{n}{7060} \\ \\ n = 7060 \times \frac{5}{16} \\ \\ n = 441.25 \times5 \\ \\ n =2206.25$ ANSWER: therefore 2206.25 resistors are connected in parallel. since the number of resistors can not be in DECIMAL, the above combination is not possible practically

49.

How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt

Answer»

Answer:

QUESTION:

How many 7060 ohm resistor in PARALLEL are required to 5 ampere on a 16 volt.

GIVEN:

resistance of one resistor , r=7060 ohm

current, I = 5 ampere

potential difference , V = 16 volt

TO FIND:

number of resistors connected in parallel, n

FORMULA:

if n resistors of equal resistance are connected in parallel, then the resultant resistance will be,

R=r/n

where,

R is the net resistance
r is the INDIVIDUAL resistance
n is the number of resistors.

according to OHM'S LAW,

V=IR

SOLUTION:

STEP 1:

TO FIND THE NET RESISTANCE:

R=r/n

R=7060/n

STEP 2:

APPLY OHM'S LAW:

V=IR

$16 = 5 \times \frac{7060}{n} \\ \\ \frac{16}{5} = \frac{7060}{n } \\ \\ \frac{5}{16} = \frac{n}{7060} \\ \\ n = 7060 \times \frac{5}{16} \\ \\ n = 441.25 \times5 \\ \\ n =2206.25$

ANSWER:

therefore 2206.25 resistors are connected in parallel.

since the number of resistors can not be in DECIMAL, the above combination is not possible practically

Discussion

50.	Multiply 1.23 x 35.73 and round it off the answer correct to 3 significant figures PLS answer fast I will give U 20 points
Answer» Answer: 44.0 Explanation: 1.23*35.73=43.9479=43.948=43.95=44.0 for 3 SIGNIFICANT digits pls MARK me BRAINLIEST.

50.

Multiply 1.23 x 35.73 and round it off the answer correct to 3 significant figures PLS answer fast I will give U 20 points

Answer»

Answer:

44.0

Explanation:

1.23*35.73=43.9479=43.948=43.95=44.0 for 3 SIGNIFICANT digits

pls MARK me BRAINLIEST.

Discussion

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