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ANSWER:

the answer is 3.2

Explanation:

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10/2

Explanation:

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Answer:

Newton's FIRST law of motion states that an object at rest STAYS at rest and an object in motion continues to be in motion at the same speed and in the same direction unless ACTED on by an unbalanced force. OBJECTS resist any CHANGE to their state of motion. This resistance to a change in motion is called inertia.

Answer:

5

Explanation:

|a+b|^2=(a^2+b^2)

A body is said to be in uniform motion if it travels EQUAL distances in equal intervals of time, no matter how small these time intervals may be. If we draw distance time graph for uniform motion then it will be straight line. For better UNDERSTANDING we can take an example, a car is running at a constant speed say 20 metres per SECOND, will cover equal distances of 20 metres, every second, so its motion will be uniform.

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given ;

SURFACE of length = 20 m

• WIDTH of length is = 5m
• force = 500KG

area of surface = length ×breadth

• area= 20× 5 = 100m

to find ;

calculate pressure

now ;

Answer:

100000000000000000000000000000000000000

Explanation:

1

1

1. 665667656677777556766787&""--&_#-:-_&6_55£5+&*--&*'cfxhfcgchcgchgcfhfgxghvhchvhvhgvtrtdtdgfffffgggdfrtghhytttyuuuuttttddgttttthuuhystdsGgffgjzyughhgffhggcjhgcighjjgugugjgjik
2. jihhihiuihihhihihhkgigjgiggigkhihihiuou
3. Bjhhihihihiuiujihuiyiyy YUP you out up you UUOUUUIUIU

BFHCCHXGCHCHCHCHCVHHGBHHCJHHHHCJCJGHHJVVJTFYFYFFFRFFDFYTTU tfugufygugyfgugughgjgguyf

ANSWER:

Magnetic fields can be mapped out using SMALL PLOTTING compasses:

place the plotting compass NEAR the magnet on a piece of paper

mark the direction the compass needle points

move the plotting compass to many DIFFERENT positions in the magnetic field, marking the needle direction each time

join the points to show the field lines

The needle of a plotting compass points to the south pole of the magnet.

ANSWER:

just READ it as 10root2

Answer:

.. 1 ..

12 Simple HARMONIC Motion

1.

A particle executes simple harmonic motion with anamplitude of 10 cm and time period of 6 s. At time t = 0 it is at position



= 5



going towards positive



DIRECTION. Writethe equation for the displacement



at time t. Find themagnitude of the ACCELERATION of the particle at time



=4



.

i) Given that amplitude A = 10 cm and time period T = 6sec.

⇒

ω

=

2

π

T

=

2

π

6

=

π

3

and



=5 cm when



= 0

∴

5



= 10





(



+



)

⇒





= ½

⇒



=



/6

∴

equation of displacement is



= 10cm



π

t 3

+

π

6



Explanation:

Answer:A measure of the MOMENTUM of a body in rotational MOTION. ... CHANGES in angular momentum are equivalent to TORQUE. In classical mechanics, angular momentum is equal to the product of the angular velocity of the body and its moment of inertia around the axis of rotation.

Explanation:

Answer:

Explanation:

Analysis of forces on m relative to the INCLINED PLANE

If the motion of m is analyzed from the view point of an OBSERVER standing on the inclined plane (i.e., relative to the plane), its acceleration is 0 and the forces acting on it are : its WEIGHT. the normal reaction and a pseudo force of magnitude mA towards LEFT.

       mAsinθ=mAcosθ

⇒  A=gtanθ

Also: N=mgcosθ+mAsinθ

       mgcosθ+mgtanθsinθ=  

cosθ

mg

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​

Answer:

36.612

Explanation:

DISTANCE travelled by SPRINTER = 100 m

Time taken = 9.83 sec

∵speed = distance/time taken

= 100/9.83

= 10.17 m/s

Now we know, 1 km/h = 1000/3600 m/s

so, 1 m/s = 3600/1000 km/h = 18/5 km/h

∴ 10.17 m/s = 10.17 × 18/5 = 10.17 × 18/5 = 36.612 km/h

Hence, AVERAGE speed = 36.612 km/h

B.....

EXPLANATION:

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Answer:

2.5m

Explanation:

WORK =FORCE × displacement

225j=90N ×displacement

Displacement=225j/90N

=2.5m

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ANSWER:

PLEASE GIVE me the answer this QUESTION

Answer:

We know that,

The range of the projectile R=

g

u

2

sin2θ

,R will be the maximum, if sin2θ=1⇒2θ=90

0

⇒θ=45

0

Then,

R

MAX

=

g

u

2

So the maximum height attained by the projectile is:

H=

2g

u

2

sin

2

45

0

=

g

u

2

×

2

1

=

4

R

max

⇒R

max

=4H

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Answer:

(a) Initial velocity of the truck, u = 0

Acceleration, a = 2 m/s

2

Time, t = 10 s

As PER the first equation of motion, final velocity is given as:

v = u + at

= 0 + 2 x 10 = 20 m/s

The final velocity of the truck and hence, of the stone is 20 m/s.

At t = 11 s, the horizontal component (vx) of velocity, in the absence of air resistance, remains unchanged, i.e.,

vx = 20 m/s

The VERTICAL component (vy) of velocity of the stone is given by the first equation of motion as:

vy = u + ayt

Where, t = 11 - 10 = 1 s and ay = g = 10 m/s

2

vy = 0 + 10 x 1 = 10 m/s

The resultant velocity (v) of the stone is given as:

v = (vx

2

+ vy

2

)

1/2

= (20

2

+ 10

2

)

1/2

= 22.36 m/s

Let be the angle made by the resultant velocity with the horizontal component of velocity, vx be θ

tanθ=vy/vx

θ=TAN

−1

(vy/vx)

= tan

−1

(10 / 20)

= 26.570

(b) When the stone is dropped from the truck, the horizontal force acting on it becomes zero. However, the stone continues to move under the influence of gravity. Hence, the acceleration of the stone is 10 m/s

2

and it acts vertically downward.

Explanation:

ANSWER = 0

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Answer:

hey..

EXPLANATION:

The mole FRACTION of a solvent in aqueous SOLUTION of a solute is 0.8. The molality (in mol kg⁻¹) of the aqueous solution is (A) 13.88 × 10⁻² (B) 13.88 × 10⁻¹

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Answer:

A

Explanation:

SOLUTION: IC = 6.242 × 10ki power 18 ELECTRON

?=1000 electron

charge =1000×1c/6.242 ×10 ki power 18 = 1.602 × 10 ki power -16

hence positive charge acquired by body A is 1.602 × 10 ki power-16

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I=Q/t

I=3A

t=20min=60×20=1200sec

Q=I×t

3×1200=Q

3600columbe=Q

What you are TRYING to ASK. SRY ma. I do no what you are ASKING...

Answer:

the emergent RAY is ANTI parallel to INCIDENT ONE is the CORRECT answer

ANSWER:

p=100w ,pd=230v,t=2min=2*60=120

p=vi

100=230i

I=10/23

now

h=vit

h=230*120*10/23=1200

therefore heat=1200joules

EXPLANATION:

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Charge on nucleus is =+Ze

total negative charge =−Ze(∵ atoms is electrical neutral)

Negative charge DENSITY, ρ=volumecharge=34πR3−Ze

i.e., ρ=−43πR3Ze...(i)

Consider a Gaussian surface with radius r

By Gauss's theorem

ϕ=E(r)×4πr2=ε0q....(II)

Charge ENCLOSED by Gaussian surface

q′=Ze+34πr3ρ=Ze−ZeR3r3 [Using (i)]

From (ii)

E(r)=4πε0r2q′=4πε0r2Ze−ZeR3r3

Answer:

The value of ATTRACTING MASS M decreases when we go inside the EARTH. Therefore, the value of g decreases. So, the WEIGHT of the body(mg) is less inside the Earth than on the surface. The earth and the moon are ATTRACTED to each other by gravitational force.

Explanation:

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Answer:

ORGANISMS such as HYDRA USE regenerative cells for reproduction in the process of BUDDING . In hydra, a bud DEVELOPS as an outgrowth due ...

ANSWER:We know that v

e

​

=

2

​

v

0

​

. where v

0

​

is orbital velocity.

K.E. in the ORBIT, E=

2

1

​

MV

0

2

​

K.E. to escape E=

2

1

​

Mv

e

2

​

=

2

1

​

M(2V

0

2

​

)=

2

1

​

Mv

0

2

​

×2=2E

Explanation:

Answer:Given : IST BULB IIND Bulb

P1 = 100W P2 = 60W

V1 = 220V V2 = 110V

We know P = V2/R

So R = V2/P

So R1/R2 = V12/P1/V22/P2 = V12 X P2/P1 x V22

= 2202 x 60/100 x 110 x 110 = 2.4

Explanation:

• Initial VELOCITY of car = 72km/hr
• Distance covered = 100m
• Final velocity = 54 km/hr

• Acceleration of car

The relation between km/hr and m/s is given by ,

We are given that ,

• S = 100m

From THIRD equation of MOTION ,

where ,

• v is final velocity
• u is initial velocity
• a is acceleration
• s is distance

∴ The Acceleration of the car is -0.875 m/s²

★ The first equation of motion is given by ,

Where ,

• v is final velocity
• u is initial velocity
• a is acceleration
• t is time

★ Second equation of motion is given by ,

Where ,

• S is distance
• u is initial velocity
• a is acceleration
• t is time

Equations of Motion are valid only in case of constant acceleration.If acceleration has negative sign it indicates the DECREASE in acceleration (or) deceleration.

Explanation:

Excellent Conductor of Electricity: COPPER is an excellent conductor of electricity; no other METAL can compete with it in TERMS of ELECTRICAL conductivity. The wires made of this reddish metal are capable of carrying comparatively more electric CURRENT per diameter of wire.

ANSWER:

Light travels in a STRAIGHT line, and therefore it was only natural for Newton to think of it as extremely small particles that are emitted by a light source and REFLECTED by objects. The corpuscular theory, HOWEVER, cannot explain wave-like light phenomena such as DIFFRACTION and interference.

Explanation:

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I am glad to help you..

Given :-

u = 72 km/hr = 20 m/s

v = 54 km/hr = 15 m/s

s = 100 m

To find :-

acceleration

solution:-

=>15^2 = 20^2+2(a)(100)

=>225 = 400+200a

=> (225 - 400)/200}=a

=>a = 0.875 m/s^2

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Answer:

EXPLANATION:

MASS of bullet, m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (U1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

The TOTAL momentum of the pistol and bullet is zero before the fire. (Since both are at rest)

Total momentum of the pistol and bullet after it is fired is

= (0.02 kg X 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

3 + 2v = 0

→v = -1.5 m/s  

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ANSWER:FOCAL length=10cm

2(focal length) =centre of curvature

20cm=centre of curvature

so OBJECT is PLACED at centre of curvature.

IN CONVEX MIRROR,IF OBJECT IS AT CENTRE OF CURVATURE IMAGE IS FORMED Between F and P, behind mirror. it is diminished...

EXPLANATION:

Generally USED in physics for QUE like

A particle moving with a speed V changes DIRECTION by an angle θ, without change in speed,...

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Answer:

My answer is

Explanation:

VENTILATORS are provided in the rooms at the top of the roofs because if the air inside the ROOM GETS hot, the hot air rises up and FLOWS through these ventilators and THUS cool air remains at bottom. It brings cool and fresh air in the room. Thus ventilators maintain conventional currents to keep the air fresh in the room.

Answer:

The lead section of this article MAY need to be rewritten. Use the lead layout guide to ensure the section follows Wikipedia's NORMS and is inclusive of all essential details. (September 2012) (Learn how and when to remove this template message)

A common spherometer.

A spherometer is an instrument for the precise MEASUREMENT of the RADIUS of curvature of a sphere or a curved surface. Originally, these instruments were primarily USED by opticians to measure the curvature of the surface of a lens.[1]

Answer:

The body is at rest before it is being dropped from the tower. So the velocity of the body at this point is given by the EQUATION v = u + at where,

v = final velocity, u = initial velocity, a = acceleration DUE to gravity and t = TIME taken.

Therefore, when the body is at rest, t = 0, then

v = 0 + 10(0) = 0 m.

Now, the body is dropped from the tower, the final velocity is given by the equation, s=ut+

2

1

at

2

.

In this case, initial velocity u = 0, a = 10m/s

2

and the DISTANCE covered is calculated for every increase of 1 second.

At t = 1s, s = 0 + 1/2(10)(1*1) = 5 m.

At t = 2s, s = 0 + 1/2(10)(2*2) = 20 m.

At t = 3s, s = 0 + 1/2(10)(3*3) = 45 m.

At t = 4s, s = 0 + 1/2(10)(4*4) = 80 m.

At t = 5s, s = 0 + 1/2(10)(5*5) = 125 m.

At t = 6s, s = 0 + 1/2(10)(6*6) = 160 m.

Therefore, the displacement 'd' every second 't' are as follows,

t = 0, d = 0 m,

t = 1, d = 5 m,

t = 2, d = 20 m,

t = 3, d = 45 m,

t = 4, d = 80 m,

t = 5, d = 125 m,

t = 6, d = 160 m.

Answer:ELECTRIC current is defined to be the rate at which charge flows. A large current, such as that used to start a truck engine, moves a large AMOUNT of charge in a SMALL time, whereas a small current, such as that used to operate a hand-held calculator, moves a small amount of charge over a long period of time. In equation form, electric current I is defined to be

I

=

Δ

Q

Δ

t

,

where ΔQ is the amount of charge passing through a given area in time Δt. (As in previous chapters, INITIAL time is often taken to be zero, in which case Δt = t.) (See Figure 1.) The SI unit for current is the ampere (A), named for the French physicist André-Marie Ampère (1775–1836). Since I = ΔQ/Δt, we see that an ampere is one coulomb PER second:

1 A = 1 C/s

Not only are fuses and circuit breakers rated in amperes (or amps), so are many electrical appliances.

Explanation:

ANSWER:

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Answer:

10 Hz

Explanation:

FREQUENCY= NUMBER of oscillation/time TAKEN

= 10/1 = 10 Hz

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ANSWER:

I WANT to KNOW the answer

Answer:

use the formula: force of gravity = mg, where m is the MASS of the object andg is the acceleration of the object DUE togravity. Since g is ALWAYS 9.8 m/s^2, just MULTIPLY the object's mass by 9.8 and you'll get its force of gravity

Answer:

Check the correctness of physical equation, s = ut +1/2at2, Where U is the initial VELOCITY, v is the final velocity, a is the acceleration, s is the displacement and t is the time in which the change occurs. From (1) and (2) we have [L.H.S.] = [R.H.S.]

ANSWER: 40w

Explanatioansn:if LAMP TAKE 250V and 100w

When lamp take 100v and x w

•: 100×100/250=x which will be 40w

Sorry for bad English

Answer:

VOLTAGE drives current while resistance impedes it.

Ohm ‘s Law refers to the PROPORTION relation between voltage and current. It also applies to the specific equation V=IR, which is valid when considering circuits that contain SIMPLE resistors (whose resistance is independent of voltage and current).

Circuits or components that obey the relation V=IR are KNOWN as ohmic and have current-voltage plots that are linear and PASS through the origin.

There are components and circuits that are non-ohmic; their I-V plots are not linear and/or don’t pass through the origin.