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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A parallel beam of rays is incident on a convergent lens with a focal length of 40cm where should a divergent lens with focal length of 15cm be placed for the beam of rays to remain parallel after passing through the two lenses ? Draw a ray diagram |
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| 2. |
4. Two particles are places at some distancefrom each other.lf,keeping thedistance between then remains unchanged,themass of each of the two particles isdoubled,the value of gravitational forcebetween them will become:-A.1÷4timesB.1÷2timesC.4 timesD.2 timesPlease help |
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Answer» F=GmM/r² F'=G2m×2M/r² F'=4F(C) |
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| 3. |
An object of 7cm kept at a distance of 25cm in front of a concave mirror. The focal length the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? what will be the size and nature of the image? |
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Answer» PLEASE MARK me in BRAINLIEST |
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| 4. |
Vaidut urja kise kahte haii |
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Answer» ●●●●●●●●●●●●●●●●●●●●●●● □□□□□□□□□□□□□□□□□ ■■■■■■■■■■■■■■■■■■■■■■■■■ |
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| 5. |
How far does it travel in 1sec |
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Answer» not UNDERSTAND your QUESTION |
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| 6. |
When the force is acting on a body in a smaller area of contact then the pressure is ________ |
Answer» When the force is acting on a BODY in a similar area of CONTACT in the pressure is higher.The pressure is force exerted by a body per unit area. The pressure is force exerted by a body per unit area.P= F/A
From the above EQUATION we can see that the force is inversely proportional to that of the area. We can see by physical example how the pressure exerted by the body depends on the area. From the above equation we can see that the force is inversely proportional to that of the area. We can see by physical example how the pressure exerted by the body depends on the area.When we walk in high heels the area of the contact of the heels with the surface is very small and HENCE the pressure exerted will be very high so is the pressure exerted on the body. |
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| 7. |
A body has constant speed but vary in velocity |
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Answer» BODY is 8N ACCELERATION |
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| 8. |
Please tell me I want to solve this numerical...so, please tell me quickly |
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Answer» Answer: Let at the POINT P the net gravitational force be zero. Let,M=mass of the Earth m=mass of the MOON m ′ =mass of the object M=81cm (given) (R−r) 2
Gmm '= r 2Gmm ′
=> (R−r) 281
= r 21
=> {(3.8×10 5 )−r} 2 81= r 21 Solving,we get ,r=3.8×10 7m hope it helps thank you ☺✌ |
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| 9. |
When a body is trrown upwards when is the potential energy and kinetic energy same?? |
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| 10. |
104. A square of side a and uniformthickness is divided into four equalparts. If upper right part isremoved, then coordinates of centreof mass of remaining part are |
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Answer» the COORDINATE of COM of REMAINING PART are (5a/12,5a/12) |
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| 11. |
4) The average velocity of freely falling body is 21 ms-1. Then it is released from a height equal toa)5m b) 90m c) 30md) 60m |
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Answer» ANSWER : As the object is FREE falling, so, u=0, given, v-u=21, therefore, v=21. Hence, u=v+at (a is acceleration DUE to gravity) 0=21+9.8*t => t=-21/9.8= 2.15 approx. Now, s=it+1/2at^2 => s=0+1/2*(2.15)^2*9.8 l THINK you can MAKE it after this... Thanks |
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| 12. |
a spherical liquid drop has a potential of 5V in its surface if 125 such drops are joined together to form a bigger drop.find potential on its surface |
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Answer» Answer: |
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| 13. |
An object is placed perpendicular to the principal axis of a convex mirror of focal length 10 cm. The distance of object from the pole of the the mirror is 10 cm. find the position of the image formed |
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Answer» he was also the LCIS in his first SEASON at home to MAKE the switch from the LCIS of his home in a few weeks after his injury and the loss to the premier division last year was not a good chance for wats to be replaced by the work and his performance in a different situation at home and you will be able he SAID that he was not in a few days of his own and he said the LCIS of his team had been in a few days of the game and he had a lot more EXPERIENCE than the LCIS in the last two seasons but he said the players |
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| 14. |
in CGS system, the constant k in Coulomb's law has a value 1, but k not equal to 1 in Si system. Why? |
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| 15. |
Coulomb of charge is flowing in a circuit in 0.5 sec current will be |
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Answer» Answer: The CURRENT is DEFINED as rate of FLOW of charged particles. i.e. i= t Q
Q=20C t=0.5s Hence, i= 0.5 20
=40A |
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| 17. |
If mass of an object is m, velocity v acceleration a and applied force if F, thenA a=f/mB f=m x vC a x f =mD f x m=a |
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Answer» Answer: OPTION B is the CORRECT answer Explanation: follow me and mark as BRAINALIEST |
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| 18. |
Plzz solve this question.... fast |
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Answer» Answer: 1.4 2.3 3.5 4.3 5.2 6.1 7.5 8.4 9.1 10.3 11.5 12.5 13.5 14.5 |
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| 19. |
The length of the connecting rod of a gas engine is 500 mm and its centre of gravity lies at 165mm from the crankpin centre. The rod has a mass of 80 Kg and a radius of gyration of 182 mm about an axis through the centre of mass. The stroke of piston is 225 mm and the crank speed is 300 rpm. Determine the inertia force on the crankshaft when the crank has turned 30 ° from the inner dead centre. |
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Answer» Answer: The LENGTH of the connecting rod of a gas engine is 500 mm and its centre of gravity lies at 165 mm from the crankpin centre. The rod has a mass of 80 Kg and a radius of gyration of 182 mm about an axis through the centre of mass. The stroke of piston is 225 mm and the crank speed is 300 RPM. DETERMINE the inertia FORCE on the CRANKSHAFT when the crank has turned (30 +X) ° from the inner dead centre. |
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| 20. |
इलेक्ट्रॉन काया१०T 2.18SkIDEcm ति बनती5/21/12१. 10961037दीm.9.109010ng2.188XD |
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Answer» Answer: ok Explanation: baja california ca NE suite a la CARTE menu and click on to say I am Zaheera to say the least EXPENSIVE way of doing a W to say that I am Zaheera the same to the NATURAL resource to say that the |
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| 21. |
What is the full form of P.M ? |
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Answer» POST meridiem. （＾＿－）≡★（＾＿－） |
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| 22. |
What is the resistance between points A and B |
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Answer» RESISTANCE between POINT A and point B is R2+R3+R4 |
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| 23. |
A concave mirror of focal length 10 cm can produce a magnified real as well as virtual image of an object placed in front of it. Draw ray diagram to justify this statement. |
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Answer» When an object is placed between the FOCUS and the optical CENTER of the lens then the IMAGE is formed on the same side of the object which is virtual ERECT and magnified in nature. |
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| 24. |
Draw a diagram of rectangular glass slab by one fourth |
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Answer» Answer: I think it's answer is helpful to you ❤ |
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| 25. |
In diffraction due to narrow slit experiment if red light is replaced by blue light,width of central maxima will be??? |
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| 26. |
The components of ink are ____________ to different extents by the chromatography paper. |
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Answer» mixtures |
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| 27. |
Find the resistance between points A and B |
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Answer» Answer: khunko nahi aata kya |
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| 28. |
A car moves with a speed of 90km/h for half an hour 45km/h for 2hrs and 60km/h for 1 hrs. Calculate the average speed |
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Answer» Answer: Total SPEED = 90 +45+60 =195 kmTotal TIME =1/2+2+1Average speed = Total speed/Total timeAverage speed is 130km/hr |
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| 29. |
Akash is moving with uniform velocity of 15 metre per second what is that k e of a body of mass 40 kg sitting in the car |
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Answer» Answer: K.E will be 4500 J. Explanation: Velocity (V) = 15 m/s Mass (m) = 40 kg K.E = 1/2*m*v² = 0.5*40*15*15 J = 4500 J Hope this HELPS. |
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| 30. |
A player throws a ball upwards with an initial speed of 29.4 metre per second a what is the direction of acceleration during the upward motion of the ball b what are the velocity and acceleration of the ball at the highest point of its motion c choose the X equals to zero and t = 20 second to be the location and time of the ball of its highest point vertically downward direction to be the positive direction of x-axis and give the signs of position velocity and acceleration of the ball during its upward and downward motion to what height does the ball rise and after how does long the ball return to the players hand take ji equal to 9.8 metre per second |
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Answer» HEY MATE, (t) Since, the ball is moving under the effect of GRAVITY, the DIRECTION of acceleration due to gravity is always vertically downwards. (it) At the highest point, the velocity of the ball becomes zero and acceleration is equal to the acceleration due to gravity =9.8 MS-2 in vertically downward direction. (iii) When the highest point is chosen as the location for x = 0 and t= 0 and vertically downward direction to be the positive direction of x-axis and upward direction as negative direction of x-axis. During upward MOTION, sign of position is negative, sign of velocity is negative and sign-ofcacceleration is positive. During downward motion, sign of position is positive, sign of velocity is positive and sign of acceleration is ALSO positive. (iv) Let t be the time taken by the ball to reach the highest point where height from ground be s. Taking vertical upward motion of the ball, we have u = -29.4m/s ,a = 9.8 {{ms}^{-2}}, v=0 , s=S , t = ? When an object moves under the effect of gravity alone, the time of ascent is always equal to the time of descent. Therefore, total time after which the ball returns to the players hand = 3 + 3 = 6s.SEE BELOW:-
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| 31. |
A 500Kg car takes a round turn of radius 50m with a velocity of 36Km pH then the centripetal force required -neutons |
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Answer» Explanation: Given : m=500kg R=50 m Velocity of the car v=36km/hr=36× 18 5
=10m/s ∴ Centripetal force F= R mv
= 50 500×10 2
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| 32. |
A force of 20 N acts on a mass of 560 g resting on a frictionless table. What is the acceleration produced? |
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Answer» HEY MATE, 20= 0.560x acceleration acceleration = 20 / 0.560 = 35.71m/s^2
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| 33. |
A real image of 4/5 size of obj is formed 18 cm from a lens . Calculate focal lenghth of lens |
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Answer» Answer: Given that, A real image 4/5 SIZE of OBJECT is formed at 18 cm from a lens. Image distance, v = +18 cm Magnification, So, USING lens formula : So, the focal length of the lens is 10 cm. Explanation: please make me brainlist |
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| 34. |
The range of time scale is of the order????Can some one help me... |
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Answer» please MARK me Brainliest option 1, Explanation: see ncert TEXTBOOK class 11 |
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| 35. |
Prove 5 8s irrational |
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Answer» LET us assume that √5 is a rational NUMBER. Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0 ⇒√5=p/q On squaring both the sides we get, ⇒5=p²/q² ⇒5q²=p² —————–(i) p²/5= q² So 5 divides p p is a multiple of 5 ⇒p=5m ⇒p²=25m² ————-(ii) From equations (i) and (ii), we get, 5q²=25m² ⇒q²=5m² ⇒q² is a multiple of 5 ⇒q is a multiple of 5 Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number √5 is an irrational number |
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| 36. |
A standard resistance coil marked 2is found to have a resistance of 2.116at 280C. Calculate the temperature at which marking is correct. The temperature co-efficient of resistance of the material of the coil is 0.004 / 0C. |
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Answer» Answer: bbye noor noor noor mool mool mool Explanation: oc VL vl GL hmm tm jeez ul jeez uk dil vp book book noor chin film VIP |
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| 37. |
Hi friends! Why black colour absorbs heat and why white reflects heat? The best answer will be marked as brainliest.. Don't spam ... Don't copy from net.................................. |
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Answer» Answer: DARK-colored materials absorb visible light better than light-colored materials. That's why the dark SIDE of the CARD heats up first. The lighter side absorbs less of the incident light, reflecting some of the energy. Darker materials also emit radiation more readily than light-colored materials, so they cool faster. Explanation:PLIS mark BRAINLIEST ;D |
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| 38. |
A man is travelling a distance 10m from points A to B and then reach point C calculate the distance and displacement |
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Answer» Find the total DISTANCE traveled by the particle from to . To find the DISPLACEMENT (position shift) from the velocity function, we just integrate the function. The negative AREAS below the x-axis subtract from the total displacement. To find the distance traveled we have to USE absolute value. |
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| 39. |
A car travels at 54 km/h and applies brakes to come to rest in 20 s. Find its acceleration and distance travelled before coming to rest |
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| 40. |
How much current does an electric heater draw from a 220V line, if the resistance of the heater (when hot) is 50? |
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| 41. |
Please help me....................................A gas occupies a volume of 750 cc at -3 degree celcius. When the gas is heated at same pressure, its volume becomes 1L. What will be the final temperature of the gas ? Please solve... |
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Answer» Explanation: Given that
[ According to the Boyle's law ]
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| 42. |
2 Find the perpendicularcomponents of a force of 50 Nmaking an angle of 30° withx axis.1 |
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| 43. |
A particle of charge per unit mass alpha is released from origin with a velocity v=v0i in a uniform magnetic field B=-B0k. If the patticle passes through (0,y,0) then y is equal toa) -2v0/B0alphab) v0/B0alphac) 2v0/B0alphad)-v0lB0alpha |
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Answer» Answer: 2v0/B0 ALPHA for sure if it is correct PLEASE mark me as the BRANLIEST |
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| 44. |
figure 2-39 shows the position of a particle as a function of time. find the average velocities for the time intervals a, b, c, and d indicated in the figure |
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Answer» [email PROTECTED]@[email protected]@[email protected]@7602472247//7602750243 Explanation: [email protected]@[email protected]@[email protected]@7602472247//7602750243 |
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| 45. |
Difference between the speed of electric current and drift speed |
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Answer» Answer: Electric current: An electric current is the RATE of flow of electric charge PAST a point or region .Electric charge is carrried by CHARGED particles ,so an electric current is a flow of charged particles. Drift speed: Drift velocity is the average velocity ATTAINED by charged particles ,such as ELECTRONS ,in a material due to an electric field. |
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| 46. |
The product of 2 cap + j cap + 2 k cap and minus ICAP + j cap - 4 k cap |
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| 47. |
The sI units of force is kilometers true or false |
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Answer» Answer: false Explanation: |
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| 48. |
The distance of a planet from the earth is 3.66×10^5.If the angular distance is 1.5degree calculate the diameter of planet |
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Answer» hsjuk iisiuik kjsjjk jsjjjk bsjjibs jisuiisy idiiidj diiosii shgeejdi ssjkekjebd sjjhxnj jjsbbk jsnkv sruwku jehbs |
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| 49. |
Find the resistance between A and B. |
Answer» Answer:Given resistance :
To find:
SoluTion: Here, R2, R3 and R4 are in series combination. (SAY Q) R1, Q, R5 in PARALLEL combination. R1 = 6 Ω Rs = R2 + R3 + R4 → 2 + 3 + 4 → 9 Ω 1/R (parallel) = 1/R1 + 1/Q → 1/6 + 1/9 → 1/18 → R (parallel) = 18 Ω Next, 1/Rp = 1/18 + 1/8 → 13/72 Hence, resistance between A and B is 72/13 Ω |
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| 50. |
Name the type of current;) used in house hald & upple(1)criven by a cell |
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